Which scenario represents exponential growth?
Responses

A water tank is filled at a rate of 222 gallons per minute.
A water tank is filled at a rate of 222 gallons per minute.,

A vine grows 6 inches every week.
A vine grows 6 inches every week.,

A species of fly doubles its population every month during the summer.
A species of fly doubles its population every month during the summer.,

Car Distance increases from a garage as it travels at a constant speed of 25 miles per hour.

The probability of winning the game is the same in both instances, so I will pick a card and put it back before picking the second card.

The probability of an event is a number that indicates how likely the event is to occur and is expressed as a number in the range from 0 and 1, or, using percentage notation, in the range from 0% to 100%.

The  card has  total of 10 possible pairs:

(1,2), (1,3), (1,4), (1,5), (2,3), (2,4), (2,5), (3,4), (3,5), and (4,5).

we have that only (3,5) n adds up to 8,  .

In conclusion, the probability of winning the game is 1/10 or 10%.

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Answer: The correct answer is 8.12%-11.88%.

We can use the formula for a confidence interval for a proportion:

p ± z*SE

where p is the sample proportion, z* is the z-score corresponding to the desired level of confidence (in this case, 1.96 for a 95% confidence interval), and SE is the standard error of the proportion.

SE = sqrt(p*(1-p)/n) = sqrt(0.1*0.9/1015) = 0.0094

Plugging in the values, we get:

0.1 ± 1.96*0.0094

= 0.1 ± 0.0184

So the 95% confidence interval is (0.0816, 0.1184), which is equivalent to 8.12%-11.88%.

Step-by-step explanation:

A reduced echelon matrix in R3 is 1--1 if and only if the homogeneous system Ax = 0 has only the trivial solution if and only if there are no free variables.

The statement is true.

A reduced echelon matrix in R3 represents a linear system of equations that can be solved using Gaussian elimination.

The reduced echelon form of a matrix is obtained by performing row operations that reduce the matrix to a triangular form, with ones on the main diagonal and zeros below it.
If the homogeneous system Ax = 0 has only the trivial solution, it means that the only solution to the system is the zero vector.

In other words, there are no non-zero vectors that satisfy the system.

This is equivalent to saying that the rank of the matrix is equal to the number of columns, or in other words, there are no free variables in the system.
If the system has no free variables, it means that each variable can be expressed as a unique function of the other variables.

This implies that the system has a unique solution, or in other words, the mapping from the system of equations to the solution vector is one-to-one.
If the system is one-to-one, it means that each solution vector corresponds to a unique system of equations.

This implies that there are no redundant equations or variables, and therefore no free variables.

Hence, the homogeneous system Ax = 0 has only the trivial solution.
The statement is true.

A reduced echelon matrix in R3 is 1--1 if and only if the homogeneous system Ax = 0 has only the trivial solution if and only if there are no free variables.

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Answer:

240m

Step-by-step explanation:

You need to find the area of each surface.

FORMULAS

A= L × W

A= 1/2(L × W)

SIDES

Base = 12×6 = 72

Top of triangle = 6×13 = 78

Side of triangle = 5×6 = 30

Triangular side 1 = 1/2(5×12) = 30

Triangular side 2 = 1/2(5×12) 30

Now you need to add all of the surface areas together.

72+78+30+30+30 = 240

Therefore, the surface area of the triangular prism is 240m.

IM SO SORRY IF THIS DOESN'T MAKE ANY SENSE!

Friday's practice session was 3 and 153/896 hours longer than

To find out how much longer Friday's practice session was than Wednesday's, we need to subtract Wednesday's practice time from Friday's practice time.

Friday's practice time is 2 3/7 hours. To make it easier to subtract, we can convert this mixed number to an improper fraction:

2 3/7 = (2 × 7 + 3) / 7 = 17/7

Now we can add this to Wednesday's practice time, which is already in improper fraction form:

1 1/8 = (1 × 8 + 1) / 8 = 9/8

Adding these two fractions, we get:

17/7 + 9/8

To add these fractions, we need to find a common denominator. The smallest number that both 7 and 8 divide into is 56, so we can convert both fractions to have 56 as the denominator:

17/7 × 8/8 = 136/56

9/8 × 7/7 = 63/56

Now we can add the numerators:

