A laboratory measurement finds 200 μg of hemoglobin per μL of blood. Hemoglobin, the blood protein that transports oxygen, has a molecular weight of 64 kDa or 64,000 u , where 1 dalton ( Da ) = 1 atomic mass unit ( u ) = 1.66×10^−24g . Estimate the number of hemoglobin proteins in one red blood cell. Express your answer in hemoglobin per red blood cell.

Answers

Answer 1

One red blood cell contains an estimated 251 molecules of haemoglobin, according to our estimation.

What size does a red blood cell typically have?

The average red blood cell has a diameter of 6 to 8 micrometres, according to the American Society of Haematology, and a volume of 113-268 μm³ or 113-268x10⁻¹² L.

Let's first change the haemoglobin concentration from grammes per litre to grammes per litre so that it has the same units as the molecular weight:

200 μg/μL x 1 g/1000 μg x 10⁶ μL/L = 0.2 g/L

Next, let's translate hemoglobin's molecular weight from kDa to grammes per molecule:

64 kDa x 1000 Da/kDa x 1.66x10⁻²⁴ g/Da = 1.06x10⁻²⁰ g/molecule

Using Avogadro's number, we can now determine how many haemoglobin molecules are present in a single litre of blood ([tex]6.022*10^{23}[/tex] molecules/mol): 0.2 g/L x 1 mol/1.06x10⁻²⁰ g x [tex]6.022*10^{23}[/tex] molecules/mol = 1.13x10¹⁵ molecules/L.

Divide the total number of molecules in 1 litre of blood by the volume of red blood cells to get the amount of haemoglobin molecules per red blood cell. The typical red blood cell count range, according to the American Society of Haematology, is between 4.5-5.5 million cells/L, which translates to 4.5-5.5x10¹² cells/L.

When we divide the quantity of red blood cells in 1 L by the quantity of haemoglobin molecules, we get:

1.13x10¹⁵ molecules/L / 4.5x10¹² cells/L = 251 Red blood cell haemoglobin molecules, rounded to the closest integer.

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Related Questions

A uniform beam of length and mass is inclined at an angle to the horizontal. Its
upper end is connected to a wall by a rope, and its lower end rests on a rough, horizontal surface.
Assume the angle is such that the static friction force between the beam and the surface is at its
maximum value. Determine what statement is true. There may be more than one answer.
a. The static frictional force relative to the pivot point does not exert a torque on the beam.
b. The torque produced by the gravitational force relative to the pivot point is equal to
= − sin /2.
c. The torque produced by the tension force relative to the pivot point is equal to
= sin where is the magnitude of the tension force.
d. If the angle were reduced from its present value, the magnitude of the tension force must
decrease in order to restore static equilibrium.
e. The coefficient of state friction must equal = /, where is the magnitude of the
tension force

Answers

Statement (a) is true: The static frictional force relative to the pivot point does not exert a torque on the beam.

What is Force?

Force is a physical quantity that describes the interaction between two objects or systems. It is defined as the push or pull that one object exerts on another, resulting in a change in the object's motion or deformation. Force is a vector quantity, which means it has both magnitude and direction.

The torque produced by a force about a pivot point is given by the product of the force and the perpendicular distance from the pivot point to the line of action of the force. In this case, the gravitational force acting on the beam can be considered to act at the center of mass of the beam, which is located at the midpoint of the beam due to its uniformity.

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By how much do you stretch your 0.600-cm diameter nylon rope when you hang 23.0m
below a rock outcropping. Assume your mass is 75.0 kg and your nylon rope has Young’s modulus of 5.00 × 10^9 N/m^2.

Answers

Answer:

To solve for the amount of stretch in the nylon rope, we can use the equation for the elongation (stretch) of a rope under tension:

ΔL = FL / AE

where ΔL is the change in length of the rope, F is the force on the rope, L is the original length of the rope, A is the cross-sectional area of the rope, and E is the Young's modulus of the rope.

First, we need to find the force on the rope. This is equal to the weight of you and the rope:

F = mg = (75.0 kg + mass of rope)g

Next, we need to find the cross-sectional area of the rope. The diameter of the rope is given as 0.600 cm, so the radius is 0.300 cm = 0.00300 m. Therefore, the cross-sectional area is:

A = πr^2 = 2.83 × 10^-6 m^2

Now we can plug in the given values and solve for ΔL:

ΔL = FL / AE = [(75.0 kg + mass of rope)g](23.0 m) / [(2.83 × 10^-6 m^2)(5.00 × 10^9 N/m^2)]

We can simplify this expression by using the fact that the mass of the rope is much smaller than your mass, so we can assume that the force on the rope is equal to your weight:

ΔL = (mg)(23.0 m) / (A E) = (75.0 kg)(9.81 m/s^2)(23.0 m) / [(2.83 × 10^-6 m^2)(5.00 × 10^9 N/m^2)]

Solving for ΔL, we get:

ΔL = 0.068 cm

Therefore, the nylon rope stretches by approximately 0.068 cm when you hang 23.0 m below a rock outcropping.

