what is the frequency of a 7.43 x 10-5 m wave

Answer:

The speed of the crate when it reaches the bottom can be calculated using the equation:

v = √(2gh)

Where v is the speed, g is the acceleration due to gravity (9.8 m/s2), h is the height of the ramp (3.20 m).

Therefore, the speed of the crate is:

v = √(2 * 9.8 * 3.20) = 7.7 m/s

In the longitudinal wave, the particles of the medium have to and fro motion about their mean motion which is along the direction of wave motion. So, the correct option is A.

Longitudinal waves are defined as those waves in which the displacement of the medium is in the same or opposite direction to the wave propagation and the vibration of the medium is parallel or along the direction of wave travel.

Mechanical longitudinal waves are also known as compression or compression waves as they produce compression and rarefaction when passing through a material. In a longitudinal wave, the particles of the medium move about with their average speed which is in the direction of wave motion.

Hence the correct option is A.

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Your question is incomplete, most probably the complete question is :

In a longitudinal wave, the medium moves

The correct option is C. The blue-shifted spectral lines of Sirius indicate that it has a radial velocity that is towards us.

Radial velocity is a measure of the motion of an object in a straight line towards or away from an observer. In physics, it is commonly used to describe the motion of celestial bodies, such as stars and planets, as they move towards or away from the Earth.

Radial velocity is typically measured using the Doppler effect, which is the apparent shift in the frequency of electromagnetic waves due to the motion of the source of the waves. For example, if a star is moving toward the Earth, the wavelengths of light it emits will be compressed, resulting in a blue shift. Conversely, if a star is moving away from the Earth, the wavelengths of light will be stretched, resulting in a redshift.

A radial velocity is an important tool for astronomers, as it can be used to determine the distance, mass, and orbit of celestial objects. It is also used in other fields of physics, such as in the study of fluid dynamics, where it is used to describe the motion of fluids in circular or radial patterns.

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A cοmpοnent οr pictοrial diagram is an illustratiοn that depicts hοw actual cοmpοnents appear.

The pictοrial diagram is the mοst fundamental type οf diagram. It shοws a diagram οr sketch οf the variοus system cοmpοnents as well as the wiring between these cοmpοnents. Even if yοu are unfamiliar with the physical appearance οf system cοmpοnents, this simplified diagram allοws yοu tο quickly identify them.

This diagram shοws the variοus cοmpοnents withοut regard tο their physical lοcatiοn, hοw the wiring is labelled, οr hοw the wiring is rοuted. It dοes, hοwever, shοw the sequence in which the cοnstituents are linked.

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All you have to do to convert 27 to a decimal is divide it by 100.

One of the number types in algebra that has a whole integer and a fractional portion separated by a decimal point is a decimal. The decimal point is the dot that appears between the parts of a whole number and a fraction. An example of a decimal number is 34.5.

The square root of the perfect square number 100, which is 10, is 10. Since 100% represents a full number, 100 is used as the basis for percentages. One dollar is divided into 100 cents.

100 is not a prime. One hundred is divisible by 1, 2, 4, 5, 10, 20, 25, and one hundred. 100 is not a prime number because it has more than two factors, including 1, 2, 4, 5, 10, 20, 25, 50, and 100.

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The maximum deflection of the spring k2 is approximately 0.31 m.

The spring constant, k, is a measure of the spring's stiffness. It varies depending on the spring and material. The greater the spring constant, the stiffer the spring and more difficult to stretch.

To solve this problem, we can use conservation of energy and Hooke's law.

1/2 k1 x[tex]1^2[/tex] = 1/2 m [tex]v^2[/tex]

v = [tex](2 k1 x1 / m)^{0.5[/tex] = [tex](2 x 2.0 N/m x 0.050 m / 0.2 kg)^{0.5[/tex] ≈ 0.5 m/s

1/2 m [tex]v^2[/tex] = 1/2 k2 [tex]x^2[/tex]

x = [tex](m v^2/ k2)^{0.5[/tex] =[tex](0.2 kg x (0.5 m/s)^2 / 1.1 N/m)^{0.5[/tex] ≈ 0.31 m

Therefore, the maximum deflection of the spring k2 is approximately 0.31 m.

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As a general guideline, it is believed that a current of 100 milliamperes (mA) or higher passing through the human body can be lethal. Currents of this magnitude can cause the heart to go into fibrillation or stop beating altogether, leading to death.

