Answer:
4
Step-by-step explanation:
A mode is the number having the highest frequency, that is, the number which occurs the most times. (The number which occurs the most here is 4, there are two 4s. You only have one of the rest of the numbers.)
Use the information above to answer the questions that follow.
2.2.1
2.2.2
2.2.3
2.2.4
sanitation in Johannesburg if a property is 175 m².
Write down, to the nearest ten cents and excluding VAT, the cost for
Calculate the cost for 4,1 ke sanitation in Cape Town before the increase.
Mr Jones lives in Johannesburg and Ms Brown lives in Cape Town. They
both own a property with an area of 550 m² and each was billed for 22 kl
sanitation.
Use the table above to determine the difference in the cost of sanitation
for the two properties.
Explain how the tariff system used in Johannesburg is beneficial to
home owners in terms of water usage.
(2)
(8)
(2)
[34]
mor
MO
ud.
0
0
Mr. Jones in Johannesburg is billed R9,767.12 and Ms. Brown in Cape Town is billed R680.24 for their respective properties.
From the provided information for Cape Town's sanitation tariffs:
0-4.2 kl: R16.03 per kl
Since 4.1 ke is equivalent to 4100 liters, which is less than 4.2 kl, we can use the tariff rate for the 0-4.2 kl range.
Cost for 4.1 ke of sanitation
= 4.1 ke x R16.03 per kl
= 4100 liters x R16.03 per kl
= R65.83
For Mr. Jones and Ms. Brown, who own properties with an area of 550 m² each and were billed for 22 kl of sanitation.
we need to determine the applicable tariff rate based on the property size and calculate the cost.
In Johannesburg, based on the provided information, the tariff rate for properties larger than 300 m² to 1,000 m² is R443.96.
Cost of sanitation for Mr. Jones in Johannesburg:
= 22 kl x R443.96 per kl
= R9,767.12
Cost of sanitation for Ms. Brown in Cape Town:
= 22 kl x R30.92 per kl = R680.24
Therefore, Mr. Jones in Johannesburg is billed R9,767.12 and Ms. Brown in Cape Town is billed R680.24 for their respective properties.
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A normal distribution has a mean of 137 and a standard deviation of 6. Find the z-score for a data value of 155.
Round to two decimal places
Answer:
3
Step-by-step explanation:
To find the z-score for a data value of 155 in a normal distribution with a mean of 137 and a standard deviation of 6, you can use the formula:
z = (x - μ) / σ
where:
x is the data value,
μ is the mean, and
σ is the standard deviation.
Plugging in the values, we have:
z = (155 - 137) / 6
Calculating this expression:
z = 18 / 6 = 3
highest common factor of a² + ab and ab + b²
[tex]a^2+ab=a(a+b)\\ab+b^2=b(a+b)[/tex]
Therefore
[tex]\text{hcf}(a^2+ab,ab+b^2)=a+b[/tex]
The Tenorio Dairy makes cheese to supply to stores in its area. The dairy can make 250 pounds of cheese per day, and the demand at area stores is 180 pounds per day. Each time the dairy makes cheese, it costs $125 to set up the production process. The annual cost of carrying a pound cheese in a refrigerated storage area is $12. Determine the optimal size and the total annual inventory cost.
Answer:
The optimal size of each production run is 180 pounds, and the total annual inventory cost is $832,825.
Step-by-step explanation:
To determine the optimal size and total annual inventory cost, we need to consider the production capacity, demand, setup costs, and carrying costs.
Given:
Production capacity per day = 250 pounds
Demand per day = 180 pounds
Setup cost = $125
Carrying cost per pound per year = $12
First, let's calculate the optimal production size. We want to produce enough cheese to meet the demand without exceeding the production capacity.
Optimal production size per day = Minimum(Production capacity, Demand)
Optimal production size per day = Minimum(250 pounds, 180 pounds) = 180 pounds
Next, let's calculate the total annual inventory cost. This cost includes both the setup cost and the carrying cost.
