Which of the following electronic transitions represents an increase in energy in a multi-electron atom? A) 4s _ . 3d B) Sp _. 4d C) 4d _. Ss D) 4f _. 6s E) 5d

The mass in the formula units would be 2.407 x 10^25 g or 2.407 x 10^22 kg

To calculate the number of formula units, we need to use Avogadro's number. Avogadro's number is approximately 6.022 x 10^23 particles per mole.

To calculate the number of moles of FeSO4 in the sample, we need to divide the mass by the molar mass of FeSO4.

= 1 x 55.85 g/mol + 1 x 32.07 g/mol + 4 x 16.00 g/mol

= 151.91 g/mol

Number of moles of FeSO4 = mass of sample / molar mass of FeSO4

= 39.9 g / 151.91 g/mol

= 0.263 mol

Finally, to calculate the number of formula units in the sample, we need to multiply the number of moles by Avogadro's number:

Number of formula units = number of moles x Avogadro's number

= 0.263 mol x 6.022 x 10^23 particles/mol

= 1.583 x 10^23 particles

Therefore, the mass of iron (II) sulfate in formula units is:

Mass in formula units = number of formula units x formula mass

= 1.583 x 10^23 particles x 151.91 g/mol

= 2.407 x 10^25 g or 2.407 x 10^22 kg

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Due to the latent heat of fusion, when a modest amount of heat is added, ice will transform into water without changing the temperature. Therefore, a portion of the ice may melt (but not all of it). The right answer is A.

The sun and stars are both powered by fusion. Fusion is the process by which two hydrogen atoms join, or fuse, to create a helium atom. Throughout the process, a portion of both the hydrogen's energy is converted into energy.

When multiple light nuclei combine by fusion, a heavy nucleus is produced. The process results in the production of energy because as the size of the single nucleus that forms is less than the sum of the masses of the two original nuclei. Every leftover mass is transformed into energy.

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Answer: 37.1 grams of aluminum hydroxide can be produced from the given amounts of aluminum oxide and water

Explanation:

The balanced chemical equation for the synthesis of aluminum hydroxide from aluminum oxide and water is:

Al2O3 + 3H2O -> 2Al(OH)3

From the equation, we can see that 1 mole of Al2O3 reacts with 3 moles of H2O to produce 2 moles of Al(OH)3.

We need to first calculate the number of moles of Al2O3 and H2O we have:

Number of moles of Al2O3 = mass / molar mass = 24.3 g / 101.96 g/mol = 0.238 moles

Number of moles of H2O = mass / molar mass = 82.1 g / 18.02 g/mol = 4.56 moles

From the balanced equation, we know that 1 mole of Al2O3 produces 2 moles of Al(OH)3. So, the number of moles of Al(OH)3 produced will be:

Number of moles of Al(OH)3 = (0.238 mol Al2O3) x (2 mol Al(OH)3 / 1 mol Al2O3) = 0.476 mol Al(OH)3

Finally, we can calculate the mass of Al(OH)3 produced:

Mass of Al(OH)3 = number of moles x molar mass = 0.476 mol x 78.0 g/mol = 37.1 g

Therefore, 37.1 grams of aluminum hydroxide can be produced from the given amounts of aluminum oxide and water.

Answer: fish

Explanation: they are living organisms; they live in water

Answer:

14 moles

Explanation:

This is balanced equation:

BaBr2 + K2SO4 => 2KBr + BaSO4

1 mole of BaBr2 will produce 2 moles of KBr

=> 7 moles of BaBr2 will produce 7x2 = 14 moles of KBr

The absorbance of a sample of the solution is 0.74, which is equivalent to the molar absorptivity of the Co2+(aq) solution, which is 4.48 x 10⁴ L/mol-cm.

Moles are small, burrowing mammals found throughout much of the world. They have a cylindrical body, covered in short, velvety fur, and stocky legs. They have a rounded snout and small eyes, and their fur is usually black, brown, or gray. Moles feed mainly on earthworms, insects, and grubs, and use their powerful front paws to dig extensive tunnel systems in gardens and lawns. Moles are solitary creatures, living and foraging alone, and they are active both day and night.

This can be used to calculate the [Co2+] in the solution.

[Co2+] = Absorbance / (Molar absorptivity x Sample path length)

[Co2+] = 0.74 / (4.48 x 10^4 L/mol-cm x 0.0500 L)

[Co2+] = 0.0164 M

The number of moles of Co2+(aq) in the 50.00 mL solution can be calculated using the following equation:

Moles Co2+ = [Co2+] x Volume

Moles Co2+ = 0.0164 M x 0.050 L

Moles Co2+ = 8.20 x 10⁻³ mol Co2+

The mass percent of Co in the 0.630 g sample of the ore can be calculated using the following equation:

Mass percent Co = (Mass of Co2+ x 100) / Mass of sample

Mass percent Co = (8.20 x 10⁻³mol Co2+ x 58.93 g/mol Co2+) / 0.630 g

Mass percent Co = 5.04%

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The type of reaction shown in the above image is a combustion reaction (option D).

