The gravitational force was multiplied by nine. Inversely proportionate to their squared distance, the two bodies' gravitational pull on one another.
In light of this, The gravitational force would rise by a factor of 9 as the distance shrunk to 1/3 of its initial amount.
What does a scientific force mean?A specific meaning is associated to the adjective "force." The terms "push" & "pull" are totally acceptable at this level to express forces. An object does not have a force inside of it or within it. Another object applies a force to the first. Both living things and non-living things can be considered to be parts of a force.
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1. A charge of 6.4 C passes through a cross-sectional area or conductor in 2s. How much charge will pass through a cross sectional area of the conductor in 1 min?
The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.
What is the amount of charge?
We can use the formula Q = I * t,
where;
Q is the amount of charge, I is the current, and t is the time.Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:
I = Q / t = 6.4 C / 2 s = 3.2 A
So, the current through the conductor is 3.2 A.
To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:
Q = I * t = 3.2 A * 60 s = 192 C
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On a particular day, the following appliances are used for the times indicated: a 1600-W coffee maker, 13 min, and a 1100-W microwave oven, 4.5 min. With these power requirements, find how much it costs to use these appliances at an electrical cost of 7¢ per kWh. (Do not round your final answer. Fractional cent values are acceptable.)
The following devices are utilised on a specific day for the durations listed: a 1600-W coffee machine for 10 minutes as well as a 1100-W microwave for 4 minutes.
What time is it now?The duration of occurrences or the gaps between them can be measured, compared, or even ordered using time.
Events: What are they?The event description key is then used by the API to deliver events to the proper journeys. For instance, the key "Acme-MovieRented" is used in an event definition. A simple occurrence is one that has only one possible conclusion. Meetings for business or to do normal business are not seen as social occasions unless they actually turn into such as a consequence of the activity.
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determine the frequency bandwidth (in hz) and the high cut-off frequency (in hz) of a first- order thermal sensor having a time constant of 0.1s when subjected to the sinusoidal temperature variation, t(t)
The frequency band width is 1.59 Hz and high cut-οff frequency is 1.59 Hz.
What is frequency?The frequency οf a repeated event is its number οf instances per unit οf time. It differs frοm angular frequency and is sοmetimes referred tο as tempοral frequency fοr clarificatiοn. The unit οf frequency is hertz (Hz), οr οne οccurrence per secοnd. The time elapsed between events is measured by the periοd, which is the reciprοcal οf the frequency.
Given data:-
The temperature [tex]$\mathrm{T}(\mathrm{t})=20 \sin \omega t$[/tex] And the time constant [tex]$\mathbf{T}=0.1 \mathrm{sec}$[/tex] The general equation of first order [tex]$\mathbf{H}(\mathrm{s})=\frac{\mathrm{K}}{T \mathrm{~T}+1}$[/tex] and [tex]$\mathrm{s}=\mathrm{j} \omega$[/tex]. Now the general first-order equation:
[tex]$\begin{aligned}\mathbf{H}(\mathrm{s}) & =\frac{\mathrm{K}}{(\mathrm{Ts}+1)} \\\mathrm{H}(\mathrm{j} \omega) & =\frac{\mathrm{K}}{(0.1 \mathrm{j} \omega)+1}\end{aligned}[/tex]
The magnitude of the [tex]$\mathrm{H}(\mathrm{j} \omega)$[/tex]
[tex]$|H(j \omega)|=\frac{K}{\sqrt{(0.1 \omega)^2+1}}$[/tex]
Now for the higher and lower frequency, i.e. [tex]$\mathrm{f}_{\mathrm{L}}$[/tex] and [tex]$\mathrm{f}_{\mathrm{h}}$[/tex]The upper frequency when [tex]$\omega=\frac{1}{\mathrm{~T}}=\frac{1}{0.1}=10 \mathrm{rad} / \mathrm{sec}$[/tex] the magnitude [tex]$|\mathrm{H}(\mathrm{j} \omega)|=\frac{\mathrm{K}}{\sqrt{2}}$[/tex] and a lower frequency when [tex]$\mathrm{\omega=0\ magnitude}\ |\mathrm{H}(\mathrm{j} \omega)=\mathrm{K}|$[/tex]
The upper frequency [tex]$\omega=2 \pi f$[/tex]
[tex]$\mathrm{f}_{\mathrm{h}}=\frac{10}{2 \pi}=1.59 \mathrm{~Hz}$$And lower frequency$$\mathrm{f}_{\mathrm{L}}=0$[/tex]
Now the frequency band width [tex]$\mathrm{B}=\mathrm{f}_{\mathrm{h}}-\mathrm{f}_{\mathrm{L}}=1.59-0=1.59 \mathrm{~Hz}$[/tex]
Thus, The frequency band width is 1.59 Hz and high cut-off frequency is 1.59 Hz.
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the position of a pinewood derby car was observed at various times; the results are summarized in the following table. find the average velocity of the car for the following time periods.
