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Related Questions
PLEASE HELP MARKING AS BRAINLIST!
Answers
Hello :)
P(A) = 1/2
P(B) = 5 or greater = 5,6 => 2/6 = 1/3
P(A and B) = 1/2 x 1/3 = 1x1/2x3 = 1/6 ≈ 0.17
the answer is 0.17
convert an effective rate of 14,5% per annum, to a nominal rate per annum compounded half yearly
Answers
The nominal rate per annum compounded half-yearly, equivalent to an effective rate of 14.5% per annum, is approximately 14.900625%.
To convert an effective rate to a nominal rate compounded half-yearly, we can use the formula:
Nominal rate [tex]= (1 + r/m)^m - 1[/tex]
Where:
r = effective rate
m = number of compounding periods per year
In this case, the effective rate is 14.5% per annum, and we want to convert it to a nominal rate compounded half-yearly.
Since compounding is done semi-annually, m would be 2.
Plugging in the values:
Nominal rate [tex]= (1 + 0.145/2)^2 - 1[/tex]
Simplifying the expression inside the parentheses:
Nominal rate [tex]= (1 + 0.0725)^2 - 1[/tex]
Calculating the exponent:
Nominal rate [tex]= (1.0725)^2-1[/tex]
Performing the calculations:
Nominal rate = 1.14900625 - 1
Nominal rate = 0.14900625
Converting the nominal rate to a percentage:
Nominal rate = 14.900625%
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Snacknow, a food service firm, is calculating its monthly productivity report. From the following raw data calculate the labor, Multifactor, and Energy productivity.
Labor rate $10
Units produced 10,000
Labor hours 1,000
Cost of materials $2000
Cost of energy $500
Answers
The calculated productivities are:
Labor Productivity: 10 units per labor hour.
Multifactor Productivity: 0.8 units per dollar.
Energy Productivity: 20 units per dollar.
Answers to the aforementioned questionsTo calculate the labor productivity, divide the units produced by the labor hours:
Labor Productivity = Units Produced / Labor Hours
Labor Productivity = 10,000 / 1,000 = 10 units per labor hour.
To calculate the multifactor productivity, divide the units produced by the sum of labor, material, and energy costs:
Multifactor Productivity = Units Produced / (Labor Cost + Material Cost + Energy Cost)
In this case, the labor cost is $10 per labor hour, so the labor cost is 1,000 labor hours * $10 = $10,000.
The material cost is $2,000, and the energy cost is $500.
Multifactor Productivity = 10,000 / ($10,000 + $2,000 + $500)
Multifactor Productivity = 10,000 / $12,500 = 0.8 units per dollar.
Finally, to calculate the energy productivity, divide the units produced by the energy cost:
Energy Productivity = Units Produced / Energy Cost
In this case, the units produced are 10,000, and the energy cost is $500.
Energy Productivity = 10,000 / $500 = 20 units per dollar.
Therefore, the calculated productivities are:
Labor Productivity: 10 units per labor hour.
Multifactor Productivity: 0.8 units per dollar.
Energy Productivity: 20 units per dollar.
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simplify [tex]2x^{2} +10x\ x^{2}+2x-15[/tex]
Its a fraction
Answers
Answer: [tex]=\frac{2x}{x-3}[/tex]
Step-by-step explanation:
[tex]\frac{2x^{2} +10x}{x^{2} + 2x-15}[/tex] >Take out GCF(greatest common factor) on top
>factor the bottom, find 2 numbers that mulitply to
"c" term, -15 and adds to the "b" term, +2
>+5 and -3 mulitpy to -15 and add to +2
> put +5 and -3 into factored form on bottom
[tex]=\frac{2x(x+5)}{(x-3)(x+5)}[/tex] >reduce the x+5 on top and bottom
[tex]=\frac{2x}{x-3}[/tex] >This is simplified
HELP!!!!!!!!!!!!!!!!!!
