What happens to heat energy when it is not increasing the temperature of the substance in the beaker

Answer:

E) 9.0

Explanation:

pH = -log [1×10^-9] = 9

The pH of buffered solution is:

The two buffered solutions have 'equal' pH values.

Comparison between two buffer solutions:

To compare the pH of two different buffer solutions with different concentrations, Henderson-Hasselbalch equation is used.

pH = pKa + log [tex]\frac{Salt}{Acid}[/tex]

pKa of HOAc = 4.76

In solution 1:

Concentration of salt= 5 M

Concentration of acid= 5 M

Putting the values in the equation,

pH = 4.76 + log [tex]\frac{5}{5}[/tex]

pH = 4.76 + log1

pH = 4.76

In solution 2:

Concentration of salt= 0.050 M

Concentration of acid= 0.050 M

Putting the values in the equation,

pH = 4.76 + log[tex]\frac{0.050}{0.050}[/tex]

pH = 4.76 + log1

pH = 4.76

As the ratio  [tex]log\frac{salt}{acid}[/tex] is the same for the different solutions.

Therefore, the pH of the solution remains the same in both the buffer solutions even if the two solutions have different concentrations.

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In a mining community, water pollution kills the fish in local river.

Large amounts of water are frequently used in mining, which has the potential to contaminate local groundwater, rivers, streams, and other water sources. A community's ability to grow its own food may be hampered by mining since it consumes grazing or agricultural land and pollutes the soil and the environment.

Metals that leach from the rock also contaminate nearby water sources when they do so. chemical processing pollution: When minerals are extracted from their ores using cyanide or sulfuric acid and water, the runoff pollutes the rivers in the area.

Through erosion and sedimentation, dewatering of wetlands, diverting and channelizing streams, and poisoning surface water and aquifers with harmful chemicals, surface mining can have an impact on fish and aquatic resources.

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Answer:

a

Explanation:

The vapor pressure of pure B is 1.77atm

Given:-

Vapor pressure of Pure A = 0.700atm

Mole of A = 0.650mole

Mole of B = 0.250mole

Dalton's law of partial pressures states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressures of all of the constituent gases.

So, Ptotal =  [tex]P_A + P_B[/tex]

According to Raoult's law, a solvent's partial vapor pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapor pressure times the mole fraction present in the solution.

So, Ptotal =  [tex]X_AP_A + X_BP_B[/tex]

Ptotal = 1atm

1atm = (0.650/0.650+0.250 X 0.700atm) + 0.250/0.650+0.250 X [tex]P_B[/tex]

1atm = 0.722 X 0.700atm + 0.278 X [tex]P_B[/tex]

1atm = 0.506atm + 0.278 X [tex]P_B[/tex]

1atm - 0.506atm =  0.278 X [tex]P_B[/tex]

0.494atm = 0.278 X [tex]P_B[/tex]

[tex]P_B[/tex] =  0.494atm / 0.278

[tex]P_B[/tex] = 1.77atm

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Glucose becomes a better leaving group.

In a manner similar to how protonation of an alcohol makes it easier to substitute a -OH group, glucose becomes a better leaving group when the oxygen atom is protonated.

A substance that releases or donates hydrogen ions during a chemical reaction is referred to as a Bronsted-Lowry acid. A Bronsted-Lowry base, on the other hand, takes hydrogen ions. Another way to look at it is that a base accepts protons whereas a Bronsted-Lowry acid donates them. Amphoteric species are those that, depending on the circumstance, can either give or take protons.

Every Bronsted-Lowry acid gives a species that is its conjugate base a proton in exchange for the species' support. Each base in the Bronsted-Lowry system similarly accepts a proton from its conjugate acid.

I understand the question you are looking for is this:

For what mechanistic reason does G1 of lactase first act as a Bronsted acid during catalysis?

A) G1 becomes a better nucleophile

B) G2 becomes a better nucleophile

C) Glucose becomes a better leaving group.

D) Galactose becomes a better leaving group.

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The name of the amide bond between amino acids will be peptide bond.

Peptide bonds are amide-type covalent bonds that form bonds that connect two adjacent alpha-amino acids throughout peptide or protein chains, starting at C1 of one as well as [tex]N_{2}[/tex] of another.

The substances are known as amino acids, or the "building blocks of proteins," and play a variety of vital functions in the human body. Humans require them for essential functions like producing hormones, neurotransmitters, even proteins. In meals high in protein like meat, fish, as well as soybeans, amino acids could be concentrated.

