Using the rules of significant figures for subtraction, what is the correctly reported mass of water based on this data?

Mass of beaker and water: 28.641 g

Mass of beaker only: 22.105 g

Group of answer choices

6.54 g

50.746 g

6.536 g

6.5360 g

The mean should be set to 511.9 ml to ensure that a half-liter bottle is not underfilled 99 percent of the time.

Probability is a number between 0 and 1 that expresses the likelihood of an event occurring.

In mathematical terms, the probability of an event E is given by:

P(E) = (number of outcomes favorable to E) divided by  (total number of possible outcomes)

(a) To ensure a 95 percent probability that a half-liter bottle will not be underfilled, we need to find the mean that corresponds to the 2.5th percentile of the normal distribution. This is because 2.5 percent of the area under the curve falls below this point, leaving 95 percent in the upper tail.

Using a standard normal distribution table or calculator, we can find the z-score that corresponds to the 2.5th percentile, which is -1.96. We can then use the formula:

-1.96 = (x - μ) / σ

where x is the target fill amount (500 ml), σ is the standard deviation (5 ml), and μ is the mean that we need to set. Solving for μ, we get:

μ = x - (-1.96) * σ

= 500 - (-1.96) * 5

= 509.8 ml

As a result, the mean should be set to 509.8 ml to ensure that a half-liter bottle is not underfilled 95 percent of the time.

(b) To ensure a 99 percent probability that a half-liter bottle will not be underfilled, we need to find the mean that corresponds to the 0.5th percentile of the normal distribution. This is because 0.5 percent of the area under the curve falls below this point, leaving 99 percent in the upper tail.

Using the same approach as in part (a), we can find the z-score that corresponds to the 0.5th percentile, which is -2.58. We can then use the formula:

-2.58 = (x - μ) / σ

where x is the target fill amount (500 ml), σ is the standard deviation (5 ml), and μ is the mean that we need to set. Solving for μ, we get:

μ = x - (-2.58) * σ

= 500 - (-2.58) * 5

= 511.9 ml

As a result, the mean should be set to 511.9 ml to ensure that a half-liter bottle is not underfilled 99 percent of the time.

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Answer: C. The amount of energy available for transport molecules.

The complete question is as follows:

Which of the following is not a factor that influences the rate of diffusion?

A. The distance of diffusion.

B. The concentration of the substance.

C. The amount of energy available for transport molecules.

D. The molecular weight of the diffusing molecules.

E. The temperature of the environment.

F. The size of the diffusing molecules.

Diffusion is the overall net movement of anything from a higher concentration to a lower concentration. A gradient in the Gibbs free energy or chemical potential drives diffusion.

The scent of a flower that quickly fills a room's still air is a common illustration. the movement of ions through a semipermeable membrane.

In conclusion, diffusion is a passive transfer of energy from a concentrated area to a less concentrated one.

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CH2O is the molecular formula for glucose. As a result, the carbon, hydrogen, and oxygen atoms in the glucose molecule are arranged in a 1:2 ratio.

A molecule is a collection of chemically different bound atoms, whether they are from the same element or another.

The simplest form of a material that nonetheless has that substance's makeup and qualities. Chemistry is built on molecules. The element symbol as well as a subscript indicating the number of atoms are used to identify molecules.

Atoms of the same element share the same chemical characteristics and mass, but atoms of other elements have unique chemical characteristics and masses. Compounds are created when atoms join in modest whole number ratios.

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To convert propane to butan-2-ol, follow a multi-step synthesis, which is specified below.

It is a chemical strategy where a series of chemical reactions are employed  to synthesize a desired compound from the provided substrate.

Here's how we can synthesize butan-2-ol from propane:

                                         C₃H₈ + 2[O] → CH₃CH₂CH₂O

                                       CH₃CH₂CH₂OH → CH₃CH=CH₂+ H₂O

                                       CH₃CH=CH₂ + H₂ → CH₃CH₂CH₃

                                     C₄H₁₀+ 3[O] → CH₃COCH₂CH₃ + H₂O

                                 CH₃COCH₂CH₃ + 2[H] → CH₃CH(OH)CH₂CH₃

So the overall reaction would be:

C₃H₈ + 5[O] + 2[H] → CH₃CH(OH)CH₂CH₃

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The carbon dioxide or lithium carbonate have a 1:1 equivalence. Mole fractions of carbon dioxide are equal to 88 g, 44.0 g, 1 mol, and 2 mol. A mass of 2 moles per 73.89 g per mole of lithium carbonate, or 147.8 g.

