Answer:The period of a pendulum, as measured by an observer moving at a relativistic velocity with respect to the pendulum, can be calculated using the concept of time dilation from special relativity.
The formula for time dilation in special relativity is given by:
Δt' = Δt / sqrt(1 - (v^2 / c^2))
where:
Δt' is the time interval measured by the moving observer
Δt is the time interval measured in the rest frame of the pendulum
v is the relative velocity between the pendulum and the moving observer
c is the speed of light in vacuum
In this case, the relative velocity between the pendulum and the moving observer is 0.95c, where c is the speed of light in vacuum (approximately 3 x 10^8 meters per second). Let's assume the period of the pendulum as measured in its rest frame is 3 seconds.
Plugging in the values into the formula:
Δt' = 3 / sqrt(1 - (0.95c)^2 / c^2)
Simplifying the expression:
Δt' = 3 / sqrt(1 - 0.95^2)
Using a calculator to evaluate the square root and simplify further, we get:
Δt' = 3 / sqrt(0.0975)
Δt' = 3 / 0.3125
Δt' ≈ 9.6 seconds
So, the period of the pendulum, as measured by an observer moving at a speed of 0.95c (95% of the speed of light) with respect to the pendulum, would be approximately 9.6 seconds. This demonstrates the concept of time dilation in special relativity, where the observed time interval changes due to relative motion at relativistic velocities.
Explanation:
5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?
The traffic cop needs 23.3 seconds to pass the automobile.
What is the acceleration of a car moving in a straight line at a constant speed?When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.
[tex]d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m[/tex]
[tex]d = d1 = 35.0 m[/tex]
[tex]d2 = v2*t + (1/2)at^2[/tex]
[tex]d2 = (1/2)at^2[/tex]
[tex]v2*t + (1/2)at^2 = (1/2)at^2[/tex]
[tex]v2*t = (1/2)at^2[/tex]
Solving for t, we get:
[tex]t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s[/tex] (rounded to 2 decimal places)
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What new question occurred to scientists after they discovered that the
ocean floor was not flat?
O A. Are there bathtubs that have shapes similar to that of the Mid-
Atlantic Ridge?
OB. Why is the ocean floor not flat and smooth like the bottom of a
bathtub?
C. How much cable will it take to go from North America to England?
OD. How deep is the ocean?
Answer:
b
Explanation:
The answer is B. Why is the ocean floor not flat and smooth like the bottom of a bathtub?
Scientists were surprised to find that the ocean floor was not a flat and featureless plain, but rather had mountains, valleys, and other geological features. This discovery raised questions about how these features formed and what processes were involved. Scientists began to investigate the causes of these features, such as plate tectonics and volcanic activity, and how they might have shaped the ocean floor over millions of years. Understanding the complex and dynamic nature of the ocean floor has since become an important area of study in earth science and oceanography.
Mathias is going to do some informational interviewing. What is one of the main benefits of doing these interviews?
O A.
OB.
O C.
O D.
A.He will gain insight about a new career opportunity.
B.He will likely be offered a position with a company.
C.He will be able to ask questions about job openings.
D.He will find out how much money everyone earns.
Answer:
A
Explanation:
One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.
Ozone intake can cause irritation in what system of the body?
A. Respiratory
B. Immune
C. Nervous
D. Circulatory
A. Ozone intake can cause irritation in the respiratory system of the body. Ozone is a gas composed of three oxygen atoms that can be harmful when inhaled. It can irritate the lungs and cause inflammation, making it difficult to breathe. Prolonged exposure to ozone can lead to respiratory problems such as asthma, bronchitis, and emphysema. Ozone can also affect other systems of the body, such as the immune system, but respiratory irritation is the most common and well-documented effect.
Find the ratio of the coulomb electric force Fe to the gravitational force Fg between two electrons in vacuum.
What is the SI unit that is equal to 0.01 meters?
Answer:one centimeter is equal to one hundredth of a meter (1 cm = 0.01 m).
Explanation:
Which of the following statements best summarizes the law of conservation of energy before and after a change in a system?
A. The potential energy is the same before and after the change, and
the kinetic energy is the same before and after the change.
B. The sum of the potential energy before and after the change
equals the sum of the kinetic energy before and after the change.
C. The sum of the potential energy and the kinetic energy before the
change equals the sum of the potential energy and the kinetic
energy after the change.