136/56 + 63/56 = 199/56

This is the total practice time for both Wednesday and Friday. To find out how much longer Friday's practice session was than Wednesday's, we need to subtract Wednesday's practice time from this total:

199/56 - 9/8

To subtract fractions, we need to find a common denominator again:

199/56 - 9/8 = (199/56) × (8/8) - (9/8) × (7/7) = 1425/448 - 63/56

Now we can subtract the numerators:

1425/448 - 63/56 = 2841/896

This is the difference between Friday's practice time and Wednesday's practice time, expressed as an improper fraction. To convert this back to a mixed number, we can divide the numerator by the denominator:

2841 ÷ 896 = 3 with a remainder of 153

So the answer is Friday's practice session was 3 and 153/896 hours longer than Wednesday's practice session.

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Answer:

330 cubic inches

Step-by-step explanation:

The formula for a rectangular prism is l x w x h

so, let's input the numbers:

2 x 15 x 11

and solve:

330

So, the volume of a rectangular prism is 330 cubic inches

We can see here that the displays that can be used to display the data set of the water districts are:

The data set of the water districts is:

Data refers to any information or facts that can be collected, stored, and analyzed. This can include a wide range of things, such as numbers, text, images, audio recordings, and more.

Data can be used to provide insights, make decisions, and drive actions in a variety of fields, including science, business, medicine, and more. In order to be useful, data needs to be organized, structured, and analyzed in a way that can provide meaningful insights and information.

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The slope of the points in this table is equal to 1.2.

In Mathematics and Geometry, the slope of any straight line can be determined by using this mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Based on the information provided in the table, we can logically deduce the following data points on the line:

Substituting the given points into the slope formula, we have the following;

Slope, m = (3.7 + 1.1)/(1 + 3)

Slope, m = 4.8/4

Slope, m = 1.2.

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Answer:

-5

Step-by-step explanation:

if u graph it, you can see where the y-intercept is.

Therefore , the solution of the given problem of angles comes out to be  

x = 7 is the answer to the equation (16x + 17) = 129° for the variable x.

A skew greatest and smallest walls are located where the roads leading to its ends meet. A crossroads could be where two paths converge. Angle is another outcome of two things interacting. They mimic dihedral shapes more than anything. A two-dimensional curve can be created by arranging two line beams in various ways between their endpoints.

Here,

The steps below can be used to find x in the equation (16x + 17) = 129°:

To find the term with x on one side of the equation, first subtract 17 from both sides of the equation:

=> 16x + 17 - 17 = 129 - 17

=> 16x = 112

Step 2: To find x, multiply both sides of the equation by 16:

=> 16x / 16 = 112 / 16 x = 7

Thus, x = 7 is the answer to the equation (16x + 17) = 129° for the variable x.

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The height of the antenna is approximately 29 meters.

The point of rise is a point that is framed between the even line and the view. An angle of elevation is formed when the line of sight extends upward from the horizontal line.

We should refer to the level of the structure as "h" and the level of the receiving wire "x". Two equations can be created with the help of the tangent function:

Since the elevation angle to the roof is 32 degrees,

tan(32) = h/20, and

tan(43) = (h+x)/20

because the elevation angle to the antenna's peak is 43 degrees.

We can solve for "h" in the first equation by multiplying both sides by 20:

h = 20 tan(32)

We can substitute this expression for "h" into the second equation:

tan(43) = (20 tan(32) + x)/20

Now we can solve for "x":

x = 20 tan(43) - 20 tan(32)

We can then add the height of Isaiah's eyes (1.62 meters) to get the total height of the antenna:

height = x + 1.62

Plugging in the values and using a calculator, we get:

height ≈ 28.7 meters

As a result, the antenna stands about 28.7 meters tall. The answer is 29 meters when rounded to the nearest meter.