However, the range of electric current that generally causes death depends on various factors such as the type of current, duration of exposure, the path it takes through the body, and the health status of the person. It is important to note that even lower currents can cause serious injury, and any electric shock should be taken seriously and treated as a medical emergency.

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The acceleration, given that the force is 13 KN and the mass is 58 Kg is 224.14 m/s²

Force and acceleration is related according to the following equation:

Force = mass × acceleration

From the question given above, the following data were obtained:

The acceleration can be obtained as illustrated below:

Force = mass × acceleration

13000 = 58 × acceleration

Divide both sides by 58

Acceleration = 13000 / 58

Acceleration = 224.14 m/s²

This, from the calculation made above, we can conclude that the acceleration is 224.14 m/s²

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The acceleration of the object is determined as 224.1 m/s².

Acceleration is the rate at which an object's velocity changes over time. It is the change in velocity divided by the time interval over which that change occurred.

The acceleration of an object can be determined by applying Newton's second law of motion as shown below;

F = ma

where;

The acceleration of the object is calculated as;

a = F / m

a = ( 13,000 N ) / ( 58 kg )

a = 224.1 m/s²

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The power used is the work done divided by the time taken. Work is calculated by multiplying the force by the distance moved. In this case, the work done is 70 N x 20 m = 1400 Nm. The time taken is 5 seconds, so the power used is 1400 Nm / 5 s = 280 W.

Force is a fundamental concept in Physics and is defined as an interaction between two objects that causes a change in the motion of one or both objects. Force is a vector quantity, meaning it has both magnitude and direction. Forces can be exerted by both natural and man-made objects, and can cause changes from linear motion to changes in shape or rotation. Examples of forces include gravity, friction, and magnetism. In Physics, the study of forces is called mechanics.

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The energy that the Earth receives from the Sun is the basic cause of our changing weather. Solar heat warms the huge air masses that comprise large and small weather systems.

The Sun is a massive, luminous ball of gas at the center of our solar system. It is the closest star to Earth, located approximately 93 million miles away. The Sun is made up of primarily hydrogen and helium, with small amounts of other elements.

In physics, the Sun is studied in terms of its energy production, which is generated by nuclear fusion reactions in its core. These reactions involve the fusion of hydrogen atoms to form helium, releasing enormous amounts of energy in the process.

The Sun's energy output drives the weather and climate on Earth, and its magnetic field influences space weather and the behavior of charged particles in the solar system. The study of the Sun and its effects on the Earth and other planets is a crucial field of research in astrophysics, with important implications for understanding the origins and evolution of the solar system, and for developing technologies that can harness solar energy.

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Gravitational attraction is the driving force for option (A)Stellar fusion Formation of Moons (C) Formation of stars (D) Formation of planets and (D) Formation of nebulae

Gravitational attraction is the driving force for the following processes:

Formation of moons: Gravity is responsible for the formation and maintenance of moons in orbit around planets.

Formation of stars: Gravity causes the collapse of gas and dust clouds, leading to the formation of protos tars and ultimately stars.

Formation of planets: The gravitational attraction between dust and gas particles in a protoplanetary disk causes them to clump together and form planets.

Formation of nebulae: Gravity can cause the collapse of interstellar gas and dust clouds, leading to the formation of nebulae.

Expansion of the Universe: Although not a "process" per se, gravity plays a key role in the expansion of the universe by pulling matter together, slowing the expansion.

Stellar fusion is not driven by gravitational attraction but by the intense pressure and temperature in the core of a star, where hydrogen atoms combine to form helium.

Therefore, the correct options are (A) Stellar fusion Formation of Moons (C) Formation of stars (D) Formation of planets and (D) Formation of nebulae

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The magnitude of the electric field due to the bent rod at the maximum on the z-axis is given by (kQ) / (4πε0 [tex]R^2)^{ (3/2)}[/tex], where Q is R is the circle's radius, and C is the total charge on the rod.

To find the electric field at a point on the z-axis due to the charged ring, we can use the formula for the electric field due to a uniformly charged ring:

[tex]E = (kQz) / (R^2 + z^2)^{(3/2)}[/tex]

where k is Coulomb's constant, Q is the total charge on the ring, R is the radius of the ring, and z is the distance of the point on the z-axis from the centre of the ring.

