To find the probability that 15 or more instructors choose the book with the better format and illustrations, we can use the binomial distribution formula.
Let's denote the event of an instructor choosing the book with the better format and illustrations as "success" (S), and the event of an instructor choosing the other book as "failure" (F). The probability of success is p = 0.5, and the probability of failure is q = 1 - p = 0.5.
We want to find the probability of 15 or more successes in a sample of 25 instructors. We can calculate this probability by summing the probabilities of exactly 15, 16, 17, ..., 25 successes.
P(X ≥ 15) = P(X = 15) + P(X = 16) + ... + P(X = 25)
Using the binomial distribution formula, the probability of exactly k successes in a sample of n trials is:
P(X = k) = C(n, k) * p^k * q^(n-k)
where C(n, k) is the binomial coefficient "n choose k," given by:
C(n, k) = n! / (k! * (n-k)!)
Applying this to our problem, we can calculate the probability as follows:
P(X ≥ 15) = P(X = 15) + P(X = 16) + ... + P(X = 25)
= Σ[ k = 15 to 25 ] ( C(25, k) * p^k * q^(25-k) )
Let's calculate this probability using the binomial distribution formula:
P(X ≥ 15) = Σ[ k = 15 to 25 ] ( C(25, k) * (0.5)^k * (0.5)^(25-k) )
Calculating this sum gives us the probability that 15 or more instructors choose the book with the better format and illustrations.
In 2020, the Ministry of Health, in a report on investment in infrastructure and equipment for health units (2007-2020), counted 2,074 health units (between new and improved). If the number of improved health units exceeds the new ones by 200, how many new and improved health units are shown in the report?
The number of new health units is 937, and the number of improved health units is 1,137.
The number of improved health units exceeds the new ones by 200. In other words, I = N + 200.
We also know that the total number of health units counted in the report is 2,074.
Therefore, we have the equation N + I = 2,074.
Substituting the value of I from the first equation into the second equation, we can solve for N:
N + N + 200 = 2,074
2N + 200 = 2,074
2N = 1,874
N = 937
Now, we can substitute the value of N back into the first equation to find I:
I = N + 200
I = 937 + 200
I = 1,137
Therefore, the number of new health units is 937, and the number of improved health units is 1,137.
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a) Simplify p x q x 4
b) Simplify t x t x t
The expressions are simplified to;
a. 4pq
b. t³
What are algebraic expressions?Algebraic expressions are defined as expressions that are made up of terms, variables, coefficients, factors and constants.
These algebraic expressions are also made up of mathematical or arithmetic operations, such as;
AdditionMutiplicationDivisionBracketParenthesesSubtractionFrom the information given, we have that;
The expressions are;
1. p x q x 4
Multiply the terms, we have that;
4qp
2.t x t x t
Multiply the terms, we get;
t³
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solve the simultaneous equations
2x + 5y = -4
The solution to the system of equations is x = 2 and y = -1.
To solve the system of equations:
2x - 5y = 9 ...(1)
3x + 4y = 2 ...(2)
Multiplying equation (1) by 4 and equation (2) by 5, we can eliminate the variable 'y':
8x - 20y = 36 ...(3)
15x + 20y = 10 ...(4)
Adding equation (3) and equation (4), the 'y' terms cancel out:
(8x - 20y) + (15x + 20y) = 36 + 10
23x = 46
Dividing both sides of the equation by 23, we find:
x = 2
Plugging the value of 'x'
2(2) - 5y = 9
4 - 5y = 9
Subtracting 4 from both sides of the equation:
-5y = 9 - 4
-5y = 5
y = -1
Therefore, the solution to the system of equations is x = 2 and y = -1.
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A man had a square window with sides equal to 1 metre in his house. He decided that it lets in too much light, so he boarded up half of it and still had a square window 1 metre high and 1 metre wide. How did he do that? (6) Total: 40 marks
The man rotated the window by 45 degrees and covered one of the diagonals, resulting in a smaller square window with sides measuring 1 meter.
The man achieved the transformation of his square window by dividing it into two equal halves and boarding up one of them.
Let's analyze the steps he took to accomplish this:
Initially, the man had a square window with sides measuring 1 meter
This means that the window had an area of 1 square meter (1m x 1m = 1m²).
To reduce the amount of light coming through the window, the man decided to board up half of it.
This implies that he covered one of the equal halves of the square window, while leaving the other half open.
By boarding up half of the window, he effectively blocked off half of the area of the square window.