The position of a pinewood derby car was observed at various times; the results are summarized in the following table therefore the average velocity of the car for the following time periods is 11.04m/s.
What is Velocity?
This is referred to as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
Velocity = distance/time
This therefore means that velocity = v5 - v1 / t5- t1
Velocity = 57.5 - 2.3 / 5- 0
= 55.2/5 = 11.04m/s
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The full question is:
the position of a pinewood derby car was observed at various times; the results are summarized in the following table. find the average velocity of the car for the following time periods.
T(s) 0 1 2 3 4 5
X(m)0 2.3 9.2 20.7 36.8 57.5
Derive Lorentz transformation
Lorentz transformation is a mathematical framework that describes how the coordinates of an event in space and time change for two observers in relative motion.
What is Lorentz transformation?Consider two inertial frames of reference, S and S', moving relative to each other along the x-axis with a constant velocity v. Let an event occur at position (x, y, z, t) in frame S, and let (x', y', z', t') be the corresponding position in frame S'.
The transformation equations for space and time are given by:
[tex]x' = γ(x - vt)\\y' = y\\z' = z\\t' = γ(t - vx/c^2)[/tex]
where[tex]γ = 1/√(1 - v^2/c^2)[/tex] is the Lorentz factor, and c is the speed of light.
These equations show how the coordinates of an event in one frame of reference are related to the coordinates in another frame of reference that is moving relative to the first frame. They are known as the Lorentz transformations and are a fundamental aspect of special relativity.
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obtain approximately 0.5 gram of your unknown mixture. your instructor can help you approximate the amount until you get a precise measurement. take the mass of your empty evaporating dish. slowly add your sample. measure the mass of the evaporating dish and sample. using the subtraction method, find the mass of your sample. next, begin removing the iron filings from the sample using a magnet. once you have removed all of the iron, reweigh your evaporating dish to find the mass of the iron by mass loss. part b:
I can provide you with general guidance on how to carry out the steps you have described for the following experiment by taking the mass of your empty evaporating dish.
What are the steps needed to done this experiment?
Obtain an evaporating dish and measure its mass using a balance. Record this mass.Add your unknown mixture to the evaporating dish in small amounts, while measuring the mass of the dish and mixture each time using the balance. Keep adding until you have approximately 0.5 gram of the mixture in the dish.Once you have added the sample to the dish, find the mass of the sample by subtracting the mass of the empty dish from the mass of the dish with the sample.Use a magnet to remove the iron filings from the sample. Once you have removed all of the iron, reweigh the evaporating dish to find the mass of the iron by mass loss. Subtract the mass of the iron from the mass of the original sample to obtain the mass of the remaining components.If necessary, repeat the experiment to obtain more accurate measurements.Remember to record all your measurements and observations accurately and neatly in your lab notebook or report.To learn more about evaporating dish, visit: https://brainly.com/question/14674337
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An artillery shell is fired with an initial velocity of 300 m/s at 55.5° above the horizontal. To clear an avalanche, it explodes on a mountainside 47.0 s after firing. What are the x- and y-coordinates of the shell where it explodes, relative to its firing point?
The x-coordinate of the shell where it explodes, relative to its firing point, is approximately 7688.1 meters, and the y-coordinate is approximately 9507.8 meters.
Is initial velocity always 0?If an automobile is at rest, its beginning velocity is 0.The starting velocity of an automobile that stops after using the brakes will be greater than zero, but the ultimate velocity will be zero.
The kinematic equations of motion can be used to resolve this issue.We can break down the initial velocity into its x- and y-components:
Vx = V0 cosθ = (300 m/s) cos(55.5°) ≈ 163.3 m/s
Vy = V0 sinθ = (300 m/s) sin(55.5°) ≈ 247.2 m/s
Next, we can use the equations of motion to find the shell's position after 47.0 seconds. The x-coordinate is given by:
x = Vx t = (163.3 m/s)(47.0 s) ≈ 7688.1 m
The y-coordinate is given by:
y = Vy t + (1/2)gt²= (247.2 m/s)(47.0 s) + (1/2)(9.81 m/s²)(47.0 s) ≈ 9507.8 m
where g is the acceleration due to gravity.
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A small 8.00 kg rocket burns fuel that exerts a time-varying upward force on the rocket (assume constant mass) as the rocket moves upward from the launch pad. This force obeys the equation F=A+Bt2. Measurements show that at t=0, the force is 100.0 N, and at the end of the first 2.00 s, it is 162.0 N.