Since the ring has a uniform charge distribution, we can express the total charge on the ring Q in terms of the linear charge density λ, which is defined as the charge per unit length:

Q = λ * 2πR

where 2πR is the ring's circumference.

To find the maximum electric field on the z-axis, we need to find the distance z from the centre of the ring where the denominator of the above equation is minimized. This occurs when z = R, so we can substitute z = R in the equation and simplify:

[tex]E_{MAX}[/tex] = (kλR) / (4πε0[tex]R^2)^{(3/2)}[/tex]

where 0 represents the free space permittivity.

We can simplify the expression further by substituting the expression for λ in terms of Q:

λ = Q / (2πR)

[tex]E_{MAX}[/tex] = (kQ) / (4πε0[tex]R^2)^{ (3/2)}[/tex]

Therefore, the magnitude of the electric field due to the bent rod at the maximum on the z-axis is given by (kQ) / (4πε0 [tex]R^2)^{ (3/2)}[/tex], where Q is R is the circle's radius, and C is the total charge on the rod.

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Answer:

Work done by the shopper on the cart: The force of 40 N at an angle of 30 degrees downward from the horizontal can be resolved into its horizontal and vertical components. The horizontal component of the force is:F_horizontal = F * cos(theta) = 40 N * cos(30) = 34.64 N

The work done by the shopper on the cart is equal to the force applied multiplied by the distance moved, multiplied by the cosine of the angle between the force and the displacement. In this case, the displacement is 15 m, and the angle between the force and the displacement is 30 degrees. Therefore:Work = F * d * cos(theta) = 34.64 N * 15 m * cos(30) = 448.5 J

Speed of the cart at the tofu section: The initial potential energy of the cart and shopper is equal to their combined mass (85 kg) multiplied by the acceleration due to gravity (9.81 m/s^2) multiplied by the height of Twin Peaks (600 m). 

Therefore: Potential energy = m * g * h = 85 kg * 9.81 m/s^2 * 600 m = 498,690 J

Since the shopper neglects friction, all of the potential energy is converted into kinetic energy at the bottom of the hill. The kinetic energy of the cart and shopper can be found using the formula:

Kinetic energy = 0.5 * m * v^2

where m is the mass of the cart and shopper, and v is their speed.

Therefore:Kinetic energy = 0.5 * 85 kg * v^2 Since the potential and kinetic energies are equal, we can set them equal to each other and solve for the speed v: Potential energy = Kinetic energym * g * h = 0.5 * m * v^2v = sqrt(2 * g * h) = sqrt(2 * 9.81 m/s^2 * 600 m) = 109.43 m/s

Power exerted by the shopper in stopping the cart:The shopper brings the cart to rest over a distance of 15 m in a time of 2.7 s. The average force exerted by the shopper on the cart can be found using Newton's second law: F = m * a = m * (v_f - v_i) / twhere m is the mass of the cart, v_i is the initial speed of the cart (which is zero), v_f is the final speed of the cart, and t is the time taken to stop the cart. Solving for F gives:F = m * (v_f / t)The work done by the shopper in stopping the cart is equal to the force applied multiplied by the distance moved, which is 15 m. Therefore:Work = F * d = m * (v_f / t) * d = 24 kg * (0 - 0) / 2.7 s * 15 m = 0 JSince no work is done in bringing the cart to rest, the power exerted by the shopper is zero.Acceleration due to gravity on the unknown planet:The final speed of the 4 kg ball is 12 m/s, and it falls a distance of 60 m. The initial speed is zero, so the final velocity is equal to the velocity acquired due to gravity. The final velocity can be found using the formula:v_f^2 = v_i^2 + 2 * g * hwhere v_i is the initial velocity (which is zero), h is the height fallen, and g is the acceleration due to gravity.

Answer:

i got u

Explanation:

To find the time taken to cover a distance of 180 km with velocity magnitude 20 m/sec, we can use the formula:

time = distance / velocity

Converting the distance to meters, we get:

180 km = 180,000 m

Plugging in the values, we get:

time = 180,000 m / 20 m/sec

Simplifying, we get:

time = 9,000 seconds

Therefore, the time taken to cover a distance of 180 km with velocity magnitude 20 m/sec is 9,000 seconds.