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The completed checking account register can be presented as follows;

[tex]\begin{tabular}{ | c | c | l | c | c | c |}\cline{1- 6}Date & Check \# & Transaction Description & Payment (-) & Deposit (+) & Balance \\cline{1-6}\cline{1- 6}06/30 & --- & Beginning Balance & - & \$150 & \$150 \\cline{1- 6}\cline{1- 6}07/01 & 0001 & Rent payment & \$500.00 & - & \$-350 \\cline{1-6}\cline{1- 6}07/01 & --- & Paycheck & --- & \$575 & \$225 \\cline{1-6}\cline{1- 6}07/07 & 0002 & Utilities & \$102.74 & --- & \$122.26 \\cline{1-6}\cline{1- 6}\cline{1- 6}\end{tabular}[/tex]

[tex]\begin{tabular}{ | c | c | l | c | c | c |} \cline{1- 6} \cline{1- 6} Date & Check \# & Transaction Description & Payment (-) & Deposit (+) & Balance \ \cline{1-6} \cline{1- 6} 07/08 & --- & Groceries & \$64.96 & - & \$57.30 \ \cline{1-6} \cline{1- 6} \cline{1-6}07/10 & --- & Babysitting & - & \$42.00 & \$99.30 \ \cline{1-6} \cline{1-6} \cline{1- 6} 07/12 & --- & Movies & \$18.65 & - & \$80.65\ \cline{1-6} \cline{1- 6} 07/14 & --- & Gas & \$31.61 & - & \$49.04 \ \cline{1- 6} \cline{1- 6} \end{tabular}[/tex]

[tex]\begin{tabular}{ | c | c | l | c | c | c |}\cline{1- 6}Date & Check \# & Transaction Description & Payment (-) & Deposit (+) & Balance \ \\\cline{1-6} 07/15 & --- & Paycheck & - & \$575 & \$624.04 \ \cline{1-6} \cline{1-6} 07/19& 0003&Car Insurance&\$78.50&-&\$545.54\cline{1-6} \cline{1-6} 07/22&---&Groceries&\$58.30&-&\$487.24\cline{1-6} \cline{1-6} \end{tabular}[/tex]

[tex]\begin{tabular}{ | c | c | l | c | c | c |}\cline{1-6}Date & Check # & Transaction Description & Payment (-) & Deposit (+) & Balance \ \cline{1-6} \cline{1-6} 07/26&0004&Phone&\$80&-&\$407.24 \cline{1-6}\cline{1-6}07/26 & 0005 & Internet & \$62.75 & - & \$344.49 \ \cline{1-6}\cline{1-6}07/28 & 0006 & Cable TV& \$87.00 & - & \$257.49 \ \cline{1-6}\cline{1-6}07/30 & --- & Gas & \$35.22 & - & \$222.27 \ \cline{1-6}\cline{1-6}\end{tabular}[/tex]

A check register, which may also be known as a cash disbursement journal is a register for recording the transactions done with check and cash, by a business during an accounting period.

Some of the reasons why it is important to examine bank records includes;

1. To ensure accuracy; When bank records are regularly checked, it ensures that transactions using a bank account are recorded accurately

2. To prevent fraud; Bank record review help prevents fraud which includes identity theft, charges which are not authorized, and other forms of fraudulent activity

3. Budget planning and monitoring; Bank record examination ensures visualization of where money in a bank account is going, such as to enable proper planning, and budgeting

4. Resolution of disputes; Disputes such as unauthorized credit or debit on an account can be detected and raised with a bank when a bank account is checked regularly.

5. Maintaining good financial health; Regular examination of bank records help ensures that a bank account is secure and accurate.

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Answer: To expand the expression, we can use the distributive property of multiplication:

(x+3)(x-3)(3x+2)

= (x^2 - 9)(3x+2) // using (a+b)(a-b) = a^2 - b^2

= 3x(x^2) + 2(x^2) - 9(3x) - 18 // using FOIL

= 3x^3 + 2x^2 - 27x - 18

This is the expanded form of the expression.

To simplify further, we can factor out the greatest common factor of the terms:

= 3(x^3 - 9x) + 2(x^2 - 9)

= 3x(x^2 - 9) + 2(x^2 - 9)

= (3x+2)(x^2 - 9)

= (3x+2)(x-3)(x+3)

So, the simplified expression is (3x+2)(x-3)(x+3).

Check the picture below.

btw that picture above is misleading, whenever is 3 longer than 7?  and 2 longer than 7? =)

so let's just get the area of the trapezoidal face and multiply that by the depth of 7.

[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=3 \end{cases}\implies A=\cfrac{3(2+4)}{2}\implies A=9 \\\\[-0.35em] ~\dotfill\\\\ (9)(7)\implies \text{\LARGE 56}\qquad \impliedby volume[/tex]

Answer:

Step-by-step explanation:

1.To arrange all 6 tables in a line, we can use the factorial function which calculates the product of all positive integers up to a given number. We can write:

6! = 6 x 5 x 4 x 3 x 2 x 1 = 720

Therefore, there are 720 ways to arrange all 6 tables in a line.

