The total area under the frequency polygon for a continuous random variable equals 1? True or False

Answer:

Step-by-step explanation:

Decimals are out of 100.

7/10 = 70/100

Which equals to 0.70 or 0.7

So your answer is 0.70 (0.7)

Answer:

The exact decimal equivalent of 7/10 is 0.7

Step-by-step explanation:

The reason for this is because when you divide something by ten you move the decimal place one place to the left.

So then 7.0 becomes 0.7 because the decimal place is moved once divided by ten.

The length of the addition to the room will be 8 feet.

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the rectangle in a two-dimensional plane is called the area of the rectangle.

Given that Teri has a living room that is 9 feet wide and has an area of 108 square feet. She is adding to the room. The remodelled living room will have a total area of 180 square feet.

The added length will be calculated as:-

TA = A₁ + A₂

180 = 108 + 9x

72 = 9x

x = 72 / 9

x = 8 feet

Therefore, the length of the room addition will be 8 feet.

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The value of millimeter in elevation can be calculated by simply dividing the millimeter by25.4 so 10 mm is0.394 elevation.

Unit conversion is the process of rephrasing the dimension of a given quantum between different units, constantly through multiplicative conversion factors that change the value of the measured volume without changing its goods.

Converting from millimetres to elevation

Between millimetres( mm) and elevation( in)

computation of elevation( dec) in elevation( frac) in bases plus Inches ft mm to elevation

* The value is rounded to the nearest1/64 bit for the elevation bit.

How to change metric units to elevation

elevation are equal to0.03937007874 millimetres in length

1 mm = (1/25.4) ″ = 0.03937007874 ″

The distance d in millimetres( mm) divided by25.4 gives the distance d in elevation( ′ ′)

d( ″) = d( mm)/25.4

illustration of 20 mm converted to elevation

d( ″) = 20 mm/25.4 = 0.7874 ″

How numerous millimetres are in one inch

elevation are equal to one millimetre

1 mm = 1 mm/25.4 mm/ in

= 0.03937 in.

What's the millimetre to inch conversion

millimetres make up one inch.

1 inch Equals 25.4 millimetres per inch.

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Option D. Nominal measurement is used primarily to name or categorical data.

Nominal measurement is one of the four levels of measurement used in statistics, along with ordinal, interval, and ratio measurement. Nominal data are qualitative or categorical data that can be assigned to discrete categories based on some characteristic or attribute, such as color, gender, or species. Nominal data do not have a natural ordering, so they cannot be ranked or ordered based on magnitude or size.

Nominal measurement is a type of measurement in which data are named or categorized based on some characteristic or attribute. Nominal data are typically qualitative or categorical in nature, meaning that they are not numerical in value. Examples of nominal data include gender, race, religion, color, or type of animal.

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Answer:2/8 + 2/8

Step-by-step explanation:

so, you start at 2/8

then, you add the extra 2/8

then, you add them together ( don’t forget: when the bottom numbers of the fraction are the same the stay at the same number ex: 3/8 + 3/8 = 6/8)

then after adding them up you get 4/8 which could also mean 1/2

20 centimeter is approximately equal to 7.8740 inches ( rounded to four decimal places )

To convert 20 cm to inches, we can use the following formula:

1 cm = 0.393701 inches

The conversion is the process of changing the unit of one quantity to another units  

The conversion factor is defined as the number that is used to change one unit to another units by multiplying or dividing

Therefore,

The length in inches = conversion factor × The length in centimeter

Substitute the values in the equation

20 cm = 20 x 0.393701

Multiply the numbers

= 7.8740 inches ( rounded to four decimal places )

Therefore, 20 centimeter is 7.8740 inches

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Usually there are 52 Sundays in a year approximately.

There are a total of 52 weeks in a year if we take a rough estimate.

Every week has one sunday in it. So, going by this logic, each year will have about 52 sundays in it.

Now, one thing that we should notice here is that is not certain that there will be definitely 52 sundays. This number of 52 can increase also by a number of one or two because it is possible that the year might not starting from sunday. Because when we do 365/7 we get 52.14 so, this decimal place might include one or two Sundays in it.

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The original price of the article without the discount is %60.

Discount is the state of having a bond's price lower than its face value. The difference between the purchase price and the item's par value is the discount.

Discounts are different types of price reductions or deductions from a product's cost. It is frequently employed in consumer transactions when consumers receive discounts on a range of goods.

Let us suppose original price = x.

Given that, after a discount, the marked price of an article is 48$ and the discount is 20%.