Total annual inventory cost = (Setup cost * Number of setups per year) + (Carrying cost per pound * Optimal production size * Number of days in a year)
Number of setups per year = Number of production runs per year
Number of production runs per year = Total days in a year / Days per production run
Assuming a year has 365 days and each production run takes one day:
Number of production runs per year = 365 days / 1 day = 365 runs
Total annual inventory cost = ($125 * 365) + ($12 * 180 pounds * 365)
Total annual inventory cost = $45,625 + $787,200
Total annual inventory cost = $832,825
find the theoretical probability.
[tex]|\Omega|=8\\|\text{odd}|=4\\\\P(\text{odd})=\dfrac{4}{8}=\dfrac{1}{2}[/tex]
Answer:
4/8
or, 1/2
Step-by-step explanation:
odd numbers (O) = (1,3,5,7) = 4
total numbers (T) = 8
P(odd) = n(O)/n(T)
= 4/8
Function c
is defined by the equation c(n)=50+4n
. It gives the monthly cost, in dollars, of visiting a gym as a function of the number of visits, n
.
True or False? The inverse function is as follows:
n=(c(n) − 50)×4
Responses
Answer:
False
Step-by-step explanation:
1. The inverse function should have c(n) isolated
2. When finding the inverse of a function, the variables c(n) and n are interchanged (and then c(n) is isolated).
It would look like this --->c(n)=50+4n--->n=50+4(c(n)) ---> c(n)=(n-50)/4
Find the area of a circle with radius,
r
= 42cm.
Give your answer rounded to 3 SF.
Answer:
5541.77 cm^2
Step-by-step explanation:
All else being equal, if you cut the sample size in half, how does this affect the margin of error when using the sam
to make a statistical inference about the mean of the normally distributed population from which it was drawn?
ME-
Z.S
O The margin of error is multiplied by √0.5.
O The margin of error is multiplied by √√2-
O The margin of error is multiplied by 0.5.
O The margin of error is multiplied by 2.
Answer:
When you cut the sample size in half while making a statistical inference about the mean of a normally distributed population, the effect on the margin of error depends on the relationship between the sample size and the margin of error. Generally, the margin of error is inversely proportional to the square root of the sample size.
So, if you reduce the sample size by half, it means you are taking a smaller sample, which will result in a larger margin of error. In other words, the margin of error is multiplied by a factor greater than 1.
Among the given options, the correct answer is:
D. The margin of error is multiplied by 2.
This option correctly reflects the relationship between reducing the sample size by half and the resulting increase in the margin of error.
Snacknow, a food service firm, is calculating its monthly productivity report. From the following raw data calculate the labor, Multifactor, and Energy productivity.
Labor rate $10
Units produced 10,000
Labor hours 1,000
Cost of materials $2000
Cost of energy $500
The calculated productivities are:
Labor Productivity: 10 units per labor hour.
Multifactor Productivity: 0.8 units per dollar.
Energy Productivity: 20 units per dollar.
Answers to the aforementioned questionsTo calculate the labor productivity, divide the units produced by the labor hours:
Labor Productivity = Units Produced / Labor Hours
Labor Productivity = 10,000 / 1,000 = 10 units per labor hour.
To calculate the multifactor productivity, divide the units produced by the sum of labor, material, and energy costs:
Multifactor Productivity = Units Produced / (Labor Cost + Material Cost + Energy Cost)
In this case, the labor cost is $10 per labor hour, so the labor cost is 1,000 labor hours * $10 = $10,000.
The material cost is $2,000, and the energy cost is $500.
Multifactor Productivity = 10,000 / ($10,000 + $2,000 + $500)
Multifactor Productivity = 10,000 / $12,500 = 0.8 units per dollar.
Finally, to calculate the energy productivity, divide the units produced by the energy cost:
Energy Productivity = Units Produced / Energy Cost
In this case, the units produced are 10,000, and the energy cost is $500.
Energy Productivity = 10,000 / $500 = 20 units per dollar.