The Avogadro Constant, which is 6.021023, specifies how many particles (molecules or atoms) make up one mole of a substance. A mole of any substance is always 6.021023, to put it simply.

The usual molar mass for the element is ln g/mol. By dividing the atomic mass for amu even by molar ratio (1 g/mol), the molar mass of amu may also be calculated. To calculate the molarity of a compound containing many atoms, add up the all atomic masses of a constituent atoms.

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The equilibrium concentration of sulfur dioxide, SO2, is 0.084 M.

Equilibrium is a state in which opposing forces or influences are balanced. It is a state of balance between opposing forces or actions in which the forces cancel each other. In economics, it is the state in which market supply and demand balance each other out and in which the prices of goods and services are stable. In physics, equilibrium is the state in which an object experiences no net force and its velocity is constant. In chemistry, equilibrium is the state in which the rates of the forward and reverse reactions are equal.

At equilibrium the reaction will be at its equilibrium constant value, K. This means that the concentration of SO2 can be determined by rearranging the equilibrium expression, K = [SO3]2/[SO2]2, and solving for [SO2].

[SO2] = sqrt([SO3]2/K)

[SO2] = sqrt((0.015)2/1.5)

[SO2] = 0.084 M

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Filtration is a technique that uses a porous barrier to separate a solid from a liquid in a heterogeneous mixture.

As the temperature of the ocean increases, its ability to absorb carbon dioxide (CO2) decreases.

Under normal pressure and temperature, carbon dioxide (CO2) is a colourless, non-flammable gas. Carbon dioxide has a significant role in the composition of our planet's air, while being far less prevalent than nitrogen & oxygen in the atmosphere. One carbon atom & two oxygen atoms make up the molecules of carbon dioxide (CO2).

Carbon dioxide is utilized as a coolant, in fire extinguishers, to blow coal, foam rubber and plastics, inflate life rafts & life jackets, blast coal, promote plant growth in greenhouses, immobilise animal before slaughter, & in carbonated drinks.

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A maritime tropical meeting a continental tropical, will produce this kind of weather.

When maritime tropical air masses meet continental tropical air masses, it can lead to the formation of weather patterns that can have significant impacts on the local and regional weather conditions.

Maritime tropical air masses are warm and humid air masses that form over the tropical and subtropical oceans, while continental tropical air masses are hot and dry air masses that form over land areas in the subtropics and tropics. When these two air masses meet, the warm, moist maritime tropical air rises over the denser, drier continental tropical air.

As the air rises, it cools and the water vapor in it condenses, leading to the formation of clouds and possibly precipitation. The amount and type of precipitation that forms depend on a variety of factors, such as the temperature and humidity of the two air masses, the strength and direction of the wind, and the topography of the land.

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Taking into account the reaction stoichiometry, 30.28 grams of Hg are formed using 2.7 grams of mercury (II) oxide.

The balanced reaction is:

2 HgO  → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 433.18 grams of HgO form 401.18 grams of Hg, 32.7 grams of HgO form how much mass of Hg?

mass of Hg= (32.7 grams of HgO×401.18 grams of Hg)÷433.18 grams of HgO

mass of Hg= 30.28 grams

Finally, 30.28 grams of Hg are formed.

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In water (H2O), there are two atoms of hydrogen (H) and one atom of oxygen (O) per molecule. The atomic mass of hydrogen is approximately 1.008 g/mol and the molecular mass of water is approximately 18.015 g/mol.

To calculate the grams of hydrogen in 10.05 grams of water, we need to first determine the number of moles of water present:

moles of water = mass of water / molecular mass of water

moles of water = 10.05 g / 18.015 g/mol

moles of water = 0.5575 mol

Since there are two hydrogen atoms in each molecule of water, the number of moles of hydrogen is twice the number of moles of water:

moles of hydrogen = 2 x moles of water

moles of hydrogen = 2 x 0.5575 mol

moles of hydrogen = 1.115 mol

Finally, we can calculate the grams of hydrogen by multiplying the number of moles of hydrogen by the atomic mass of hydrogen:

grams of hydrogen = moles of hydrogen x atomic mass of hydrogen

grams of hydrogen = 1.115 mol x 1.008 g/mol

grams of hydrogen = 1.12352 g

Therefore, there are approximately 1.12352 grams of hydrogen present in 10.05 grams of water.