Thus,

48 = x(1 - 20/100)

48 = x(80/100)

x = 60

Hence, the original price of the article without the discount is %60.

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Answer:

[tex](u \circ \; w)(2) = \boxed{7}[/tex]

[tex](w \circ \;u)(2) = \boxed{3}[/tex]

Step-by-step explanation:

We have the two functions as

[tex]u(x) = x^2 + 3\\\\w(x) = \sqrt{x + 2}[/tex]

[tex](u \circ w)(x)[/tex] also written as [tex]u(w(x))[/tex]  is the composite function;  it means that
[tex]x = w(x)[/tex] should be substituted in [tex]u(x)[/tex]

To determine [tex](u \circ w)(x)[/tex], simply substitute the expression for [tex]w(x)[/tex] wherever there is an x in [tex]u(x)[/tex]

For a specific value of x, in this case x = 2,

Part 1
[tex](u \circ w)(2):\\\\w(2) = \sqrt{2 + 2} = 4(u \circ w)(2) = 2^2 + 3 = 4 + 3 = 7[/tex]

For [tex](w \circ u)(x),[/tex] we substitute the expression for [tex]u(x)[/tex] into [tex]w(x)[/tex] wherever an [tex]x[/tex] appears in [tex]w(x)[/tex]

For a specific value of x, say 2, find the value of u(2) and substitute it into [tex]w(x)[/tex]

[tex]u(2) = 2^2 + 3 = 7[/tex]

[tex](w \circ u)(2), = \sqrt{7 + 2} = \sqrt{9} = 3\\[/tex]

a. The probability of finding oil is 0.45

b. The probability of finding high-quality oil is 0.25

c. P(medium quality oil) = 0.20

d. P(no oil) = 0.55

The probabilty of finding oil

P(oil) = P(high quality oil) + P(medium quality oil)

= 0.25 + 0.20

= 0.45

b. P(soil high quality oil) = 0.20

P(medium qty) = 0.80

P(no oil) = 0.20

The probability of finding oil is good.

Given the probability of finding good soil, the oil company is more likely to find medium quality oil.

The new probability of finding oil is

P(High quality) + P(medium quality) =

0.15625 + 0.5

= 0.65625

Using the conditional probabilty formula

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Answer:

110

Step-by-step explanation:

The integral for the mass of a thin wire in the shape of a parabola density is [tex]\int[-1,1]\int[0,x^2] x^2 y^2 dy dx[/tex]

To find the mass of the thin wire in the shape of a parabola with density function ρ(x, y) = [tex]x^2 y^2[/tex],

we can set up a double integral over the region that describes the parabola. The mass M is given by the following integral:

M = ∬ρ(x,y) dA

where dA represents the area element in the xy-plane. To set up this integral, we need to first determine the limits of integration for x and y.

The parabola can be described by the equation y =[tex]x^2[/tex], where x ranges from -1 to 1. Therefore, the limits of integration for x are -1 to 1.

For each value of x, the y-values range from the parabola to the x-axis, which is the region between y = 0 and y = [tex]x^2[/tex]. Therefore, the limits of integration for y are 0 to[tex]x^2[/tex].

Using these limits of integration, the integral for the mass of the thin wire is:

M = ∫∫ρ(x,y) dA

=[tex]\int[-1,1]\int[0,x^2] x^2 y^2 dy dx[/tex]

This integral can be evaluated using standard integration techniques.

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The eigenvalues are λ₁= 2 and λ₂=4. The eigenvectors are [tex]\vec{v_1}=\left[\begin{array}{c}-1\\1\end{array}\right][/tex] and [tex]\vec{v_2}=\left[\begin{array}{c}1\\1\end{array}\right][/tex]. The general solution is [tex]\begin{aligned}x(t)&=-C_1e^{2t}+C_2e^{4t}\\y(t)&=C_1e^{2t}+C_2e^{4t}\end{aligned}[/tex].

An eigenvector is considered as a non-zero vector x of matrix A such that Ax=λx. This scalar (λ) is the eigenvalue.

Given the equations are x'(t) = 3x(t) + y(t) and y'(t) = x(t) + 3y(t). Now, let's write them in the matrix form as follows,

[tex]\begin{aligned}\left[\begin{array}{c}x'\\y'\end{array}\right] &=\left[\begin{array}{cc}3&1\\1&3\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]\\X'&=AX\end{aligned}[/tex]

From, the above expression, the coefficient matrix A is written as [tex]A=\left[\begin{array}{cc}3&1\\1&3\end{array}\right][/tex].

