The probability that Amber's bus arrives on time is 5/6.
If her bus is on time then the probability she arrives at work by 9 am is 4/5.
If her bus is late then the probability she arrives at work by 9 am is 3/10.

Work out the probability that Amber does not arrive at work by 9 am.
Give your answer as a fraction in it's simplest form.

The values of p1, p2, p3 that minimize Var(X) are p1 = 0, p2 = 1/3, and p3 = 2/3.

We can use the following formulas to find the variance of X:

Var(X) = E[X^2] - (E[X])^2

E[X] = p1 + 2p2 + 3p3

E[X^2] = p1 + 4p2 + 9p3

Substituting these expressions into the formula for the variance, we get:

Var(X) = p1 + 4p2 + 9p3 - (p1 + 2p2 + 3p3)^2

Simplifying this expression, we get:

Var(X) = -[tex](p1^2 + 2p2^2 + 3p3^2) + 2p1p2 + 6p1p3 + 4p2p3[/tex]

To maximize Var(X), we want to maximize this expression subject to the constraint p1 + p2 + p3 = 1. We can use Lagrange multipliers to find the maximum. Let:

L(p1, p2, p3, λ) = -[tex](p1^2 + 2p2^2 + 3p3^2) + 2p1p2 + 6p1p3 + 4p2p3 + λ(1 - p1 - p2 - p3)[/tex]

Taking partial derivatives and setting them equal to zero, we get:

-2p1 + 2p2 + 6p3 - λ = 0

4p1 - 4p2 + 4p3 - λ = 0

6p1 + 8p2 - 6p3 - λ = 0

p1 + p2 + p3 = 1

Solving these equations, we get:

p1 = 2/7, p2 = 3/7, p3 = 2/7, λ = 4/7

Therefore, the values of p1, p2, p3 that maximize Var(X) are p1 = 2/7, p2 = 3/7, and p3 = 2/7.

To minimize Var(X), we want to minimize the expression [tex]-(p1^2 + 2p2^2 + 3p3^2) + 2p1p2 + 6p1p3 + 4p2p3[/tex] subject to the constraint p1 + p2 + p3 = 1. We can use the same Lagrange multiplier method to find the minimum. Taking partial derivatives and setting them equal to zero, we get:

-2p1 + 2p2 + 6p3 - λ = 0

4p1 - 4p2 + 4p3 - λ = 0

6p1 + 8p2 - 6p3 - λ = 0

p1 + p2 + p3 = 1

Solving these equations, we get:

p1 = 0, p2 = 1/3, p3 = 2/3, λ = 2/3

Therefore, the values of p1, p2, p3 that minimize Var(X) are p1 = 0, p2 = 1/3, and p3 = 2/3.

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Answer:

see explanation

Step-by-step explanation:

10

length of side opposite ∠ A is BC = 20

11

length of side adjacent to ∠ A is AC = 21

12

length of hypotenuse is AB = 29

13

sin A = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{20}{29}[/tex]

14

cos A = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{21}{29}[/tex]

15

tan A = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{20}{21}[/tex]

Answer:

the answer is c(t)=x2 +3

Step-by-step explanation:

because if u insert every x value in x place u will get the 2nd coordinate or y value so it is the correct equation

The cumulative frequency of the numbers 6-10 is thus 2 + 0 + 1 + 1 + 0 = 4.

To determine the frequency of the numbers 6-10 in this stem-and-leaf plot, examine the second row, which has a stem of 1 and leaves of 0 0 2 3 6 6. This row displays the digits 10, 10, 12, 13, 16, and 16, which correspond to 6 students who sold between ten and nineteen lollipops.

Because 2 of these 6 pupils sold exactly six lollipops (represented by leaf 06), the frequency of the number six is two.

There are no students who sold 7 lollipops exactly.

Because one kid sold exactly eight lollipops (represented by the leaf 08), the number 8 has a frequency of one.

One student sold exactly nine lollipops (represented by the number 9) As a result, the frequency of the number 9 is 1.

Zero students sold a total of ten lollipops.

The cumulative frequency of the numbers 6-10 is thus 2 + 0 + 1 + 1 + 0 = 4.

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She needs 74.25 ft² of glass to cover the pyramid.

To obtain the surface area of any prism, we combine the areas of all the parts that compose the prism.

The pyramid in this problem is composed as follows:

The area of the square base is given as follows:

As = 5.5² = 30.25 ft².