2.To choose 4 out of the 6 tables, we can use the combination function, which calculates the number of ways to choose k items out of n distinct items, without regard to their order. We can write:

C(6,4) = 6! / (4! x 2!) = (6 x 5 x 4 x 3) / (4 x 3 x 2 x 1) = 15

Therefore, there are 15 ways to choose 4 out of the 6 tables.

There are 720 ways to arrange all 6 tables in a line.

And, there are 15 ways to choose 4 out of the 6 tables.

A combination is a technique to determines the number of possible arrangements in a collection of items where the order of the selection does not matter.

Given that;

Mrs. Smith has 6 activity tables she wants to line up side by side in her classroom.

Now, After arrange all 6 tables in a line, we can use the factorial function which calculates the product of all positive integers up to a given number. We can write:

6! = 6 x 5 x 4 x 3 x 2 x 1 = 720

Hence, there are 720 ways to arrange all 6 tables in a line.

And, For choose 4 out of the 6 tables, we can use the combination function, which calculates the number of ways to choose k items out of n distinct items, without regard to their order. We can write:

⁶C₄ = 6! / (4! x 2!)

= (6 x 5 x 4 x 3) / (4 x 3 x 2 x 1)

= 15

Thus, there are 15 ways to choose 4 out of the 6 tables.

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The value of c for the intersecting secants is derived to be equal to 2 cm

The intersecting secant theorem, also known as the secant-secant theorem, states that when two secant lines intersect outside a circle, the product of the length of one secant segment and its external segment is equal to the product of the length of the other secant segment and its external segment.

c × 18 cm = 3 cm × 12 cm

c18 cm = 36 cm²

c = 36 cm²/18 cm

c = 2 cm

Therefore, the value of c for the intersecting secants is derived to be equal to 2 cm.

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Answer:

c=2cm

Step-by-step explanation:

ab=cd

3•12=18•c

36=18(c)

36/18=2

18(c)=c

c=2

LaTisha's calculation of the distance for the brake anchor placement is incorrect because she didn't take into account the height at which the cable is attached to the starting tree.

The bungee cord is attached 16 feet above the ground, which will also contribute to the length of the cable needed to reach the ending tree.

To correctly calculate the distance, we can use the Pythagorean theorem, considering the height (16 feet) and the length of the stretched bungee cord (24 feet + 18 feet = 42 feet). Let's denote the horizontal distance from the base of the ending tree to the brake anchor as 'd'. We have:

d² + 16² = 42²

Now, we can solve for d:

d² + 256 = 1764

d² = 1508

d = √1508 = 38.8 feet (rounded to one decimal place)

The brake anchor should be placed approximately 38.8 feet from the base of the ending tree.

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The company boss is planning on ordering a gift for each of his employees.

This can be a great way to show appreciation for their hard work and dedication. When boss is planning to choosing gifts, it's important to consider the company culture and values, as well as the individual preferences and interests of each employee.

Some popular gift ideas include personalized items such as mugs or keychains, gift cards to local restaurants or stores, or company branded merchandise such as t-shirts or hats. Whatever the gift may be, it's important to make sure that it's thoughtful and meaningful to show that the boss truly values and appreciates the hard work of his employees.

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Using relevant theorems the measures are:

1. x = 61°; y = 61°    2. x = 12; y = 7   3. x = 5; y = 13

4. x = 97°;    5. x = 6  6. x = 9

1. x = 61° [based on the vertical angles theorem]

y = 61° [based on the corresponding angles theorem]

2. 8x = 96 [based on the corresponding angles theorem]

x = 96/8

x = 12

8x = 11y + 19 [based on the vertical angles theorem]

Plug in the value of x:

8(12) = 11y + 19

96 = 11y + 19

96 - 19 = 11y

77 = 11y

77/11 = y

y = 7

3. 8x + 2 = 42 [based on the alternate interior angles theorem]

8x = 42 - 2

8x = 40

x = 40/8

x = 5

8x + 2 + [6(2y - 3)] = 180 [based on the linear angles theorem]

8(5) + 2 + 12y - 18 = 180

40 + 12y - 16 = 180

24 + 12y = 180

12y = 180 - 24

12y = 156

y = 156/12

y = 13

4. x = 97° [corresponding angles theorem]

5. 8x = 4x + 24 [based on the alternate exterior angles theorem]

8x - 4x = 24

4x = 24

x = 6

6. 11x + 33 + 6x - 6 = 180

17x + 27 = 180

17x = 180 - 27

17x = 153

x = 9

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After solving the given angles we can conclude that ∠4 is (D) 140° respectively.