D. The potential energy equals the kinetic energy before the change
and after the change.
The statement that best summarizes the law of conservation of energy before and after a change in a system is "The sum of the potential energy and the kinetic energy before the change equals the sum of the potential energy and the kinetic energy after the change"
What is the law of conservation of energy?The law of conservation of energy is a fundamental principle of physics that states that the total amount of energy in a closed system remains constant over time. This means that energy cannot be created or destroyed, only transformed from one form to another.
The above statement summarizes the law of conservation of energy, which states that energy cannot be created or destroyed, only transformed from one form to another. The total amount of energy in a closed system remains constant before and after any change, even though the energy can change from one form to another.
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Determine the correct address of Earth in the Universe.
A. Observable universe, Sagittarius A supercluster, Orion Arm, Milky Way galaxy, Sol System, Planet 3
B. Observable universe, Sagittarius A supercluster, Virgo Arm, Milky Way galaxy, Sol System, Planet 4
C. Observable universe, Virgo supercluster, Sol Arm, Milky Way galaxy, Orion System, Planet 3
D. Observable universe, Virgo supercluster, Milky Way galaxy, Orion Arm, Sol System, Planet 3
Answer::
The earth is planet 3 in the solar system,
That leaves only A and D
Since the solar system is also within the Milky Way galaxy that leaves only
(A) must be the correct answer
find a recent (less than 5 years old) article addressing some aspect of
environmental science that we have covered so far this year.
"Greenland ice sheet melting at alarming rate of 8,300 tonnes per second" is a recent article addressing some aspect of environmental science that we have covered so far this year.
This article, published in The Guardian in January 2021, addresses the melting of the Greenland ice sheet, which is a topic covered in environmental science. The article highlights a new study that found the ice sheet is melting at a rate of 8,300 tonnes per second, which is seven times faster than in the 1990s.
The melting of the Greenland ice sheet contributes significantly to rising sea levels and could have disastrous consequences for coastal communities worldwide. The article discusses the causes and potential consequences of this rapid melting, as well as the urgent need for action to mitigate climate change and its effects. This topic relates to the study of climate change, the cryosphere, and the impacts of human activity on the environment.
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Estimate the power in [kW] of a "realistic ocean wave" captured by a wave-power station over a crest-length of 10 m, with the wave parameters characteristic of the Baltic sea: wave height of 1.25 m, wave period of 5 s (e.g., Northern Gotland Basin).
O a. 5
O b. 40
O c. 25
O d. 250
O e. 100
The power in kilowatts (kW) of a realistic ocean wave is 40 kW.
option B.
What is the realistic power?The power in kilowatts (kW) of a realistic ocean wave can be estimated using the following formula:
Power (kW) = 0.5 x (Crest Length in meters) x (Wave Height in meters)^2 x (Wave Period in seconds) x (Density of Water in kg/m^3) x (Gravity in m/s^2)
Given the wave parameters for the Baltic Sea: wave height of 1.25 m, wave period of 5 s, and a crest length of 10 m, we can plug in these values to calculate the power.
Wave height (H) = 1.25 m
Wave period (T) = 5 s
Crest length (L) = 10 m
Density of water (ρ) = 1025 kg/m^3 (typical value for sea water)
Gravity (g) = 9.81 m/s^2 (typical value on Earth)
Plugging in these values into the formula:
Power (kW) = 0.5 x 10 x (1.25)^2 x 5 x 1025 x 9.81
Calculating the above expression, we get:
Power ≈ 40 kW
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A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355-L cans per minute. At point 2 in the pipe, the gauge pressure is 152 kPa and the cross-sectional area is 8.00 cm2. At point 1, 1.35 m above point 2, the cross-sectional area is 2.00 cm2.
Find the gauge pressure at point 1.
Express your answer in kilopascals
The gauge pressure at point 1 = 145.2 kPa.
What is Bernoulli's equation?The equation states that the sum of the pressure, kinetic energy, and potential energy per unit volume of a fluid is constant along a streamline, in the absence of external forces like friction or viscosity.
The principle of continuity of mass flow rate and Bernoulli's equation, which connects pressure, velocity, and height of a fluid in a flow, can be used to solve this issue.