Answers
Answer:
D 0.89275
Step-by-step explanation:
PLSSA HELP ME
Describe a way to transform to . Be specific
Answers
The way to transform A to B is (1,-1).
We are given that;
The coordinates (-1,1),(-3,1),(-1,3) and (1,-1),(3,-1),(1,-3).
Now,
To transform the coordinates (-1,1),(-3,1),(-1,3) to (1,-1),(3,-1),(1,-3), you can apply a reflection about the origin. This transformation can be represented by the matrix [-1 0; 0 -1]. When you multiply this matrix with the original coordinates, you will get the transformed coordinates.
First, represent the point (-1,1) as a column vector:
[-1]
[ 1]
Then, multiply this vector by the reflection matrix [-1 0; 0 -1]:
[-1 0; 0 -1] * [-1] = [ 1]
[ 1] [-1]
Therefore, by transformation the answer will be (1,-1).
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For which situations would it be appropriate to calculate a probability about the difference in sample means?
1) Both population shapes are unknown. n1 = 50 and n2 = 100.
2) Population 1 is skewed right and population 2 is approximately Normal. n1 = 50 and n2 = 10.
3) Both populations are skewed right. n1 = 5 and n2 = 10.
4) Population 1 is skewed right and population 2 is approximately Normal. n1 = 10 and n2 = 50.
5) Both populations have unknown shapes. n1 = 50 and n2 = 100.
6) Both populations are skewed left. n1 = 5 and n2 = 40.
Answers
It is generally appropriate to calculate a probability about the difference in sample means when the sample sizes are large (typically n ≥ 30) and the populations are approximately normally distributed.
How did we arrive at this assertion?To determine if it is appropriate to calculate a probability about the difference in sample means, consider the assumptions and conditions for conducting a hypothesis test or constructing a confidence interval. The appropriateness of calculating a probability about the difference in sample means depends on the following factors:
1) Both population shapes are unknown. n1 = 50 and n2 = 100:
- It is generally appropriate to calculate a probability about the difference in sample means when the sample sizes are large (typically n ≥ 30) and the populations are approximately normally distributed. Since the population shapes are unknown in this case, it is difficult to assess this condition. However, the large sample sizes (n1 = 50 and n2 = 100) may suggest that it is reasonable to approximate the population distributions as normal. Therefore, calculating a probability about the difference in sample means could be considered.
2) Population 1 is skewed right and population 2 is approximately Normal. n1 = 50 and n2 = 10:
- In this case, the assumption of approximately normally distributed populations is violated for population 1, which is skewed right. When the population distributions are not approximately normal, it may not be appropriate to calculate a probability about the difference in sample means. The small sample size for population 2 (n2 = 10) may also limit the accuracy of any inference made based on this sample.
3) Both populations are skewed right. n1 = 5 and n2 = 10:
- Similar to the previous case, the assumption of approximately normally distributed populations is violated for both populations. Additionally, the small sample sizes (n1 = 5 and n2 = 10) may not provide sufficient information for reliable inferences. Therefore, it is generally not appropriate to calculate a probability about the difference in sample means in this situation.
4) Population 1 is skewed right and population 2 is approximately Normal. n1 = 10 and n2 = 50:
- Similar to case 2, the assumption of approximately normally distributed populations is violated for population 1, which is skewed right. In this case, the sample size for population 1 (n1 = 10) is also small, which may limit the accuracy of any inference made based on this sample. The larger sample size for population 2 (n2 = 50) might make it more reasonable to approximate the population distribution as normal. However, the violation of the assumption for population 1 suggests caution when interpreting the results. It is not generally appropriate to calculate a probability about the difference in sample means in this situation.
5) Both populations have unknown shapes. n1 = 50 and n2 = 100:
- Similar to case 1, the population shapes are unknown. However, the large sample sizes (n1 = 50 and n2 = 100) might suggest that it is reasonable to approximate the population distributions as normal. As mentioned before, calculating a probability about the difference in sample means could be considered in this case.