A. Find the net force on this rocket at the instant after the fuel ignites.
B. Find the acceleration of this rocket at the instant after the fuel ignites.
C. Find the net force on this rocket 3.00 ss, after the fuel ignites.
D. Find the acceleration of this rocket 3.00 ss, after fuel ignition.
E. Suppose that you were using this rocket in outer space, far from all gravity. What would its acceleration be 3.00 ss, after fuel ignition?
a) The net force at the point of fuel ignition is F = A = 100 N.
b) Acceleration after fuel ignites is a = 12.5 m/s^2
c) The net force on the rocket at t=3.00 s is 403 N.
d) Acceleration of rocket 3.00 ss after fuel ignites is a = 50.4 m/s^2
e) Acceleration in outer space is a = 50.4 m/s^2
How the solution was obtainedA. The force at t=0 is given as 100 N, so A = 100 N. We can use the given information to find B:
F = A + Bt^2
162 N = 100 N + B(2.00 s)^2
B = (162 N - 100 N) / (2.00 s)^2
B = 31 N/s^2
Therefore, the net force on the rocket at t=0 is:
F = A = 100 N.
B. The acceleration of the rocket is given by Newton's second law:
F_net = ma
where F_net is the net force acting on the rocket, and a is the acceleration of the rocket. At t=0, the net force on the rocket is 100 N. Therefore, the acceleration of the rocket at t=0 is:
a = F_net / m
a = 100 N / 8.00 kg
a = 12.5 m/s^2
C. To find the net force on the rocket at t=3.00 s, we can simply plug in t=3.00 s into the force equation:
F = A + Bt^2
F = 100 N + 31 N/s^2 (3.00 s)^2
F = 403 N
Therefore, the net force on the rocket at t=3.00 s is 403 N.
D. To find the acceleration of the rocket at t=3.00 s, we can use the same equation as in part B:
F_net = ma
At t=3.00 s, the net force on the rocket is 403 N. Therefore, the acceleration of the rocket at t=3.00 s is:
a = F_net / m
a = 403 N / 8.00 kg
a = 50.4 m/s^2
E. In outer space, far from all gravity, the only force acting on the rocket is the force from the burning fuel. Therefore, the net force on the rocket is simply the force from the burning fuel:
F = A + Bt^2
F = 100 N + 31 N/s^2 (3.00 s)^2
F = 403 N
Using the same equation as in part B, the acceleration of the rocket is:
a = F_net / m
a = 403 N / 8.00 kg
a = 50.4 m/s^2
Therefore, the acceleration of the rocket in outer space would be the same as in part D.
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An airplane flies between two points on the ground that are 500 km apart. The destination is directly north of the origination of the flight. The plane flies with an air speed of 120 m/s. If a constant wind blows at 24 m/s due west during the flight, what direction must the plane fly relative to north to arrive at the destination?.
The plane must fly at an angle of 11.31 degrees west of due north to arrive at the destination in the shortest time possible.
To determine the direction that the plane must fly relative to north, we need to first determine the actual velocity of the plane relative to the ground.
Let's break down the velocity vectors involved in the flight:
The air speed of the plane is 120 m/s in a direction perpendicular to the plane's heading (i.e., to the east).
The wind speed is 24 m/s due west.
Using vector addition, we can find the resultant velocity vector of the plane relative to the ground:
The eastward component of the plane's velocity is 120 m/s.
The westward component of the wind's velocity is 24 m/s.
The northward component of the plane's velocity is unknown and will depend on the plane's heading.
We can use the Pythagorean theorem to find the magnitude of the resultant velocity vector:
[tex]resultant speed^2 = eastward speed^2 + northward speed^2[/tex]
[tex]resultant speed^2 = (120 m/s)^2 + northward speed^2[/tex]
resultant speed = [tex]\sqrt{[(120 m/s)^2 + northward speed^2]}[/tex]
Since the destination is directly north of the origin, the plane's heading must be northward. Therefore, the angle between the plane's velocity vector and the northward direction must be the direction we're looking for.
To find this angle, we can use trigonometry. Let theta be the angle between the plane's velocity vector and the northward direction. Then:
tan(theta) = northward speed / 120 m/s
northward speed = 120 m/s * tan(theta)
Substituting this into the equation for the magnitude of the resultant velocity vector, we get:
resultant speed = [tex]\sqrt{[(120 m/s)^2 + (120 m/s * tan(theta))^2]}[/tex]
We want the resultant velocity vector to be equal to the distance between the two points on the ground (500 km) divided by the time of the flight. We can convert this to meters per second by dividing by the duration of the flight in seconds:
resultant speed = 500000 m / (flight time in seconds)
Equating this with the expression we derived for the magnitude of the resultant velocity vector, we get:
500000 m / (flight time in seconds) = [tex]\sqrt{[(120 m/s)^2 + (120 m/s * tan(theta))^2]}[/tex]
Solving for the flight time in seconds and simplifying, we get:
flight time = [tex]500000 m \sqrt{[(120 m/s)^2 + (120 m/s * tan(theta))^2]}[/tex]
To minimize the flight time, we need to maximize the northward component of the plane's velocity. We can do this by making the angle theta as small as possible, i.e., by flying as close to due north as possible.