Figure B5.1 below is a diagram showing a wave travelling along a string in the direction shown

Answers

Figure B5.1 is a diagram showing a wave travelling along a string. The wave is propagating in the rightward direction, as indicated by the curved arrows.

What is direction?

Direction is a type of guidance that provides the recipient with specific instructions on how to proceed. Direction can involve information on where to go, what to do, or what to avoid. It could be used to provide instructions on a task, a journey, or an event. Direction could also be used to provide motivation and help someone stay focused on their goals. Direction can be provided verbally, through writing, or through body language. It can come from a supervisor, a teacher, or a parent. Direction is important in helping someone follow their path and achieve their goals.

The wave is depicted by a series of oscillations along the string, represented by the vertical lines. The amplitude of the wave is represented by the distance between the highest and lowest points of the oscillations. As the wave travels in the rightward direction, the oscillations move along the string, and the amplitude remains unchanged.

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What new question occurred to scientists after they discovered that the
ocean floor was not flat?
O A. Are there bathtubs that have shapes similar to that of the Mid-
Atlantic Ridge?
OB. Why is the ocean floor not flat and smooth like the bottom of a
bathtub?
C. How much cable will it take to go from North America to England?
OD. How deep is the ocean?

Answers

Answer:

b

Explanation:

The answer is B. Why is the ocean floor not flat and smooth like the bottom of a bathtub?

Scientists were surprised to find that the ocean floor was not a flat and featureless plain, but rather had mountains, valleys, and other geological features. This discovery raised questions about how these features formed and what processes were involved. Scientists began to investigate the causes of these features, such as plate tectonics and volcanic activity, and how they might have shaped the ocean floor over millions of years. Understanding the complex and dynamic nature of the ocean floor has since become an important area of study in earth science and oceanography.

When does a force do maximum work

Answers

Answer:

when the angle between the displacement and direction of force is zero

Answer:

Only when the force is applied in the same direction as the displacement of the object on which it acts, it does maximum work. This is because the work done by a force is given by the dot product of the force and displacement vectors. The dot product of two vectors is maximum when they are parallel to each other. Therefore, when a force is applied in the direction of displacement, it does maximum work.

When a force is applied perpendicular to the displacement, it does no work at all. This is because the dot product of two perpendicular vectors is zero. When a force is applied at an angle to the displacement, it does some work but not maximum.

It's important to note that the amount of work done by a force also depends on its magnitude and the distance over which it acts. The greater the magnitude of the force and the longer the distance over which it acts, the more work it will do.

In summary, a force does maximum work only when it is applied in the same direction as the displacement of the object on which it acts.

URGENT 50 POINTS
Show all Steps of your work.
7. Mohammed whose mass is 50kg swings back and forth on a long vine makes an angle 45 from the vertical resting position. His friend Abdella notices in amazement that he makes 30 complete swings in 2.0 minuies.
(a) What is the frequency (in hertz) of Tarzan's swing?
(b) What is the period of oscillation?
(c) How long is the vine he is using?
(d) Calculate the Restoring force on Mohammed?

Answers

The frequency of oscillation of the swing is 0.25 Hz.

The time period of oscillation of the swing is 4 s.

The length of the vine of the swing is 3.97 m.

The restoring force acting on Mohammed is 692.9 N.

Mass of Mohammed, m = 50 kg

Angle made by the vine with the vertical, θ = 45°

Number of complete swings made by Mohammed, n = 30

Time taken for this swing, t = 2 minutes = 120 seconds

a) The frequency of the swing is defined as the number of complete oscillations in one second.

So, the frequency of oscillation of the swing is,

f = n/t

f = 30/120

f = 0.25 Hz

b) The time period of oscillation of the swing is,

T = 1/f

T = 1/0.25

T = 4 s

c) The expression for the time period is given by,

T = 2π√(l/g)

T² = 4π² x (l/g)

l/g = T²/4π²

Therefore, the length of the vine of the swing is,

l = T²g/4π²

l = 4² x 9.8/4 x (3.14)²

l = 3.97 m

d) The restoring force acting on Mohammed,

F = mg sinθ

F = 50 x 9.8 x sin 45°

F = 490 x 1/√2 = 490/1.414

F = 692.9 N

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A hydraulic system has two pistons. Input force on one piston is 15.8 lb and the other piston can lift a weight of 93 lb. What is the mechanical advantage?​

Answers

Answer:

The mechanical advantage of a hydraulic system is given by the ratio of the output force to the input force. In this case, the input force is 15.8 lb and the output force is 93 lb.

