Which type of cell is associated with the statements below? Fill in the blank with either (voltaic cell, electrolytic cell, both).
Non-spontaneous reaction occurs:
Spontaneous reaction occurs:
Oxidation occurs at anode:
Electrolyte supports electron flow:

Answer:

terminal

Explanation:

When a hydrogen atom is part of a molecular structure, it is always a terminal atom.

re write the question.

Explanation:

it seems incomplete.

Explanation:

One of the most fascinating chemical experiments is the reaction between silver nitrate and copper wire in water. Characterised by fractal-like precipitates, this experiment is a stunning example of a simple redox reaction.

Copper reacting with silver nitrate is a chemical change. In a chemical change, new substances are formed with different chemical properties.

Copper (Cu) is a metal, and silver nitrate is a compound made of silver (Ag), nitrogen (N), and oxygen (O).When copper is added to silver nitrate, a reaction occurs. The copper atoms react with the silver nitrate molecules, resulting in the formation of new substances.

The reaction produces copper nitrate  and silver (Ag) as products.Copper nitrate is a compound formed by the combination of copper, nitrogen, and oxygen, while silver remains unchanged.

The color of the solution changes, indicating a chemical reaction has taken place. Copper nitrate is usually a blue-green color, while silver is a metallic silver color.The chemical properties of the substances involved in the reaction are altered. Copper, being a metal, is malleable and conducts electricity, whereas copper nitrate is a compound and does not possess these properties.

Thus, the reaction between copper and silver nitrate is a chemical change because new substances with different properties are formed.

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Answer:

6.21 moles O

Explanation:

To find the moles of oxygen, you need to (1) convert grams Mn(ClO₄)₄ to moles Mn(ClO₄)₄ (via molar mass) and then (2) convert moles Mn(ClO₄)₄ to moles O (via mole-to-mole ratio from formula subscripts). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.

Molar Mass (Mn(ClO₄)₄): 452.74 g/mol

1 Mn(ClO₄)₄ = 1 Mn and 4 Cl and 16 O

175.7 g Mn(ClO₄)₄           1 mole                   16 moles O
---------------------------  x  -------------------  x  ---------------------------  =  6.21 moles O
                                       452.74 g            1 mole Mn(ClO₄)₄

18.06 ₓ [tex]10^{23}[/tex] molecules in 3 mol of carbon dioxide (CO2).

The proportionality factor that connects the quantity of substance in a sample to the number of constituent particles in that sample is called the Avogadro constant. The reciprocal mole, which is its SI unit, is specified precisely as NA 6.02214076 × [tex]10^{23}[/tex] [tex]mol^{-1}[/tex]. It bears Amedeo Avogadro's name, an Italian scientist.

When dealing with very big quantities, chemistry uses Avogadro's number. It serves as the foundation for the mole, a unit of measurement that makes converting between moles, mass, and the number of molecules simple. The quantity, for instance, can be used to determine how many water molecules make up a single snowflake.

1 Mole is 6.02ₓ [tex]10^{23}[/tex] molecules.

Therefore 3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =3(6.02ₓ [tex]10^{23}[/tex])

3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =18.06 ₓ [tex]10^{23}[/tex]molecules of [tex]CO_{2}[/tex].

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Answer:

Yes

Explanation:

Answer:it act as a precursor to proteins

Explanation:

Answer:

1.81 x 10²⁴ atoms He

Explanation:

You can find the amount of atoms by multiplying the given moles by Avogadro's Number. This number represents the amount of atoms per 1 mole. It is important to arrange the ratio in a way that allows for the cancellation of units.

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

3 moles He           6.022 x 10²³ atoms
--------------------  x  --------------------------------  =  1.81 x 10²⁴ atoms He
                                       1 mole

It is correct to state that Amines are suitable for preparing buffers are often synthesized by treating ammonia with epoxides. The relative structures of compound B are attached accordingly.

Amine is a family of basic chemical compounds formed by replacing hydrogen with one or more monovalent hydrocarbon radicals.

Apart from medications and pharmaceuticals, amines are employed in the production of azo-dyes and nylon.

They are commonly employed in the development of crop protection, pharmaceutical, and water purification chemicals. They are also used in personal care products.

Ethanol amines are the most widely utilized form of amine on the global market.

It should be noted that ammonia attacks epoxides at the least substituted carbon to produce (A.)

The generated product is then made to react with another epoxide, resulting in the synthesis of successive products.

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The 0.25 volume in liters of 1.0 M [tex]K_{2}CO_{3}[/tex] solution is required to provide 0.5 moles of [tex]K[/tex](aq).

Calculation,

The Potassium carbonate dissolves as follows:

[tex]K_{2}CO_{3}(s)[/tex] → [tex]2K(aq) +[/tex][tex]CO_{3}^{-2} (aq)[/tex]

The mole ratio is 1: 2

It means, the 1 mole [tex]K_{2}CO_{3}[/tex] required to form 2 mole of [tex]K[/tex](aq).