Now let's write the characteristic equation |A-λI|=0 as follows,

[tex]\begin{aligned}\left|\begin{array}{cc}3-\lambda&1\\1&3-\lambda\end{array}\right|&=0\\\lambda^2-6\lambda+8&=0\end{aligned}[/tex]

Solving the above equation, we get λ₁= 2 and λ₂=4.

For λ₁= 2, we obtain the eigenvector as follows,

[tex]\left[\begin{array}{cc}3&1\\1&3\end{array}\right]\left[\begin{array}{c}x_1\\x_2\end{array}\right]=\left[\begin{array}{c}2x_1\\2x_2\end{array}\right][/tex].

From this, the equations are written as 3x₁+x₂=2x₁ and x₁+3x₂=2x₂. Solving we get, x₁=-x₂ and x₂=x₂. Then, the eigenvector is written as[tex]\vec{v_1}=\left[\begin{array}{c}-1\\1\end{array}\right][/tex].

For λ₂=4, we obtain the eigenvector as follows,

[tex]\left[\begin{array}{cc}3&1\\1&3\end{array}\right]\left[\begin{array}{c}x_1\\x_2\end{array}\right]=\left[\begin{array}{c}4x_1\\4x_2\end{array}\right][/tex].

From this, the equations are written as 3x₁+x₂=4x₁ and x₁+3x₂=4x₂. Solving we get, x₁=x₂ and x₂=x₂. Then, the eigenvector is written as[tex]\vec{v_2}=\left[\begin{array}{c}1\\1\end{array}\right][/tex].

Then, the general solution is,

[tex]\begin{aligned}X(t)&=C_1e^{\lambda_1t}\vec{v_1}+C_2e^{\lambda_2t}\vec{v_2}\\ \left[\begin{array}{c}x\\y\end{array}\right]& =C_1e^{2t}\left[\begin{array}{c}-1\\1\end{array}\right] +C_2e^{4t}\left[\begin{array}{c}1\\1\end{array}\right] \end{aligned}[/tex]

And, the component-wise, the general solution is written as

[tex]\begin{aligned}x(t)&=-C_1e^{2t}+C_2e^{4t}\\y(t)&=C_1e^{2t}+C_2e^{4t}\end{aligned}[/tex]

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The required, measure of QK is approximately 10.82.

In a right-angled triangle, its sides, such as hypotenuse, perpendicular, and the base is Pythagorean triplets.

First, we can use the Pythagorean theorem to find the length of side XZ:

[tex]XZ^2 = XY^2 - YZ^2[/tex]

[tex]YZ = \sqrt{(XY^2 - XZ^2) }[/tex]
[tex]= \sqrt(24^2 - 22^2) = 10[/tex]

The length of the perpendicular bisector of XY is half the distance between points A and the midpoint of XY. The midpoint of XY can be found by dividing the length of XY by 2:

midpoint of XY = (X + Y)/2

Since we are given the length of XY, we can find the coordinates of its endpoints X and Y. Let X be the origin (0,0) and let Y have coordinates (24,0) (since XY = 24). Then the midpoint of XY is the midpoint of XY
= (X + Y)/2
= (0 + 24)/2
= (12,0)

Now we can use the distance formula to find the distance between A and the midpoint of XY distance between A and the midpoint of XY
= [tex]= \sqrt((12 - 0)^2 + (0 - 15)^2)[/tex]
= [tex]\sqrt(12^2 + 15^2)[/tex]
=[tex]3 \sqrt(29)[/tex]

This is the length of the perpendicular bisector of XY, which passes through the center of the circumscribed circle. So the distance from Q to the center of the circle is the distance from Q to center = 15 - 9 = 6

Finally, we can use the Pythagorean theorem to find QK:

[tex]QK^2 = QJ^2 + JK^2 = QJ^2 + (distance \ from \ Q \ to\ center)^2[/tex]

[tex]QK^2 = 9^2 + 6^2 = 81 + 36 = 117[/tex]

[tex]QK = \sqrt(117)\\ = 10.82[/tex]

Therefore, QK is approximately 10.82.

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The number of  used games consoles is 9 and the number of new game consoles is 5

Here we use the Linear equation method to solve the problem. Since we don't know the number games, represent them with variables x and y.

Now for two linear equations according to the conditions as given in the problem. Solve the equations for the values of both x and y by using the substitution method.

