You are a musician and want to know the frequency of a guitar string you measure the length of the string to be 0.6meters and the tension in the string to be 0.6 newton if the mass of the string is 0.01 kg what is the frequency of string? Hertz (Hz) length meter (m) tension newton(N)mass(M) kilograms kg

Answers

Answer 1

The frequency of the guitar string is approximately 2.325 Hz.

To calculate the frequency of a guitar string, we can use the formula for the fundamental frequency of a vibrating string:

f = (1/2L) * sqrt(T/m)

Where:

f is the frequency,

L is the length of the string,

T is the tension in the string, and

m is the mass of the string.

Given:

Length of the string (L) = 0.6 meters

Tension in the string (T) = 0.6 newtons

Mass of the string (m) = 0.01 kilograms

Substituting the values into the formula:

f = (1/2 * 0.6) * sqrt(0.6 / 0.01)

f = 0.3 * sqrt(60)

To simplify the calculation, let's approximate the square root of 60 as 7.75:

f ≈ 0.3 * 7.75

f ≈ 2.325

This means that the string vibrates 2.325 times per second. The frequency of a vibrating string determines the pitch of the sound produced. In this case, the calculated frequency represents the fundamental frequency of the string, which is the lowest pitch that can be produced by the string when played without any harmonics or overtones.

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Related Questions

During a race on level ground, Andrea runs with an average speed of 6.02 m/s to the east. What is Andrea's displacement after 137s?
Question Blank 1 of 1
type your answer...

Answers

Andrea's displacement after 137 seconds is 824.74 meters to the east. This means that she has moved a distance of 824.74 meters in the eastward direction from her starting position.

Andrea's displacement after 137 seconds can be calculated by multiplying her average speed by the time traveled. Since she is running to the east, her displacement will be positive.

Displacement is given by the formula: Displacement = Average speed × Time

Substituting the given values, we have: Displacement = 6.02 m/s × 137 s

Calculating this expression, we find: Displacement = 824.74 m Displacement is a vector quantity that not only represents the magnitude (distance) but also the direction of motion. In this case, Andrea's displacement is positive because she ran to the east, indicating a displacement in the positive x-direction.

It's important to note that displacement is different from distance. While distance refers to the total path traveled, displacement only considers the change in position from the starting point to the final position.

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In the diagram, q1 = +2.00 x 10⁻⁵ C, q2 = +3.80 x 10⁻⁶ C, and q3 = +5.30 x 10⁻⁵ C. What is the electric potential energy, Ue, for charge q1? Include the correct sign (+ or -)​

Answers

The electric potential energy, Ue, for charge q₁ is -1.88 x 10⁻¹¹ J.

How to find electric potential energy?

The electric potential energy between two charges is given by the following equation:

Ue = k × q₁ × q₂ / r

where:

Ue is the electric potential energy in Joules

k is the Coulomb constant, which is equal to 8.988 x 10⁹ N m² C⁻²

q₁ and q₂ are the charges in Coulombs

r is the distance between the charges in meters

In this case:

Ue = ?

k = 8.988 x 10⁹ N m² C⁻²

q₁ = +2.00 x 10⁻⁵ C

q₂ = +3.80 x 10⁻⁶ C

r = 0.10 m

\Substituting these values into the equation:

Ue = 8.988 x 10⁹ N m² C⁻² × (2.00 x 10⁻⁵ C) × (3.80 x 10⁻⁶ C) / 0.10 m

Ue = -1.88 x 10⁻¹¹ J

Therefore, the electric potential energy for charge q1 is -1.88 x 10⁻¹¹ J. The negative sign indicates that the potential energy is attractive.

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The air temperature is 25∘C, and an air column carries a standing sound wave at a frequency of 340Hz . What is the length of the air column, which is closed at one end, if you want to hear the third harmonic?

Answers

To hear the third harmonic of a standing sound wave at a frequency of 340 Hz, the length of the closed air column should be approximately 4.55 meters.

The formula for the length of a closed-closed air column in resonance can be used to calculate the length of the air column necessary to hear the third harmonic of a standing sound wave:

L = (4/n) * v/f

Where L represents the height of the air column, n the harmonic number, v the air speed, and f the desired harmonic frequency.

Given:

25°C (298 K) is the ambient temperature.

The required harmonic's (f) frequency is 340 Hz.