So, the mechanical advantage of the hydraulic system is:

MA = Output force / Input force

MA = 93 lb / 15.8 lb

MA = 5.89

Therefore, the mechanical advantage of the hydraulic system is 5.89. This means that the system can lift a weight that is almost 6 times greater than the input force applied to the other piston.

A water wave travels a distance of 30m in 15s. What is the wave's speed in m/s?

Answers

substitute       d = 30     into formula

                        v = 15      d = v x t

                        30 = 15t

                        30/15 or 30 over 15 fraction :)

                        simplify

                             =

                             2

                        answer = 2

I hope this helps, this is what I know, I'm sorry if it's wrong :(

A piece of wood of density 400kg/m³ lump of aluminium is tied to a lump of aluminium of mass 0.01kg and density of 270kg/m³ . the arrangement has a mean density of 100kg/m³and just float in water. Determine the just float in volume of the piece of wood​

Answers

The just float in volume of the piece of wood is 0.008 cubic meters.

Just float calculation

Let's denote the volume of the piece of wood as V_wood, and the volume of the lump of aluminum as V_aluminum.

We can start by using the information given to write two equations:

Equation 1: (density of wood) * V_wood + (density of aluminum) * V_aluminum = (mean density) * (V_wood + V_aluminum)

Substituting the given values, we get:

400 * V_wood + 270 * V_aluminum = 100 * (V_wood + V_aluminum)

Simplifying and rearranging, we get:

300 * V_wood = 70 * V_aluminum

Equation 2: The total mass of the arrangement is the sum of the masses of the wood and aluminum:

(density of wood) * V_wood + (density of aluminum) * V_aluminum = (total mass)

Substituting the given values, we get:

400 * V_wood + 270 * V_aluminum = 0.01

Now we can use Equation 1 to eliminate V_aluminum from Equation 2:

300 * V_wood = 70 * V_aluminum

V_aluminum = (300/70) * V_wood

Substituting this into Equation 2, we get:

400 * V_wood + 270 * [(300/70) * V_wood] = 0.01

Simplifying and solving for V_wood, we get:

V_wood = 0.008 m^3

Therefore, the just float in volume of the piece of wood is 0.008 cubic meters.

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Many chemical reactions release energy. Suppose that at the beginning of a reaction, an electron and proton are separated by 0.115 nm , and their final separation is 0.105 nm . How much electric potential energy was lost in this reaction (in units of eV)?

Answers

The electric potential energy lost in this reaction is approximately 2.81 eV.

What is potential energy?

To calculate the electric potential energy lost in this reaction, we first need to calculate the difference in electric potential energy between the initial and final states. We can use the following formula to calculate electric potential energy:

E = kq1q2/r

where E is the electric potential energy, k is Coulomb's constant (8.99 x [tex]10^{9}[/tex] N*m²/C²), q1 and q2 are the charges of the two particles, and r is the separation distance between them.

In this case, we have an electron and a proton, which have charges of -1.602 x [tex]10^{-19}[/tex]  C and +1.602 x [tex]10^{-19}[/tex]  C, respectively. The initial separation distance is 0.115 nm, which is 1.15 x [tex]10^{-10}[/tex]  m, and the final separation distance is 0.105 nm, which is 1.05 x [tex]10^{-10}[/tex]  m.

So, the initial electric potential energy is:

E_initial = kq_electronq_proton/r_initial

= (8.99 x [tex]10^{9}[/tex]  N*m²/C²) * (-1.602 x [tex]10^{-19}[/tex] C) * (1.602 x [tex]10^{-19}[/tex]  C) / (1.15 x [tex]10^{-10}[/tex] m)

= -1.44 x [tex]10^{-18}[/tex]  J

And the final electric potential energy is:

E_final = kq_electronq_proton/r_final

= (8.99 x [tex]10^{9}[/tex] N*m²/C²) * (-1.602 x [tex]10^{-19}[/tex]  C) * (1.602 x [tex]10^{-19}[/tex]  C) / (1.05 x [tex]10^{-10}[/tex]  m)

= -1.89 x [tex]10^{-18}[/tex] J

The electric potential energy lost in this reaction is:

ΔE = E_final - E_initial

= (-1.89 x [tex]10^{-18}[/tex] J) - (-1.44  x [tex]10^{-18}[/tex] J)

= -0.45 x [tex]10^{-18}[/tex]   J

To express the electric potential energy lost in units of eV, we can use the following conversion factor:

1 eV = 1.602 x [tex]10^{-19}[/tex] J

So, the electric potential energy lost in this reaction is:

ΔE = (-0.45 x [tex]10^{-18}[/tex] J) / (1.602 x [tex]10^{-19}[/tex] J/eV)

= -2.81 eV

Therefore, the electric potential energy lost in this reaction is approximately 2.81 eV.