Here we have

An electronics store sells used game consoles for $79.00 and new ones for $149.00

Let 'x' and 'y' be the number of used and new game consoles respectively

Cost of 'x' used games consoles = 79x

Cost of 'y' new game consoles = 149y

Given total profit =$ 1456    

=> 79x + 149y = 1456 ----- (1)

The total number of game consoles = 14

=> x + y = 14

=> x = 14 - y ---- (2)

Substitute (2) in (1)

=> 79(14 - y)  + 149y = 1456

=> 1104 - 79y + 149y = 1456

=> 70y = 350

=> y = 5

From (2) => x = 14 - 5 = 9

Therefore,

The number of  used games consoles is 9 and the number of new game consoles is 5

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Answer:

$129,870.13 AUD

Step-by-step explanation:

To find out what we need to solve, we can use these exchange rates:

Now, we need to divide 100,000 by 0.77.

We do this because we need to figure out how many times 0.77 must be multiplied to get 100,000. Then, we take that amount, and multiply that by however many AUD's you have.

Therefore, for every $100,000 USD, there is $129,870.13 AUD.

The solution is found by slope of the graph and the solution is 2,200.

Let x the amount of money per hour and y the total amount of money.

Studio A:-

Rents for 100 dollars plus 50 dollars per hour.

[tex]y= 100 + 50x[/tex]

So the slope is 50 and the y intercept is 100.

Studio B:-

rents for 50 dollars plus 75 dollars per hour.

[tex]y= 50 + 75x[/tex]

So the slope is 75 and the y intercept is 50.

ThrTh solution is 2200 , see the gragraphph.

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Complete question:- You and your friends decide to rent some studio time to make a CD. Big Notes Studio rents for $100 plus $50 per hour. Great Sounds Studio rents for $50 plus $75 per hour. Solve the system by graphic method.

Answer:

Ms. Perry needs to make an additional 1/24 kg of fudge.

Step-by-step explanation:

Ms. Perry has a total of 8/8 + 1/6 = 13/6 kg of fudge. She needs 1 1/8 kg of fudge for the brownies, which is equivalent to 9/8 kg. To find how much more fudge she needs to make, we can subtract the amount of fudge she already has from the amount she needs:

9/8 - 13/6 = 27/24 - 26/24 = 1/24

Therefore, Ms. Perry needs to make an additional 1/24 kg of fudge.

A continuous variable is a variable that can take on any value within a certain range, and often takes the form of real numbers but a discrete variable is a variable that can only take on specific values within a certain range, and often takes the form of integers

Continuous and discrete variables are two types of quantitative variables in statistics.

A continuous variable is a variable that can take on any value within a certain range, and often takes the form of real numbers. Examples of continuous variables include height, weight, time, temperature, and distance. These variables can be measured using instruments with varying degrees of precision, but they can theoretically take on an infinite number of values.

On the other hand, a discrete variable is a variable that can only take on specific values within a certain range, and often takes the form of integers. Examples of discrete variables include the number of siblings a person has, the number of cars in a parking lot, and the number of points a basketball team scores in a game. These variables can only take on a limited number of values, and often represent counts or whole numbers.

The main difference between continuous and discrete variables is the way they can be measured and the number of possible values they can take. Continuous variables can take on an infinite number of values and can be measured with varying degrees of precision, while discrete variables can only take on specific values and are often measured with exact precision.

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The number of days when there were at least 40 children in the park is 5 days.

To find the number of days that saw at least 40 children in the park, check the instances when there were either 40 children or more in the park.

Given the stem and leaf plot, the children in the park on days when there were more than 40 children or 40 children was:

The number of days is therefore 5 days.

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The distance between two cities are 7000 miles apart.

What is distance ?

Distance is the amount of space between two points or objects. In the context of the question you asked earlier, "distance between two cities" refers to the actual physical distance between the two cities in terms of miles.

Given by the question:
On the map, 500 miles is represented by each 0.5 inches. Therefore, 1 inch represents 1000 miles.

So, the distance between the two cities on the map is 7 inches. This corresponds to a real-world distance of:

distance on map / scale on map = actual distance

7 inches * 1000 miles/inch = 7000 miles

Therefore, the two cities are 7000 miles apart.

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The initial value of the investment is denoted by 480 in the function.

A function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

V(t) = 480 [tex](1.065)^t[/tex]

V is the total value after t years.

Now,

480 is constant and it indicates the initial value of the investment.

1.065 indicates that there is an increase of 6.5% each year.

Thus,

480 in the function denotes the initial value of the investment.

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If the average mass of one marble is 5 grams, and you have 2 moles of marbles, you would have 2 marbles.

What is Algebraic expression ?

Algebraic expression can be defined as combination of variables and constants.

The number of marbles you have will depend on the total mass of the marbles, as the number of moles is a measure of the amount of substance (in this case, marbles) rather than the actual number of marbles.