To provide 0.5 mole of [tex]K[/tex](aq) = 1 mole ×0.5 mole /2 mole required by [tex]K_{2}CO_{3}[/tex].

To provide 0.5 mole of [tex]K[/tex](aq) ,0.25 mole required by [tex]K_{2}CO_{3}[/tex].

The morality of  [tex]K_{2}CO_{3}[/tex] = 1 M = number of moles / volume in lit

The morality of  [tex]K_{2}CO_{3}[/tex] =   1 M = 0.25 mole/ volume in lit

Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit

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Answer:

4.48 dm^3

Explanation:

As given in the problem, the conversion factor for the molar volume of all gases is 22.4 dm^3/mole at STP.  A mole of all ideal gases will occupy 22.4 liters (dm^3).  Calculate the moles of hydrogen contained in 0.4 grams of the gas by dividing the mass by the molar mass of H2.  H2 has a molar mass of 2 grams/mole.

 (0.4 g)/(2 grams/mole) = 0.2 moles H2

(0.2 moles H2 at STP)*(22.4 dm^3/mole at STP) = 4.48 dm^3  (4.48 liters at STP)

The name of the molecule above is Ethene

Organic compounds can be defined as compounds containing carbon and hydrogen.

Some classes of organic compounds are:

So therefore, he name of the molecule above is Ethene

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The oxidation number is often referred to as the oxidation state.

The number of electron/electrons which completely transferred and induced charged on an atom is called oxidation state of an atom. It is also describe as the number that is allocated to elements in a chemical combination. The number of electron that atoms in a molecule can share while forming chemical bonds with other atoms of a different elements. The oxidation number of the monoatomic (composed by atom) ion is the same as the charge of the ion.

The primary distinction between oxidation number versus oxidation state would be that the former refers to the charge that would be placed on the central atom of a coordination complex if every one of the connections around it were ionic bonds, while the latter relates to the number of electrons that an atom could either receive, lose, or share with some other atom.

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The solubility of lead(II) chloride is 0.45 g/100 mL of solution. The value of  [tex]K_{sp}[/tex] of [tex]PbCl_{2}[/tex]  is 1.7×[tex]10^{-5}[/tex] .

So, option C is correct one.

Calculation,

Number of moles of [tex]PbCl_{2}[/tex]  = mass/molar mass = 0.45/278.1 = 1.618×[tex]10^{-3}[/tex] moles

Concentration of [tex]Pb^{+2}[/tex] and [tex]Cl^{-}[/tex] ion

Molarity  of [tex]Pb^{+2}[/tex] = Number of moles of solute /volume in lit

Molarity  of [tex]Pb^{+2}[/tex] = 1.618×[tex]10^{-3}[/tex] moles /0.1 lit = 0.0162 M

[tex]PbCl_{2}[/tex] →  [tex]Pb^{+2}[/tex] +  2[tex]Cl^{-}[/tex]

For certain amount of  [tex]Pb^{+2}[/tex] , twice this amount of  [tex]Cl^{-}[/tex] ion formed.

The concentration of   [tex]Cl^{-}[/tex] ion formed = 2× 0.0162 M = 0.0324 M

Now,

The solubility of lead(II) chloride of solution = 0.45 g/100 mL

[tex]K_{sp}[/tex] of [tex]PbCl_{2}[/tex] = [ [tex]Pb^{+2}[/tex] ][tex][Cl^{-}]^{2}[/tex] = 0.0162 ×[tex][0.0324 ]^{2}[/tex] =  1.7×[tex]10^{-5}[/tex] .

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Answer:

0.375 moles Al

Explanation:

To find the moles Al, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass) and then (2) convert moles AlCl₃ to moles Al (via mole-to-mole ratio from equation coefficients). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (50.0 g).

Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)

Molar Mass (AlCl₃): 133.341 g/mol

2 Al(s) + 3 CuCl₂(aq) -----> 3 Cu(s) + 2 AlCl₃(aq)

50.0 g AlCl₃           1 mole                 2 moles Al
--------------------  x  ------------------  x  -----------------------  =  0.375 moles Al
                               133.341 g           2 moles AlCl₃

The substances composed of atoms that all have the same number of protons are called elements.

What are the names of substances made up of atoms with the same number of protons?

The substances which are made up of atoms with the same numbers of protons are called as element.

An element is a substance with the same number of protons in all of its atoms. Gold is an example of an element. A pure gold bar is made up of only one element, gold.

All matter is composed of substances known as elements, which have distinct chemical and physical properties and cannot be broken down into other substances via ordinary chemical reactions.

Gold, for example, is an element, as is carbon. Only 92 of the 118 elements occur naturally. The remaining elements are unstable because they were only created in laboratories.