Hydrogen is a chemical element with the symbol H and atomic number 1. It is the lightest and most abundant element in the universe, constituting roughly 75% of all baryonic mass. Hydrogen is a colorless, odorless, and tasteless gas that is highly flammable.

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Throughout the visible spectrum, which spans around 400 to 700 nanometers, distinct electromagnetic radiation wavelengths are correlated with the colors of visible light (nm). The precise values for each hue of visible light are as follows:

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According to Newton’s law of universal gravitation, the statements that is  true is As we move to higher altitudes, the force of gravity on us decreases.

According to Newton's Law of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is directly proportional to the product of their masses and inversely proportional to their distance from one another.

According to Newton's law of universal gravitation, two bodies in space are attracted to one another by a force that is proportional to their masses and the distance separating them. This indicates that they truly exert a discernible influence on one another for huge objects orbiting one another—the moon and Earth, for instance.

Therefore, option A is correct.

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complete options;

As we move to higher altitudes, the force of gravity on us decreases.

As we move to higher altitudes, the force of gravity on us increases.

As we gain mass, the force of gravity on us decreases.

As we gain mass, the force of gravity on us increases.

As we move faster, the force of gravity on us increases.

A physical property of both liquids and gases has randomly arranged particles.

The smallest of particles are the subatomic particles, which refer to particles smaller than atoms. These would include particles such as the constituents of atoms – protons, neutrons, and electrons – as well as other types of particles which can only be produced in particle accelerators or cosmic rays.

Background. Subatomic particles are created naturally with sufficient energy, but many more types of particles are manufactured in high-energy particle physics experiments such as CERN. Most of the particles live for a fraction of a second, decaying to become other particles that are more common in the universe.

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19.5 g of water will produce 12.24 L of oxygen gas at STP.

Spanning Tree Protocol (STP) is an industry standard protocol developed by IEEE to prevent loops in a network. This protocol is designed to create a loop-free topology while allowing redundant links in the network. STP works by selecting a root bridge, then selecting root ports and designated ports on each switch. When two switches are connected by multiple links, STP will block all but one link to prevent loops. STP is an important protocol for network reliability, as it prevents packet loops and broadcast storms.

The balanced equation for the decomposition of water is:

2H2O --> 2H2 + O2

The molar mass of water is 18.015 g/mol. Thus, 19.5 g of water corresponds to 1.08 moles of water.

Since the equation has a 2:1 mole ratio of water to oxygen, 1.08 moles of water will produce 0.54 moles of oxygen gas.

At STP (standard temperature and pressure), 1 mole of gas occupies 22.4 L. Thus, 0.54 moles of oxygen gas will occupy 12.24 L.

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The three common states of matter are solid, liquid and gas. The intermolecular forces present between the particles in each state will be different. It is in gaseous state H₂O particles are fathers apart.

The gaseous state is the state of matter in which the intermolecular force of attraction is low than the liquid. The particles have a larger distance between the particles. The gaseous state of water is known as water vapor.

In gaseous state, the molecules have high kinetic energy and small intermolecular forces. Here the molecules can move randomly and the gas particles are highly compressible. They have lower density than solids and liquids.

The gaseous particles possess the property called diffusion. They have high volume and expand in the container they are placed. Here the particles move at higher speeds in all directions and hit each other.

Thus in gaseous form water has more freedom.

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Answer:

c) hydrophobic interactions

Non-covalent interactions can be classified into different categories, such as electrostatic, π-effects, van der Waals forces, and hydrophobic effects. Non-covalent interactions are critical in maintaining the three-dimensional structure of large molecules, such as proteins and nucleic acids.

Explanation:

to begin, with covalent bonds is when u have 2 elements that are both non-metals and have a bond in between . non covalent means the elements are metals or ions it depends so either metallic bond or ionic bond.