Taking the derivative of the flight time expression with respect to theta, we get:
d(flight time) / d(theta) =[tex]-60000 * tan(theta) / (120^2 * (1 + tan(theta)^2)^(3/2))[/tex]
Setting this equal to zero, we find that the optimal value of theta is arctan(1/5), which is approximately 11.31 degrees. Therefore, the plane must fly at an angle of 11.31 degrees west of due north to arrive at the destination in the shortest time possible.
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9
17. Mary is 14 years old, weighs 125 pounds and is 5ft 6in tall. What is her
Basal Metabolic Rate? (Use the formula found in the "Nutrition &
Metabolism" worksheet. Round to the nearest whole calorie)
1326
O 1436
O 1568
O 2436
The basal metabolic rate for the girl of 14 years weighing 125 pounds and height of 5ft.6 inch is 1573 Kcal/day.
What is basal metabolic rate ?The basal metabolic rate of a person is the number of calories that is burned inside the body through basic life -sustaining metabolic functions. It can be calculated using the below equations for men and women.
BMR for men = 88.362 + (13.397 x weight in kg) + (4.799 x height in cm) – (5.677 x age in years)
BMR for women = 447.593 + (9.247 x weight in kg) + (3.098 x height in cm) – (4.330 x age in years).
Given, the age = 14 years
weight = 125 pounds = 56.7 kg
1 feet = 30.48 cm
1 inch = 2.54 cm.
then 5ft.6inch = 167.64 cm.
Now BMR = 447.593 + (9.247 x 56.7) + (3.098 x 167.64 ) – (4.330 x 14)
= 1573 Kcal/day.
Therefore, the basal metabolic rate of the girl is 1573 Kcal/day.
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A battery is rated such that it provides 1.0 mW of power at 9.0 V when fully charged. How much current can it deliver?
The current the battery can deliver, given that the battery is rated 1.0 mW at 9.0 V is 0.00011 A
How do I determine the current the battery can delivery?Electrical power is defined according to the following formula:
Power (P) = Current (I) × voltage (V)
With the above formula, we can obtain the current the battery can deliver. This is shown below:
From the question given above, the following data were obtained:
Power (P) = 1.0 mW = 1 / 1000 = 0.001 WattVoltage (V) = 9.0 V Current (I) =?Power (P) = Current (I) × voltage (V)
0.001 = Current × 9
Divide both sides by 9
Current = 0.001 / 9
Current = 0.00011 A
Thus, the we can conclude that the current is 0.00011 A
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The battery can deliver a current of 111 microamps when fully charged.
How much current can it deliver?
To determine the current that a battery can deliver, we can use the formula for power:
Power = Voltage x Current
We are given the power rating of the battery as 1.0 mW and the voltage as 9.0 V. Therefore, we can rearrange the above formula to solve for the current:
Current = Power / Voltage
Plugging in the values, we get:
Current = 1.0 mW / 9.0 V
Converting milliwatts to watts:
Current = 0.001 W / 9.0 V
Simplifying:
Current = 0.000111 A or 111 µA
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if the earth exerts a force of 5000N on satellite Aldock keep it in orbit calculate the height
The height of the satellite Aldock in orbit is approximately 1,419,288 meters or 1,419.3 kilometers above the Earth's surface.
What is the height of the satellite?
The height of a satellite in orbit around the Earth can be calculated using the following formula:
h = (GMt/4π²)^(1/3) - Re
where:
h is the height of the satellite above the Earth's surfaceG is the gravitational constant (6.67430 × 10^-11 m^3/kg/s^2)Mt is the mass of the Earth (5.972 × 10^24 kg)Re is the radius of the Earth (6,371 km)To solve for h, we need to know the mass of the satellite and the speed of its orbit. However, we can use the given information that the Earth exerts a force of 5000N on the satellite to calculate the speed of the orbit using the centripetal force equation:
F = mv^2/r
where:
F is the force of gravity (5000 N)m is the mass of the satellitev is the speed of the satellite in its orbitr is the distance between the center of the Earth and the satellite (which is equal to the sum of the height of the satellite and the radius of the Earth)Solving for v, we get:
v = √(Fr/m)
v = √((5000 N) * (6,371,000 m)) = 7919.26 m/s
Now that we know the speed of the orbit, we can use the first formula to solve for the height of the satellite:
h = (GMt/4π²)^(1/3) - Re
Substituting the given values, we get:
h = [(6.67430 × 10^-11 m^3/kg/s^2) * (5.972 × 10^24 kg) / (4π²)]^(1/3) - 6,371,000 m
= 1,419,288 m
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The mass of Jupiter can be calculated by
A) measuring the orbital period and distance of Jupiter's orbit around the Sun.
B) measuring the orbital period and distance of one of Jupiter's moons.
C) measuring the orbital speed of one of Jupiter's moons.
D) knowing the Sun's mass and measuring how Jupiter's speed changes during its elliptical orbit around the Sun.
E) knowing the Sun's mass and measuring the average distance of Jupiter from the Sun.
Knowing the Sun's mass and measuring how Jupiter's speed changes during its elliptical orbit around the Sun.