Since the original window had an area of 1 square meter, boarding up half of it reduces the effective area to 1/2 square meter (1m² ÷ 2 = 1/2m²).
The remaining open half of the window still retains its square shape, with sides equal to 1 meter.
Therefore, the man ends up with a square window that measures 1 meter in height and 1 meter in width, but with an area of only 1/2 square meter.
In summary, the man achieved the transformation by boarding up half of the square window, effectively reducing its area to half of the original size while maintaining the same dimensions for the remaining open half. This manipulation allows him to control the amount of light entering his house while preserving the square shape of the window.
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Assume that the probability density function of a continuous random variant X is
[tex]f(x)\left \{ {{0,5x, 0\ \textless \ x\ \textless \ 2} \atop {0, else}} \right.[/tex]
try to compute:
(1) E(2X)
(2) E(X^2)
The calculated values of the expected values are E(2x) = 8/3 and E(x²) = 2
How to calculate the expected valuesFrom the question, we have the following parameters that can be used in our computation:
f(x) = 0.5x, 0 < x < 2
The expected value of 2x is calculated as
E(2x) = ∫2x * f(x) dx
So, we have
E(2x) = ∫2x * 0.5x dx
Evaluate
E(2x) = ∫x² dx
Integrate the function
So, we have
E(2x) = x³/3
Using the boundaries, we have
E(2x) = (2 - 0)³/3
Evaluate
E(2x) = 8/3
The expected value of x² is calculated as
E(x²) = ∫x² * f(x) dx
So, we have
E(x²) = ∫x² * 0.5x dx
Evaluate
E(x²) = ∫0.5x³ dx
Integrate the function
So, we have
E(x²) = 0.5x⁴/4
Using the boundaries, we have
E(x²) = 0.5 * (2 - 0)⁴/4
Evaluate
E(x²) = 2
Hence, the expected values are E(2x) = 8/3 and E(x²) = 2
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wich expression is equivalent to x -5/3
Answer:
[tex] {x}^{ - \frac{5}{3} } = \frac{1}{ {x}^{ \frac{5}{3} } } = \frac{1}{ \sqrt[3]{ {x}^{5} } } [/tex]
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The value of probability P (A or B) is,
⇒ P (A or B) = 45
We have to given that;
To find the probability that either event will occur.
Now, By given figure we get;
P (A) = 25 + 5
P (A) = 30
P (B) = 5 + 15
P (B) = 20
P (A and B) = 5
Since, The formula is,
⇒ P (A or B) = P (A) + P (B) - P (A and B)
Substitute all the values we get;
⇒ P (A or B) = 30 + 20 - 5
⇒ P (A or B) = 50 - 5
⇒ P (A or B) = 45
Therefore, The value of probability P (A or B) is,
⇒ P (A or B) = 45
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which of the four venn diagrams repesents x
[tex]X'=\varepsilon\setminus X[/tex] where [tex]\varepsilon[/tex] is the universe. It means that [tex]X'[/tex] is everything except the set [tex]X[/tex], and that in shown in the image C.
State whether the equation is written in Standard, Intercept, or Vertex Form
m(x) = (x-3)(x+5)
The equation m(x) = (x-3)(x+5) is written in intercept form.
How to determine if the equation is written in Standard, Intercept, or Vertex FormThe equation m(x) = (x-3)(x+5) represents a quadratic function.
Analysing the equation.
Standard form of a quadratic equation is written as:
f(x) = ax^2 + bx + c, where a, b, and c are constants.
Intercept form of a quadratic equation is written as:
f(x) = a(x-p)(x-q), where a, p, and q are constants representing the x-intercepts.
Vertex form of a quadratic equation is written as:
f(x) = a(x-h)^2 + k, where a, h, and k are constants representing the vertex coordinates.
The factors (x-3) and (x+5) represent the x-intercepts of the quadratic function.
Therefore, the equation m(x) = (x-3)(x+5) is written in intercept form.
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how do i do this? i have test on it tomorrow
The measure of the angle ∠ADC is 36°.
Given that a circle T, the inscribed angle ∠ABC = 72°, we need to find the measure of the angle ∠ADC,
So, according to the inscribed angle theorem,
2 ∠ABC = arc AC
arc AC = 144°
Now, since the whole circumference is 360°,
So,
arc ADC = 360° - arc AC
arc ADC = 216°
So,
∠ADC = 1/2 [arc ADC - arc AC]
∠ADC = 1/2 [216° - 144°]
∠ADC = 36°
Hence the measure of the angle ∠ADC is 36°.