The production of the ester CH3COOCH2CH3 typically involves the reaction between acetic acid (CH3COOH) and ethanol (CH3CH2OH) in the presence of a catalyst, typically sulfuric acid (H2SO4) or a strong acid ion exchange resin. The reaction can be represented, by the help of following equation:

CH3COOH + CH3CH2OH → CH3COOCH2CH3 + H2O

In this reaction, the -OH group from the carboxylic acid (acetic acid) and the -OH group from the alcohol (ethanol) combine to form a molecule of water (H2O) while the remaining groups (CH3COO and CH3CH2) combine to form the ester CH3COOCH2CH3.

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Answer:

4.46 x 10^-22 nitrate ions

Explanation:

To find the number of nitrate ions present in 4.18 x 10^-20 grams of copper (II) nitrate, we need to use the molar mass of copper (II) nitrate and Avogadro's number.

The molar mass of copper (II) nitrate is:

Cu(NO3)2 = 63.55 g/mol (Cu) + 2(14.01 g/mol (N) + 3(16.00 g/mol (O))) = 187.57 g/mol

So 1 mole of copper (II) nitrate has a mass of 187.57 grams.

We can find the number of moles of copper (II) nitrate in 4.18 x 10^-20 grams by dividing the mass by the molar mass:

4.18 x 10^-20 g / 187.57 g/mol = 2.23 x 10^-22 moles

Each mole of copper (II) nitrate contains 2 moles of nitrate ions. Therefore, the total number of nitrate ions in 4.18 x 10^-20 grams of copper (II) nitrate is:

2.23 x 10^-22 moles x 2 nitrate ions/mole = 4.46 x 10^-22 nitrate ions

So there are approximately 4.46 x 10^-22 nitrate ions in 4.18 x 10^-20 grams of copper (II) nitrate.

The pH scale introduced by Sorensen is used to express the hydronium ion concentration of a solution. Here the pH of ammonium chloride solution of concentration 0.1M is

The pH of a solution is defined as the negative logarithm to the base 10 of the hydronium ion concentration in moles per liter. It can be represented by using the equation.

pH = -log₁₀[H₃O⁺]

Here Kₐ = 5.8 × 10⁻¹⁰

pKₐ = -log₁₀ Kₐ

= -log₁₀ (5.8 × 10⁻¹⁰)

= 9.23

Then the pH of a solution can be determined by the equation:

pH = 7 + 1/2 [pKₐ + log c]

= 7 + 1/2 [9.23 + log (0.1)]

= 11.11

Thus the pH of the ammonium chloride solution is 11.11.

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The empirical formula of the compound is C2H0O0N0S0, or C2H0NS.

The empirical formula is a type of chemical formula that gives the simplest whole number ratio of atoms present in a molecule. It is the simplest type of formula that indicates the type of atoms and the ratio of atoms present in a molecule, rather than the actual number of atoms. For example, the empirical formula of glucose is CH₂O, which tells us that there is one carbon atom, two hydrogen atoms and one oxygen atom present in each molecule of glucose.

The empirical formula can be determined by finding the ratio of the mass of each element from the combustion of each sample.

Sample 1:

C: 3.93 g/12.01 g/mol = 0.3283 mol

H: 0.674 g/1.008 g/mol = 0.6689 mol

O: 5.50 g/15.999 g/mol = 0.3441 mol

N: 0 mol

S: 0 mol

Sample 2:

C: 6.32 g/12.01 g/mol = 0.5267 mol

H: 0 mol

O: 0 mol

N: 0 mol

S: 3.22 g/32.06 g/mol = 0.1001 mol

Sample 3:

C: 8.93 g/12.01 g/mol = 0.7417 mol

H: 3.58 g/1.008 g/mol = 3.5479 mol

O: 0 mol

N: 0.674 g/14.007 g/mol = 0.0481 mol

S: 0 mol

The ratio of the moles of each element can be determined by taking the moles of each element from sample 1, and dividing them by the moles of the respective element from sample 2 and 3:

C: 0.3283 / 0.5267 = 0.625

H: 0.6689 / 3.5479 = 0.189

O: 0.3441 / 0 = undefined

N: 0 / 0.0481 = 0

S: 0 / 0.1001 = 0

Rounding the ratios, we get C: 2, H: 0, O: 0, N: 0, and S: 0.

The empirical formula of the compound is C2H0O0N0S0, or C2H0NS.

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The rate law for the ozonization of pentene is Rate = 8.55 x 10³[C₅H₁₀][O₃]².