With the provided data, we can first determine the soft drink's mass flow rate:
mass flow rate =[tex](220 cans/min) x (0.355 L/can) x (1 kg/L) x (1 min/60 s)[/tex] = [tex]1.235 kg/s[/tex]
Then, we may compare the soft drink's velocities at positions 1 and 2 using the principle of continuity:
[tex]A1 v1 = A2 v2[/tex]
where A1 and A2 are the pipe's cross-sectional areas at points 1 and 2, respectively, and v1 and v2 are the soft drink's velocities at those same locations. When we solve for v1, we get:
[tex]v1 = (A2/A1) v2 = (8.00 cm^2)/(2.00 cm^2) v2 = 4 v2[/tex]
Now, we can link the pressures, velocities, and heights of the soft drink at points 1 and 2 using the Bernoulli's equation:
P1 + (1/2)ρv1²+ ρgh1 = P2 + (1/2)ρv2²+ ρgh2
where P1 and P2 are the gauge pressures at points 1 and 2, respectively; ρ is the soft drink's density; g is gravity's acceleration; and h1 and h2 are the heights of the respective points 1 and 2 above a reference level.
As the soft drink contains primarily water, we may calculate its density using the formula: = 1000 kg/m3. Moreover, we can decide to set the reference level at point 2, making h2 = 0.When the supplied values and the velocity relation are substituted, we obtain:
[tex]P1 + (1/2)(1000 kg/m^3)(16 v2^2) + (1000 kg/m^3)(9.81 m/s^2)(1.35 m)[/tex] =[tex]152 kPa + (1/2)(1000 kg/m^3)(v2^2)[/tex]
By condensing and figuring out P1, we get at:
[tex]P1 = 152 kPa + (1/2)(1000 kg/m^3)(15 v2^2) - (1000 kg/m^3)(9.81 m/s^2)(1.35 m)[/tex] = [tex]152 kPa + 6.75 v2^2 - 13.33 kPa[/tex]
We must now locate v2. We can link the velocity and the cross-sectional area at point 2 using the mass flow rate relation and the density of the soft drink:
[tex]A2 v2[/tex] = (mass flow rate)/ρ =[tex]1.235/(1000 kg/m^3)[/tex]= [tex]0.001235 m^3/s[/tex]
Upon solving for v2, we obtain:
v2 =[tex]0.001235 m^3/s / (8.00 cm^2 / 10000 cm^2)[/tex]= [tex]0.1544 m/s[/tex]
Last but not least, we can insert this value into the P1 expression to obtain:
[tex]P1[/tex] =[tex]152 kPa + 6.75 (0.1544 m/s)^2 - 13.33 kPa[/tex] = [tex]145.2 kPa[/tex]
As a result, point 1's gauge pressure is 145.2 kPa.
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URGENT QUICK N EASY!
50 POINTS!
LOOK AT THE PICTURE!!
PART C!!
Find the maximum magnitude of the acceleration.
Express your answer using two significant figures.
1. The period of the mass is 0.47 second
2. The amplitude is 0.02 m
1. How do i determine the period?The period of the mass can be obtained as illustrated below:
Mass attached (m) = 0.95 KgSpring constant of spring (K) = 170 N/mPi (π) = 3.14Period (T) =?T = 2π√(m/k)
T = (2 × 3.14) × √(0.95 / 170)
T = 6.28 × √(0.95 / 120)
T = 0.47 second
Thus, from the above calculation, we can conclude that the period is 0.47 second
2. How do i determine the amplitude?The amplitude of the wave can be obtained as shown below:
Mass attached (m) = 0.95 KgSpring constant of spring (K) = 170 N/mMaximum speed (v) = 0.25 m/sAmplitude (A) =?A = v√(m/k)
A = 0.25 × √(0.95 / 170)
A = 0.02 m
Thus, the amplitude is 0.02 m
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Many chemical reactions release energy. Suppose that at the beginning of a reaction, an electron and proton are separated by 0.115 nm , and their final separation is 0.105 nm . How much electric potential energy was lost in this reaction (in units of eV)?
The electric potential energy lost in this reaction is approximately 2.81 eV.
What is potential energy?
To calculate the electric potential energy lost in this reaction, we first need to calculate the difference in electric potential energy between the initial and final states. We can use the following formula to calculate electric potential energy:
E = kq1q2/r
where E is the electric potential energy, k is Coulomb's constant (8.99 x [tex]10^{9}[/tex] N*m²/C²), q1 and q2 are the charges of the two particles, and r is the separation distance between them.