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The critical angle for total internal re
ection at a liquid-air interface is
42.5.
(a) If a ray of light traveling in the liquid has an angle of incidence at the
interface of 35.0, what angle does the refracted ray in the air make
with the normal?
(b) If a ray of light traveling in air has an angle of incidence at the
interface of 35.0, what angle does the refracted ray in the liquid make
with the normal?

Answers

Answer:

(a) If the critical angle for total internal reflection at a liquid-air interface is 42.5, and a ray of light traveling in the liquid has an angle of incidence at the interface of 35.0, then the angle of refraction in the air can be found using Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

where n₁ is the refractive index of the liquid and n₂ is the refractive index of air, which is approximately 1.00.

Rearranging this equation gives:

sin θ₂ = (n₁/n₂) sin θ₁

Plugging in the values gives:

sin θ₂ = (n₁/1.00) sin 35.0
sin θ₂ = (n₁/1.00) (0.5736)
sin θ₂ = 0.5736n₁

To find θ₂, we need to take the inverse sine of both sides:

θ₂ = sin⁻¹(0.5736n₁)

Substituting n₁ = 1.33 (refractive index of water) gives:

θ₂ = sin⁻¹(0.5736 × 1.33)
θ₂ = 46.5 degrees

Therefore, the refracted ray in the air makes an angle of 46.5 degrees with the normal.

(b) If a ray of light traveling in air has an angle of incidence at the interface of 35.0, the angle of refraction in the liquid can be found using the same formula and approach as above:

n₁ sin θ₁ = n₂ sin θ₂

where n₁ is the refractive index of air, which is approximately 1.00, and n₂ is the refractive index of the liquid, which is 1.33.

sin θ₂ = (n₁/n₂) sin θ₁
sin θ₂ = (1.00/1.33) sin 35.0
sin θ₂ = (0.7519)(0.5736)
sin θ₂ = 0.431

θ₂ = sin⁻¹(0.431)
θ₂ = 25.8 degrees

Therefore, the refracted ray in the liquid makes an angle of 25.8 degrees with the normal.

How much more force can the larger piston exert compared with the force applied to the smaller piston

Answers

The force that the larger piston can exert is directly proportional to the difference in the surface area of the two pistons. Assuming that the pressure is the same on both pistons, the larger piston can exert a force that is equal to the force applied on the smaller piston multiplied by the ratio of the surface area of the larger piston to the surface area of the smaller piston.

For example, if the surface area of the larger piston is four times larger than the surface area of the smaller piston, then the larger piston can exert a force that is four times greater than the force applied on the smaller piston.

why does widening the prism cause the beam to bend more?

Answers

Widening the prism adds additional glass, which slows light down even further and increases the amount of refraction.

Is a prism reflective or flexible?

The angles and plane sides of a prism cause light to be bent, or refracted, when it flows through them; the degree of refractive distortion varies somewhat depending on the wavelength of light.

When light travels from the air to the prism's glass, its speed changes, causing the light to bend and shift course. Once light enters the prism, it bends because the refraction indices of the air and glass differ. The light exits the prism bent even more since the sides are slanted.

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4. Define the terms; I. Frequency II. Wavelength III. Velocity as applied to a periodic wave motion. State the relationship between them. b) Two turning forks have frequencies of 200Hz and 300Hz. Calculate the difference in the wavelengths of the notes they emit. [Speed of sound in air = 330ms-¹]​

Answers

Answer:

Wavelength : It is defined as the distance travelled by a wave during the time a particle of the medium completes one vibration. It is denoted by k. Its SI unit is metre. Frequency: It is the number of occurrences of a repeating event per unit of time. Its SI unit is Hertz (Hz).

Explanation:

130% 00 1. A 345 g of copper is hanged on a spring wire of 30 cm in diameter as a result, the spring stretches from 75 cm to 80 cm. (8 marks)
1.1. What is the stress of the spring?
1.2 What is the strain of the spring?
1.3 What is the young's modulus of the spring?
1.4 Calculate the spring constant.​

Answers

To solve this problem, we need to use the following formulas:

1. Stress (σ) = Force (F) / Area (A)
2. Strain (ε) = Change in Length (ΔL) / Original Length (L)
3. Young's Modulus (E) = Stress (σ) / Strain (ε)
4. Spring Constant (k) = Force (F) / Extension (x)

First, we need to find the force exerted by the copper on the spring wire. We can use the formula:

Force (F) = mass (m) x gravity (g)

where mass (m) = 345 g = 0.345 kg, and gravity (g) = 9.81 m/s^2.