6) Both populations are skewed left. n1 = 5 and n2 = 40:
The assumption of approximately normally distributed populations is violated for both populations, as they are skewed left. Additionally, the small sample sizes (n1 = 5 and n2 = 40) may not provide sufficient information for reliable inferences. Therefore, it is generally not appropriate to calculate a probability about the difference in sample means in this situation.
Summarily, it is generally appropriate to calculate a probability about the difference in sample means when the sample sizes are large (typically n ≥ 30) and the populations are approximately normally distributed. However, when the population distributions are not approximately normal or when the sample sizes are small, it is generally not appropriate to calculate a probability about the difference in sample means.
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How many significant digits are in 26.04813?
Answers
7 significant figures.
Zeros that come at the start do not count as significant figures.
Eg. 0.0001 would only be 1 significant figure.
Zeros that come after is counted as a significant figure.
Eg. 2.20 Is three significant figures.
help please, i have a test tomorrow
Answers
The value of variables in the figure is,
⇒ x = 80
⇒ y = 70
We have to given that;
By using given figure we have to find the value of each variable.
Now, We can formulate;
⇒ 55 = 1/2 (180 - y)
Solve for y;
⇒ 55 × 2 = 180 - y
⇒ 110 = 180 - y
⇒ y = 180 - 110
⇒ y = 70
And, The value of x is,
⇒ x = 180 - (60 + 40)
⇒ x = 180 - 100
⇒ x = 80
Thus, The value of variables in the figure is,
⇒ x = 80
⇒ y = 70
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An employee started a new job and must enroll in a new family health insurance plan. One of the plans involves prescription drug coverage. The employee estimates that the entire family will fill 10 prescriptions per month, totaling $1,250. The employee has two options to choose from:
Option A: $94 monthly premium; 80% coverage for all prescription costs
Option B: $42 monthly premium; 75% coverage for first $500 in prescription costs, then 85% coverage for all prescription costs over $500
Which option would result in the highest overall cost for the employee, and by how much?
A) Option A has the highest overall cost by $64.50.
B)Option B has the highest overall cost by $64.50.
C) Option A has the highest overall cost by $106.50.
D) Option B has the highest overall cost by $106.50.
Answers
Option B has the highest overall cost by $64.50.
To determine the option that would result in the highest overall cost for the employee
we need to compare the costs of both options based on the estimated prescription drug expenses.
Option A:
Monthly premium: $94
Prescription coverage: 80%
Option B:
Monthly premium: $42
Prescription coverage: 75% for the first $500, 85% for costs over $500
Let's calculate the costs for each option:
Option A:
Total prescription drug cost: $1,250
Employee's share (20%): 20% × $1,250 = $250
Monthly premium: $94
Total cost for Option A: $250 + $94 = $344
Option B:
Total prescription drug cost: $1,250
Employee's share for the first $500 (25%): 25% × $500 = $125
Employee's share for costs over $500 (15%): 15% × ($1,250 - $500) = $112.50
Monthly premium: $42
Total cost for Option B: $125 + $112.50 + $42 = $279.50
Comparing the total costs for each option, we see that Option B has a lower overall cost for the employee.
Hence, Option B has the highest overall cost by $64.50.
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PLSSS FIND BOTH x’s THANK YOUUU
Answers
Hello!
Solutions = -3 and 1.5
Use the information above to answer the questions that follow.
2.2.1
2.2.2
2.2.3
2.2.4
sanitation in Johannesburg if a property is 175 m².
Write down, to the nearest ten cents and excluding VAT, the cost for
Calculate the cost for 4,1 ke sanitation in Cape Town before the increase.
Mr Jones lives in Johannesburg and Ms Brown lives in Cape Town. They
both own a property with an area of 550 m² and each was billed for 22 kl
sanitation.
Use the table above to determine the difference in the cost of sanitation
for the two properties.
Explain how the tariff system used in Johannesburg is beneficial to
home owners in terms of water usage.