Two rays that have a common terminal and are referred to as the angle's sides and vertices, respectively, make up an angle in Euclidean geometry.

Two rays can form angles in the plane where they are positioned.

Angles are also produced when two planes intersect.

These are what are known as dihedral angles.

Acute, obtuse, right, straight, reflex and full rotation are examples of basic angles.

So, according to the given image, we know that:

∠ 1 + ∠ 2 = 180

Then,

(3x + 20) + x = 180

4x + 20 = 180

4x = 180 - 20

4x = 160

x = 160 / 4

x = 40

We got that:

∠ 1 = ∠ 4

∠ 2 = ∠ 3

Simply substitute for x and solve if ∠1 = ∠4:

3x + 20 = 3(40) + 20 = 120 + 20 = 140

Therefore, after solving the given angles we can conclude that ∠4 is (D) 140° respectively.

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Answer: the range of surveyed students that agreed with the statement is between 82.3% and 89.7%.

Step-by-step explanation: The present study's margin of error has been estimated as ±3.7%. This indicates that the reported proportion of 86% of students who concurred with the statement may exhibit a margin of error of ±3.7%, encompassing potential values lower or higher than the reported percentage figure.

To ascertain the range of students surveyed who assented to the given statement, it is essential to ascertain the uppermost and lowermost attainable percentages that the factual percentage could reveal.

The maximum attainable percentage is equivalent to the sum of 86% and 3.7%, which yields a total of 89.7%.

The minimum percentage attainable has been calculated to be 82.3% by subtracting 3.7% from the initial value of 86%. Such a formulation adheres to the precision and technical accuracy expected in academic writing.

The equation used to determine the number of days, x, required for the substance to decay to 63 grams is: x ≈ 83.60

To determine the number of days, x, required for a radioactive substance to decay to 63 grams, we can use the exponential decay formula. The equation that represents the decay of a radioactive substance over time is:

N(t) = N₀ * (1/2)^(t/h)

Where:

N(t) is the remaining mass of the substance at time t

N₀ is the initial mass of the substance

t is the time elapsed

h is the half-life of the substance

In this case, we have an initial mass of 475 grams, and we want to find the number of days required for the substance to decay to 63 grams. We can set up the equation as follows:

63 = 475 * (1/2)^(x/20)

To solve for x, we can isolate the exponential term on one side of the equation:

(1/2)^(x/20) = 63/475

Next, we can take the logarithm (base 1/2) of both sides to eliminate the exponential term:

log(base 1/2) [(1/2)^(x/20)] = log(base 1/2) (63/475)

By applying the logarithmic property log(base b) (b^x) = x, the equation simplifies to:

x/20 = log(base 1/2) (63/475)

Finally, we can solve for x by multiplying both sides of the equation by 20:

x = 20 * log(base 1/2) (63/475)

Using a calculator to evaluate log(base 1/2) (63/475) ≈ 4.1802, we find:

x ≈ 20 * 4.1802

x ≈ 83.60

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Answer:

Step-by-step explanation:

Hopefully this is right.

Area = (pi)r²

Which is pi times the the radius squared

The radius is 2, so 2² is 4, So we multiply 3.14, which is pi, by 4.

Multiply 3.14 by 4, and the answer is 12.56, the question says round to the nearest tenth, so the final answer will be 12.6

My math teacher back in 7th grade gave us this sentence to help us memorize the equations.

Cherry Pie Delicious (C=(pi)d), Apple Pie Are Too (A=(pi)r²)

Do the same with the other two questions, and the answer for question two will be 3.14, rounded to the nearest tenth will be 3.1

Question three do the same as well, and the answer will be 660.185, rounded will be 660.2

Hope this helps!

there were 28,800 handshakes that occurred at the meeting.

How to solve the question?

In order to calculate the number of handshakes that occurred, we can use the formula for the sum of the first n-1 positive integers. The reason we use n-1 is because each person shakes hands with n-1 other people (themselves excluded).