Therefore, F = 0.345 kg x 9.81 m/s^2 = 3.38 N.

1.1. The stress of the spring is:

σ = F / A

where A is the area of the spring wire. The diameter of the spring wire is 30 cm, which gives a radius of 15 cm or 0.15 m. Therefore, the area of the wire is:

A = πr^2 = π(0.15 m)^2 = 0.0707 m^2.

Thus, the stress of the spring is:

σ = 3.38 N / 0.0707 m^2 = 47.8 N/m^2.

1.2. The strain of the spring is:

ε = ΔL / L

where ΔL is the change in length of the spring and L is the original length of the spring. The spring stretches from 75 cm to 80 cm, which gives a change in length of:

ΔL = 80 cm - 75 cm = 0.05 m.

The original length of the spring is half the distance it stretches when holding the copper, or:

L = (75 cm + 80 cm) / 2 = 77.5 cm = 0.775 m.

Thus, the strain of the spring is:

ε = 0.05 m / 0.775 m = 0.0645.

1.3 The Young's modulus of the spring is defined as the ratio of stress to strain. We have already calculated the stress and strain of the spring in the previous parts of the question. So the Young's modulus of the spring is:

Young's modulus (E) = stress (σ) / strain (ε)
E = 47.8 N/m^2 / 0.0645 = 740.9 N/m^2

Therefore, the Young's modulus of the spring is 740.9 N/m^2.

1.4 The spring constant is defined as the ratio of the force applied to the spring to the resulting extension. We have already calculated the force applied to the spring in the previous parts of the question. To calculate the spring constant, we need to find the extension of the spring.

The extension of the spring is the difference between the final length and the original length. The original length of the spring is half the distance it stretches when holding the copper, or:

Original length (L) = (75 cm + 80 cm) / 2 = 77.5 cm = 0.775 m

The final length of the spring when holding the copper is 80 cm. So the extension of the spring is:

Extension (x) = Final length - Original length
x = 80 cm - 77.5 cm = 2.5 cm = 0.025 m

Therefore, the spring constant is:

Spring constant (k) = Force (F) / Extension (x)
k = 3.38 N / 0.025 m = 135.2 N/m

Therefore, the spring constant is 135.2 N/m.

Estimate the power in [kW] of a "realistic ocean wave" captured by a wave-power station over a crest-length of 10 m, with the wave parameters characteristic of the Baltic sea: wave height of 1.25 m, wave period of 5 s (e.g., Northern Gotland Basin).

O a. 5
O b. 40
O c. 25
O d. 250
O e. 100

Answers

The power in kilowatts (kW) of a realistic ocean wave is 40 kW.

option B.

What is the realistic power?

The power in kilowatts (kW) of a realistic ocean wave can be estimated using the following formula:

Power (kW) = 0.5 x (Crest Length in meters) x (Wave Height in meters)^2 x (Wave Period in seconds) x (Density of Water in kg/m^3) x (Gravity in m/s^2)

Given the wave parameters for the Baltic Sea: wave height of 1.25 m, wave period of 5 s, and a crest length of 10 m, we can plug in these values to calculate the power.

Wave height (H) = 1.25 m

Wave period (T) = 5 s

Crest length (L) = 10 m

Density of water (ρ) = 1025 kg/m^3 (typical value for sea water)

Gravity (g) = 9.81 m/s^2 (typical value on Earth)

Plugging in these values into the formula:

Power (kW) = 0.5 x 10 x (1.25)^2 x 5 x 1025 x 9.81

Calculating the above expression, we get:

Power ≈ 40 kW

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Can u please help with first two tasks
Workbook:complete physics for Cambridge secondary first

Answers

You can generate electricity by moving a coil of wire in a magnetic field. The size of the voltage  depends on the speed of the movement and the strength of the magnet

In a model generator, a coil rotates between the poles of a magnet. If a coil with more turns is used, the voltage is greater. If the coil spins faster, the voltage is also greater.

What is electromagnetic induction?

Electromagnetic induction is a phenomenon in physics that occurs when a varying magnetic field produces an electric current or voltage in a conductor. It was first discovered by Michael Faraday in the early 19th century and is now a fundamental principle of modern electrical technology.

When a conductor, such as a wire, is moved through a magnetic field, or when the magnetic field itself changes, a voltage is induced across the ends of the conductor. The magnitude of the induced voltage is proportional to the rate of change of the magnetic field and the number of turns of wire in the coil.

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URGENT QUICK N EASY!
50 POINTS!
LOOK AT THE PICTURE!!

PART C!!
Find the maximum magnitude of the acceleration.
Express your answer using two significant figures.