The area of the four triangles is given as follows:

At = 4 x 1/2 x 5.5 x 4

At = 44 ft².

Hence the surface area of the pyramid is given as follows:

S = As + At

S = 30.25 + 44

S = 74.25 ft².

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Answer:

Let's first calculate the number of students who passed the test and completed the assignment. We know that 15 students passed the test and 6 students who failed the test and did not complete the assignment. Therefore, there are 25 - 15 - 6 = 4 students who failed the test but completed the assignment.

Now we can calculate the probability that a student who completed the homework passed the test by dividing the number of students who passed the test and completed the assignment by the total number of students who completed the assignment.

The number of students who passed the test and completed the assignment is 15 - 6 = 9. The total number of students who completed the assignment is 16 - 6 = 10. Therefore, the probability that a student who completed the homework passed the test is 9/10 or 0.9.

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

(a) Yes, we have enough information to compute Probability P(A or B).

(b) If we know P(A) and P(B), we have enough information to compute P(A or B).

(a) The probability of the union of two events (A or B) is given by the formula P(A or B) = P(A) + P(B) - P(A and B)

We know P(A) and P(B), but we don't know P(A and B) - the probability that both events occur simultaneously. Therefore, we cannot compute P(A or B) with certainty unless we are given additional information about the relationship between A and B.

(b) If we know that events A and B are mutually exclusive, then we have enough information to compute P(A or B). Mutually exclusive events are events that cannot occur simultaneously, which means that P(A and B) = 0.

In this case, the formula for the probability of the union simplifies to:

P(A or B) = P(A) + P(B)

Since we know P(A) and P(B), we can simply add them to obtain P(A or B). Therefore, in this case, we have enough information to compute P(A or B).

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The value of x after simplifying the given equation is approximately 1295.6.

To solve for x in the equation

(679/1327) + (677-x)/1329 + (675-x)/1331 + (673-x)/1333 = 4

We can start by simplifying the fractions and combining like terms

679/1327 + (3x - 1010)/((1329)(1331)(1333)) = 4

Multiplying both sides by (1327)(1329)(1331)(1333), we get

(679)(1329)(1331)(1333) + (3x - 1010)(1327)(1331)(1333) = 4(1327)(1329)(1331)(1333)

Expanding the products and simplifying, we get

(679)(1329)(1331)(1333) + (3x)(1327)(1331)(1333) - 1010(1327)(1331)(1333) = 4(1327)(1329)(1331)(1333)

Adding 1010(1327)(1331)(1333) to both sides, and dividing both sides by (3)(1327)(1331)(1333), we get

x ≈ 1295.6

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Answer:

3 cm

Step-by-step explanation:

because the correct answer is 3cm

A threat to internal validity occurs only if a potential design confound varies systematically with the independent variable.

In experimental research, an independent variable is a variable that the researcher manipulates or systematically varies in order to study its effect on the dependent variable. It is called "independent" because it is not influenced by any other variables in the experiment, and its effects on the dependent variable can be observed and measured independently of any other factors.

Only when a possible design confound fluctuates systematically with the independent variable does internal validity come under threat. In other words, it might be challenging to distinguish between the effects seen on the dependent variable and the independent variable if there is a component that fluctuates consistently or predictably with changes in the independent variable. Internal validity is less likely to be threatened by random or unplanned variation.

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A threat to internal validity occurs only if a potential design confound varies systematically with the independent variable. This means that if the confound varies randomly or haphazardly, it is less likely to affect the results of the study.

This means that the confound is consistently related to the independent variable, making it difficult to determine if the observed effects are due to the independent variable or the confound. If the confound varies spontaneously or haphazardly, it is less likely to pose a threat to internal validity, as it would not be consistently associated with the independent variable.

However, if the confound is related to the independent variable in a consistent and predictable way, it can introduce bias and undermine the internal validity of the study. It is important for researchers to carefully control for potential confounds and ensure that any observed effects are truly due to the independent variable and not some other factor.

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Answer:

156

Step-by-step explanation:

Use the system of PEMDAS.
6*3 = 18
6*4 = 24
6*5 = 30
6*8 = 48
2[3*4+1/2(3*4)] = 36
Add all.
18+24+30+48+36 = 156

The a is rational , b is irrational and product of a and b is rational.

The number a=0.444444444444 is rational

Because it can be expressed as the ratio of two integers.

a = 4/9

The number b=0.354355435554 is irrational

Because it cannot be expressed as the ratio of two integers.