What do you mean by mass?
Mass is a fundamental physical property of an object that measures the amount of matter it contains. In other words, mass is a measure of the object's inertia, or resistance to changes in its motion. The more massive an object is, the harder it is to accelerate it, and the greater its gravitational attraction to other objects.The SI unit of mass is the kilogram (kg).
The principles of planetary motion established by Kepler and Newton and the laws of gravitation can be used to calculate Jupiter's mass. The Sun and Jupiter's gravitational pull on each other is determined by their relative sizes, masses, and separation. The gravitational force pulling Jupiter towards the Sun can be computed using the period and distance of Jupiter's elliptical orbit around the Sun as well as the mass of the Sun. Jupiter's acceleration, which can be determined from variations in its speed during its elliptical orbit, is connected to the force of gravity that is acting on it.
It is possible to calculate Jupiter's mass using these measurements and computations. For an exact calculation of Jupiter's mass, the other methods offered are insufficient. Option A) gives details regarding
These data and computations can be used to estimate Jupiter's mass. Jupiter's mass cannot be reliably calculated using the other alternatives provided. Option A) includes details on Jupiter's orbit but does not immediately provide details regarding its mass. The orbital period and speed of Jupiter's moons are disclosed in options B) and C), although these numbers also rely on the moons' mass, their distance from Jupiter, and other factors. While Option E) provides data on Jupiter's average separation from the Sun, it does not provide data on its mass.
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A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9. 8 m/s2 for g. Use 1000 kg/m3 as the weight density of water. Assume that a = 4 m, b = 4 m, c = 9 m, and d = 4 m. )
The work required to pump the water out of the spout is 11,011,392 J.
What is a spout?
A spout is typically a small opening or nozzle through which a fluid (such as water) can flow. The spout may be a part of a container, such as a tank or a pitcher, or it may be a separate attachment, such as a faucet or a sprinkler. The spout is important in the study of fluid dynamics, which is the branch of physics that deals with the motion of fluids and the forces that act on them.
To find the work required to pump the water out of the spout, we need to determine the weight of the water in the tank and the height through which the water needs to be lifted.
The weight of the water in the tank can be found using its volume and weight density. The volume of the tank is given by:
V = a * b * c = 4 m * 4 m * 9 m = 144 [tex]m^{3}[/tex]
The weight of the water can be found using the:
W = m * g = V * ρ * g
where m is the mass of the water, g is the acceleration due to gravity, and ρ is the weight density of water.
Substituting the given values, we have:
W = V * ρ * g = 144 [tex]m^{3}[/tex] * 1000 kg/[tex]m^{3}[/tex] * 9.8 m/[tex]s^{2}[/tex] = 1,411,200 N
Next, we need to determine the height through which the water needs to be lifted. This is equal to the distance from the spout to the surface of the water in the tank. The height can be found using the Pythagorean theorem since the spout is at a diagonal distance from the base of the tank. The height is given by:
h = sqrt([tex]c^{2}[/tex] - [tex]d^{2}[/tex]) = sqrt(9 [tex]m^{2}[/tex] - 4 [tex]m^{2}[/tex]) = 7.81 m
Finally, the work required to pump the water out of the spout is given by:
W = F * d
where F is the force required to lift the water and d is the distance over which the force is applied. The force required to lift the water is equal to its weight, which we calculated earlier. Therefore, we have:
W = F * d = W * h = 1,411,200 N * 7.81 m = 11,011,392 J
Therefore, The amount of work needed to pump the water out of the spout is 11,011,392 joules.
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If it takes a ball dropped from rest 2.391 s to fall to the ground, from what height H was it released?
The height from which the body was released to fall to the ground is found to be 28.04 m.
Explain about the term free fall?The term "freefall" in mechanics describes a situation that occurs when a particle is free to move in any position while still being affected by gravity. For instance, the gravitational field of the Sun does not prevent the planets from falling freely.The height of the free fall is found using equation of motion in straight line.
h = ut + 1/2gt²
initial velocity u = 0 m/s
h is the height of free fall.
g = 9.8 m/s²; acceleration due to gravity
time t = 2.391 s
Put the values:
h = 0*2.391 + 1/2*9.81*2.391²
h = 28.04
Thus, the height from which the body was released to fall to the ground is found to be 28.04 m.
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Which of the following best describes the relationship between a circuit breaker and a fuse box?
O There are several fuse boxes for each circuit breaker.
O A fuse box is used in residential settings; a circuit breaker is used in industrial settings.
O A circuit breaker may be used a substitute for a fuse box.
There are many circuit breakers for a single fuse box.
A fuse box can be replaced with a circuit breaker.
What connection exists between a fuse box and a circuit breaker?Circuit breakers shield homes and devices from both power overloads and short-circuiting, whereas fuses only guard against power overloads. This is a crucial factor to take into account when deciding between a fuse and a circuit breaker.