"The hang time of the parachute increased with string length, as it increases the air resistance. Even while gravity was always pushing on the object, the shorter strings increased the force it was exerting."

The primary forces that affect a parachute are drag and gravity. Gravity pulls the parachute downward when you first open it, which causes it to fall quickly to the earth. However, the drag gets worse as the pace falls.

A parachute falls more slowly the more air it needs to push aside due to its larger surface area.

Air resistance increases with string length, extending hang time and delaying parachute fall. Even though gravity was always pulling on the object, the shorter ropes enhanced the power that gravity was exerting on it.

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Approximately 5.6 cm of the steel cylinder is above the surface of the mercury.

What is Density ?

Density is a physical property that describes the amount of mass in a given volume of a substance. It is defined as the mass of a substance per unit volume, usually expressed in grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).

The formula for density is:

Density = Mass / Volume

This means that density is directly proportional to the mass of a substance and inversely proportional to its volume. A substance with a higher mass and a smaller volume will have a higher density than a substance with a lower mass and a larger volume.

To determine the length of the steel cylinder that is above the surface of the mercury, we need to consider the buoyant force acting on the cylinder. The buoyant force is equal to the weight of the fluid displaced by the object, which in this case is the mercury.

Since the cylinder is floating, the buoyant force acting on it is equal in magnitude to its weight. We can calculate the weight of the cylinder using its density and volume. The density of steel is about 7,800 kg/m³, and the volume of the cylinder can be calculated as:

V = πr²h

where r is the radius of the cylinder (which is half the diameter) and h is its height. Substituting the given values, we get:

V = π(0.05 m)²(0.20 m) = 0.000785 m³

The weight of the cylinder is then:

W = mg = ρVg

where ρ is the density of steel, g is the acceleration due to gravity, and m is the mass of the cylinder (which we can calculate using its density and volume). Substituting the given values, we get:

m = ρV = (7,800 kg/m³)(0.000785 m³) = 6.123 kg

W = mg = (6.123 kg)(9.81 m/s²) = 60.053 N

The buoyant force acting on the cylinder is equal to its weight, so:

Fb = W = 60.053 N

We can also calculate the volume of mercury displaced by the cylinder. Since the cylinder is perpendicular to the surface of the mercury, the volume of mercury displaced is equal to the volume of the cylinder that is submerged in the mercury. The submerged volume can be calculated as:

Vsub = [tex]\pi r^2x[/tex]

where x is the length of the cylinder that is submerged in the mercury. Substituting the given values, we get:

Vsub =[tex]\pi(0.05 m)^2x[/tex]

We can now use Archimedes' principle to relate the buoyant force to the submerged volume of mercury:

Fb = ρgVsub

where ρ is the density of mercury, g is the acceleration due to gravity, and Vsub is the volume of mercury displaced. Substituting the given values, we get:

[tex]\mathrm60.053 N = (13,600 kg/m^3)(9.81 m/s^2)\pi(0.05 m)^2x[/tex]

Solving for x, we get:

x = 0.144 m

Therefore, the length of steel above the surface of the mercury is:

[tex]h - x = 0.20 m - 0.144 m = 0.056 m[/tex]

So, approximately 5.6 cm of the steel cylinder is above the surface of the mercury.

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During day, atmosphere gets warm causing air to rise and circulate and at night it cools down and radiates heat back into space leading to stability.

The daily conditions in the Earth's atmosphere are complex and variable, influenced by a range of factors including temperature, pressure, humidity, and wind patterns. Understanding these conditions is essential for predicting and responding to weather events and for developing strategies to mitigate the impact of climate change on the planet.

The Earth's atmosphere is the layer of gases that surrounds the planet and plays a crucial role in supporting life. The daily conditions in the Earth's atmosphere can vary depending on various factors, such as the time of day, location, and weather patterns.

During the day, the atmosphere experiences warming due to the energy from the sun, which causes the air to rise and circulate, leading to the formation of clouds and other weather phenomena. The intensity of the warming depends on the angle of the sun's rays and the amount of cloud cover, which can affect the temperature and humidity levels.

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The form of heat transfer that occurs when you step outside and feel the heat of the sun on your skin is radiation.