Therefore, the name of the amide bond between amino acids will be peptide bond.

Hence, the correct answer will be option (e)

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Imidazole's cyclic structure is aromatic and the lone pair present at the N₁ atom available for donation. hence, according to question N₁ is the most basic atom in the structure.

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The number of molecules and number of moles of [tex]CH_{4}[/tex] is 4 moles and 24.088×[tex]10^{23}[/tex] molecules.

Calculation,

Atomic mass of carbon is 12 u and H is 1 u

So, molar mass of [tex]CH_{4}[/tex] = 12 + 1×4 = 16 u = 16 g/mole

Number of moles = given mass / molar mass = 64 g/ 16 g/mol = 4 moles

1 moles of substance contains 6 .022 ×[tex]10^{23}[/tex] molecules.

So, number of molecules in 3 moles of methane = 4×6.022 ×[tex]10^{23}[/tex]  

number of molecules in 3 moles of methane  = 24.088×[tex]10^{23}[/tex] molecules.

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Based on the calculations, the enthalpy of the overall chemical reaction is equal to: C. -14.3 kJ.

A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.

A chemical equation can be defined as a group of chemical symbols that is typically used in chemistry to represent the chemical reaction between two (2) or more chemical elements.

Mathematically, an expression for enthalpy of the overall chemical reaction is given by:

ΔHrxn = (n × ΔH₃) + (-n × ΔH₁) + (n × ΔH₂)

Where:

n represents the number of moles.

Substituting the given points into the formula, we have;

ΔHrxn = (2 × ΔH₃) + (-1 × ΔH₁) + (1 × ΔH₂)

ΔHrxn = (2 × (-92.3)) + (-1 × (-74.6)) + (1 × (-95.7))

ΔHrxn = -184.6 + 74.6 + 95.7

ΔHrxn = -14.3 kJ.

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The lowest smallest whole-number coefficient for H₂S is 5. Option C

Now we know that a redox reaction is one in which there is a loss and gain of electrons One specie is oxidized (looses electrons) while another specie is reduced (gains electrons). The electrons must be transferred leading to an increase in oxidation number of one specie and a decrease in the oxidation number of another.

Now the reduction half equation is;

MnO4^-(aq) + 8H^+(aq) + 5e^- ----> Mn^2+(aq) + 4H2O (l)

The oxidation  half equation is;

H2S(aq) ----> S^2-(aq) + 2H^+(aq) + 2e^-

Multiplying the reduction half equation by 2 and the  oxidation  half equation is 5

2MnO4^-(aq) + 16H^+(aq) + 10e^- ----> 2Mn^2+(aq) + 8H2O (l)

And;

5H2S(aq) ----> 5S^2-(aq) + 10H^+(aq) + 10e^-

The overall balanced reaction equation is;

2MnO4^-(aq) + 6H^+(aq) + 5H2S(aq) ----> 2Mn^2+(aq) + 8H2O (l) + 5S^2-(aq)

Thus the lowest smallest whole-number coefficient for H₂S is 5.

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3.3 g of hydrogen gas will be produced.

Stoichiometry helps to measure quantitative relationships between the amounts of products and reactants that are given in a reaction.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

Mg + 2HNO₃  → Mg(NO₃)₂ + H₂

According to Stoichiometry

[tex]40.9\ \text{g Mg} \times \frac{1\ \text{mol Mg}}{24.31\ \text{g Mg}} \times \frac{1\ \text{mol}\ H_2}{1\ \text{mol Mg}} \times \frac{2.02\ g\ H_2}{1\ \text{mol}\ H_2}[/tex]

= 3.3 g H₂

Thus from the above conclusion we can say that 3.3 g of hydrogen gas will be produced.

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Answer:

111600 moles

Explanation:

Number of moles= Mass ×Mr, where Mr is the relative molecular mass of the substance of interest. Note that the mass is calculated in terms of grams (1 kg= 1000 g), while the Mr can be found using the periodic table.

Mass of iron

= 2 kg

= 2(1000)

= 2000 g

Mr of iron= 55.8

Number of moles

= 2000(55.8)

= 111600 mol

Additional:

To learn more about stoichiometry, do check out the following!

The value of a mole is 6.022 ×[tex]10^{23}[/tex]. The other name of mole is Avogadro's number.