Therefore, the calculated productivities are:
Labor Productivity: 10 units per labor hour.
Multifactor Productivity: 0.8 units per dollar.
Energy Productivity: 20 units per dollar.
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PLEASE HELP MARKING AS BRAINLIST!
Hello :)
P(A) = 1/2
P(B) = 5 or greater = 5,6 => 2/6 = 1/3
P(A and B) = 1/2 x 1/3 = 1x1/2x3 = 1/6 ≈ 0.17
the answer is 0.17
Draw a box plot for each set of data. {65,92,74,61,55,35,88,99,97,100,96} Cost of MP3 Players ($)
A construction of the box-and-whisker plot representing the data set is shown below.
What is a box-and-whisker plot?In Mathematics and Statistics, a box-and-whisker plot and it can be defined as a type of chart that can be used to graphically or visually represent the five-number summary of a data set with respect to locality, skewness, and spread.
Based on the data (information) provided above, the five-number summary for the given data set include the following:
Minimum (Min) = 35.First quartile (Q₁) = 61.Median (Med) = 88.Third quartile (Q₃) = 97.Maximum (Max) = 100.In conclusion, we can logically deduce that the maximum number is 100 while the minimum number is 35, and the median is equal to 88.
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Which of the following angles is not coterminal to
120°
A 180°
B. 240°
C. 840°
D. - 600°
Give a rational Number between 4/7 and 6/11
Hello!
4/7 = 44/77
6/11 = 42/77
42/77 < 43/77 < 44/77
the rationnal number between 4/7 and 6/11 is 43/77
Directions: Below are hypotheses stated in different ways. Answer the following questions about each item.
a) In what form is the hypothesis stated?
b) Does it use a directional or non-directional test?
c) What level of measurement is each of the variables?
d) Convert the non-directional into directional.
1. The performance of the Staff Nurses is affected by their level of anxiety.
A. The hypothesis is stated in a correlational form.
B. It does not specify whether it uses a directional or non-directional test.
C. The level of measurement for these variables is not specified.
D. The higher the level of anxiety among Staff Nurses, the lower their performance.
What are the responses to other questions?a. The hypothesis "The performance of the Staff Nurses is affected by their level of anxiety." is stated in a correlational form.
b) The given hypothesis does not specify whether it uses a directional or non-directional test.
c) The variables in this hypothesis are "performance of the Staff Nurses" and "level of anxiety." The level of measurement for these variables is not specified.
d) To convert the non-directional hypothesis into a directional one, we would need to specify the direction of the relationship between the variables. For example: "The higher the level of anxiety among Staff Nurses, the lower their performance."
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convert an effective rate of 14,5% per annum, to a nominal rate per annum compounded half yearly
The nominal rate per annum compounded half-yearly, equivalent to an effective rate of 14.5% per annum, is approximately 14.900625%.
To convert an effective rate to a nominal rate compounded half-yearly, we can use the formula:
Nominal rate [tex]= (1 + r/m)^m - 1[/tex]
Where:
r = effective rate
m = number of compounding periods per year
In this case, the effective rate is 14.5% per annum, and we want to convert it to a nominal rate compounded half-yearly.
Since compounding is done semi-annually, m would be 2.
Plugging in the values:
Nominal rate [tex]= (1 + 0.145/2)^2 - 1[/tex]
Simplifying the expression inside the parentheses:
Nominal rate [tex]= (1 + 0.0725)^2 - 1[/tex]
Calculating the exponent:
Nominal rate [tex]= (1.0725)^2-1[/tex]
Performing the calculations:
Nominal rate = 1.14900625 - 1
Nominal rate = 0.14900625
Converting the nominal rate to a percentage:
Nominal rate = 14.900625%
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simplify [tex]2x^{2} +10x\ x^{2}+2x-15[/tex]
Its a fraction
Answer: [tex]=\frac{2x}{x-3}[/tex]
Step-by-step explanation:
[tex]\frac{2x^{2} +10x}{x^{2} + 2x-15}[/tex] >Take out GCF(greatest common factor) on top
>factor the bottom, find 2 numbers that mulitply to
"c" term, -15 and adds to the "b" term, +2
>+5 and -3 mulitpy to -15 and add to +2
> put +5 and -3 into factored form on bottom
[tex]=\frac{2x(x+5)}{(x-3)(x+5)}[/tex] >reduce the x+5 on top and bottom
[tex]=\frac{2x}{x-3}[/tex] >This is simplified
Music students and art students at a middle school were surveyed to choose a cardiovascular activity: playing sports or dancing.