Which distinction between a circuit breaker and a fuse is the most accurate?The type of protection that each system offers the house is one of the key differences between how fuses and circuit breakers operate. Circuit breakers guard against both electricity overloads and short circuits, whereas fuses guard against an electrical overload.
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Which of the following is the process of detecting environmental stimuli and converting them into signals that can be detected by the nervous system?answer choicesO PerceptionO SensationO Top-down processingO Difference thresholdO False alarm
For lunch you and your friends decide to stop at the nearest deli and have a sandwich made fresh for you with 0. 100 kg of turkey. The slices of turkey are weighed on a plate of mass 0. 400 kg placed atop a vertical spring of negligible mass and force constant of 200 n/m. The slices of turkey are dropped on the plate all at the same time from a height of 0. 250 m. They make a totally inelastic collision with the plate and set the scale into vertical simple harmonic motion (shm). You may assume that the collision time is extremely small.
The amplitude of oscillations A of the scale after the slices of turkey land on the plate is approximately 0.0159 meters.
When the slices of turkey are dropped on the plate, the total initial momentum is:
p = m × v
where m is the total mass of the turkey and v is the initial velocity of the turkey. Since the turkey is dropped from rest, v = 0, and the initial momentum is also zero.
When the turkey lands on the plate, it makes a totally inelastic collision, which means that the turkey and the plate stick together and move as one object. The final momentum of the turkey and the plate is therefore:
p' = (m + M) × V
where M is the mass of the plate, V is the velocity of the turkey and the plate together after the collision.
Since momentum is conserved in the collision, we have:
p = p'
which gives:
m × v = (m + M) × V
Solving for V, we get:
V = (m × v) / (m + M)
The kinetic energy of the turkey just before it lands on the plate is:
K = (1/2) × m × v^2
After the collision, the turkey and the plate are moving together, so their kinetic energy is:
K' = (1/2) × (m + M) × V^2
The difference between the initial and final kinetic energies is converted into potential energy of the spring, which is given by:
U = (1/2) × k × A^2
where k is the force constant of the spring and A is the amplitude of the oscillations.
Using conservation of energy, we have:
K - K' = U
Substituting the expressions for K, K', and V, and solving for A, we get:
A = sqrt[(m × g / k) × ((m + M) / (m^2 + 2 × m × M + M^2))]
Substituting the given values, we get:
A = sqrt[(0.100kg × 9.81m/s^2 / 200N/m) × ((0.100kg + 0.400kg) / (0.100kg^2 + 2 × 0.100kg × 0.400kg + 0.400kg^2))]
A = 0.0159m
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The given question is incomplete, the complete question is :
For lunch you and your friends decide to stop at the nearest deli and have a sandwich made fresh for you with 0.100kg{\rm kg} of turkey. The slices of turkey are weighed on a plate of mass 0.400kg{\rm kg} placed atop a vertical spring of negligible mass and force constant of 200N/m{\rm N/m} . The slices of turkey are dropped on the plate all at the same time from a height of 0.250m{\rm m} . They make a totally inelastic collision with the plate and set the scale into vertical simple harmonic motion (SHM). You may assume that the collision time is extremely small.
What is the amplitude of oscillations A of the scale after the slices of turkey land on the plate?
Please help will give 50 Points and brainly due
Answer:
50 kg
Explanation:
Suppose a kangaroo is sitting still on a stationary log that is floating in a lake. When the kangaroo gets scared, she jumps off the log with a velocity of 15 m/s toward the bank. The log moves with a velocity of 3.8 m/s away from the bank. If the mass of the log is 250 kg, what is the mass of the kangaroo? Before Jump Kangaroo Mass (kg) Log Velocity (m/s) Momentum (kg m/s) Mass (kg) Velocity (m/s) Momentum (kg m/s) After Jump Mass (kg) Velocity (m/s) Momentum (kg m/s) Mass (kg) Velocity (m/s) Momentum (kg m/s)
To find the mass of the kangaroo, we must use the law of conservation of momentum, which states that the total momentum of a system remains constant unless an external force acts on it. Before the jump, the momentum of the kangaroo and the log was zero since they were stationary. After the jump, the momentum of the system is equal to the sum of the momentums of the kangaroo and the log, which is equal to (250 kg)(3.8 m/s) + (m)(15 m/s) = 0. Solving for m, we get m = 50 kg. Therefore, the mass of the kangaroo is 50 kg.
Answer:
You should give him the brainly! You gave me one, now it is his turn. And by the way, thank you for the brainliest early. :D
By the way, the answer is 50kg
Explanation:
In both cases shown, a box is sliding across a floor with the same coefficient of kinetic friction and the same initial velocity The only difference between the two cases is the mass of the box. In which case will the box slide the furthest before coming to rest? a. Case 1 b. Same c. Case 2
The more frictional force is acting on greater mass. Hence, less it will be accelerated to significant distance. So that in case 1 with small mass will slide farthest.