The mole is define as  6.022 ×[tex]10^{23}[/tex] of the chemical unit like atoms , molecules, ions or others.It is very convenient unit because of huge numbers o f atoms, molecules or others. This is very important unit used by chemist.

One mole = atomic Mass of atoms / molecular mass of molecule

Example: one mole of sodium = 23 g = atomic mass

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You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚ 100 g H₂O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol

The percent by mass of each element present in a compound is called Mass Percent.

(a) Water is 11.19% hydrogen by mass.

Here it is given mass of hydrogen is 11.19 %. That means 11.19 % of solute should be added in 100 g H₂O.

(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.

Here it is given mass of oxygen is 53.29 %. That means in 53.29% of solute should be added in 100 g fructose.

(c) Octane, a component of gasoline, is 84.12% carbon by mass.

Here it is given mass of carbon is 84.12 %. That means in 84.29% of solute should be added in 100 g Octane.

(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.

Here it is given mass of carbon is 52.14 %. That means in 52.14% of solute should be added in 100 g Ethanol.

Thus from the above conclusion we can say that You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚100 g H2O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. Write the conversion factor (including units) inherent in each mass percent composition.

(a) Water is 11.19% hydrogen by mass.

(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.

(c) Octane, a component of gasoline, is 84.12% carbon by mass.

(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.

The correct option is D. H2O.

For the combustion of ethane (C2H6); the chemical equation is;

2 C2H6 + 7 O2 --> 4 CO2 + 6 H2O.

All hydrocarbons go through combustion processes, and the only byproducts are water (H2O) & carbon dioxide (CO2).

Any of a group of organic molecules with only the atoms carbon (C) & hydrogen are known as hydrocarbons (H). The hydrogen atoms bind to the carbon atoms in a variety of ways to create the compound's structural framework. chemical mixture.

The classification of hydrocarbons are done by-

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The complete question is -

Given the incomplete equation for the combustion of ethane (C2H6): 2 C2H6 + 7 O2 --> 4 CO2 + 6 ___

Group of answer choices:

A. H2O2

B. HCOOH

C. CH3OH

D. H2O

Since volume and temperature are constant, this means that pressure and number of moles are directly proportional. the sample with the largest number of moles will have the high pressure.

Since, the ideal gas equation is also called ideal gas law. So,  according to ideal gas equations,

PV = nRT

At constant volume and temperature the equation become ,

P ∝ nR

since, R is also constant. So, conclusion of the final equation is

P  ∝ n

The number of moles and pressure of the sample is directly proportion. So, on increasing number of moles in the sample , pressure of the sample also increases.

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The amount in moles of the excess reactant left is 0.5 mole

2ZnS (s) + 3O₂(g) --> 2ZnO (s) + 2SO₂(g)

From the balanced equation,

2 moles of ZnS reacted with 3 moles of O₂

From the balanced equation,

2 moles of ZnS reacted with 3 moles of O₂

Therefore,

4.2 moles of ZnS will react with =(4.2 × 3) / 2 = 6.3 moles of O₂

From the calculations made above, we can see that only 6.3 moles of O₂ out of 6.8 moles given, is required to react completely with 4.2 moles of ZnS.

Thus, ZnS is the limiting reactant and O₂ is the excess reactant.

The excess reactant is O₂. Thus the mole remaining after the reaction can be obtained as illustrated below:

Mole of O₂ remaining = (Mole of O₂ given) - (Mole of O₂ that reacted)

Mole of O₂ remaining = 6.8 - 6.3

Mole of O₂ remaining = 0.5 mole

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Answer:

Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g)

Explanation:

The equation Zn + 2 HCI -> H₂ +zncl2 on reduction and oxidation, it results as below;

The equations above are half cell.

On combination of the above half cell reaction equations gives;

Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).

Therefore, the half reaction equation for Zn + 2 HCI -> H₂ +zncl2 is given by;

Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).

Answer:

C. Gas

Explanation:

I think this is the right answer because it fits the description

Answer:

869 g Cl₂O

Explanation:

To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).

1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)

Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol

Molar Mass (Cl₂O): 86.904 g/mol

10.0 moles SO₂         1 mole Cl₂O            86.904 g
------------------------  x  ----------------------  x  ------------------  = 869 g Cl₂O
                                    1 mole SO₂              1 mole

There is 0.0600moles of MgCl2 in 60.0ml of 0.100M MgCl2 solution.

Explanation:

First we need to determine the number of moles of MgCl2 in 60.0L of solution.