Answers

1. The period of the mass is 0.47 second

2. The amplitude is 0.02 m

1. How do i determine the period?

The period of the mass can be obtained as illustrated below:

Mass attached (m) = 0.95 KgSpring constant of spring (K) = 170 N/mPi (π) = 3.14Period (T) =?

T = 2π√(m/k)

T = (2 × 3.14) × √(0.95 / 170)

T = 6.28 × √(0.95 / 120)

T = 0.47 second

Thus, from the above calculation, we can conclude that the period is 0.47 second

2. How do i determine the amplitude?

The amplitude of the wave can be obtained as shown below:

Mass attached (m) = 0.95 KgSpring constant of spring (K) = 170 N/mMaximum speed (v) = 0.25 m/sAmplitude (A) =?

A = v√(m/k)

A = 0.25 × √(0.95 / 170)

A = 0.02 m

Thus, the amplitude is 0.02 m

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What is Ceres?


The largest asteroid identified to date.


The asteroid closest in orbit to the Earth.


The comet that passes near Earth most often.


The meteor that probably killed the dinosaurs.

Answers

The Ceres is (a).The largest asteroid identified to date is correct option.

With a diameter of around 590 miles (940 km), Ceres is the biggest asteroid between Mars and Jupiter. It is regarded as a minor planet, like Pluto, and was found in 1801 by Giuseppe Piazzi. Ceres is made of rock and ice, and due to its low density, it is likely that it contains a substantial amount of water ice inside.

The NASA Dawn spacecraft visited Ceres in 2015 and orbited the dwarf planet for more than three years, gathering useful information and taking stunning pictures of it.

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of the following stars, which one has a mass less than that of our sun? The choices are Sirius B, Altair, Arcturus, Spica, and Rigel.

Answers

Answer:

Sirius B

Explanation:

Here we go !!!!

Sirius B: A white dwarf star and companion to Sirius A, the brightest star in the sky. It has a mass of only about 0.98 times that of the sun, making it less massive than our sun.Arcturus: A red giant star located in the constellation Boötes, with a mass of about 1.1 times that of the sun.Spica: A binary star system composed of two hot, blue stars located in the constellation Virgo. The primary star has a mass of about 11 times that of the sun.Rigel: A blue supergiant star located in the constellation Orion, with a mass of about 17 times that of the sun. It is one of the brightest stars in the sky and is a part of Orion's Belt.Altair: A main-sequence star of spectral type A7V, located in the constellation Aquila. It has a mass of about 1.8 times that of the sun, which means it is more massive than the sun.

I hope this information helps!

HELPPPPP MEEEEEEE. genes can __________ many traits and can be ____________ through biotechnology

Answers

Genes can shape many traits and can be modified through biotechnology.

What are genetic engineering techniques?

The expression genetic engineering techniques refer to all procedures that use recombinant DNA to create or redesign gene sequences, which invariably may modify or change the expression of a given phenotypic feature in the target organism in which this sequence is being inserted.

Therefore, with this data, we can see that genetic engineering techniques can modify a phenotype to express a desirable trait such as by inserting the insulin gene into bacteria.

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Find the ratio of the coulomb electric force Fe to the gravitational force Fg between two electrons in vacuum.​

Answers

The Coulomb's law expresses the force between two charged particles as:

Fe = k * (q1 * q2) / r^2

where k is Coulomb's constant, q1 and q2 are the charges of the particles, and r is the distance between them.

The gravitational force between two particles is given by:

Fg = G * m1 * m2 / r^2

where G is the gravitational constant, m1 and m2 are the masses of the particles, and r is the distance between them.

For two electrons, the charges q1 and q2 are equal and have a magnitude of 1.602 x 10^-19 C, and their masses m1 and m2 are also equal and have a value of 9.109 x 10^-31 kg.

Using the values of Coulomb's constant (k = 8.987 x 10^9 N.m^2/C^2) and gravitational constant (G = 6.674 x 10^-11 N.m^2/kg^2), we can calculate the ratio of the Coulomb electric force to the gravitational force between two electrons in vacuum as:

Fe/Fg = [k * (q1 * q2) / r^2] / [G * m1 * m2 / r^2]
Fe/Fg = k * (q1 * q2) / (G * m1 * m2)
Fe/Fg = (8.987 x 10^9 N.m^2/C^2) * (1.602 x 10^-19 C)^2 / [(6.674 x 10^-11 N.m^2/kg^2) * (9.109 x 10^-31 kg)^2]
Fe/Fg = 2.396 x 10^42

Therefore, the ratio of the Coulomb electric force to the gravitational force between two electrons in vacuum is approximately 2.396 x 10^42.