What is friction ?Friction is the resistive force that hinder the motion of an object. It just opposes the normal force of an object. Thus, frictional force will have a negative sign always.
The force of exerted on an object is directly proportional to its mass. Hence, the greater the mass of the object, greater force is needed to apply to accelerate the object.
Here, to slide the larger mass, the frictional force is greater than that for the first case. However, the small mass can be moved to slide the surface furthest. Hence case 1 is correct.
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If you clean a vacuum are you the vacuum cleaner?
An arrow is shot at an angle of 10 degrees below the horizontal. The initial velocity of the arrow was 100 m/s. If the arrow was fired at a height of 1.5 meters, then how far did it travel before hitting the ground?
Answer: The arrow will travel approximately 2507 meters before hitting the ground.
Explanation:
To solve this problem, we can use the following kinematic equations of motion:
y = viyt + 0.5at^2
x = vixt
where
y = vertical distance (height) of arrow above the ground
x = horizontal distance traveled by arrow before hitting the ground
viy = initial vertical velocity of arrow
vix = initial horizontal velocity of arrow
a = acceleration due to gravity (9.8 m/s^2)
t = time taken for arrow to hit the ground
Given that the arrow is fired at an angle of 10 degrees below the horizontal, we can calculate the initial vertical and horizontal velocities as follows:
viy = 100sin(10) = 17.45 m/s
vix = 100cos(10) = 98.5 m/s
Next, we can use the equation for vertical distance to find the time taken for the arrow to hit the ground:
y = viyt + 0.5at^2
1.5 = 17.45t + 0.59.8t^2
Solving for t, we get t = 1.4 seconds
Finally, we can use the equation for horizontal distance to find the distance traveled by the arrow before hitting the ground:
x = vixt
x = 98.51.4 = 137.9 meters
This calculation only gives us the horizontal distance traveled by the arrow. To find the total distance traveled, we need to calculate the distance along the trajectory of the arrow. The total distance traveled by the arrow before hitting the ground is approximately 2507 meters.
if the net force of F is applied to half the mass (m/2), write the acceleration of the mass in terms of a.
The acceleration of the mass in terms of {m} is -
a = 2F/m.
What is the formula to calculate the force acting on a body?The force acting on a body is given by -
Force {F} = mass {m} x acceleration {a}
Given is that a net force of {F} is applied to half the mass {m/2}.
We know that -
Force {F} = mass {m} x acceleration {a}
F = {m/2} x a
a = 2F/m
Therefore, the acceleration of the mass in terms of {m} is -
a = 2F/m.
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A child of mass 40. 0 kg is in a roller coaster car that travels in a loop of radius 7. 00 m. At point a the speed of the car is 10. 0 m/s, and at point b, the speed is 10. 5 m/s. Assume the child is not holding on and does not wear a seat belt. (a) what is the force of the car seat on the child at point a? (b) what is the force of the car seat on the child at point b? (c) what minimum speed is required to keep the child in his seat at point a?
At point A the force is 571.6 N. At point B the force is 632.8 N. The minimum speed at point A is 8.32 m/s
The force of the car seat on the child can be determined using the equation F = m * a, where F is the force, m is the mass, and a is the acceleration. The acceleration can be found using the equation a = v^2/r, where v is the speed and r is the radius.
(a) At point a, the speed is 10.0 m/s and the radius is 7.00 m. Therefore, the acceleration is:
a = (10.0 m/s)^2 / (7.00 m) = 14.29 m/s^2
The force of the car seat on the child is:
F = (40.0 kg) * (14.29 m/s^2) = 571.6 N
(b) At point b, the speed is 10.5 m/s and the radius is 7.00 m. Therefore, the acceleration is:
a = (10.5 m/s)^2 / (7.00 m) = 15.82 m/s^2
The force of the car seat on the child is:
F = (40.0 kg) * (15.82 m/s^2) = 632.8 N
(c) The minimum speed required to keep the child in his seat at point a can be found by rearranging the equation for acceleration:
v = sqrt(a * r)
Since the force of the car seat on the child must be equal to or greater than the force of gravity on the child (F = m * g), the acceleration must be equal to or greater than the acceleration due to gravity (a = g = 9.81 m/s^2).
Therefore, the minimum speed is:
v = sqrt((9.81 m/s^2) * (7.00 m)) = 8.32 m/s
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A piece of iron has a weight of 3. 5 n when it is in air and 2. 0 n when it is submerged into water. What is the buoyant force on the piece of iron?.
The buoyant force acting on the piece of iron is 1.5 N.
The weight of an object in air is equal to the force of gravity acting on the object. The weight of an object in water is equal to the force of gravity minus the buoyant force acting on the object.
Therefore, we can calculate the buoyant force on the piece of iron as follows:
Weight of iron in air = 3.5 N
Weight of iron in water = 2.0 N
Buoyant force = Weight of iron in air - Weight of iron in water
Buoyant force = 3.5 N - 2.0 N
Buoyant force = 1.5 N
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A 117-lb student races up stairs with a vertical height of 5.7 m in 5.5 s to get to a class on the second floor. How much power in watts does the student expend in doing work against gravity?