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Empirical formula mass

[tex]\\ \tt{:}\dashrightarrow 12+2+16[/tex]

[tex]\\ \tt{:}\dashrightarrow 30g/mol[/tex]

n:-

[tex]\\ \tt{:}\dashrightarrow \dfrac{Molecular\:mass}{Empirical\:mass}[/tex]

[tex]\\ \tt{:}\dashrightarrow \dfrac{90}{30}[/tex]

[tex]\\ \tt{:}\dashrightarrow 3[/tex]

Molecular formula

[tex]\\ \tt{:}\dashrightarrow n\times Empirical\: formula [/tex]

[tex]\\ \tt{:}\dashrightarrow 3(CH_2O)[/tex]

[tex]\\ \tt{:}\dashrightarrow C_3H_6O_3[/tex]

Half-life in geology is defined as the time it takes for a radioactive material or element to decay half its original quantity into a daughter radiogenic isotope.

From the radioactive elements listed the Carbon-14 would be most preferable for dating a specimen.

Radiometric dating is defined as the process that is used by scientists to calculate the age of geologic materials.

From the data given in the table above, the radioactive element with the most recent half-life is carbon-14 being 5,730 years.

The uses os Carbon-14 include the following:

The carbon-14 is preferably used for dating specimen because it is the most stable and accurately dates archaeological artifacts.

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Answer:

1ppm = 1 mg/kg

60460 = 0.13

0.13

Explanation:

Answer:0.013 ppb

Explanation:

One way in which God showed precision in his creation was his mighty love on the he has on his creation

The book of John made us to know that: For God do love the world that he gave his only begotten son that whosoever believeth in him shall not perish but have everlasting life.

Creations is the art of producing or making something out of something

So therefore, one way in which God showed precision in his creation was his mighty love on the he has on his creation

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In the reaction catalyzed by the pyruvate dehydrogenase complex, the two carbons constituting the acetyl group are oxidized by NAD+ while attached to the lipoamide.

A multienzyme complex called pyruvate dehydrogenase (PDH) catalyzes the oxidative conversion of pyruvate into acetyl coenzyme A (CoA), carbon dioxide (CO2), and reducing equivalents in the form of NADH.

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At a particular temperature, the solubility of He in water is 0.060 M when the partial pressure is 0.90 atm. 2.27 atm is the partial pressure of Kr would give a solubility of 0.150 M.

Solution:

The solubility of gas is directly proportional to partial pressure. It is expressed as:

S = [tex]K_ h \times P _g_a_s[/tex]

where, S = Solubility of gas

[tex]K_h[/tex] = Henry's Law constant

[tex]P_g_a_s[/tex] = Partial pressure of gas

Now, put the values in above expression we get

0.060M = [tex]K_h[/tex] × 0.9 atm

   [tex]K_h[/tex] =  = 0.066 M/atm

Now we have to find the partial pressure of He

0.150 M = 0.066 M/atm × [tex]P_g_a_s[/tex]

[tex]P_g_a_s[/tex] = 2.27 atm

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Dalton's law

States that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture.

Dalton's law, which states that a gas mixture's overall pressure is equal to the sum of its component gases' partial pressures. The pressure that each gas would produce if it occupied the same volume of the mixture by itself at the same temperature is known as the partial pressure.

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Answer:

1120 mm Hg

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Yes, it will be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions because it is negative.

This is a substance which speeds up the rate of a chemical reaction by lowering the activation energy.

ΔG being negative indicates a a slow reaction which is why a catalyst under standard conditions should be used.

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The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs

A substance's half-life is the amount of time it takes for half of it to decompose.

Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.

When n half-lives have passed, the formula for estimating the amount still left is:-

A=A°/2^n

where,

A=initial amount

A°=remaining amount

n=t/t_{1/2}

A=150/2^t/30yrs

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Answer:

3 Electron shell/orbit

Explanation:

the number of shell an element has is what determines the period of that element.

Considering the definition of empirical formula, the empirical formula is C₃H₈.

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

In this case, in first place you know the percent composition:

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 81.71 grams of carbon and 18.29 grams of hydrogen H.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

To express this relationship in the form of simple integers, it is necessary to multiply by a simple number to achieve this:

Therefore the C: H mole ratio is 3: 8

Finally, the empirical formula is C₃H₈.

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Dry powder extinguishers

They are for Class D or combustible metal fires, only. They are ineffective on all other classes of fires.

Extinguishing Agent means a source of extinguishment in which to quickly and effectively suppress the fire.

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A solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL. Details about weights per volume can be found below.

Weights per volume is a unit for measuring density of a substance. It can be converted to g/mL using the following expression:

w/v% = g/100mL

According to this question, a solution contains 7.8% W/V ethanol. The equivalent of this in g/mL is as follows:

7.8% W/V = 7.8g/100mL

= 0.078g/mL

Therefore, a solution that contains 7.8% W/V ethanol is equivalent to 0.078g/mL.

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