(2)
(8)
(2)
[34]
mor
MO
ud.
0
0
Answers
Mr. Jones in Johannesburg is billed R9,767.12 and Ms. Brown in Cape Town is billed R680.24 for their respective properties.
From the provided information for Cape Town's sanitation tariffs:
0-4.2 kl: R16.03 per kl
Since 4.1 ke is equivalent to 4100 liters, which is less than 4.2 kl, we can use the tariff rate for the 0-4.2 kl range.
Cost for 4.1 ke of sanitation
= 4.1 ke x R16.03 per kl
= 4100 liters x R16.03 per kl
= R65.83
For Mr. Jones and Ms. Brown, who own properties with an area of 550 m² each and were billed for 22 kl of sanitation.
we need to determine the applicable tariff rate based on the property size and calculate the cost.
In Johannesburg, based on the provided information, the tariff rate for properties larger than 300 m² to 1,000 m² is R443.96.
Cost of sanitation for Mr. Jones in Johannesburg:
= 22 kl x R443.96 per kl
= R9,767.12
Cost of sanitation for Ms. Brown in Cape Town:
= 22 kl x R30.92 per kl = R680.24
Therefore, Mr. Jones in Johannesburg is billed R9,767.12 and Ms. Brown in Cape Town is billed R680.24 for their respective properties.
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highest common factor of a² + ab and ab + b²
Answers
[tex]a^2+ab=a(a+b)\\ab+b^2=b(a+b)[/tex]
Therefore
[tex]\text{hcf}(a^2+ab,ab+b^2)=a+b[/tex]
how to find the base area of a rectangular prism from length width and volume
Answers
If you want to find the base area of a rectangular prism, then all you need is length and width only.
[tex] \boxed{Volume = length \times width \times height} [/tex]
You don't need height. So, this is a must be easy.
[tex]\blue{\small{\mathfrak{That's \: it. \: Thanks \::)}}} [/tex]
The cost of 1kg potatoes and 2kg tomatoes was 30 on a certain day. After two days the cost of 2kg potatoes and 4kg tomatoes was found to be 66.
Answers
Let's represent the cost of 1kg of potatoes as 'p' and the cost of 1kg of tomatoes as 't'.
From the first statement, we know that:
1p + 2t = 30 (Equation 1)
From the second statement, we know that:
2p + 4t = 66 (Equation 2)
We can now solve this system of equations to find the values of 'p' and 't'.
Multiplying Equation 1 by 2, we get:
2p + 4t = 60 (Equation 3)
Now, we can subtract Equation 2 from Equation 3 to eliminate 'p':
(2p + 4t) - (2p + 4t) = 60 - 66
0 = -6
This implies that there is no consistent solution for the given system of equations.
The cost of 3kg potatoes and 3kg tomatoes on the day was 54.
Please help urgent thank you so much
Answers
Answer: 4, 14
Step-by-step explanation:
Bring everything over to other side that is not in the absolute value:
3 |x - 9| + 5 = 20 >Subtract 5 from both sides
3 |x - 9| = 15 >Divide both sides by 3
|x - 9| = 5 >Create a positive and negative version to
drop the absolute value
x - 9 = 5 x - 9 = -5
x= 14 x = 4
A normal distribution has a mean of 137 and a standard deviation of 6. Find the z-score for a data value of 155.
Round to two decimal places
Answers
Answer:
3
Step-by-step explanation:
To find the z-score for a data value of 155 in a normal distribution with a mean of 137 and a standard deviation of 6, you can use the formula:
z = (x - μ) / σ
where:
x is the data value,
μ is the mean, and
σ is the standard deviation.
Plugging in the values, we have:
z = (155 - 137) / 6
Calculating this expression:
z = 18 / 6 = 3
Give a rational Number between 4/7 and 6/11
Answers
Hello!