(n) = 3 for the harmonic number

At room temperature, the speed of sound in air can be roughly calculated to be 343 m/s. It must be adjusted for the current air temperature because the speed of sound is temperature-dependent.

Using the equation: v = 331.5 + 0.6 * T, where T is the Celsius value of the air temperature.

If T = 25 °C is used in the formula:

v = 331.5 + 0.6 * 25 v ≈ 331.5 + 15 v ≈ 346.5 m/s

We can now determine how long the air column is:

4.55 metres for L = (4/3) * 346.5 / 340 L.

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If a nucleus had a diameter of 8.0 fm, what would be its expected mass, in atomic mass units?

Answers

The atomic mass unit is 37.04unit

The size of a nexus is  generally expressed in terms of its compass, not periphery. The compass of a  nexus is related to its mass number( A) by a general empirical formula known as the" nuclear compass formula"  

 [tex]R = R_o(A\frac{1}{3}) ,[/tex]  

where R is the compass of the  nexus,

R ₀ is a constant(  roughly1.2 fm),

and A is the mass number.  

To determine the anticipated mass of the  nexus in  infinitesimal mass units( u), we can use the following equation  

Mass =  A × mass of a single nucleon,  

where the mass of a single nucleon is  roughly 1  infinitesimal mass unit( 1 u).  

Given that the periphery of the  nexus is8.0 fm, we can calculate the compass  

R = [tex]\frac{8.0fm}{4.0}[/tex]= 4.0 fm.  

Now, we can use the nuclear compass formula to estimate the mass number( A)  

fm =  R ₀ A(1/3).  

By rearranging the formula and  working for A,

we have   A = ((4.0 fm/ R ₀))  

Substituting the value of R ₀(  roughly1.2 fm) into the equation  

A = ((4.0 fm/1.2 fm))  

A ≈(3.33) 3

A ≈37.04.  

Thus, the anticipated mass of the  nexus in infinitesimal mass units would be  roughly37.04u.

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A science teacher asks her class to compare the way in which heat is transferred to water in a pond as opposed to soil at the edge of the pond. Which of the following investigations will help them make this comparison?

Answers

The investigation" Place soil in the bottom of a container and water on top, place it in the sun, and measure the temperature of the container" will help them make this comparison.

How to carryout this investigation?

A starting point for conducting a comparative analysis is to fill a container with soil followed by pouring water on top.

The next step involves placing it under sun rays while simultaneously recording its temperature. Post that, we need to separate the sand from water to rapidly gauge any change in temperature.

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Complete question:

A science teacher asks her class to compare the way in which heat is transferred to water in a pond as opposed to the soil at the edge of the pond. Which of the following investigations will help them make this comparison?

a. Mix water and soil in a container, place it in the sun, and measure the temperature of the container.

b. Place soil and water in separate containers, place them indoors, and monitor the temperature of the containers.

c. Place soil and water in separate containers, place them in the sun, and monitor the temperatures of each container.

d. Place soil in the bottom of a container and water on top, place it in the sun, and measure the temperature of the container.

To determine the weight of the capacitor the z components of Cable 1 and 2 (both
positive) are added together.
True
O False

Answers

The statement "To determine the weight of the capacitor the z components of Cable 1 and 2 (both positive) are added together" is false.

How to determine the weight of the capacitor?

To calculate precisely how much pressure a particular capacitor is enduring, it is necessary to take into account both Cable 1 and Cable 2's corresponding z components in combination.

We then proceed by multiplying that number using acceleration caused by gravity in order to ascertain its overall weight.

The force on the capacitor is calculated as follows:

W = F * g

Where;

W is the weight of the capacitor

F is the force on the capacitor

g is the acceleration due to gravity

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5. Where did the blood come from BEFORE it entered the Right atrium ​

Answers

Answer: superior vena cava (SVC) and inferior vena cava (IVC),

Explanation:

Oxygenated blood returns from the body to the heart through the superior vena cava and the inferior vena cave

What wavelength of light (in nm) is associated with a frequency of 5.72 E14 Hz

Answers

Answer: 520 nm; 5.77 × 1014 Hz; 3.82 × 10−19 J

A block of density 900kg/m3 floats face down in a fluid of density 1300kg/m3. The block has a height of 5.5cm.
(a) By what depth is the block submerged?
(b) if the block is held fully submerged and then released, what is the magnitude of its acceleration?