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Complete the table by identifying u and du for the integral.
can anyone help me
The required first answer u = [tex]x^{2}[/tex] + 1 and du = 2x and second answer u = tanx and du = [tex]sec^2 x[/tex] .
Given that if [tex]\int\limits {f(g(x)) g'(x)} \, dx[/tex] then u = g(x) and du = g'(x),
[tex]\int\limits {\frac{x}{\sqrt{x^2+1} } } \, dx[/tex] and [tex]\int\limits {tan^2 x sec^2 x} \, dx[/tex]
To find u and du by using the integral property
[tex]\int\limits {f(g(x)) g'(x)} \, dx = f(g(x))[/tex].
Consider [tex]\int\limits {\frac{x}{\sqrt{x^2+1} } } \, dx[/tex]
The above integral can be expressed as
[tex]\int\limits {\frac{x}{\sqrt{x^2+1} } } \, dx = \int\limits {\frac{1}{\sqrt{x^2+1} } } \,x dx[/tex]
That implies, u = g(x) = [tex]x^{2}[/tex] + 1.
Differentiating with respect to x gives,
du = g'(x)
du = d/dx( [tex]x^{2}[/tex] + 1 )
du = 2x + 0.
du = 2x.
Consider [tex]\int\limits {tan^2 x sec^2 x} \, dx[/tex]
The above integral can be expressed as
[tex]\int\limits {tan^2 x sec^2 x} \, dx = \int\limits {(tanx)^2 sec^2 x} \, dx[/tex]
That implies, u = g(x) = tanx.
Differentiating with respect to x gives,
du = g'(x)
du = d/dx( tanx )
du = [tex]sec^2 x[/tex].
du = [tex]sec^2 x[/tex].
Hence, the required first answer u = [tex]x^{2}[/tex] + 1 and du = 2x and second answer u = tanx and du = [tex]sec^2 x[/tex].
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State if the triangles in each pair are similar. If so, state how you know they are similar and
complete the similarity statement.
1)
16
ADEF-
12
18
24
D
12
similar; AA similarity; AJKL
similar; SAS similarity; AKLJ
not similar
no
The triangle ∆DEF is similar by the SSS similarly to the triangle ∆JKL
What are similar trianglesSimilar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.
To know if the triangles DEF and JKL are similar, we check if their sides corresponds in the same ratio, that is;
JK/DE = KL/EF = JL/DF
JK/DE = 9/12 = 3/4
KL/EF = 18/24 = 3/4
JL/DF = 12/16 = 3/4
Therefore, the triangle ∆DEF is similar by the SSS similarly to the triangle ∆JKL
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How many paths are there from $A$ to $B,$ if you travel along the edges? You can travel along each edge at most once, but you can pass through the same point more than once. (You can pass through $B,$ as long as you end up at the point $B.$)
Answer:
9
Step-by-step explanation:
You don't need to pass through each edge once.
If we name the top vertex 1 and the bottom vertex 2 then here are the possible combinations:
A-1-B
A-B
A-2-B
A-1-B-A-2-B
A-2-B-A-1-B
A-B-1-A-2-B
A-B-2-A-1-B
A-1-B-2-A-B
A-2-B-1-A-B
Some people say 6 because they think you need to pass through all the edges. But the only restriction with travelling on the edges is you can't pass one twice. The point is read the wording and it becomes easy.
Hope this helps!
Hello i need help please
[tex]2\cdot20\text{ m}\cdot n+2\cdot20\text{ m}\cdot 5\text{ m}+2\cdot 5\text{ m}\cdot n=1100\text{ m}^2\\40n\text{ m}+200\text{ m}^2+10n\text{ m}=1100\text{ m}^2\\50n\text{ m}=900\text{ m}^2\\n=18\text{ m}[/tex]
Beridze Manufacturing expects to produce 2,400 units in January and 3,700 units in February. Beridze budgets $45 per unit for direct materials. The amount of indirect materials needed for production has been determined to be insignificant and will therefore not be considered in the calculation. The balance in the Raw Materials Inventory account (all direct materials) on January 1 is $39,150. Beridze desires the ending balance in Raw Materials Inventory to be 10% of the next month's direct materials needed for production. Desired ending balance for February is $50,200. What is the cost of budgeted purchases of direct materials needed for January?