In this case, we have an electron and a proton, which have charges of -1.602 x [tex]10^{-19}[/tex] C and +1.602 x [tex]10^{-19}[/tex] C, respectively. The initial separation distance is 0.115 nm, which is 1.15 x [tex]10^{-10}[/tex] m, and the final separation distance is 0.105 nm, which is 1.05 x [tex]10^{-10}[/tex] m.
So, the initial electric potential energy is:
E_initial = kq_electronq_proton/r_initial
= (8.99 x [tex]10^{9}[/tex] N*m²/C²) * (-1.602 x [tex]10^{-19}[/tex] C) * (1.602 x [tex]10^{-19}[/tex] C) / (1.15 x [tex]10^{-10}[/tex] m)
= -1.44 x [tex]10^{-18}[/tex] J
And the final electric potential energy is:
E_final = kq_electronq_proton/r_final
= (8.99 x [tex]10^{9}[/tex] N*m²/C²) * (-1.602 x [tex]10^{-19}[/tex] C) * (1.602 x [tex]10^{-19}[/tex] C) / (1.05 x [tex]10^{-10}[/tex] m)
= -1.89 x [tex]10^{-18}[/tex] J
The electric potential energy lost in this reaction is:
ΔE = E_final - E_initial
= (-1.89 x [tex]10^{-18}[/tex] J) - (-1.44 x [tex]10^{-18}[/tex] J)
= -0.45 x [tex]10^{-18}[/tex] J
To express the electric potential energy lost in units of eV, we can use the following conversion factor:
1 eV = 1.602 x [tex]10^{-19}[/tex] J
So, the electric potential energy lost in this reaction is:
ΔE = (-0.45 x [tex]10^{-18}[/tex] J) / (1.602 x [tex]10^{-19}[/tex] J/eV)
= -2.81 eV
Therefore, the electric potential energy lost in this reaction is approximately 2.81 eV.
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Observe the distance between the compressions shown in the image. What do you notice about the sound waves in front of the truck compared to the sound waves behind the truck? Was your prediction correct?
The sound waves in front of the truck compared to the sound waves behind the truck is using Doppler effect.
The prediction is correct.
What is the doppler effect?The Doppler effect or Doppler shift is described as the apparent change in frequency of a wave in relation to an observer moving relative to the wave source.
The apparent frequency heard by the listener differs from the frequency of the source of sound when there is relative motion between the source and listener.
The perceived frequency increases as the source and the listener go closer together, and it decreases as they get farther apart. It's called the Doppler effect.
The wave-fronts move closer as the source and listener approach closer to each other. Thus, the observed frequency is greater than the actual.
The pitch depends on frequency, greater is the pitch
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Figure B5.1 below is a diagram showing a wave travelling along a string in the direction shown
Figure B5.1 is a diagram showing a wave travelling along a string. The wave is propagating in the rightward direction, as indicated by the curved arrows.
What is direction?Direction is a type of guidance that provides the recipient with specific instructions on how to proceed. Direction can involve information on where to go, what to do, or what to avoid. It could be used to provide instructions on a task, a journey, or an event. Direction could also be used to provide motivation and help someone stay focused on their goals. Direction can be provided verbally, through writing, or through body language. It can come from a supervisor, a teacher, or a parent. Direction is important in helping someone follow their path and achieve their goals.
The wave is depicted by a series of oscillations along the string, represented by the vertical lines. The amplitude of the wave is represented by the distance between the highest and lowest points of the oscillations. As the wave travels in the rightward direction, the oscillations move along the string, and the amplitude remains unchanged.
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A water wave travels a distance of 30m in 15s. What is the wave's speed in m/s?
substitute d = 30 into formula
v = 15 d = v x t
30 = 15t
30/15 or 30 over 15 fraction :)
simplify
=
2
answer = 2
I hope this helps, this is what I know, I'm sorry if it's wrong :(
If the fundamental frequency of this harmonic is 7 Hz, at which frequency is this created? (Just type the number, not the units) pic attached below
If the fundamental frequency of the harmonic is 7 Hz, the frequency at which it is created depends on the harmonic being referred to.
How do we explain?Frequency of harmonics
If the fundamental frequency of a harmonic is 7 Hz, then the frequency at which the harmonic is created depends on the harmonic series being used.