Radiation is a type of heat transfer that occurs through electromagnetic waves. These waves can travel through a vacuum (such as space) and do not require a medium to transfer heat. In the case of the sun, it emits radiation in the form of visible light, ultraviolet light, and infrared radiation, which are all forms of electromagnetic waves. When these waves come into contact with your skin, they are absorbed by the molecules in your skin, causing them to vibrate and produce heat. This is why you feel the warmth of the sun on your skin, even though the air temperature may be relatively cool. Radiation is different from conduction and convection, which are two other forms of heat transfer. Conduction is the transfer of heat through direct contact between two objects, while convection is the transfer of heat through the movement of fluids (such as air or water). In contrast, radiation can transfer heat through empty space, and does not require a medium to transfer heat. In summary, when you step outside and feel the heat of the sun on your skin, this is an example of radiation, a form of heat transfer that occurs through electromagnetic waves.

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The time period of the simple pendulum on Venus is found to be 2.41 seconds.

Another mechanical mechanism that oscillates is the straightforward pendulum. It consists of a point mass "m" hung from a fixed support by a light, inextensible string with length L.

Time period:

T= 2π√(L/g)

g on Venus = 8.8 m/s²

T = 2*3.14*√(1.3/8.8)

T = 2.41

Thus, the time period of the simple pendulum on Venus is found to be 2.41 seconds.

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8.09 C of charge is present on each electrode.

Each electrode has an 8.09 C charge (microcoulombs).

Using the equation Q = CV, where Q denotes the charge, C the capacitance, and V the potential difference, this may be determined. The formula C = A/d can be used to compute capacitance, where A is the area of the electrodes, d is the distance between them, and is the permittivity of free space.

We may calculate C as follows by plugging in the supplied values: C = (8.85 x 10-12 F/m)(0.06 m x 0.06 m)/(0.001 m) = 3.186 x 10-11 F.

Once this is done, Q = CV = (3.186 x 10-11 F)(9.0 V) = 2.8674 x 10-10 C = 8.09 C.

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Insolation results in changes in the temperature of a gas, which then results in changes in pressure, leading to motion in the atmosphere.

When insolation heats up the Earth's surface, it causes the air in contact with it to warm up through conduction. The heated air then expands and becomes less dense, which makes it rise and creates an area of low pressure at the surface. Conversely, areas that receive less insolation will be cooler, and the air in those regions will be denser, leading to higher surface pressure.

As the pressure in one area changes due to differences in temperature, it creates a pressure gradient that leads to motion in the atmosphere. Air will flow from areas of high pressure to areas of low pressure, creating wind and atmospheric circulation patterns. These pressure differences can also lead to the formation of weather systems, such as cyclones and anticyclones, which can affect large regions of the atmosphere.

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Informational Goals Do a lab procedure to investigate the connection between temperature and solubility.

According to temperature, heat energy will naturally move from a hotter body (one with a higher temperature) to a colder object (one with a lower temperature).

The velocity of these particles likewise increases as the temperature rises. A thermometers or a digital thermometer is used to determine the temperature. The SI unit for temperature, oC, is symbolised by the symbol ′T′. The Celsius scale, the Fahrenheit scale, and the Kelvin scale are the three scales that are most frequently used to measure temperature.

This scale too is known as the SI temperature scale. Most of the scientific community uses it. It was created to pay tribute to renowned physicist Lord Kelvin.

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Yes, a capacitor can be used as a high-pass filter. A high-pass filter is a type of electronic circuit that allows high-frequency signals to pass through while blocking or attenuating low-frequency signals.

In a high-pass filter, the capacitor is connected in series with the input signal and a resistor is connected in parallel to the output. The capacitor acts as a barrier to low-frequency signals, allowing only high-frequency signals to pass through to the output. The resistor is used to limit the output signal amplitude and to control the cutoff frequency of the filter.

The cutoff frequency of a high-pass filter is determined by the values of the capacitor and resistor in the circuit. As the cutoff frequency increases, the filter becomes more effective at blocking low-frequency signals and allowing only high-frequency signals to pass through.

Capacitors are commonly used in high-pass filters in a variety of applications, such as in audio equipment to remove low-frequency noise and in signal processing to extract high-frequency components of a signal.

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When a car travels around a curve in the road centripetal force helps to keep the car traveling in a curved path.

The primary factor is the force of friction between the tires and the road. This force is what allows the car to maintain traction and grip the road surface, preventing it from sliding off the curve. As the car turns, the force of friction acting on the tires generates a centripetal force, which pulls the car towards the center of the curve.