Answers

a)  the block is submerged to a depth of approximately 0.0377 meters.

b) the magnitude of the block's acceleration when released fully submerged is approximately 0.444 m/s^2.

(a) To determine the depth to which the block is submerged, we can use Archimedes' principle, which states that the buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced by the object.

The weight of the fluid displaced by the block is equal to the weight of the block itself. The weight of the block can be calculated using its volume and density, where weight = density × volume × acceleration due to gravity (W = ρVg).

Let's assume the height of the block that is submerged in the fluid is h.

The volume of the block can be calculated as V = area × height, where the area is given by the product of the length and width of the block.

The weight of the block is W = ρ_block × V × g, where ρ_block is the density of the block and g is the acceleration due to gravity.

The weight of the fluid displaced is equal to the weight of the block, so we can set up the equation:

W = ρ_fluid × V_submerged × g

where ρ_fluid is the density of the fluid and V_submerged is the volume of the block submerged in the fluid.

Since the volume of the block is equal to the volume submerged, we can substitute V_submerged with A × h, where A is the area of the block.

ρ_block × A × h × g = ρ_fluid × A × h × g

The area and acceleration due to gravity cancel out, and we're left with:

ρ_block × h_block = ρ_fluid × h_submerged

Solving for h_submerged:

h_submerged = (ρ_block / ρ_fluid) × h_block

Plugging in the given values:

ρ_block = 900 kg/m^3

ρ_fluid = 1300 kg/m^3

h_block = 5.5 cm = 0.055 m

h_submerged = (900 / 1300) × 0.055 = 0.0377 m

Therefore, the block is submerged to a depth of approximately 0.0377 meters.

(b) When the block is fully submerged, it experiences an upward buoyant force equal to the weight of the fluid it displaces. When released, the block accelerates upward until the buoyant force matches its weight, resulting in a state of equilibrium.

The magnitude of the acceleration can be determined using Newton's second law, where the net force acting on the block is equal to its mass multiplied by its acceleration (F_net = m × a).

The net force acting on the block is the difference between its weight (mg) and the buoyant force (ρ_fluid × V_submerged × g).

The buoyant force is equal to the weight of the fluid displaced, which is given by the density of the fluid multiplied by the volume of the block submerged.

The mass of the block is equal to its volume multiplied by its density (m = ρ_block × V_block).

The equation for the net force becomes:

F_net = m × a

mg - ρ_fluid × V_submerged × g = ρ_block × V_block × a

The volume of the block is equal to the area of the block multiplied by the height submerged (V_block = A × h_submerged).

Substituting the values and simplifying:

900 × A × h_submerged × g - 1300 × A × h_submerged × g = 900 × A × h_submerged × a

The area of the block (A) and acceleration due to gravity (g) cancel out, and we're left with:

900 - 1300 = 900 × a

Simplifying further:

-400 = 900 × a

Dividing both sides by 900:

a = -400 / 900 = -0.444 m/s^2

The magnitude of the acceleration is 0.444 m/s^2.

Note that the negative sign indicates that the acceleration is directed opposite to the downward force of gravity, which is expected as the block is moving upward towards equilibrium.

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A circuit has a 3 cell battery in series each single cell has 1.5 volts and 2 resistors in parallel each with 8 ohms of resistance. Calculate the current in circuit.

Answers

Answer:

3÷5 1.2÷2 ×8i I think that is the best

How can we break an atom

Answers

Answer:

Breaking an atom refers to a process called nuclear fission, which involves splitting the nucleus of an atom into smaller nuclei. This is typically accomplished by bombarding the atom with a neutron, which causes the nucleus to become unstable and split apart, releasing a large amount of energy in the process. This energy is what is harnessed in nuclear power plants to generate electricity. However, it should be noted that nuclear fission can also have potentially harmful effects, such as the release of radioactive material and the potential for nuclear accidents.

determine the height of liquid A if the density is 1.20g/cm cubic

Answers

More details are required in order to calculate liquid A's height. Without knowing the volume or mass of the liquid, the density alone is not enough to determine the height. But if we assume that liquid A's density stays constant throughout and we have a known-volume container filled with liquid A, we may apply the following formula:

Height = Volume / Base Area

Assume liquid A has a volume of 100 cm3. To adjust the formula for height, we may do the following:

Height = Volume / Base Area = 100 cm³ / Base Area

If the base area is known, we may use the formula to get the height by substituting the base area. Otherwise, it is impossible to calculate the height of liquid A without more details.