A chemical reaction is a process, typically involving the breaking or making of interatomic bonds, in which one or more substances are changed into others.

Combustion reaction is a process wherein a fuel is combined with oxygen, usually at high temperature, releasing heat.

According to this question, methane reacts with oxygen to produce water and carbondioxide. It can be said that methane undergoes combustion.

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Provide an alternative method for producing that does not employ a Related trades alkylation and can be done in good yields by starting with benzene.

The trade of the carpenter. trades like sewing, carpentry, and ceramics; the craft of producing plays. Weaving, Quilting, Macramé, Lace-making, Knitting, and Tapestry Art.

You would be involved with the planning, chopping, and construction of furniture as a carpenter utilising various types of wood. Working on a job site, at a client's house, or in a shop are all options. They build, set up, and fix wooden furniture, doors, and window frames, among other things.

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The polarity would be determined by the shape of the molecule and the arrangement of the atoms.

To determine the polarity of a polyatomic molecule, you need to consider the polarity of its individual bonds and the molecular geometry of the molecule.

The polarity of a bond is determined by the electronegativity difference between the atoms that form the bond. If the electronegativity difference is large, the bond is polar, and if it is small, the bond is nonpolar.

Once you have determined the polarity of the individual bonds, you can use the molecular geometry of the molecule to determine its overall polarity. To do this, you need to consider the arrangement of the atoms in the molecule and the direction of the polarity of each bond.

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Answer:

To determine the mass of Al that was needed to produce 47.5 L of H2 gas at STP, we can use the stoichiometry of the balanced chemical equation to calculate the amount of Al required.

First, we need to convert the volume of H2 gas at STP to the corresponding amount in moles. At STP, 1 mole of gas occupies 22.4 L of volume. Therefore, 47.5 L of H2 gas is equal to 2.12 moles of H2 gas.

From the balanced chemical equation, we can see that 3 moles of H2 gas are produced for every 2 moles of Al consumed. Therefore, the amount of Al needed to produce 2.12 moles of H2 gas can be calculated as:

2.12 moles H2 x (2 moles Al / 3 moles H2) = 1.41 moles Al

Finally, we can use the molar mass of Al to convert moles of Al to its mass in grams. The molar mass of Al is 26.98 g/mol. Therefore, the mass of Al required can be calculated as:

1.41 moles Al x 26.98 g/mol = 38.1 g Al (rounded to one decimal place)

Therefore, approximately 38.1 grams of Al were needed to react with excess HCl to produce 47.5 L of H2 gas at STP.

Explanation:

In this balanced chemical equation, 2 moles of Al react with 6 moles of HCl to produce 2 moles of AlCl3 and 3 moles of H2. We are given the volume of H2 gas produced at STP and asked to calculate the mass of Al needed to react with excess HCl to produce this amount of H2 gas. To solve this problem, we used stoichiometry to relate the amount of H2 gas produced to the amount of Al required, and then used the molar mass of Al to convert from moles of Al to its mass in grams.

Hope this helps!!

Using an Hypothetical scenario, the Lab Data is given below:

Ruler Measurement for Respirometer:  1

Starting Height of Gas Bubble: 3.2 cm

In a laboratory experiment involving respirometers, it is necessary to measure the initial height of the gas bubble in each respirometer to establish a baseline for further measurements.

To do this, a ruler is used to measure the distance between the top of the gas bubble and the bottom of the respirometer tube. The measurement is recorded in the lab data as the starting height of the gas bubble in respirometer 1, which indicates the initial volume of air in the respirometer.

Therefore, This measurement is important for comparing the amount of oxygen consumed by the organism or plant being studied during the respiration process. By measuring the change in the gas bubble height over time, it is possible to calculate the rate of oxygen consumption and analyze the respiration process of the organism or plant.

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In site-directed mutagenesis experiments, glycine (Gly) is often successfully substituted for valine (Val) because Gly is a smaller and more flexible amino acid.

In a mutagenesis experiment, the smaller size of Gly means it can fit into the space previously occupied by Val without causing any major changes to the protein structure. However, Val is larger and bulkier than Gly, so it is more difficult to substitute Val for Gly without causing any disruptions to the protein structure. This is why Val can rarely substitute for Gly in site-directed mutagenesis experiments.

Additionally, Gly is a nonpolar, neutral amino acid, while Val is a hydrophobic amino acid. This difference in polarity can also affect the protein structure and function, making it more difficult to substitute Val for Gly. Overall, the size, flexibility, and polarity of Gly make it a more versatile amino acid that can be successfully substituted for other amino acids, including Val, in site-directed mutagenesis experiments.