Katie, a 60 kg person, stands at the edge of a well and holds a rope attached to an 8 kg bucket of water resting in the water below. With her first tug up on the rope, the bucket speeds up to 3 m/s while it rises 0.9 m. What is the bucket’s acceleration? How quickly is Katie accelerating? How hard is Katie pulling on the bucket? What is the normal force on Katie?

Answers

The acceleration of the bucket is 5 m/s^2.Katie is pulling on the rope with a force of 1075.6 N.The normal force on Katie is -487.6 N

Force calculation

To solve this problem, we can use the following equations:

F_net = ma (Newton's second law)

F_tension - F_gravity - F_buoyancy = ma (sum of forces on the bucket)

F_gravity - F_tension - F_normal = 0 (sum of forces on Katie)

where:

F_tension is the tension in the ropeF_gravity is the weight of the bucket and KatieF_buoyancy is the buoyant force on the bucketF_normal is the normal force on Katiea is the acceleration of the bucket

First, we can find the tension in the rope:

F_net = ma

F_tension - F_gravity - F_buoyancy = ma

F_tension = ma + F_gravity + F_buoyancy

The weight of the bucket is:

F_gravity_bucket = m_bucket * g = 8 kg * 9.8 m/s^2 = 78.4 N

The weight of Katie is:

F_gravity_Katie = m_Katie * g = 60 kg * 9.8 m/s^2 = 588 N

The buoyant force on the bucket is equal to the weight of the water displaced by the bucket, which is:

F_buoyancy = m_water * g = m_bucket * g = 78.4 N

Substituting these values, we get:

F_tension = (m_bucket + m_Katie) * a + F_gravity_bucket + F_gravity_Katie + F_buoyancyF_tension = (8 kg + 60 kg) * a + 78.4 N + 588 N + 78.4 NF_tension = 68 a + 744.8 N

Next, we can find the acceleration of the bucket:

We can use the kinematic equation:

v^2 = u^2 + 2as

where:

v is the final velocity (3 m/s)u is the initial velocity (0 m/s)s is the displacement (0.9 m)

Solving for a, we get:

a = (v^2 - u^2) / 2sa = (3 m/s)^2 / (2 * 0.9 m)a = 5 m/s^2

Therefore, the acceleration of the bucket is 5 m/s^2.

Next, we can find the tension in the rope:

F_tension = 68 a + 744.8 NF_tension = 68 * 5 m/s^2 + 744.8 NF_tension = 1075.6 N

Therefore, Katie is pulling on the rope with a force of 1075.6 N.

Finally, we can find the normal force on Katie:

F_gravity_Katie - F_tension - F_normal = 0

F_normal = F_gravity_Katie - F_tension

F_normal = 588 N - 1075.6 N

F_normal = -487.6 N

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A person fires a gun close to a wall (40m). An echo is heard 0.24 after the original shot. Based on this information only, find the speed of sound in air?

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The speed of sound in air can be calculated using the following formula:speed of sound = distance / timeIn this case, we know that the distance between the person and the wall is 40 meters, and the time it takes for the echo to be heard after the original shot is 0.24 seconds. However, we need to account for the fact that sound travels to the wall and back, so the total distance the sound wave covers is twice the distance to the wall, or 2 x 40 = 80 meters.Thus, using the formula above, we can calculate the speed of sound:speed of sound = distance / time = 80 m / 0.24 s ≈ 333.33 m/sTherefore, the speed of sound in air is approximately 333.33 meters per second.

) Find mass and speed of 2 MeV electron​

Answers

According to the equation E=(-1)mc2, where [tex]E=3.2 x 1013 J[/tex] and [tex]=1.0000037[/tex], a 2 MeV electron has a mass of [tex]9.11 x 1031 kg[/tex] and a speed of [tex]2.195 x 108 m/s.[/tex]

How are masses expressed in MeV?

Additionally, as energy and mass are connected by Einstein's famous equation E = mc2, the masses of elementary particles are sometimes stated in electron volts as well. An electron, for instance, has a mass of 0.51 MeV/c2, where c is the speed of light.

What does 2 MeV proton mean?

Moving perpendicular to a 2.5 T magnetic field is a 2 MeV proton. The proton is under a force of (1.6 10 27 kg of proton mass)

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what is parallel universe ?

Answers

Answer:

I really hope this helps.:)

Explanation:

A parallel universe, also known as a parallel dimension, alternate universe, or alternate reality, is a hypothetical self-contained plane of existence, co-existing with one's own. The sum of all potential parallel universes that constitute reality is often called a "multiverse".