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unit to measure the weight
We use
of lighter objective

Answers

Answer:

Pounds

Explanation:

the unit of measurement for weight is pounds

Very Good! Has your understanding widened about the different physical fitness tests involved in our daily lives after the discussion? Let us see how much you have learned in this module. Directions: Base on your Physical Fitness Tests conducted, state your understanding about your results by completing the phrases below. Write your answers in your activity notebook. Activity 1: Fill in the Gap 1. In this lesson, I have learned that ______________________________________________________________ ______________________________________________________________ 2. Base on the results of my physical fitness tests, I have found out that I am capable of doing ________________________________________________ and needs improvement in ________________________________________ 3. The health-related fitness component that I like the most is_____________________because_________________________________ ______________________________________________________________ 4. As a student, I will promise ________________________________________ ____________________________________________________________

Answers

In this lesson, I have learned that physical fitness tests are essential in assessing and measuring various aspects of our physical well-being.

They provide valuable information about our current fitness levels, strengths, and areas that require improvement. These tests help in determining our overall health, identifying potential health risks, and developing personalized fitness programs.

Based on the results of my physical fitness tests, I have found out that I am capable of doing a moderate level of cardiovascular endurance exercises, such as running or cycling, and I have good flexibility.

However, I need improvement in my muscular strength and endurance, as well as my agility and coordination. These areas require more attention and targeted exercises to enhance my overall physical fitness.

The health-related fitness component that I like the most is cardiovascular endurance because it allows me to engage in activities that raise my heart rate and improve the efficiency of my cardiovascular system.

It not only enhances my overall stamina but also has numerous health benefits, such as reducing the risk of cardiovascular diseases and improving mental well-being.As a student, I will promise to incorporate regular physical activity into my daily routine.

I understand that physical fitness is crucial for my overall well-being and academic performance. I will make a conscious effort to engage in activities that target my areas of improvement, such as strength training exercises and agility drills.

Additionally, I will strive to maintain a balanced and nutritious diet to support my physical fitness goals. By prioritizing my health and fitness, I aim to lead a more active and fulfilling lifestyle while achieving my academic objectives.

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Look at the equation below. This is an example of
a. double replacement
b. Synthesis
c. decomposition
d. Combustion

AB+CDAC + BD (2.2.5)

Answers

The equation AB + CD -> AC + BD represents a double replacement reaction, also known as a metathesis reaction. In a double replacement reaction, the cations and anions of two different compounds switch places, resulting in two new compounds. In this case, the cations A and C switch places, as do the cations B and D.

Crew members attempt to escape from a damaged submarine 110m below the surface. What force must be applied to a pop-out hatch, which is 1.7m by 0.8m, to push it out at that depth? Assume the density of the ocean water is 1024kg/m3 and the internal air pressure is at 1atm

Answers

The pressure differential between the inside and outside of the submarine must be taken into account in order to determine the force needed to push out the pop-out hatch at a depth of 110 metres below the surface. The following formula may be used to calculate the force:

Force = Pressure Difference × Area

The difference between the interior air pressure and the exterior water pressure is known as the pressure differential. The external water pressure at a depth of 110 metres may be computed as follows:

Water Pressure = Density of Water × Gravitational Acceleration × Depth

On putting all the given values we get

Water Pressure = 1024 kg/m³ × 9.8 m/s² × 110 m = 1,174,784 Pa

Given that the internal air pressure is 1 atm, or 101,325 Pa, the pressure differential is as follows:

Pressure Difference = Water Pressure - Internal Air Pressure = 1,174,784 Pa - 101,325 Pa = 1,073,459 Pa

force is calculated as,

Force = Pressure Difference × Area = 1,073,459 Pa × (1.7 m × 0.8 m) = 1,375,899 N

Hence, a force of approximately 1,375,899 Newtons must be applied to the pop-out hatch to push it out at a depth of 110m below the surface.

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what is the lewis structure for 4,5,9, and 10?