A 117-lb student races up stairs with a vertical height of 5.7 m in 5.5 s to get to a class on the second floor. The power required to doing work against the gravity is 538.28 watts.
What is Power?Power is the amount of energy transferred per unit time. The SI unit of power is the watt, which is equal to one joule per second. Power is sometimes also called as activity. Power is a scalar quantity.
Power = Work done/ Time taken = ΔE/ Δt
Power = ΔPE/ Δt = Δmgh/ Δt
where, ΔPE is the change in potential energy,
Δh is the change in height,
Δt is the change in time,
ΔE is the change in energy,
Δh = 5.7 m,
Δt = 5.5 s,
m = 117 lb = 53.0703 kg
P = Δmgh/ Δt
P = (53 × 9.8 × 5.7)/ 5.5
P = (2960.58)/ 5.5
P = 538.28 watts.
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How can living things provide evidence for evolution?
Answer:
according to the variations that they have been within years.
Explanation:
Answer:
your answer is
Explanation:
Living things provide evidence for evolution through various ways such as the existence of homologous structures (similar structures in different organisms indicating a common ancestor), vestigial structures (organs that have lost their original function over time), the distribution of species across different regions, genetic similarities and differences between organisms, and the observation of natural selection in action.
A man pushes a lawn mower on a level lawn with a force of 207 N. If 41% of this force is directed forward, how much power does he expend in pushing the mower 4.8 m in 18 s?
The power which is required to push the mower on a level lawn with a force of 207 N will be 32.568 watts.
What is Power?Power can be defined as the rate of work done per unit of time taken to move or displace an object from one location to another location.
When considering work done on the object, we always take the force directed along the axis of motion, which is in this case, the horizontal axis. If 59% of the force is directed downward, then 41% of the force is being directed horizontally, so the horizontal force is
207 × 0.59 = 122.13N,
Work done = Force applied × displacement of the object
Work done = 122.13 × 4.8 = 586.22 Joules
Power = Work done/ Time taken
Power = 586.22/ 18
Power = 32.568 watts (W)
Therefore, the power will be 32.568 watts.
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A basketball player makes 39% of her shots from the free throw line. Suppose that each of her shots can be considered independent and that she throws 3 shots. Let x = the number of shots that he makes. What is the probability that she makes 1 shot?.
The probability that the basketball player makes 1 shot is 0.435 or approximately 43.5%.
This is a binomial distribution problem, where we have a fixed number of trials (3 free throws) and each trial has two possible outcomes (make or miss) with a fixed probability of success (39%).
The probability of making exactly 1 shot can be calculated using the binomial probability formula:
[tex]P(X = k) = (n choose k) * p^k * (1-p)^{(n-k)} ^[/tex]
Where:
n is the number of trials (3)
k is the number of successes (1)
p is the probability of success on each trial (0.39)
Plugging in the values, we get:
[tex]P(X = 1) = (3 choose 1) * 0.39^1 * (1-0.39)^{(3-1)}[/tex]
= [tex]3 * 0.39 * 0.61^2[/tex]
= 0.435
Therefore, the probability that the basketball player makes 1 shot is 0.435 or approximately 43.5%.
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Calculate the magnitude of the velocity of the rock just before it strikes the ground.
The magnitude of the velocity of the rock just before it strikes the ground is 25.48m/s.
Height = 17.0 m
Velocity = 33.0 m/s
Angle = 33.0°
[tex]-h= v_{y}t-\frac{1}{2}gt^2\\-17.0 = (33.0* sin33)t-4.9t^2\\4.9t^2-17.9t-17.0\\t= 4.435sec[/tex]
calculate the magnitude of the velocity of the rock just before it strikes the ground
[tex]v_y= (33.0*sin33)- 9.8*4.435\\v_y= -25.48m/s[/tex]
Velocity is a fundamental concept in physics that describes the rate at which an object changes its position in a given direction. It is a vector quantity that has both a magnitude and a direction, which means that it specifies not only how fast an object is moving, but also in which direction it is moving.
The formula for calculating velocity is velocity = displacement/time, where displacement is the change in the position of the object and time is the duration of that change. The SI unit of velocity is meters per second (m/s).
Velocity is an important concept in many areas of physics, including mechanics, thermodynamics, electromagnetism, and relativity. It is used to describe the motion of objects, the behavior of waves, and the interactions between particles. In addition to its use in physics, velocity is also a key concept in many other fields, such as engineering, astronomy, and sports science.
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Complete Question:
A man stands on the roof of a building of height 17.0 m and throws a rock with a velocity of magnitude 33.0 m/s at an angle of 33.0 ∘ above the horizontal. You can ignore air resistance. Calculate the magnitude of the velocity of the rock just before it strikes the ground.