The frequency of the nth harmonic in a harmonic series is equal to n times the fundamental frequency. Therefore, the first five harmonics of a harmonic series with a fundamental frequency of 7 Hz would be:
First harmonic (fundamental): 7 Hz
Second harmonic: 2 x 7 Hz = 14 Hz
Third harmonic: 3 x 7 Hz = 21 Hz
Fourth harmonic: 4 x 7 Hz = 28 Hz
Fifth harmonic: 5 x 7 Hz = 35 Hz
So, the frequency at which the harmonic with a fundamental frequency of 7 Hz is created depends on which harmonic is being referred to.
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If the coefficients of static and kinetic friction between the 20 kg block A and the 100 kg cart B are both essentially the same value of 0.50, determine the acceleration of each part for (a) F = 60 N and (b) F = 40 N. by drawing free body diagram
For F = 60 N, the acceleration of both block A and cart B is 2.38 m/s^2, while for F = 40 N, block A and cart B have accelerations of -0.81 m/s^2 and -0.40 m/s^2 respectively, both moving backwards.
To determine the acceleration of block A and cart B, we need to draw a free body diagram for each object and apply Newton's second law, F = ma.
(a) When F = 60 N:
The forces acting on block A are the force of friction f1, the force of gravity mg1, and the applied force F. The forces acting on cart B are the force of friction f2 and the force of gravity mg2. Since the two objects are connected by a rope, they have the same acceleration a.
For block A:
F - f1 = ma
For cart B:
f1 - f2 = (m1 + m2)a
mg2 - F = m2a
Using the coefficient of friction, we can find the force of friction:
f1 = μ1N1 = μ1mg1
f2 = μ2N2 = μ2mg2
where N1 and N2 are the normal forces acting on block A and cart B, respectively.
Since the coefficient of friction is the same for both static and kinetic friction, we can assume that the block and cart are not moving relative to each other. Therefore, we can use the coefficient of static friction to find f1 and f2.
μs = 0.5
N1 = m1g1 = [tex](20 kg)(9.8 m/s^2) = 196 N[/tex]
N2 = m2g2 = [tex](100 kg)(9.8 m/s^2) = 980 N[/tex]
f1 = μsN1 = (0.5)(196 N) = 98 N
f2 = μsN2 = (0.5)(980 N) = 490 N
Substituting these values into the equations above, we get:
60 N - 98 N = 20 kg a
98 N - 490 N = (20 kg + 100 kg) a
980 N - 60 N = 100 kg a
Solving for a, we get:
[tex]a = 2.38 m/s^2[/tex] for both block A and cart B.
(b) When F = 40 N:
Following the same steps as in part (a), we can find:
μs = 0.5
N1 = m1g1 =[tex](20 kg)(9.8 m/s^2) = 196 N[/tex]
N2 = m2g2 = [tex](100 kg)(9.8 m/s^2) = 980 N[/tex]
f1 = μsN1 = (0.5)(196 N) = 98 N
f2 = μsN2 = (0.5)(980 N) = 490 N
Substituting these values into the equations above, we get:
40 N - 98 N = 20 kg a
98 N - 490 N = (20 kg + 100 kg) a
980 N - 40 N = 100 kg a
Solving for a, we get:
[tex]a = -0.81 m/s^2[/tex]for block A, indicating that it is moving backwards, and[tex]a = -0.40 m/s^2[/tex] for cart B, indicating that it is also moving backwards.
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A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 5.50×10−5T and points into the Earth at an angle of 58.0 below a line pointing due north. A 6.90-A clockwise current passes through the coil.
The Earth's magnetic field at the location has a magnitude of 5.50×10^−5 T and points into the Earth at an angle of 58.0 degrees below a line pointing due north.
What is Magnetic Field?
A magnetic field is a region of space surrounding a magnet or a current-carrying conductor in which magnetic forces are exerted on other magnetic objects or moving charged particles. Magnetic fields are characterized by their direction, magnitude, and polarity. The direction of a magnetic field is defined as the direction in which a magnetic north pole would be pulled or aligned, and is conventionally represented by magnetic field lines that form closed loops.
Based on the information provided, it seems like you have described a situation where a circular coil with a diameter of 14.0 cm and containing nine loops is lying flat on the ground.
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A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 5.00×10−5T and points into the Earth at an angle of 58.0 ∘ below a line pointing due north. A 6.90-A clockwise current passes through the coil. Determine the torque on the coil, and which edge of the coil rises up: north, east, south, or west?
what is parallel universe ?