Question content area bottom
Part 1
A.$ 108 comma 000
$108,000
B.$ 79 comma 650
$79,650
C.$ 124 comma 650
$124,650
D.$ 85 comma 500
A
Step-by-step explanation:
Priya and Hadley, fans of this player, calculate the expected value of X is E(X) = 0.80. Priya says, "The probability that this player makes a free-throw is 0.80, on average." Hadley says, "This player will make 0.80 free-throws in his next set of 2." Whose statement is correct based on the expected value? Choose 1 answer: B Only Priya's Only Hadley's Both statements are correct. Neither statement is correct.
Only Priya's statement is correct based on the expected value. The expected value of X represents the average or mean number of successful free-throws that the player makes. Therefore, it is correct to say that the probability of making a free-throw is 0.80 on average. Hadley's statement about the next set of 2 free-throws is incorrect because the expected value does not tell us exactly how many free-throws the player will make in a given set, but rather what the average or expected number of successful free-throws will be over a series of trials.
Please Answer!
Given the following diagram, find the required measures.
Answer:
55°
Step-by-step explanation:
if angle 4 = 105°, then angle 3 must be 180 - 105 = 75° (angles in straight line add up to 180°).
angles in a triangle also add up to 180°.
so we expect angle 2 to be 180 - angle 6 - angle 3
= 180 - 50 - 75
= 55°.
A boy walks 1260m on a bearing of 120°. How far south is he from his starting point
The boy is 630 meters south from his starting point.
To determine how far south the boy is from his starting pointWe must take into account the southward component of his shift.
We can imagine a right-angled triangle where the hypotenuse represents the boy's total displacement of 1260 meters, the angle between the hypotenuse and the south direction is 120°, and the side next to the angle represents the southward displacement given that the boy walks 1260 meters on a bearing of 120°.
We can use trigonometric functions to calculate the displacement to the south. Since the adjacent side and hypotenuse of a right triangle are connected in this instance, we will use the cosine function.
cos(120°) = adjacent / hypotenuse
cos(120°) = adjacent / 1260
Solving for the adjacent side (southward displacement):
adjacent = cos(120°) * 1260
adjacent = (-0.5) * 1260
adjacent = -630
The negative sign indicates that the southward displacement is in the opposite direction or "south" relative to the starting point.
Therefore, the boy is 630 meters south from his starting point.
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Two snails have shells that are similar in shape. The younger snail has a shell with a height of 3.9 centimeters and a volume of 3 cubic centimeters. The older snail has a shell with a volume of 10 cubic centimeters. Estimate the height of the older snail’s shell. Round your answer to the nearest tenth.
can someone pls answer this asap and show ur work
The estimated height of the older snail's shell is approximately 13 centimeters.
To estimate the height of the older snail's shell, we can use the concept of proportional relationships between the heights and volumes of the snail shells.
Let's denote the height of the older snail's shell as "h" (in centimeters). We can set up a proportion based on the relationship between the heights and volumes of the snail shells:
(height of younger snail) / (volume of younger snail) = (height of older snail) / (volume of older snail)
Substituting the given values:
3.9 / 3 = h / 10
To solve for "h," we can cross-multiply and then divide:
3 * h = 3.9 * 10
3h = 39
h = 39 / 3
h ≈ 13
The estimated height of the older snail's shell is approximately 13 centimeters.
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Line l bisects segment BC of triangle ABC, where A is at (3, -3), B is at (1, 4), and C is at (3, -2). If line l also travels through point A, what is its equation?
A. y=-5x-1
B. y=-2x+4
C. y=-4x+9
D. y=4x-1
E. y=5x+4
Answer:
Option C y = -4x + 9
Step-by-step explanation:
Equation of a line:The line l bisects BC. The line l passes through the midpoint of BC.
B(1, 4) ; C(3 , -2)
[tex]\sf Midpoint \ of \ BC = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]
[tex]\sf = \left(\dfrac{1+3}{2},\dfrac{4-2}2{}\right)\\\\\\=\left(\dfrac{4}{2},\dfrac{2}{2}\right)\\\\\\=(2 , 1)[/tex]
Line l passes through (2,1) and A(3 , -3),
[tex]\sf \boxed{Slope =\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]\sf =\dfrac{-3-1}{3-2}\\\\\\=\dfrac{-4}{1}\\\\=-4[/tex]
m = -4
Equation of line in slope intercept form: y =mx +c
Here, m is the slope and c is the y-intercept.
y = -4x + c
As the line l is passing through (2,1), substitute the point (2,1) in the above equation and find c.
1 = -4*2 + c
1 = -8 + c
1 + 8 = c
c = 9
Equation of the line l:
y = -4x + 9
How to solve triangle inequalities?