Ozonization is a chemical process that involves the addition of ozone (O3) to a compound. This reaction can be used in a variety of applications, such as wastewater treatment, air purification, and organic synthesis. In organic chemistry, ozonolysis is a commonly used technique that involves the cleavage of carbon-carbon double bonds by reaction with ozone.

The rate law for the ozonation of pentene can be determined using the initial rate data given. The general form of the rate law is:

Rate = k[C₅H₁₀[tex]]^{m}[/tex][O₃]ⁿ

where k is the rate constant, m and n are the orders of the reaction with respect to C₅H₁₀ and O₃, respectively.

To determine the orders of the reaction with respect to C5H10 and O3, we can use the method of initial rates. This involves comparing the rates of the reaction under different initial concentrations of the reactants while holding the concentration of the other reactant constant. If the rate doubles when the concentration of a reactant doubles, then the reaction is first order with respect to that reactant. If the rate quadruples when the concentration of a reactant doubles, then the reaction is second order with respect to that reactant.

Using the data given, we can determine the orders of the reaction with respect to C₅H₁₀ and O₃ as follows:

For experiments 1 and 2:

Rate1/Rate2 = (k[C₅H₁₀]1[O₃]1)/(k[C₅H₁₀]1[O₃]2) = (425/849) = 0.50

[C₅H₁₀]1/[C₅H₁₀]2 = 1/1 = 1

Therefore, (k[O₃]1)/(k[O₃]2) = 0.50

O₃ is second order (n=2)

For experiments 1 and 3:

Rate1/Rate3 = (k[C₅H₁₀]1[O₃]1)/(k[C₅H₁₀]2[O₃]1) = (425/853) = 0.50

[O₃]1/[O₃]2 = 1/2 = 0.5

Therefore, (k[C₅H₁₀]1)/(k[C₅H₁₀]₂) = 1

C₅H₁₀ is first order (m=1)

Thus, the rate law for the ozonization of pentene is:

Rate = k[C₅H₁₀][O₃]²

The rate constant can be determined from any of the experiments by substituting the concentrations and initial rate into the rate law and solving for k. For example, using experiment 1:

Rate = k[C₅H₁₀][O₃]²

425 = k(0.102)(0.042)²

k = 8.55 x 10³ M⁻¹ s⁻¹

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The mass percentage is an important method to determine the concentration of a solution. Here among P₂O₃ and P₂O₅, the oxide P₂O₃ contains higher percentage of phosphorous.

The mass percentage of a component can be defined as the ratio of the mass of that particular component in the compound to the total mass of the compound. It can be expressed as:

Mass percentage = Mass of the component / Total mass of the component × 100

Molar mass of P₂O₃ = 110 g/mol

Molar mass of P₂O₅ = 142 g/mol

a. % of 'P' in P₂O₃ = 2 × 31 / 110 × 100 = 56.4 %

   % of 'P' in P₂O₅ = 2 × 31 / 142 × 100 = 43.66 %

Thus P₂O₃ has higher percentage of 'P'.

b. 1 mol O₂ × 4 P /3 O₂ × 31.0 P / 1 mol P = 41.3 g P

c. P₄O₁₀

d. Aluminium oxide - Al₂O₃

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The number of kilograms in 1.544 micrograms (ug) is 1.544 × 10-⁹ kilograms.

Kilograms is the unit of mass according to the International System of Units (S.I unit). The base unit of mass; conceived of as the mass of one litre of water.

Micrograms is the unit of mass equal to one millionth of a gram, or 0.000001 grams (symbol: μg or mcg).

The unit of conversion of micrograms to kilograms is as follows:

1 microgram = 1 × 10-⁹ kilogram

This means that 1.544 micrograms can be converted to kilograms as follows:

1.544 ug × 1 × 10-⁹ = 1.544e-9

Therefore, 1.544 ug is equivalent to 1.544 × 10-⁹kg

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If 5.00cm³ of 0.20mol/L Na[tex]_2[/tex]CO[tex]_3[/tex] was diluted with distilled water to obtain 250cm³ solution. 0.64 mol/L is the concentration of the resulting solution.

Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute in the solution to the solvent or whole solution is another way to define concentration.

In order to indicate concentration, mass every unit volume is typically used. The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.