Answer:
I really hope this helps.:)
Explanation:
A parallel universe, also known as a parallel dimension, alternate universe, or alternate reality, is a hypothetical self-contained plane of existence, co-existing with one's own. The sum of all potential parallel universes that constitute reality is often called a "multiverse".
A bus travelling 80 km/h accelerates for 20 seconds to a speed of 100 km what is the acceleration 
A block of wood weighing 15 N rest on top of the table. How mush force is exerted by the table on the blockso that it will remainat rest. Explain your answer
The force exerted by the table on the block to keep it at rest is equal in magnitude but opposite in direction to the force exerted by the block on the table.
This is due to Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.Therefore, the force exerted by the table on the block is 15 N, the weight of the block. This is because the block is at rest and not accelerating, which means that the net force acting on it must be zero.
Since the force of gravity acting on the block is 15 N and it is not accelerating, the force exerted by the table on the block must also be 15 N but in the opposite direction, which balances out the gravitational force.
In summary, the force exerted by the table on the block to keep it at rest is 15 N, which is equal in magnitude but opposite in direction to the force exerted by the block on the table.
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What affects how much gravitational force the objects will exert on each other? O A. the objects' masses and the distance between them O B. O C. Object 1 the objects' shapes and colors the objects' masses and their surface areas O D. the objects' surface areas and distance between them
The objects' masses and the distance between them affects how much gravitational force the objects will exert on each other. Hence option A is correct.
Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F ∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
This is analogous with coulomb's law which gives force between two charges.
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A 2.3 kg block on a frictionless incline of 27 degrees. The acceleration of gravity is 9.8 m/s2. Answer in units of ms. What is the normal force on the block...
The normal force on the block is approximately 20.05 N.
What is force acting on a body?Force describes the interaction between objects or between an object and its environment. It causes a change in the motion of the body it acts upon.
The normal force, which counteracts the force of gravity dragging the block downward, is the force generated by the slope acting perpendicular to its surface. As the incline has no friction, there is no force acting parallel to its surface.
To ascertain the parts of the force of gravity pulling on the block, we can apply trigonometry. There are two parts to the force of gravity: one that is parallel to the incline's surface and the other that is perpendicular to it. The weight of the block, mg, where m is its mass and g is its gravitational acceleration, is equal to the component of gravity perpendicular to the inclination. mg sin θ, where is the angle of the incline, is the component of gravity that is parallel to the incline.
To calculate the acceleration of the block moving down the incline, we can apply Newton's second law, F = ma. The component of gravity parallel to the inclination, or mg sin θ, represents the net force exerted on the block. As a result, we have:
[tex]mg sin(theta) = ma[/tex]
To solve for a, we obtain:
[tex]a = g sin(theta)[/tex]
Substituting the given values, we get:
[tex]a = 9.8 m/s^2 * sin(27°)[/tex] ≈ [tex]4.69 m/s^2[/tex]
Now that we know the normal force acting on the block, we can use Newton's second law once more. The component of gravity's force perpendicular to the incline is equal in magnitude to the normal force and moves in the opposite direction. As a result, we have:
[tex]mg cos(theta) = N[/tex]
Inputting the values provided yields:
[tex]N = 2.3 kg * 9.8 m/s^2 * cos(27°)[/tex] ≈ [tex]20.05 N[/tex]
Therefore, the normal force on the block is approximately 20.05 N.
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Can u please help with this two tasks?
Workbook:complete physics for Cambridge secondary first
For electricity generation the words in order are:
a You can generate electricity by moving a coil of wire in a magnetic field. The size of the voltage depends on the speed of the movement and the strength of the magnet.
b In a model generator, a coil rotates between the poles of a magnet. If a coil with more turns is used the voltage is greater. If the coil spins faster, the voltage is greater.
What is the influence of induced voltage?a. If the student moved the magnet towards the coil at a slower speed, she would notice that the induced voltage on the voltmeter decreases. This is because the voltage induced is proportional to the rate of change of the magnetic field, which decreases as the speed decreases.
b. If the student moved the magnet towards the coil at the same speed, she would notice that the induced voltage on the voltmeter remains the same. This is because the voltage induced is proportional to the rate of change of the magnetic field, which is constant if the speed is constant.
c. If the student turned the magnet round and moved it towards the coil, she would notice that the induced voltage on the voltmeter is in the opposite direction. This is because the direction of the induced voltage is determined by the direction of the change in magnetic field, which is reversed when the magnet is turned round.