To calculate the number of marbles, you would need to know the mass of one marble, and then divide the total mass of the marbles by the mass of one marble.

For example, if the average mass of one marble is 5 grams, and you have 2 moles of marbles, you would first calculate the total mass:

mass = number of moles x molar mass

where the molar mass of a single marble is equal to its mass in grams, and the number of moles is given as 2:

mass = 2 moles x 5 grams/mole = 10 grams

Then, you can calculate the number of marbles by dividing the total mass by the mass of one marble:

number of marbles = total mass / mass of one marble

number of marbles = 10 grams / 5 grams/marble = 2 marbles

Therefore, if the average mass of one marble is 5 grams, and you have 2 moles of marbles, you would have 2 marbles.

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Answer:

[tex]a = \frac{5 \sqrt{2} }{2} [/tex]

[tex]c = \frac{3 \sqrt{3} }{2} [/tex]

Step-by-step explanation:

The first triangle is an isoceles right triangle, so the length of the hypotenuse is √2 times the length of each leg. So we have:

[tex]a \sqrt{2} = 5[/tex]

[tex]a = \frac{5}{ \sqrt{2} } = \frac{5 \sqrt{2} }{2} [/tex]

The second right triangle is a 30°-60°-90° triangle, so the length of the shorter leg is one-half the length of the hypotenuse, and the length of the longer leg is √3 times the length of the shorter leg. Here, the length of the shorter leg is 3/2, or 1.5, and so we have:

[tex] {( \frac{3}{2}) }^{2} + {c}^{2} = {3}^{2} [/tex]

[tex] {c}^{2} = \frac{27}{4} [/tex]

[tex]c = \frac{3 \sqrt{3} }{2} [/tex]

The conversion of 64kg in pounds  is equivalent to approximately 141.09568 pounds.

The kilogram (kg) is the SI unit of mass. It is equal to the mass of the international prototype of the kilogram. This prototype is a platinum-iridium international prototype kept at the International Bureau of Weights and Measures. One kg is approximately equal to 2.20462262184878 pounds.One pound, the international avoirdupois pound, is legally defined as exactly 0.45359237 kilograms.

To convert 64 kilograms to pounds, you can use the conversion factor of 1 kilogram = 2.20462 pounds.

Therefore,64 kilograms = 64 x 2.20462 pounds

= 141.09568 pounds (rounded to 5 decimal places)

So, 64 kilograms is equivalent to approximately 141.09568 pounds.

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The value of 350 milliliters to ounce after conversion the unit is equal to  11.8349 ounce.

Formula used to convert milliliters to ounce is written as:

One milliliter is equal to 0.033814 fluid ounce .

Now substitute the value 350 milliliters to convert into ounce we get,

⇒ 350 milliliters = ( 350 ) × (  0.033814 ) fluid ounce

⇒ 350 milliliters = ( 11.8349 ) fluid ounce

Therefore, the converted value of the milliliters to ounce for 350 milliliters is equal to  ( 11.8349 ) fluid ounce.

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The volume of the rectangular prism in the image is 480 cubic units.

What is volume ?

Volume is a measurement of the amount of space occupied by a three-dimensional object. It is a physical quantity that is measured in cubic units such as cubic meters (m³), cubic centimeters (cm³), or cubic feet (ft³).

The image shows a rectangular prism with a length of 12 units, a width of 8 units, and a height of 5 units.

To find the volume of a rectangular prism, you need to multiply its length, width, and height.

So, the volume of the rectangular prism in the image is:

Volume = length x width x height

Volume = 12 units x 8 units x 5 units

Volume = 480 cubic units

Therefore, the volume of the rectangular prism in the image is 480 cubic units.

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Answer:

0.06

Step-by-step explanation:

Identify the probability to the nearest hundredth that a point chosen randomly inside the rectangle either is in the hexagon or in the circle

Area of rectangle = 26.2 * 13 =  340.6 sq inch

Area of Hexagon  = 3√3(side)²/2 = 3√3 (1.8)²/2 = 8.42 sq inch

Area of circle = π(radius)² = 3.14 * (2)² = 12.56 sq inch

Area of hexagon + area of circle = 12.56 + 8.42 = 20.98 sq inch

Probability of selecting point inside the hexagon or in the circle  = 20.98/340.6

= 0.06

Answer:

1 Microliter = 0.001 Milliliter

Step-by-step explanation:

A unit can be used for measurement, and is commonly found in mathematics to describe length, size, etc.

Converting these units:

Therefore, for every 1 microliter it is equivalent to 0.001 Milliliter.