you drop a stone into a deep well and hear the splash 2.5 s later. how deep is the well? (ignore air resistance and assume speed of sound is 340 m/s.)

Answers

Answer 1

The depth of the well is approximately 30.6 meters.

To determine the depth of the well, we need to use the equation:
d = (1/2) g t^2
d = depth of the well
g = acceleration due to gravity (9.81 m/s^2)
t = time taken for sound to travel from the top of the well to the surface of the water and back again
distance = speed x time
distance = 340 m/s x 2.5 s
distance = 850 m
distance = 850 m / 2
distance = 425 m
d = (1/2) g t^2
d = (1/2) x 9.81 m/s^2 x (2.5 s/2)^2
d = 30.26 m
The depth of the well is approximately 30.26 m.

To determine the depth of the well, we need to separate the time it takes for the stone to fall and the time it takes for the sound to travel back up. Let's denote the time for the stone to fall as t1 and the time for the sound to travel back up as t2. We know that t1 + t2 = 2.5 s.
let's find t1. The distance the stone falls (depth of the well) can be represented as d = 0.5 * g * t1^2, where g is the acceleration due to gravity (9.81 m/s^2).
Next, let's find t2. The distance the sound travels back up is the same as the depth of the well. We can represent this as d = 340 m/s * t2.
Now we can set up the following equation:
t1^2 = (2*d) / g
t1 = √((2*d) / g)
Since t1 + t2 = 2.5, we can rewrite this as:
√((2*d) / g) + (d / 340) = 2.5
Solving for d in this equation: d ≈ 30.6 meters

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Explanation:

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Answer:

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Answer:

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Answer:

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Answer:

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2, A rectangulv Container of base socmby 30cm is filled
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Correct question is;

2, A rectangular Container of base 50 cm by 30cm is filled with water to be depth of 5cm. how much is the pressure exerted at the base? (take pw= 1000kg /m3 and g=10m/s)​

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Answer:

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