Do you prefer dancing or playing sports?
Playing sports Dancing Row totals
Music students 32 15 47
Art students 31 22 53
Column totals 63 37 100
What is the marginal frequency of students who chose dancing?
15
22
37
53
The marginal frequency of students who chose dancing is 37.
The correct answer to the given question is option 3.
The marginal frequency of students who chose dancing can be calculated by adding up the number of students who chose dancing in each row or column. In this case, we need to add up the number of art students who chose dancing (22) and the number of music students who chose dancing (15), which gives us a total of 37. This is the marginal frequency of students who chose dancing.
Based on the survey results, it appears that a slightly higher percentage of art students prefer dancing (41.5%) compared to music students (31.9%). However, both groups of students seem to be fairly evenly split between dancing and playing sports, with a slight preference for playing sports overall.
It's worth noting that cardiovascular activity is important for overall health and well-being, and both dancing and playing sports can provide great opportunities for exercise and physical activity. Additionally, both activities can also be enjoyable and provide a sense of community and social connection, which is important for middle school students who are still developing their social skills and relationships. Ultimately, the choice between dancing and playing sports will depend on individual interests, preferences, and abilities.
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find the general term of the arithmetic sequence if a8=8, a20=44
Answer:
[tex]a_n=3n-16[/tex]
Step-by-step explanation:
[tex]a_n=a_1+(n-1)d\\\\a_8=a_1+(8-1)d\rightarrow 8=a_1+7d\\a_{20}=a_1+(20-1)d\rightarrow 44=a_1+19d[/tex]
[tex]-36=-12d\\3=d[/tex]
[tex]8=a_1+7(3)\\8=a_1+21\\-13=a_1[/tex]
[tex]a_n=-13+(n-1)(3)\\a_n=-13+3n-3\\a_n=3n-16[/tex]
How many significant digits are in 26.04813?
7 significant figures.
Zeros that come at the start do not count as significant figures.
Eg. 0.0001 would only be 1 significant figure.
Zeros that come after is counted as a significant figure.
Eg. 2.20 Is three significant figures.
Alice was provided with the following trinomial: 3x² + 7x-12x - 34 - 2x² + 10 1 Provide Alice with a step-by-step guide on how to factorize the algebraic expression.
Hello!
[tex]3x^{2} + 7x-12x - 34 - 2x^{2} + 10\\\\3x^{2}- 2x^{2} + 7x-12x - 34 + 10\\\\x^{2} - 5x - 24\\\\x^{2} + 3x - 8x - 24\\\\(x^{2} + 3x) + (-8x - 24)\\\\x(x + 3) - 8(x + 3)\\\\\boxed{(x - 8)(x+3)}[/tex]
The cost of a season train ticket is reduced by $33.10 which corresponds to a 10%
reduction. Find the original cost of the season ticket.
Answer:
Let's denote the original cost of the season train ticket as "x".
According to the given information, a reduction of $33.10 corresponds to a 10% reduction in the original cost. We can set up the following equation to represent this:
10% of x = $33.10
To solve for x, we need to convert 10% to decimal form, which is 0.10. We can rewrite the equation as:
0.10 * x = $33.10
Simplifying the equation, we have:
0.10x = $33.10
To isolate x, we divide both sides of the equation by 0.10:
x = $33.10 / 0.10
x = $331.00
Therefore, the original cost of the season train ticket is $331.00.