4/7 = 44/77
6/11 = 42/77
42/77 < 43/77 < 44/77
the rationnal number between 4/7 and 6/11 is 43/77
Function c
is defined by the equation c(n)=50+4n
. It gives the monthly cost, in dollars, of visiting a gym as a function of the number of visits, n
.
True or False? The inverse function is as follows:
n=(c(n) − 50)×4
Responses
Answers
Answer:
False
Step-by-step explanation:
1. The inverse function should have c(n) isolated
2. When finding the inverse of a function, the variables c(n) and n are interchanged (and then c(n) is isolated).
It would look like this --->c(n)=50+4n--->n=50+4(c(n)) ---> c(n)=(n-50)/4
Draw a box plot for each set of data. {65,92,74,61,55,35,88,99,97,100,96} Cost of MP3 Players ($)
Answers
A construction of the box-and-whisker plot representing the data set is shown below.
What is a box-and-whisker plot?In Mathematics and Statistics, a box-and-whisker plot and it can be defined as a type of chart that can be used to graphically or visually represent the five-number summary of a data set with respect to locality, skewness, and spread.
Based on the data (information) provided above, the five-number summary for the given data set include the following:
Minimum (Min) = 35.First quartile (Q₁) = 61.Median (Med) = 88.Third quartile (Q₃) = 97.Maximum (Max) = 100.In conclusion, we can logically deduce that the maximum number is 100 while the minimum number is 35, and the median is equal to 88.
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PLEASE HELP ASAP
ANSWE
Answers
Answer:
664 Square yards
Step-by-step explanation:
Surface area= 2lw+2lh+2hw
=2(17×6)+2(17×10)+2(10×6)
=2(102)+2(340)+2(120)
=204+340+120
=664 Square yards
Find the area of a circle with radius,
r
= 42cm.
Give your answer rounded to 3 SF.
Answers
Answer:
5541.77 cm^2
Step-by-step explanation:
Alice was provided with the following trinomial: 3x² + 7x-12x - 34 - 2x² + 10 1 Provide Alice with a step-by-step guide on how to factorize the algebraic expression.
Answers
Hello!
[tex]3x^{2} + 7x-12x - 34 - 2x^{2} + 10\\\\3x^{2}- 2x^{2} + 7x-12x - 34 + 10\\\\x^{2} - 5x - 24\\\\x^{2} + 3x - 8x - 24\\\\(x^{2} + 3x) + (-8x - 24)\\\\x(x + 3) - 8(x + 3)\\\\\boxed{(x - 8)(x+3)}[/tex]
During a normal day, there are 782 passengers in average that
are late for their plane each day. However, during the
Christmas holidays, there are 1,835 passengers that are late for
their planes each day which caused delays of 14 planes. How
many more passengers are late for their planes in each day
during the Christmas holidays?
i picked 4th grade lol
Answers
During the Christmas holidays, there are 1,053 more passengers who are late for their planes each day compared to a normal day.
To solve this problemCalculating the difference between the quantity of late passengers on a typical day and the quantity of late passengers on holidays is necessary.
1,835 travellers were late over the Christmas break.
On an average day, there are 782 travelers who are late.
Difference = Number of late passengers during the Christmas holidays - Number of late passengers on a normal day
Difference = 1,835 - 782
Difference = 1,053
Therefore, during the Christmas holidays, there are 1,053 more passengers who are late for their planes each day compared to a normal day.
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Answer:
Step-by-step explanation:
During the Christmas holidays, there is an increase of 1,053 passengers who are late for their planes each day compared to the average daily number of 782 passengers who are late. This surge in late passengers during the holiday period contributes to delays in 14 planes.
The higher volume of travelers, combined with potential factors like weather conditions, congestion, and heightened travel demand, likely leads to a greater number of individuals encountering delays and difficulties reaching their departure gates on time.