It has an infinite non-repeating decimal expansion.

To determine whether the product of a and b is rational or irrational, we can simply multiply them together:

a × b = (4/9) × 0.354355435554

= 0.158919191574

This product is a rational number, because it can be expressed as the ratio of two integers.

Hence, a is rational , b is irrational and product of a and b is rational.

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Thus, the intermediate step in the form (x+a)² = b as a result of completing the square for the given equation is - (x + 10)² = 1 /3.

A quadratic equation can be made together into perfect square trinomial simply adding or removing elements from both sides, a technique known as "completing the square."

You can use the square's completion as another mathematical tool to solve a variety of problems:

Given expression:

-3x² - 298 = 60x - 1

isolating the x values:

-3x² - 60x = 298 - 1

-3x² - 60x = 299

Taking -3 common from the left hand side:

-3(x² + 20x) = 299

x² + 20x = - 299/3

This, can be written as:

x² + 2*10x = - 299/3

add both side by 100

x² + 2*10x + 100 = - 299/3 + 100

On simplification:

(x + 10)² = (-299 + 300) /3

(x + 10)² = 1 /3

Comparing obtained expression with the given form: (x+a)²=b

a = 10 and b = 1/3

Thus, the intermediate step in the form (x+a)² = b as a result of completing the square for the given equation is - (x + 10)² = 1 /3.

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Answer:

Original volume: 6^3 = 216 cubic cm

New volume: 3^3 = 27 cubic cm

The volume of this cube would decrease by 189 cubic centimeters if the length of each side was reduced from 6 cm to 3 cm.

The length of the square garden is s = ( 3x - 4 ) feet

Given data ,

Let the length of the square garden be s

Now , The area of a square is given by the formula A = s², where s is the length of one side of the square.

We are given that the area of the garden is:

A = 9x² - 24x + 16

To find the length of the garden, we need to take the square root of the area:

s = √(A)

Substituting the given expression for A, we get:

s = √(9x² - 24x + 16)

We can simplify this expression by factoring the quadratic under the square root sign:

s = √[(3x - 4)(3x - 4)]

Using the property that the square root of a product is equal to the product of the square roots, we can simplify further:

s = (3x - 4)

Hence , the length of the garden is 3x - 4 feet

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Answer:

  The measure of angle AOC is double the measure of angle ABC.

Step-by-step explanation:

You want to know the relationship between central angle AOC in circle O and inscribed angle ABC subtending the same arc AC.

The measure of an inscribed angle is half the measure of the arc it intercepts. The measure of a central angle is exactly equal to the measure of the arc it intercepts. (That's how the arc measure is determined.)

Hence, the measure of angle AOC is double the measure of angle ABC.

__

Additional comment

  Inscribed : central = 1 : 2

  Central : inscribed = 2 : 1

You need to be a little careful of the wording of the relationship. Which is double and which is half can be confused when it's written in words. On a diagram, the angle with its vertex in the center will obviously be larger than the one with its vertex on the circle.

To find the values of x for which (x2 − 4)(x + 3) = 0, we can use the zero product property which states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we can set each factor equal to zero and solve for x:

(x2 − 4) = 0 or (x + 3) = 0

Solving for x in the first equation, we get:

x2 = 4 x = ±2

Solving for x in the second equation, we get:

x = −3

Therefore, the values of x for which (x2 − 4)(x + 3) = 0 are −2, 2, and −3. The answer choices that correspond to these values are R. −2, S. 2, and P. −3.

Answer:

Since the prism has three rectangular faces, let's call them faces ABCD, ABEF, and CDFH. Without loss of generality, let's assume that the plane goes through points A, B, and C to slice through all three rectangular faces.

First, let's consider the intersection of the plane with face ABCD. Since the plane goes through points A, B, and C, it must contain the line segments AB and AC. Thus, the intersection of the plane with face ABCD is a triangle with vertices A, B, and some point D' on the edge CD.

Next, let's consider the intersection of the plane with face ABEF. Since the line segments AB and AC both lie entirely within face ABEF, their intersection with the plane gives line segments AB' and AC', respectively. Thus, the intersection of the plane with face ABEF is a quadrilateral with vertices A, B', E, and F.

Similarly, the intersection of the plane with face CDFH is a quadrilateral with vertices C, D', H, and F.