Step-by-step explanation:
Help please, I need to get through geometry recovery class
To prove ∠AOW = 45°
Given,
∠WOZ = 90°
∠ZOB = 45°
Now,
∠XOA +∠AOW = 90°............(1)
∠XOA = ∠ZOB ( Vertically opposite angle )
∠XOA = 45°
Substitute in (1),
45° + 45° = 90°
Now,
∠WOX = ∠XOA +∠WOA
So,
∠WOA + ∠WOZ + ∠ZOB = 180°( Linear pair )
∠WOA + 90° + 45° = 180°
∠WOA = 45°
Hence proved.
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Please help urgent thank you so much
Answer: 4, 14
Step-by-step explanation:
Bring everything over to other side that is not in the absolute value:
3 |x - 9| + 5 = 20 >Subtract 5 from both sides
3 |x - 9| = 15 >Divide both sides by 3
|x - 9| = 5 >Create a positive and negative version to
drop the absolute value
x - 9 = 5 x - 9 = -5
x= 14 x = 4
PLSSS FIND BOTH x’s THANK YOUUU
Hello!
Solutions = -3 and 1.5
PLEASE HELP ASAP
ANSWE
Answer:
664 Square yards
Step-by-step explanation:
Surface area= 2lw+2lh+2hw
=2(17×6)+2(17×10)+2(10×6)
=2(102)+2(340)+2(120)
=204+340+120
=664 Square yards
4. A machine depreciates by 40% in the first year, by 25% in the second year and by 10% per annum for the next three years. Each percentage being calculated on the diminishing value, what is the average percentage of depreciation for the entire period?
4+(1/5)[-10*(25-13-3)}÷(-5)]
Answer:
7.6
Step by step explanation
The demand for good X has been estimated by Qxd = 6 − 2Px + 5Py. Suppose that good X sells at $3 per unit and good Y sells for $2 per unit. Calculate the own price elasticity.
The own price elasticity of good X is -0.60, so we can conclude that good X is price inelastic.
What is the price elasticity?The own price elasticity of good X is calculated using the formula:
Elasticity = (% Change in Quantity Demanded) / (% Change in Price)Given the demand function for good X: Qxd = 6 - 2Px + 5Py, we can calculate the initial quantity demanded at a price of $3 per unit:
Qxd1 = 6 - 2(3) + 5(2)
= 6 - 6 + 10
= 10
The new quantity demanded when the price changes to $2.90 per unit:
[tex]Qxd_2[/tex] = 6 - 2(2.90) + 5(2)
[tex]Qxd_2[/tex] = 6 - 5.80 + 10
[tex]Qxd_2[/tex] = 10.20
Now, we can calculate the percentage change in quantity demanded:
% Change in Quantity Demanded = (Qxd2 - Qxd1) / Qxd1 * 100
% Change in Quantity Demanded = (10.20 - 10) / 10 * 100
% Change in Quantity Demanded = 0.20 / 10 * 100
% Change in Quantity Demanded = 2%
Next, we calculate the percentage change in price:
% Change in Price = (New Price - Old Price) / Old Price * 100
% Change in Price = (2.90 - 3) / 3 * 100
% Change in Price = -0.10 / 3 * 100
% Change in Price = -3.33%
The own price elasticity will be:
Elasticity = (% Change in Quantity Demanded) / (% Change in Price)
Elasticity = 2% / -3.33%
Elasticity ≈ -0.60
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how to find the base area of a rectangular prism from length width and volume
If you want to find the base area of a rectangular prism, then all you need is length and width only.
[tex] \boxed{Volume = length \times width \times height} [/tex]
You don't need height. So, this is a must be easy.
[tex]\blue{\small{\mathfrak{That's \: it. \: Thanks \::)}}} [/tex]
The cost of 1kg potatoes and 2kg tomatoes was 30 on a certain day. After two days the cost of 2kg potatoes and 4kg tomatoes was found to be 66.