The formula is:

(n-1) + (n-2) + (n-3) + ... + 1

where n is the number of people in the group.

In this case, n = 240, so we plug in:

(240-1) + (240-2) + (240-3) + ... + 1

Simplifying:

239 + 238 + 237 + ... + 1

We can see that this is an arithmetic series with a common difference of -1 and a first term of 239. Using the formula for the sum of an arithmetic series, we get:

S = n/2 * (first term + last term)

S = 240/2 * (239 + 1)

S = 240/2 * 240

S = 28,800

Therefore, there were 28,800 handshakes that occurred at the meeting.

It's worth noting that this calculation assumes that each handshake is counted twice (once for each person involved). If we only counted each handshake once, then we would need to divide our final answer by 2, giving us 14,400 handshakes.

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The orthogonal projection of [tex]\vec{V}[/tex] =[−7−9] onto the line L through [26] and the origin is given by the vector [-69/10 -207/10].

What is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

To find the orthogonal projection of a vector  [tex]\vec{V}[/tex]  onto a line L, we need to follow these steps:

Find a vector [tex]\vec{n}[/tex]  that is orthogonal to the line L.

Find the projection of  [tex]\vec{v}[/tex] onto [tex]\vec{n}[/tex] . This projection will be a scalar.

The orthogonal projection of [tex]\vec{v}[/tex]  onto L is the vector that is obtained by multiplying the scalar projection of [tex]\vec{v}[/tex]  onto [tex]\vec{n}[/tex]  by the unit vector in the direction of L.

Let's apply these steps to the problem at hand:

Step 1: Find a vector [tex]\vec{n}[/tex] that is orthogonal to the line L.

The line L passes through [2 6] and the origin, so we can find the direction vector of the line by subtracting the two points:

[tex]\vec{d}[/tex] = [2 6]−[0 0]=[2 6].

To find a vector that is orthogonal to [tex]\vec{d}[/tex], we can take the cross product of  [tex]\vec{d}[/tex]with the vector [0 0 1]:

[tex]\vec{n}[/tex] = [tex]\vec{d}[/tex]  × [0 0 1] = [−6 2 0].

Step 2: Find the projection of  [tex]\vec{v}[/tex]onto [tex]\vec{n}[/tex]  .

The projection of  [tex]\vec{v}[/tex] onto  [tex]\vec{n}[/tex] is given by the formula:

proj n v = ( [tex]\vec{v}[/tex] ·  [tex]\vec{n}[/tex] ) / || [tex]\vec{n}[/tex] ||² *  [tex]\vec{n}[/tex]

where · denotes the dot product and ||  [tex]\vec{n}[/tex] || is the magnitude of  [tex]\vec{n}[/tex] .

Substituting the values we have:

proj n v = ([-7 -9] · [-6 2 0]) / ||[-6 2 0]||² * [-6 2 0]

= (-54 + (-18)) / (36 + 4) × [-6 2 0]

= -72/40 × [-6 2 0]

= [-27 9 0]/5

Step 3: The orthogonal projection [tex]\vec{v}[/tex] onto L is given by:

proj L v = (proj n v · [tex]\vec{d}[/tex]  / || [tex]\vec{d}[/tex]  ||²) × [tex]\vec{d}[/tex]  / || [tex]\vec{d}[/tex]  ||

where || [tex]\vec{d}[/tex] || is the magnitude of  [tex]\vec{d}[/tex]  .

Substituting the values we have:

proj L v = ([−27 9 0]/5 · [2 6]/(2² + 6²)) * [2 6]/(2² + 6²)

= -207/40 * [2 6]

= [-69/10 -207/10]

Therefore, the orthogonal projection of  [tex]\vec{v}[/tex] =[−7−9] onto the line L through [26] and the origin is given by the vector [-69/10 -207/10].

To learn more about Algebra the given link:

https://brainly.com/question/24875240

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Answer:

57 seven drinks sold each day 200 drinks a week

Step-by-step explanation:

Answer:

The process is below and the answer is D.

Step-by-step explanation:

[tex]perimeter \: = 2(l + b) \\ = 2((x + 1)cm + xcm) \\ = 2(x + 1 + x) \\ = 2(2x + 1)[/tex]

[tex](4x + 2)cm[/tex]

I hope it helped you

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It seems like the answer could be $6,500, but I prefer to wait for a professional tbh☹.