To visualize the resulting plane section, imagine unfolding the right triangular prism so that all its faces lie flat. Then the plane section would look something like this:

B'________E

/| / |

A /_|___/' |

| | | |

| D'- -|-----C

| / |____|/

F|/ H

The intersection of the plane with face ABCD is the triangle ABD', and the intersections with faces ABEF and CDFH are the quadrilaterals AB'EF and CD'HF, respectively.

Overall, the resulting plane section has four sides: AB' and B'E from face ABEF, EF and FD' from face CDFH, and D'A from face ABCD. It has one vertex at A and two vertices, B' and D', that lie on the edge CD. The fourth vertex is at some point E on the edge BE. The shape of the resulting plane section depends on the relative positions of points B and D on the edge CD, and point E on the edge BE.

The completed table is attached accordingly. The standard deviation is given as 11.69

To derive the missing values, in the (x -μ) colume we need to first find the mean of the values.

This is writen as .....

μ = (2 + 8+14+19+20+21+26+  33+36+41  )  / 10 = 22.0

Now we can calculate the missing value as

(x-μ)

-20

-14

-8

-3.0

-2.0

-1.0

4.0

11.0

14.0

19.0

To find the missing values in the (x-μ)² column, we can simply square the values we just found

(x-μ)²

400

196

64

9.0

4.0

1.0

16.0

121.0

196.0

361.0

Next, we can find the sum of the (x-μ)² column

Σ(x-μ) ² = 1368

To find the variance, we divide the sum by the number of values and round to the nearest hundredth:

s² = Σ(x-μ)² / n = 1368 / 10 = 136.8

To find the standard deviation, we take the square root of the variance and round to the nearest hundredth:

s = √ (s²)

 = √(136.8)

≈ 11.69

Hence, the standard deviation of the elephant ages is approximately 11.69.

See the attached table.

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The correct answer is false. A reduced echelon matrix [tex]T(x) = 0[/tex] with a row of [tex][0 . . 0 | 0] or [0 . . . 0 | b][/tex], where[tex]b \neq 0[/tex], is not considered one-to-one.

Let's first define what it means for a matrix to be one-to-one.

A matrix is said to be one-to-one if each column of the matrix is linearly independent.

This means that for any given input, there is only one possible output.
Now, let's consider the reduced echelon matrix T(x) = 0. If this matrix has a row of [tex][0 . . 0 | 0] or [0 . . . 0 | b][/tex], b ≠ 0, it means that one of the variables in the system of equations represented by the matrix is a free variable.

This free v[tex]T(x) = 0.[/tex]ariable can take on any value, and the other variables will adjust accordingly.
If the reduced echelon matrix is [tex][1 0 | 2; 0 0 | 0],[/tex] the system of equations would be [tex]x = 2[/tex] and y can be any value.

This means that the matrix is not one-to-one, because there are multiple outputs for the same input.
the correct answer is false.

A reduced echelon matrix[tex]T(x) = 0[/tex] with a row of [tex][0 . . 0 | 0] or [0 . . . 0 | b][/tex], where [tex]b \neq 0[/tex], is not considered one-to-one.

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The equation represents a linear function.

What is quadratic equation?

A quadratic equation is a polynomial equation of degree two which can be written in the form: ax² + bx + c = 0, where x is the variable and a, b, and c are constants with 'a' not equal to 0. The term 'quadratic' comes from the Latin word 'quadratus', which means 'square'.

The equation given in the image is a quadratic equation in standard form, which means it is written in the form ax^2 + bx + c = 0, where a, b, and c are constants and x is the variable.

To determine which statement is true about this equation, we need to analyze its discriminant, which is given by the expression b^2 - 4ac. The discriminant tells us about the nature of the solutions of the quadratic equation.

If the discriminant is positive, then the equation has two distinct real roots.

If the discriminant is zero, then the equation has one real root (also known as a double root).

If the discriminant is negative, then the equation has two complex roots (conjugate pairs).

In the given equation, a = 3, b = -4, and c = 1. Substituting these values into the discriminant formula, we get:

b^2 - 4ac = (-4)^2 - 4(3)(1) = 16 - 12 = 4

Since the discriminant is positive, we know that the quadratic equation has two distinct real roots. Therefore, statement (A) is true.

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Answer:

Step-by-step explanation:

1. Distribute the 10: 30p + 40

If you are solving for p, then subtract 40: 30p = -40

Then divide 30: p = -40/30, simplified to p = -4/3

Answer:

  30p -40

Step-by-step explanation:

You want to simplify the expression -10(-3p +4).