Answer: The triangle inequality theorem describes the relationship between the three sides of a triangle. According to this theorem, for any triangle, the sum of lengths of two sides is always greater than the third side.
what is the GCF of 36+60
Answer:
The GCF (Greatest Common Factor) of two numbers is the largest number that divides both of them. In this case, the GCF of 36 and 60 is 12.
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Need help on finding g .
Evaluating the piecewise function we will get:
g(-1) = -2
g(2) = 0
g(3) = 1/2
How to evaluate the piecewise function?To evaluate the piecewise function we need to use the correct part depending on the domains.
g(-1), here x = -1, then we need to use the second part of the function:
g(-1) = -(-1 - 1)² + 2 = -4 + 2 = -2
For the second one x = 2, we use the last part:
g(2) = (1/2)*2 - 1 = 0
For the last one, we have x = 3, again we need to use the last part:
g(3) = (1/2)*3 - 1 = 3/2 - 2/2 = 1/2
These are the 3 values.
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Solve h(t) = -16t^2 + 16t + 480 where t is time and h is height and finding out how long it would take a ball to hit the ground.
Answer: Factor the problem
Step-by-step explanation:
Take out the common factor (-16), it will leave you with (t^2 - t - 30)
Factor (t - 6) (t + 5)
t - 6 = 0 or t + 5 = 0
t = 6 seconds
can someone explain how to do this please?
Answer: 97 degrees
Step-by-step explanation: 180-83=97
Question
Given the frequency table below, what is the relative frequency of the data value 8?
Value
4
5
6
7
8
Frequency
2
7
9
6
6
Answer:
2
3
5
5
7
13
14
17
21
31
52
Step-by-step explanation:
but I think the town & is the best. I am not coming out of my reward.. this will be the last one day.. this will not go on. I am not coming to the office until tomorrow as I'm working for, and if I don't get any of that, I'll break it up with a choice. I am a bit worried, so I was 165 2762
find the ordered pair
The ordered pair that is a solution of the system is (-3, -3), the second option.
Which ordered pair is a solution of the system of inequalities?There are two ways of finding this.
You can use your graph and identify which of the given pointes lies in the region where the two shaded areas intersect.
Another way, is replacing the values of the coordinate points in both inequalities and checking that both are true when evaluated in the point.
Here we will use the graph, because you already had it (and you can see a more precise graph in the image at the end).
We can see that the region os solutions is on the left side of the graph, and the only point that lies on there is (-3, -3)
So that point is the solution.
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cm 84. A father's age was three times and two times of his son at 2040 and 2050 respectively. What will be the birth year of son? a. 2030 b. 2035 c. 2031 d. 2032 100
Answer:
(a)2030
Step-by-step explanation:
I'm assuming the 100 at the end of the question is a typo.
In 2040, the son's age can be written as [tex]\frac{x}{3}[/tex], where x equals the age of his father. In 2050, the son's age can be written as [tex]\frac{x-10}{2}[/tex] (as ten years is added between 2040 and 2050). When equated to each other--> [tex]\frac{x-10}{2}[/tex] = [tex]\frac{x}{3}[/tex], we can first simplify by multiplying both sides to reach the least common denomination 6, giving us 3(x-10)=2x --->3x-30=2x--->x=30 is the dad's age. The son's age in 2040, 30/3, is equal to 10 years, meaning he was born in the year 2030 (a).
A car rental company charge $50 a day and 20 cents per mile for renting a car. Let y be the total rental charge (in dollar) for a car for one day and x be the miles driven. The equation for the relationship between x and y is y = 50 + 20x How much will a person pay who rents a car for one day and drives it 100miles
Answer:$2050.
Step-by-step explanation:
To find out how much a person will pay for renting a car for one day and driving it 100 miles using the given equation, you can substitute x = 100 into the equation y = 50 + 20x and solve for y:
y = 50 + 20x
y = 50 + 20(100)
y = 50 + 2000
y = 2050
Therefore, a person who rents a car for one day and drives it 100 miles will pay $2050.
Evaluate : 3² x (-2)³ x 5 Working out:
Answer: 180
Step-by-step explanation:
Use the order of operations: PEMDAS
Parenthesis
Exponents
Multiplication/Division
Addition/Subtraction
3² x (-2)³ x 5 >There is nothing to simplify within parenthesis
>Exponents are next in Order of Operations
(3)(3) x (-2)(-2) x 5 >This is the exponents expanded
9 x 4 x 5 >Multiply from left to right
36 x 5
180