Use SOLVEM steps for the following problem.



Suppose that the earth is a smooth sphere and you could wrap a 25,000 mile band snugly around it. If you lengthen the band by 6 feet, what would be the largest animal that can fit under the new band (assuming the band is equally above the earth's surface)?

a) an amoeba

b) a 3 inch diameter snake

c) a 1 foot high opossum

d) a 1.5 foot high alligator

e) a 5 foot 11 inch tall person



Note: make sure you keep your units consistent! Circumference = Pi * Diameter

5280 feet in a mile, Pi ~ 3.14159

radius = Diameter/2

Show your work!

The tension in the rope and the spring balance reading are the same. 5N of tension is present on both sides. As a result, the spring balance reads 5N.

A simple and affordable way to determine mass is by using spring balances. The mass is suspended from the end of a spring, and the spring's deflection as a result of the mass's downward gravitational pull is measured in relation to a scale.

A spring balance calculates an object's weight by comparing the force of gravity to the force of an extended spring. The scale can be used to calculate weight and mass by recalibrating it. Some spring balances have gramme or kilogram marks and are used to determine an object's mass.

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a) Note that the final volume of the air is also 1.6 m3, and the final pressure is 4.5 bar; and

b)  the change in internal energy of the air is 0 kJ, the work done by the air is 0.966 kJ, and the total heat transferred is 487.7 kJ.

To solve this problem, we can use the ideal gas law and the first law of thermodynamics.

(a) To determine the final volume and final pressure of the air, we can use the ideal gas law, which states that:

P1V1/T1 = P2V2/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We can first use this equation to determine the final volume of the air during the isothermal process:

P1V1/T1 = P2V2/T2

(9 bar)(0.8 m3)/(1200 K) = P2V2/(927 K)

V2 = (9/4.5) * (0.8 m3)
= 1.6 m3

Now, we can use the ideal gas law again to determine the final pressure of the air during the isothermal process:

P1V1/T1 = P2V2/T2

(9 bar)(0.8 m3)/(1200 K) = (P2)(1.6 m3)/(1200 K)

P2 = (9 bar)(0.8 m3)/(1.6 m3)
= 4.5 bar

During the subsequent heat transfer process, the piston is fixed in place, which means the volume of the air remains constant at 1.6 m3.

Therefore, the final volume of the air is also 1.6 m3, and the final pressure is 4.5 bar.

(b) To determine the change in internal energy of the air, the work done by the air, and the total heat transferred, we can use the first law of thermodynamics, which states that:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat transferred, and W is the work done.

During the isothermal process, the temperature of the air remains constant at 927 K, which means the internal energy of the air does not change:

ΔU = 0

During the isothermal process, the work done by the air is:

W = -P1V1 ln(P2/P1)
= -(9 bar)(0.8 m3) ln(4.5/9)

= 0.966 kJ

During the subsequent heat transfer process, the air is heated from 927 K to 300 K, which means heat is transferred into the air:

Q = m cΔT = (P2V2/R) cΔT
= (4.5 bar)(1.6 m3)/(287 J/kg∙K) (1.005 kJ/kg∙K) (927 K - 300 K)
= 487.7 kJ

Therefore, the change in internal energy of the air is 0 kJ, the work done by the air is 0.966 kJ, and the total heat transferred is 487.7 kJ.

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It should benotedtha for 100, repeat distance =ao=0.35167 nm

linear density=1/ao=2.84 points/nm

linear packing fraction =(2)(0.1243)(2.84) =0.707

For 110

repeat distance = 2*ao/2 = 0.2487 nm

linear density = 2 /( sqrt{2} * ao ) = 4.021 points/nm

linear packing fraction = (2)(0.1243)(4.02) =1.0

For 111,

repeat distance =(sqrt{3} * ao) = 0.6091 nm

linear density = 1 / (sqrt{3} * ao ) = 1.642 points/nm

linear packing fraction = (2)(0.1243)(1.642) =0.408

"Repeat distance" refers to the distance between repeated units in a crystal lattice. This can be measured along any of the lattice vectors that define the periodicity of the crystal. For example, in a simple cubic crystal, the repeat distance along any of the three lattice vectors would be equal to the length of that vector.

"Linear density" refers to the number of atoms or ions per unit length along a specific crystallographic direction. It is usually expressed in units of atoms/angstrom or ions/angstrom. To calculate the linear density, one would count the number of atoms or ions along a given direction and divide by the length of that direction.

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The pseudocode from the Coding Log is given below.

# Intro

Print "Welcome to the adventure game!"

Ask for player name and store it in a variable

Print "Hello [player name], let's start the game!"

# Part 1

Print "You find yourself in a dark room with two doors. Do you go through door 1 or door 2?"

Use input() function to get player's choice and store it in a variable

Use a while loop to ensure the player's input is valid (either "1" or "2")

If player chose door 1, print "You find a treasure chest full of gold. Congratulations, you win!"

If player chose door 2, print "You fall into a pit and lose the game. Better luck next time!"

# Part 2

Print "You come across a fork in the road. Do you go left or right?"

Use input() function to get player's choice and store it in a variable

Use a while loop to ensure the player's input is valid (either "left" or "right")

If player chose left, print "You find a magical sword. You win!"

If player chose right, print "You encounter a troll and lose the game. Better luck next time!"

# Part 3

Print "You reach a river with a boat. Do you cross the river or follow the riverbank?"

Use input() function to get player's choice and store it in a variable

Use a while loop to ensure the player's input is valid (either "cross" or "follow")

If player chose cross, print "You safely cross the river and win the game! Congratulations!"

If player chose follow, print "You follow the river and eventually reach a waterfall. You lose the game. Better luck next time!"

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Convert to SI units, calculate, convert from base SI units to the desired units. Route 1: 52 minutes, Route 2: 48 minutes.

SI unit is an international system of measurements that are used universally in technical and scientific research to avoid the confusion with the units. Having a standard unit system is important because it helps the entire world to understand the measurements in one set of unit systems. There are several SI units used in physics that are used to express the different quantities.

The quantities can be classified into two groups i.e. base units and derived units.

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Jar is a cylinder that has an R-radius and an H-height. The jar's volume is then calculated as V = R2H. The volume of honey in the jar is V honey = (1/2)R2(H/2) = (1/4)R2H if the honey fills the jar to half its height.

The volume of any cylinder with base radius "r" and height "h" equals base times height. A cylinder's volume is therefore equal to r2h cubic units.

F_buoyancy = (density of water) x (volume of water) x (acceleration due to gravity)

F_buoyancy = 1.0 x πR^2h x g

Since the jar is in equilibrium, the weight of the jar and honey must be equal to the buoyant force. Therefore, we can set the two equations equal to each other and solve for h:

3.5πR^2H x g = πR^2h x g

h = (3.5/1) x (H/2)

h = 1.75H

Therefore, the jar will sink into the water up to a height of 1.75 times its original height.

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Explanation:

let the length be Lcm

5−325−L = 10−530−25

L = 23cm

Answer:

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