After determining the number of moles,now multiply moles of MgCl2 by its Molar mass i.e (95.205g/mol)

We know Molarity= mol of solute/L solution

∴ 0.10 M MgCl2 = 0.10mol MgCl2/L

Step1:

First convert 60.0ml to litres.

1L=1000mL

60.0mL×1L/1000mL=0.0600L

Step2:

To determine moles of MgCl2, multiply 0.0600 L by the molarity of the solution

0.0600L×0.10mL/1L=0.0600mol MgCl2

∴ 0.0600moles of MgCl2 are present in 60.0mL of 0.100M MgCl2 solution.

Relative molar mass is defined as the smallest mass unit of a compound with one twelfth of the mass of one carbon – 12 atom.

In a substance, the amount of entities present for e.g. atoms, molecules, ions, is defined as a mole. A mole of any substance is 6.022×1023 molecules. Just as we take a standard value to calculate different things e.g. 1 dozen =12 items similarly we use the mole to calculate the size of the smallest entities quantitatively.

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Molarity of a solution is defined as the number of moles of the solute dissolved per litre of the solution. I is represented as \textbf{`M`}. Thus a solution, which contains one gram mole of the the solution dissolved per litre* of the solution is regarded as molarity.

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The name of the given ether is ethyl benzyl ether .

Ethers are organic compounds formed when nan oxygen atom is bonded to two alkyl or aryl groups.

Ethers usually have relatively high boiling points as a result of the central oxygen atom. An example of an ether, is ethyl propyl ether

The name of the given ether is ethyl benzyl ether as it has a benzyl and ethyl group attached to the oxygen atom.

In conclusion, ethers are characterized by an oxygen atom bonded to two alkyl or aryl groups.

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Based on the mole ratio, the mass of oxygen reacting is 45.8 g.

The incomplete combustion of propane with oxygen produces carbon (ii) oxide and water.

The mole ratio of propane to oxygen according to the equation of the reaction is 2 : 7.

Molar mass of propane = 44 g/mol

Molar mass of oxygen = 32 g/mol

moles in 18.0 g = 18/44 mole

Mass of oxygen reacting = 18/44 * 7/2 * 32 = 45.8

In conclusion, incomplete combustion of propane produces carbon (ii) oxide.

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Answer:

66 grams of carbon dioxide

C3H8+5O2=3CO2+4H2O

Answer:

0.409 L

Explanation:

Because you are dealing with volume and temperature, you need to use the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.

V₁ = 5.18 L                            V₂ = ? L

T₁ = 76.0 °C                          T₂ = 6.0 °C

V₁ / T₁ = V₂ / T₂                                           <----- Charles' Law equation

5.18 L / 76.0 °C = V₂ / 6.0 °C                     <----- Insert values

0.06815789 = V₂ / 6.0 °C                          <----- Simplify left side

0.409 L = V₂                                              <----- Multiply both sides by 6.0

Answer: The answer is fatty acids and triglycerides

Explanation:

Nitrogen gas is formed in this reaction.

Atomic number 7 and the letter N designate nitrogen as the chemical element. Group 15 of the periodic table, often known as the pnictogens, contains nitrogen as the lightest nonmetal element. It ranks eighth in overall abundance in the Milky Way and the Solar System, making it a common element in the cosmos. Two of the element's atoms combine to create the colorless and odorless diatomic gas N2 at standard temperature and pressure. The most common element that isn't mixed, N2 makes up around 78 percent of the Earth's atmosphere. All living things contain nitrogen, which is mostly found in amino acids (and thus proteins), nucleic acids (DNA and RNA), and the energy-transfer molecule adenosine triphosphate.

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Answer:

ρHNO₃= 1.51 g/cm3

ρ = m/V

m = ρ x V

m = (1.51 g/cm3)(2 cm3)= 3.02 g de HNO₃

n = m/PM = 3.02 g/63.01 g/mol = 0.0479 mol de HNO₃

Explanation:

2 mL of concentrated nitric acid equals 0.0479 mol

In the following redox reaction, the reducing agent is MnO2 (option D). Details about reducing agent can be found below.

A reducing agent in a redox reaction is any substance that reduces, or donates electrons to another, hence, it becomes oxidized.

According to this question, a redox reaction is given as follows: MnO2(s) + 4H+(aq) + 2Cl–(aq) = Mn2+(aq) + 2H2O(l) + Cl2(g)

As shown in the equation, MnO2 is oxidized into Mn2+, therefore, it is the reducing agent.

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