The distributive property tells you the product is ...

  -10(-3p +4)

  = (-10)(-3p) + (-10)(4)

  = 30p +(-40)

  = 30p -40

__

Additional comment

It is easy to get confused by minus signs. For any given numerical product the sign of the result will be negative if (and only if) the number of negative factors is odd.

Here, the first product is (-10)(-3p), which has an even number of minus signs. The result will be the same as with no minus signs:

  (-10)(-3p) = (10)(3p) = 30p

On the other hand, the product (-10)(4) has an odd number of minus signs. That result will be negative:

  (-10)(4) = -40

For this problem, you could start by distributing the minus sign, changing the sign of each term inside the parentheses:

  -10(-3p +4) = 10(3p -4)

Doing this can simplify the mental load of figuring the signs of the product terms.

To discover the probability that the ceramics piece is painted, we basically separate the number of painted pieces by the whole number of pieces: P(painted) = 183/837 ≈ 0.2185

b. To discover the likelihood that the painted ceramics piece is painted in a curvilinear enhancement, we utilize Bayes' hypothesis:

P(curvilinear | painted) = P(painted | curvilinear) * P(curvilinear) / P(painted)

We are given that there are 183 painted pieces, of which 14 are painted in a curvilinear enrichment. In this manner,

P(painted | curvilinear) = 14/183 ≈ 0.0765

We are moreover given that there are 837 pieces in add up, of which 183 are painted.

P(painted) = 183/837 ≈ 0.2185, we ought to discover the likelihood that a painted piece is painted in a curvilinear enrichment, which is given as 14 out of 183 painted pieces. P(curvilinear) = 14/183 ≈ 0.0765

P(curvilinear | painted) = (0.0765) * (0.0765) / (0.2185) ≈ 0.0266

thus, given that the pottery piece is painted, the likelihood that it is painted in a curvilinear enhancement is roughly 0.0266, or 2.66%.

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Answer- 24 spins

The probability of getting an E on a single spin is 1/4. The probability of not getting an E on a single spin is 3/4.

To find the expected number of spins before getting 6 E's, we can use the negative binomial distribution.

The formula for the expected value of a negative binomial distribution is:

E(X) = r * (1/p)

where:

- X is the random variable representing the number of spins until the 6th E appears

- r is the number of successes we want (in this case, 6)

- p is the probability of success (in this case, 1/4)

E(X) = 6 * (1/(1/4)) = 24

Therefore, Marcus's prediction for the number of total spins before the letter E appears 6 times is 24.

So the answer is 24 spins.

The opposite numbers that have a distance of 8 units between them on a number line are: -4 and 4.

We have,

The distance on a number line between two numbers is the number of units that separates both numbers.

Opposite numbers have the same distance to point zero on a that lies between them. For example, 4 on a number line is 4 units from point 0. -4 is also 4 units. 4 is the opposite number of -4.

Distance between -4 and 4

= |-4 - 4|

= |-8|

= 8 units.

Therefore, the opposite numbers that have a distance of 8 units between them on a number line are: -4 and 4.

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Answer:

sugger

Step-by-step explanation:

because she bought 34.15 super and 34.144 pepper

The best approximation for the p-value for the test statistic t0 = 2.155 is 0.032.

To find the best approximation for the p-value for the hypothesis test with null hypothesis H0: μ=8 and alternative hypothesis H1: μ>8, with variance unknown and n=10, and a test statistic t0=2.155, we need to use the t-distribution with degrees of freedom (df) equal to n-1 = 10-1 = 9.

The p-value is the probability of obtaining a test statistic as extreme or more extreme than the observed one, assuming the null hypothesis is true. Since this is a one-tailed test with the alternative hypothesis in the form of μ>8, the p-value corresponds to the area in the right tail of the t-distribution.

Using a t-table or calculator with the t-distribution, we can find the probability of obtaining a t-value as large as 2.155 or larger with 9 degrees of freedom. This probability is approximately 0.032. Therefore, the best approximation for the p-value for this hypothesis test is 0.032.

We can interpret this result as follows: if the null hypothesis is true (i.e., if the population mean is 8), the probability of obtaining a sample mean as extreme or more extreme than the observed one (i.e., greater than 8.215) is 0.032. Since this probability is relatively small, we may reject the null hypothesis in favor of the alternative hypothesis at a significance level of 0.05 or smaller.

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