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7. A 5.0 m ladder is placed so that it leans against a wall so that the end of the ladder is 4.0 m up
the wall. If the ladder has a mass of 12.0 kg and a 45.0 kg person climbs the ladder so that they
are standing at the 3.75 m point on the ladder, what is the force that the ground exerts on the
ladder so that it remains in equilibrium?
Because the horizontal fraction of ground-generated pressure (F_ground) corresponds to F_wall, it is reasonable to assume that the duration of ground influence on the ladder is roughly 481.55 N in magnitude.
How to solveThe ladder's grounding point on the wall is 3.0 m away with the application of the Pythagorean theorem. By analyzing the torque at the ladder's foundation and surveying its diversified forces, we can derive estimates:
• The person's strength (F_person), determined by 45.0 kg * 9.81 m/s^2 calculations, is approximately 441.45 N when applied to a length of 3.75 m.
• The ladder's mass-based force (F_ladder), calculated as 12.0 kg * 9.81 m/s^2, is about 117.72 N exerted upon a distance of 2.5 m.
• Atop the ladder falls the wall's upward-directed push action- referred to as F_wall- which operates at an elevation of 4.0m from the earth's plane.
To ensure compliance: Equilibrium occurs if the equation (3.75 m * 441.45 N) + (2.5 m * 117.72 N) - (4.0 m * F_wall) equals zero.
Thus, F_wall ≈ 481.55 N after resolving the problem mathematically.
Additionally, because the horizontal fraction of ground-generated pressure (F_ground) corresponds to F_wall, it is reasonable to assume that the duration of ground influence on the ladder is roughly 481.55 N in magnitude.
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Two billiard balls, each with a mass of 0.21 kg, collide with each other on a pool table. Before the collision, one ball is moving north at 1.7 m/s and the other ball is moving south at 2.6 m/s. What is the momentum of this system after the collision? A. 0.19 kg-m/s north OB. 0.19 kg m/s south C. 0.90 kg-m/s north D. 0.90 kg-m/s south
Answer:
Explanation:
Ok I am an expert in this class. two balls which is 32 weighted for both. 21+21=41+1.7=42.7/4=10.7
Both would=10.7
A person fires a gun close to a wall (40m). An echo is heard 0.24 after the original shot. Based on this information only, find the speed of sound in air?
The speed of sound in air can be calculated using the following formula:speed of sound = distance / timeIn this case, we know that the distance between the person and the wall is 40 meters, and the time it takes for the echo to be heard after the original shot is 0.24 seconds. However, we need to account for the fact that sound travels to the wall and back, so the total distance the sound wave covers is twice the distance to the wall, or 2 x 40 = 80 meters.Thus, using the formula above, we can calculate the speed of sound:speed of sound = distance / time = 80 m / 0.24 s ≈ 333.33 m/sTherefore, the speed of sound in air is approximately 333.33 meters per second.
In what ways does ecotourism help living things in ecosystems?
Ecotourism has the potential to eliminate the requirement to hunt wildlife for a living. Ecotourism generates revenue by maintaining the rainforest; deforestation is discouraged because it reduces tourist revenue.
What role does ecotourism play in biodiversity conservation?Ecotourism firms safeguard biodiversity by preserving animals in their natural habitats and preserving natural ecosystems in biosphere reserves, wildlife sanctuaries, and national parks.
Can tourism save the environment?Ecotourism contributes to the preservation of a destination's ecological and biological diversity. For example, since Costa Rica's jungle is so popular with visitors, inhabitants work hard to protect it instead of attempting deforest it for a short-term profit.
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Bismuth-214 is radioactive. It has a half-life of 20 minutes. (a) The nuclide notation for bismuth-214 is 214Bi. State the composition of the nucleus of bismuth-214. ASSIGNM ASSIGN
The composition of the nucleus of bismuth-214 can be described using its nuclide notation, which consists of the element symbol, atomic number, and mass number.The element symbol for bismuth is Bi, which has an atomic number of 83, meaning that all atoms of bismuth have 83 protons in their nucleus.The mass number of bismuth-214 is 214, which means that a typical bismuth-214 nucleus contains 83 protons and 131 neutrons (since mass number = number of protons + number of neutrons).Therefore, the nucleus of bismuth-214 can be represented by the nuclide notation: ^214Bi.