Other factors that contribute to keeping the car on the curved path include the design of the road and the car's suspension system. Roads are often banked on curves, which means they are angled to the inside of the curve. This banking helps to create a force that pushes the car towards the center of the curve, reducing the amount of lateral force required to maintain the turn. The car's suspension system also plays a role in keeping the car stable during the turn by absorbing shocks and vibrations and helping to maintain the car's balance.

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Answer:

All galaxies appear to be moving away from all other galaxies.

Explanation:

i m smart brainlist please

Examples of systematic and random errors are Zero error in instruments, Calibration errors, Reading errors and Natural variations.

In experimental research, there are two types of errors: systematic errors and random errors.

Systematic errors are errors that are consistent and repeatable in a given experiment, and they are usually caused by flaws or limitations in the experimental design or instruments. Examples of systematic errors include:

On the other hand, random errors are errors that are unpredictable and occur randomly in an experiment. They are usually caused by fluctuations in the experimental conditions or measurement process. Examples of random errors include:

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The percent water in the hydrated salt is 8.45%. This means that the hydrated salt contains 8.45% water by mass as per gravimetric analysis.

To determine the percent water in the hydrated salt, we need to calculate the mass of water present in the hydrated salt and then divide it by the total mass of the hydrated salt. based on gravimetric analysis. We can use the data provided to calculate the mass of water as follows:

Hydrated salt mass = Crucible, lid, and hydrated salt mass - crucible and lid mass

= 21.626 g - 19.437 g

= 2.189 g

Anhydrous salt mass = Crucible, lid, anhydrous salt mass- crucible and lid mass

= 21.441 g - 19.437 g

= 2.004 g

Water mass = Hydrated salt mass - Anhydrous salt mass

= 2.189 g - 2.004 g

= 0.185 g

Now, we can calculate the percent water in the hydrated salt as follows:

Percent water = (mass of water ÷ mass of hydrated salt) × 100%

= (0.185 g ÷ 2.189 g) × 100%

= 8.45%

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The baseball will reach its maximum height after approximately 6.11 seconds using equations of motion where velocity is given

When a baseball is thrown straight up with an initial velocity of 60 m/s, it will eventually reach a maximum height before falling back down due to gravity. To determine how many seconds later the baseball will reach its maximum height, we need to use the equations of motion.

The equation we can use to find the time taken for the baseball to reach its maximum height is:

t = Vf / g

where t is the time taken, Vf is the final velocity (which is zero at the maximum height), and g is the acceleration due to gravity, which is approximately [tex]9.81 m/s^2[/tex].

Substituting:

t = 60 / 9.81

t ≈ 6.11 seconds

Therefore, the baseball will reach its maximum height after approximately 6.11 seconds. After this point, the baseball will begin to fall back down to the ground due to the force of gravity, with its velocity increasing at a rate of [tex]9.81 m/s^2[/tex]

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The maximum speed at which the car can make the turn is approximately 22.3 meters per second.

Explanation:

Using the formula v = √(u * g * r), where u is the coefficient of friction, g is the acceleration due to gravity, and r is the radius of the curve, we can calculate the maximum speed of the car:

v = √(0.850 * 9.81 m/s^2 * 35.0 m) = 22.3 m/s

In the corresponding circumstances, 750 N and 250 N; Method (b)Mass of the block, m = 25 kg

Mass of the man, M = 50 kg

Acceleration due to gravity, g = 10 m / s²

F = 25 × 10 = 250 N is the force exerted on the block.

The man's weight is W = 50 ×  10 = 500 N.

Example (a): When the man directly raises the block

In this instance, the man pushes up by exerting force. His outward weight rises as a result.

The man's movement on the floor equals 250 + 500 = 750 N.

Scenario (b): When a pulley is used by the man to elevate the block

In this instance, the man exerts pressure downward. His apparent weight is reduced as a result.

The man's movement on the floor equals 500 - 250 = 250 N.

If a normal force of 700 N can cause the floor to give way, the guy should use the second method to easily raise the block while using less force.

The complete question is:

A block of mass 25 kg is raised by a 50 kg man in two different ways as shown in figure What is the action on the floor by the man in the two cases? If the floor yields to a normal force of 700 N, which mode should the man adopt to lift the block without the floor yielding.

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