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Answer:

True

Explanation:

Self-absorption occurs when the absorbing species in a sample interacts with other absorbing species in the same sample, leading to an overestimation of the absorbance and a deviation from the linear relationship described by Beer's Law. Therefore, at high analyte concentrations, the linear relationship breaks down and the law becomes nonlinear...

97ml of the concentrated stock solution in milliliters should you use to make 2.5 L of 0.500 M HCL.

We know that molarity can be expressed as,

                 C = n V

              => n = CV

The number of moles HCL required is,

               = 2.5×0.5

               =1.25

We have to find the grams. We get the value  by multiplying by the weight of 1 mole of HCL which is equal to its mass required in grams.

Molar mass of HCL is 34.46.

So the mass required = 1.25×34.46 = 43.07grams

The concentrated form is 37.0% by mass. This means that the 100g of the concentrated solution contains 37.0g of HCL. So now we have to find the volume of concentrated solution will give us the mass we need. We have the 37.0g HCL in 100 g of concentrated solution. 1g is present in the 100/37.0g of concentrated solution.

43.07g is present in 100/37.0×43.07 is 116.40g of concentrated solution.

The density of the solution is 1.20g/ml

We know that, density = mass/volume

=> volume = mass/density

                  = 116.40 / 1.20

                  = 97 ml

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The complete question is,

Hydrochloric acid is usually purchased in concentrated form with a 37.0% HCL concentration by mass and a density of 1.20 g/ml. How much of the concentrated stock solution in milliliters should you use to make 2.5 L of 0.500 M HCL ?

The boiling point of liquid octane when the external pressure is 0.727 atm is 388.9 K.

What do you mean by boiling point?

Boiling point is the temperature at which the vapor pressure of a liquid equals the external pressure acting on the surface of the liquid, and the liquid starts to boil and transform into a gas. At the boiling point, the molecules in the liquid gain enough kinetic energy to overcome the intermolecular forces holding them together, and they escape from the surface of the liquid as gas molecules. The boiling point of a substance is a physical property that is influenced by the strength of the intermolecular forces, as well as external factors such as pressure and atmospheric conditions. The boiling point can be used to identify and characterize different substances.

We can use the Clausius-Clapeyron equation to solve this problem:

ln(P2/P1) = (-ΔHvap/R) x (1/T2 - 1/T1)

where P1 and T1 are the normal boiling point conditions (1 atm and 399 K), P2 is the external pressure (0.727 atm), ΔHvap is the molar heat of vaporization (36.5 kJ/mol), R is the gas constant (8.31 J/mol·K), and we need to solve for T2.

First, let's convert the molar heat of vaporization to J/mol:

ΔHvap = 36.5 kJ/mol = 36,500 J/mol

Now we can plug in the values and solve for T2:

ln(0.727/1) = (-36,500/R) x (1/T2 - 1/399)

ln(0.727) = (-36,500/8.31) x (1/T2 - 1/399)

-0.3176 = -4396.4 x (1/T2 - 0.0025)

1/T2 - 0.0025 = 0.0000723

1/T2 = 0.0025723

T2 = 388.9 K

Therefore, the boiling point of liquid octane when the external pressure is 0.727 atm is 388.9 K.

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Answer:

The balanced chemical equation represents the reaction between phosphorus pentachloride (PCl5) and heat, which produces phosphorus trichloride (PCl3) and chlorine gas (Cl2):

PCl5 + heat → PCl3 + Cl2

Interpreting the equation in terms of the relative number of moles, we can see that 1 mole of PCl5 reacts to produce 1 mole of PCl3 and 1 mole of Cl2.

The given equation is exothermic because it releases heat (92.9 kJ) as a product. This can be seen by the positive sign of the heat term in the equation.

Answer:

32.08

Explanation:

The molar mass of CH4 (methane) is 16.04 g/mol (1 carbon atom with a molar mass of 12.01 g/mol and 4 hydrogen atoms with a molar mass of 1.008 g/mol each).

To find the number of grams in 2 moles of CH4, we can use the following equation:

mass (in grams) = number of moles × molar mass

Substituting the values, we get:

mass = 2 moles × 16.04 g/mol

mass = 32.08 g

Therefore, 2 moles of CH4 contain 32.08 grams of CH4.

Tin metal is mixed with hydrobromic acid, creating a metal within acid situation. Therefore, in this instance, the metal is attempting to replace the hydrogen within it. (For more detail scroll down)

The distance between the hydrogen and halogen atoms increases as the anion's size expands. It gets simpler to release H+ ions from hydracids as we move lower in the halogen group. Therefore, HI>HBr>HCl>HF is the sequence of acid strength.

Since tin is higher up, it will be able displace hydrogen from the acid to create the hydrogen gas. Tin can remove the hydrogen from the solution because it is more dense than hydrogen.

Sn(s) +2 HBr(aq) ----->SnBr2(aq) +H2(g)

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