Answers

Lewis's structure is defined as the structure of atoms and their positions within the molecular representation. It is the simplest structure of the valence shell representation of electrons of the molecule.

From the given,

Lewis structure of the carbonate ion has two single bonds to negative oxygen atoms and one short double bond to neutral oxygen. The carbon atom was surrounded by three oxygen atoms.

Lewis structure of ammonium ion, There are four sigma bonds of around the nitrogen atom. Nitrogen is surrounded by hydrogen bonds. The shape of NH₄⁺ is tetrahedral shape.

Lewis structure of boron trifluoride is, BF₃ has one boron atom and three fluoride atoms. The valency of fluorine is 7 and one electron is involved in bond formation with boron, leaving it with three lone pairs to form an octet. The boron atom has three electrons and involves bonding.

Lewis structure of bicarbonate ion, the bicarbonate ion has 24 electrons and 12 electron pairs. Bonding electrons involves 10 electrons and hence it forms 7 lone pairs or 14 electrons. The oxygen atom has 3 lone pairs that forms double-bonded oxygen.

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1.1 Consider two vessels (A & B) of equal volume separated by a valve. Vessel A contains CH4 (g) at 5.0 °C and 1.5 atm. while vessel B contains CO2 (g) at 25 °C and 0.6 atm. The contents of the two vessels are allowed to mix by opening the valve that separates them until the temperature is 16 °C. Calculate the partial pressure of each gas after mixing. (8)​

Answers

The partial pressures of CH4 and CO2 after mixing are 1.06 atm and 0.43 atm, respectively.

How to calculate the value

The number of moles of gas in each vessel can be calculated using the following formula:

n_i = P_i * V / RT

Substituting the given values, we get the following equations for the number of moles of gas in each vessel:

n_A = (1.5 atm) * V / (0.08206 L atm/mol K) * 289.15 K = 0.91 mol

n_B = (0.6 atm) * V / (0.08206 L atm/mol K) * 289.15 K = 0.37 mol

Therefore, the total number of moles of gas in the system is:

n_total = 0.91 mol + 0.37 mol = 1.28 mol

The mole fraction of each gas in the system is equal to the number of moles of that gas divided by the total number of moles of gas in the system.

x_i = n_i / n_total

Substituting the given values, we get the following mole fractions for each gas:

x_CH4 = 0.91 mol / 1.28 mol = 0.71

x_CO2 = 0.37 mol / 1.28 mol = 0.29

The partial pressure of each gas is equal to the mole fraction of that gas multiplied by the total pressure of the system.

P_i = x_i * P_total

Substituting the given values, we get the following partial pressures for each gas:

P_CH4 = 0.71 * 1.5 atm = 1.06 atm

P_CO2 = 0.29 * 1.5 atm = 0.43 atm

Therefore, the partial pressures of CH4 and CO2 after mixing are 1.06 atm and 0.43 atm, respectively.

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what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm​

Answers

Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

A body of weight 200N is dropped from a certain height and it attains a maximum velocity before it hit the ground with this velocity it moves at a constant of proportionality 5kg/s .find
A, the terminal velocity
B.the height it moved ​

Answers

We can use the equations of motion and the concept of terminal velocity to solve this problem.

Let's start by finding the terminal velocity:

A. Terminal Velocity:

The terminal velocity is the maximum velocity that a falling object can reach when the resistance of the medium through which it is falling (such as air) is equal to the force of gravity acting on the object. At terminal velocity, the net force on the object is zero, so the object moves at a constant velocity.

We can find the terminal velocity using the equation:

vT = mg/k

where vT is the terminal velocity, m is the mass of the object, g is the acceleration due to gravity, and k is the constant of proportionality.

Given that the body has a weight of 200 N, its mass is:

m = F/g = 200 N/9.81 m/s^2 ≈ 20.38 kg

We are also given that the constant of proportionality is k = 5 kg/s.

Therefore, the terminal velocity is:

vT = mg/k = (20.38 kg)(9.81 m/s^2)/5 kg/s ≈ 39.77 m/s

B. Height Traveled:

Next, we can use the equations of motion to find the height that the body traveled before reaching terminal velocity. At the maximum velocity, the net force on the body is zero, so the body moves at a constant velocity. We can use the equation:

v^2 = u^2 + 2as

where v is the final velocity (terminal velocity), u is the initial velocity (which is zero), a is the acceleration, and s is the distance traveled.