Hope it helps! :)
The Tenorio Dairy makes cheese to supply to stores in its area. The dairy can make 250 pounds of cheese per day, and the demand at area stores is 180 pounds per day. Each time the dairy makes cheese, it costs $125 to set up the production process. The annual cost of carrying a pound cheese in a refrigerated storage area is $12. Determine the optimal size and the total annual inventory cost.
Answers
Answer:
The optimal size of each production run is 180 pounds, and the total annual inventory cost is $832,825.
Step-by-step explanation:
To determine the optimal size and total annual inventory cost, we need to consider the production capacity, demand, setup costs, and carrying costs.
Given:
Production capacity per day = 250 pounds
Demand per day = 180 pounds
Setup cost = $125
Carrying cost per pound per year = $12
First, let's calculate the optimal production size. We want to produce enough cheese to meet the demand without exceeding the production capacity.
Optimal production size per day = Minimum(Production capacity, Demand)
Optimal production size per day = Minimum(250 pounds, 180 pounds) = 180 pounds
Next, let's calculate the total annual inventory cost. This cost includes both the setup cost and the carrying cost.
Total annual inventory cost = (Setup cost * Number of setups per year) + (Carrying cost per pound * Optimal production size * Number of days in a year)
Number of setups per year = Number of production runs per year
Number of production runs per year = Total days in a year / Days per production run
Assuming a year has 365 days and each production run takes one day:
Number of production runs per year = 365 days / 1 day = 365 runs
Total annual inventory cost = ($125 * 365) + ($12 * 180 pounds * 365)
Total annual inventory cost = $45,625 + $787,200
Total annual inventory cost = $832,825
Which of the following angles is not coterminal to
120°
A 180°
B. 240°
C. 840°
D. - 600°
Answers
Brainly needs this to be 20 characters long but it’s just c
All else being equal, if you cut the sample size in half, how does this affect the margin of error when using the sam
to make a statistical inference about the mean of the normally distributed population from which it was drawn?
ME-
Z.S
O The margin of error is multiplied by √0.5.
O The margin of error is multiplied by √√2-
O The margin of error is multiplied by 0.5.
O The margin of error is multiplied by 2.
Answers
Answer:
When you cut the sample size in half while making a statistical inference about the mean of a normally distributed population, the effect on the margin of error depends on the relationship between the sample size and the margin of error. Generally, the margin of error is inversely proportional to the square root of the sample size.
So, if you reduce the sample size by half, it means you are taking a smaller sample, which will result in a larger margin of error. In other words, the margin of error is multiplied by a factor greater than 1.
Among the given options, the correct answer is:
D. The margin of error is multiplied by 2.
This option correctly reflects the relationship between reducing the sample size by half and the resulting increase in the margin of error.
Help please, I need to get through geometry recovery class
Answers
To prove ∠AOW = 45°
Given,
∠WOZ = 90°
∠ZOB = 45°
Now,
∠XOA +∠AOW = 90°............(1)
∠XOA = ∠ZOB ( Vertically opposite angle )
∠XOA = 45°
Substitute in (1),
45° + 45° = 90°
Now,
∠WOX = ∠XOA +∠WOA
So,
∠WOA + ∠WOZ + ∠ZOB = 180°( Linear pair )
∠WOA + 90° + 45° = 180°
∠WOA = 45°
Hence proved.
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4+(1/5)[-10*(25-13-3)}÷(-5)]
Answers
Answer:
7.6
Step by step explanation
find the general term of the arithmetic sequence if a8=8, a20=44
Answers
Answer:
[tex]a_n=3n-16[/tex]
Step-by-step explanation:
[tex]a_n=a_1+(n-1)d\\\\a_8=a_1+(8-1)d\rightarrow 8=a_1+7d\\a_{20}=a_1+(20-1)d\rightarrow 44=a_1+19d[/tex]
[tex]-36=-12d\\3=d[/tex]
[tex]8=a_1+7(3)\\8=a_1+21\\-13=a_1[/tex]
[tex]a_n=-13+(n-1)(3)\\a_n=-13+3n-3\\a_n=3n-16[/tex]