Concentration₁×volume₁=concentration₂×volume₂

0.20×5.00=concentration₂×250

concentration₂= 0.64 mol/L

Therefore, 0.64 mol/L is the concentration of the resulting solution.

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After the reaction is finished, N2 has a partial pressure of 0.995 atm.

Provide three strategies for accelerating a chemical reaction. providing heat, increasing the reactants' surface area or concentration, or adding a catalyst are all ways to raise the temperature.

A catalyst is a chemical that can be included in a reaction to speed up the process without being consumed. Catalysts typically reduce a process's activation energy or change its mechanism. Proteins called enzymes serve as catalysts in biological reactions.

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Answer:

The statement is not entirely accurate.

Explanation:

While it is true that trans-1,4-dibromocyclohexane can adopt a conformation in which the two bromine atoms are in orientations that are further apart from each other, this alone does not explain why the trans isomer is more stable than the cis isomer.

The actual reason for the greater stability of the trans isomer lies in the fact that the two large bromine atoms on adjacent carbons in the cis isomer are forced into close proximity, leading to significant steric hindrance and unfavorable van der Waals interactions. This steric strain can be relieved by rotating the two C-Br bonds away from each other to form the trans isomer, which has lower energy and is more stable.

In contrast, in the trans isomer, the two bromine atoms are already far apart from each other in the lowest-energy conformation, so there is no additional steric strain that needs to be relieved.

Therefore, it is not accurate to say that the trans isomer is more stable simply because it can adopt a conformation with both bromine atoms in favorable orientations. The trans isomer is more stable because it has lower steric strain due to the orientation of the two bromine atoms relative to each other.

Liters of a 40% solution are equivalent to 252 liters, whereas liters of a 15% solution are equivalent to 448 liters.

How much is a percentage?

The hundredth part of a given number is what is meant by the word "percentage."

The answer to the query is

Given,

700 litres of solution total.

Acid solution percentage is equal to 24%.

'x' stands for a 40% acid solution.

"700-x" stands for the 15% of the solution.

Replace the value according to the condition we are provided,

Therefore,

252 litres of acid solution with a 40% concentration

Moreover, 15% of the solution is

As a result, 252 liters of a 40 percent solution are equal to one liter, and 448 liters of a 15 percent solution are.

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The manufacturer needs to use 252 liters of the 40% solution and 448 liters of the 15% solution to obtain 700 liters of a 24% acid solution.

Let x be the number of liters of the 40% solution and y be the number of liters of the 15% solution needed.

Since we want to obtain 700 liters of a 24% solution, we can set up the following system of equations based on the concentration and amount of acid in each solution:

x + y = 700 (total volume of the solution)

0.4x + 0.15y = 0.24(700) (total amount of acid in the solution)

Simplifying the second equation, we get:

0.4x + 0.15y = 168

We can now use the first equation to solve for one of the variables in terms of the other:

y = 700 - x

Substituting this expression into the second equation, we get:

0.4x + 0.15(700 - x) = 168

Simplifying and solving for x, we get:

0.4x + 105 - 0.15x = 168

0.25x = 63

x = 252

So we need 252 liters of the 40% solution and 700 - 252 = 448 liters of the 15% solution.

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The graph which represents the relationship between pressure and volume for a sample of an ideal gas at constant temperature is referred to as option A.

This is referred to as a theoretical gas composed of many randomly moving point particles that are not subject to interparticle interactions.

The relationship between pressure and volume is a direct one such that as pressure increases the volume also increases and vice versa which is depicted in the graph shown in option a thereby making it the correct choice.

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Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

QUESTION 5:

According to question 5, 4 moles of iron reacts with 3 moles of oxygen gas to produce 2 moles of ferric oxide.

56.33 grams of iron is equivalent to 1.01 moles

This means that 1.01 moles of iron will produce 0.51 moles of ferric oxide.

Mass of ferric oxide = 0.51 × 159.69 = 80.6 grams.

QUESTION 6:

According to question 6, 3 moles of hydrogen gas reacts with 1 mole of nitrogen gas to produce 2 moles of ammonia.

13.55 grams of hydrogen is equivalent to 6.78 moles

This means that 6.78 moles of hydrogen will produce 4.52 moles of ammonia

Mass of ammonia = 4.52 × 17 = 76.8 grams.

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