We can rearrange this equation to solve for s:

s = (v^2 - u^2)/2a = v^2/2a

At terminal velocity, the acceleration is zero, so we can use the terminal velocity we found in part (A) to find the height traveled:

s = vT^2/2a = (39.77 m/s)^2/(2 × 0) = 794.60 m

Therefore, the height that the body traveled before reaching terminal velocity is approximately 794.60 meters.

Select the correct location on the image.
Which color in the visible spectrum has the highest frequency?
red
(longest
wavelength)
The Visible Light Spectrum
4
violet
(shortest
wavelength)

Answers

Violet color in the visible spectrum has the highest frequency. The violet colour has the greatest frequency of all the colours in the visible spectrum.

The range of electromagnetic waves that can be seen by the human eye is known as the visible spectrum, and it contains colours from red to violet. Based on their wavelengths, light waves that travel through a prism or diffract split into various colours.

The shortest wavelength of all the colours that may be seen, violet, correlates to a high frequency. Wavelengths and frequencies gradually change as we go from violet to red. As a result, violet has the greatest frequency of all the colours in the visible spectrum.

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Help me please !!!! Question 51

Answers

Explanation:

See image

How far would you need to travel to reach a star located 4.2 light years away in only 3 months, as measured by your own wristwatch? (need to consider the special relativity in the answer)

Answers

You would need to travel approximately 0.25 light years to reach the star located 4.2 light years away in only 3 months, as measured by your own wristwatch.

According to special relativity, as an object approaches the speed of light, time dilation occurs. This means that time would appear to pass slower for the traveler relative to a stationary observer. To calculate the distance you would need to travel, considering time dilation, we need to account for the time dilation factor γ (gamma). The formula for time dilation is T' = T / γ, where T' is the observed time by the traveler and T is the time measured by the stationary observer.

Assuming you want to travel 4.2 light years in 3 months (as measured by your wristwatch), we need to find the value of γ that satisfies T' = 3 months. Solving the equation, we find γ = T / T' = 4.2 years / 3 months. Converting years to months, we have γ = 50.4 months / 3 months = 16.8. Now, we can calculate the distance you would need to travel by dividing the observed distance (4.2 light years) by γ: 4.2 light years / 16.8 = 0.25 light years.

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3 (a) A car starts from rest and accelerates uniformly reaching a velocity of 25 m/s after travelling 100m. It travels at this velocity for 750 m. Then it decelerates uniformly and comes to rest in 5 s. Use the method of velocity- time graph to: i) iii) Find its displacement in the first 20 s, Find its total displacement, and the total time taken. [11]​

Answers

the car's displacement in the first 20 seconds is 100 m, and the total displacement is 912.5 m. The total time taken is 33 seconds.

We may apply the equation v² = u² + 2as, where v is the final velocity, u is the beginning velocity, an is the acceleration, and s is the displacement, given that the automobile starts at rest and travels 100 metres before reaching a velocity of 25 m/s. We can find the acceleration by plugging in the values:

25² = 0² + 2a(100)

625 = 200a

a = 3.125 m/s²

By using equation v = u + at, we get

25 = 0 + 3.125t

t = 8 s

displacement is given by,

s = ut + (1/2)at²:

s = 0(8) + (1/2)(3.125)(8)²

s = 100 m

car travels at a constant velocity of 25 m/s for 750 m. Therefore, the displacement during this period is simply 750 m.

The car comes to rest in 5 seconds, and since it decelerates uniformly, the final velocity is 0 m/s.

Using the equation v = u + at, the deceleration is given as,

0 = 25 + a(5)

a = -5 m/s²

Using the equation v² = u² + 2as the displacement is

0² = 25² + 2(-5)s

0 = 625 - 10s

s = 625/10

s = 62.5 m

Total displacement = displacement during initial acceleration + displacement during constant velocity + displacement during deceleration

Total displacement = 100 m + 750 m + 62.5 m

Total displacement = 912.5 m

Total time taken = time taken for initial acceleration + time taken for constant velocity + time taken for deceleration

Total time taken = 8 s + 20 s + 5 s

Total time taken = 33 s

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Q4. The following potential differences were measured in a circuit: E is at the same potential as ground and -25 volts wrt D D is -15 volts wrt C C is -10 volts wrt B B is -30 volts wrt A What are the potentials at B, C and D wrt ground. What is the potential difference of A wrt C. What is the potential difference of C wrt A. What is the potential difference of ground wrt B i) ii) iii) iv)​

Answers

We can determine the potentials at B, C, and D with respect to ground by adding up the potential differences from each point to ground:

The potential at B with respect to ground is -30 volts.The potential at C with respect to ground is -10 volts.The potential at D with respect to ground is -15 volts.