Can u please help with this two tasks?
Workbook:complete physics for Cambridge secondary first

Answers

For electricity generation the words in order are:

a You can generate electricity by moving a coil of wire in a magnetic field. The size of the voltage depends on the speed of the movement and the strength of the magnet.

b In a model generator, a coil rotates between the poles of a magnet. If a coil with more turns is used the voltage is greater. If the coil spins faster, the voltage is greater.

What is the influence of induced voltage?

a. If the student moved the magnet towards the coil at a slower speed, she would notice that the induced voltage on the voltmeter decreases. This is because the voltage induced is proportional to the rate of change of the magnetic field, which decreases as the speed decreases.

b. If the student moved the magnet towards the coil at the same speed, she would notice that the induced voltage on the voltmeter remains the same. This is because the voltage induced is proportional to the rate of change of the magnetic field, which is constant if the speed is constant.

c. If the student turned the magnet round and moved it towards the coil, she would notice that the induced voltage on the voltmeter is in the opposite direction. This is because the direction of the induced voltage is determined by the direction of the change in magnetic field, which is reversed when the magnet is turned round.

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Why is it called “static” electricity?
A. Charges can easily flow
B. Charges are not trapped in place
C. Charges cannot easily flow
D. Charges are free to move around

Answers

It is called static electricity because Charges cannot easily flow, hence option C is the answer.

Static electricity is called "static" because the charges are not free to move around easily. They tend to build up on the surface of an insulator and remain in place, rather than flowing like current in a conductor.

This buildup of charge can occur due to friction, induction, or any other mechanisms in the conductor. Therefore, option C is the correct option that says "Charges cannot easily flow".

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The center of gravity of a 5.00 kg irregular object is shown in (Figure 1). You need to move the center of gravity 1.60 cm to the left by gluing on a 1.50 kg mass, which will then be considered as part of the object.
Where should the center of gravity of this additional mass be located?

Answers

The moment of the weight of the 1.50 kg mass about the CG of the 5.00 kg object will be considered as part of the object.

The center of gravity of the additional 1.50 kg mass should be located 1.60 cm to the right of the current CG of the 5.00 kg object.

What is the moment ?

We can use the principle of moments to determine the location of the center of gravity of the additional 1.50 kg mass that needs to be glued on.

The principle of moments states that the sum of the moments of all the forces acting on an object is equal to the moment of the resultant force about any point. In this case, we can take moments about the current center of gravity (CG) of the 5.00 kg object to determine the location of the center of gravity of the additional 1.50 kg mass.

The moment of a force about a point is given by the product of the magnitude of the force and the perpendicular distance from the point to the line of action of the force. Since the gravitational force acting on the masses is the only force acting on the system, we can take moments of the weight of each mass about the CG of the 5.00 kg object.

The moment of the weight of the 5.00 kg object about its CG is zero, since the CG is the point about which the object is in rotational equilibrium. Therefore, we only need to consider the moment of the weight of the 1.50 kg mass about the CG of the 5.00 kg object.

The distance between the CG of the 5.00 kg object and the desired new CG is 1.60 cm to the left, so we need to find the distance between the current CG and the new CG. Let x be the distance from the current CG to the new CG.

The moment of the weight of the 1.50 kg mass about the current CG is:

(1.50 kg)(9.81 m/s²)(x) = 14.72x Nm

The moment of the weight of the 1.50 kg mass about the new CG is:

(1.50 kg)(9.81 m/s²)(1.60 cm + x) = 14.72x + 23.54 Ncm

Setting these two moments equal, we have:

14.72x Nm = 14.72x + 23.54 Ncm

Converting the units, we get:

0.1472x m = 0.2354 m

x = 1.60 cm (to two significant figures)

Therefore, the center of gravity of the additional 1.50 kg mass should be located 1.60 cm to the right of the current CG of the 5.00 kg object.

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A flat uniform circular disk (radius = 5.44 m, mass = 150 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a frictionless axis perpendicular to the center of the disk. A 47.0-kg person, standing 1.54 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.80 m/s relative to the ground. Find the resulting angular speed (in rad/s) of the disk.

Answers

According to the question, the resulting angular speed (in rad/s) of the disk is 0.38 rad/s.

What is angular speed?

Angular speed is the rate at which an object or particle rotates or revolves around a point or an axis. It is measured in radians per second or revolutions per minute. Angular speed is an important concept in mechanics, astrophysics, and engineering.

In this case, the angular momentum of the person is 47.0 kg×2.80 m/s×1.54 m = 186 kg m²/s.

Therefore, the change in angular momentum of the disk is equal to the angular momentum of the person, which is 186 kg m²/s.

Using the conservation of angular momentum equation, we can find the angular speed of the disk by rearranging the equation to get ω = (ΔL)/I.Therefore, the angular speed of the disk is ω = 186 kg m²/s/486 kg m² = 0.38 rad/s.

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