To determine the potential difference of A with respect to C, we subtract the potential at C from the potential at A:

The potential difference of A with respect to C is -20 volts (since the potential at A is -30 volts and the potential at C is -10 volts, so A is 20 volts less than C).

To determine the potential difference of C with respect to A, we subtract the potential at A from the potential at C:

The potential difference of C with respect to A is +20 volts (since the potential at C is -10 volts and the potential at A is -30 volts, so C is 20 volts greater than A).

To determine the potential difference of ground with respect to B, we subtract the potential at B from the potential of ground (which is assumed to be zero):

The potential difference of ground with respect to B is +30 volts (since the potential at B is -30 volts, so ground is 30 volts greater than B).

what is incandescent object
Hurry up please ​

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An incandescent object refers to an object that emits light as a result of being heated to a high temperature.

Understanding Incandescent Object

When an object is heated, its atoms and molecules gain energy, causing them to vibrate and move more rapidly. This increased energy causes the object to emit electromagnetic radiation, including visible light, which makes the object glow.

Incandescence is commonly observed in everyday objects such as incandescent light bulbs, where a tungsten filament is heated by an electric current until it reaches a temperature that causes it to emit visible light.

As the filament gets hotter, it emits light with a higher intensity and shifts towards shorter wavelengths, starting from a warm red glow and progressing towards a brighter, white light.

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Una anciana camina 0.30 km en 10 minutos dando la vuelta un centro comercial calcule su rapidez media 

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The average speed of the elderly woman walking around the shopping center is 1.80 km/h.

To calculate the average speed of the elderly woman, we can use the formula for velocity, which is equal to the distance traveled divided by the time taken. In this case, the distance traveled is 0.30 km and the time taken is 10 minutes. However, average speed is generally expressed in units of distance per unit of time, so we need to convert minutes to hours.

There are 60 minutes in one hour, so 10 minutes is equal to 10/60 = 1/6 hours.

Now we can calculate the average speed by dividing the distance traveled (0.30 km) by the time taken (1/6 hours):

Average speed = 0.30 km / (1/6 h)

= 0.30 km * (6/1 h)

= 1.80 km/h

Therefore, the average speed of the elderly woman walking around the shopping center is 1.80 km/h.

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how mindset affects learning

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Answer: mindsets can affect learning

Explanation: negative mindsets vs positive ones, individually affect someone. As everyone is different, this could differ between certain people(s). Generally, it is thought the more positive the mindset, the more positive the affect.

A mass particles of mass 5kg is pulled along a smooth horizontal surface by a horizontal string. the acceleration of the particles is 10ms^_2​

Answers

Answer:

50 N

Explanation:

To determine the force exerted on the particle, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). Mathematically, this can be expressed as:

F = m * a

Given that the mass of the particle is 5 kg and the acceleration is 10 m/s^2, we can substitute these values into the formula:

F = 5 kg * 10 m/s^2

F = 50 N

What is the magnetic power?

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Answer:

Magnetic power, also known as magnetic strength or magnetic field strength, refers to the intensity or magnitude of a magnetic field. It represents the amount of magnetic force exerted by a magnet or a magnetic field on other magnetic objects or charged particles.

The magnetic power is determined by factors such as the size and strength of the magnet, the distance from the magnet, and the magnetic properties of the materials involved. It is typically measured in units of tesla (T) or gauss (G).

In practical terms, magnetic power describes the ability of a magnetic field to attract or repel objects, influence the motion of charged particles, or induce magnetic effects in nearby materials. The higher the magnetic power, the stronger the magnetic field and the greater its impact on surrounding objects or substances.

Magnetic power finds applications in various fields, including electromagnetism, electronics, magnetic resonance imaging (MRI), magnetic levitation, and many industrial processes where magnetic fields are utilized for their properties and effects.

Explanation:

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