Answer:
The answer is C Natural selection
Explanation:
Natural selection is the differential survival and reproduction of individuals due to differences in phenotype. It is a key mechanism of evolution, the change in the heritable traits characteristic of a population over generations
According to Darwin’s theory of evolution, differences between species may be a result of Natural selection. Thus the correct option is C.
What is Darwin’s theory of evolution?According to Darwin, all species descended from a single ancestor, species can change through time, and new species can arise from existing ones which makes them interconnected with common traits.
Natural selection of traits in a species that would help the species in its survival is the process that drives diversification, the evolutionary process through which new biological species form.
Natural selection is the evolutionary mechanism stating that with many resources available in nature, creatures with genetically inherited features that promote survival and reproduction will typically produce more offspring than their conspecific competitors.
Therefore, option C is appropriate.
Learn more about Darwin’s theory of evolution, here:
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Online Privacy
1.)Explain why is online privacy a controversial topic?
2.)Explain why this issue is applicable to you and your peers.
3.)Explain why this issue is a federal issue and not a state or local issue.
Answer:
Yes
Explanation:
Online privacy is a controversial topic due to the fact that it's a very hard thing to navigate. Some websites use cookies that are used to store your data so in a way there taking your privacy away which is controversial because of the way they use the information. Some websites store it for use of ads while others sell it. This issue is applicable to me and my peers because of the way we use technology. It can be used to steal my information about where I live and what I look up online. Also, the information stored could have my credit or debit card credentials. This issue should be a federal and nationwide issue because this is an everyday occurrence and leaves tons of people in crushing debt every year.
Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMiles. Sample output for the given program:
Min miles: -10
Max miles: 40
Here's what I have so far:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int NUM_ROWS = 2;
final int NUM_COLS = 2;
int [][] milesTracker = new int[NUM_ROWS][NUM_COLS];
int i = 0;
int j = 0;
int maxMiles = 0; // Assign with first element in milesTracker before loop
int minMiles = 0; // Assign with first element in milesTracker before loop
milesTracker[0][0] = -10;
milesTracker[0][1] = 20;
milesTracker[1][0] = 30;
milesTracker[1][1] = 40;
//edit from here
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] > maxMiles){
maxMiles = milesTracker[i][j];
}
}
}
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] < minMiles){
minMiles = milesTracker[i][j];
}
}
}
//edit to here
System.out.println("Min miles: " + minMiles);
System.out.println("Max miles: " + maxMiles);
}
Answer:
See Explanation
Explanation:
Your program is correct and doesn't need an attachment.
However, there's a mismatch in placement of curly braces in your program
{
}
I've made corrections to that and I've added the corrected program as an attachment.
Aside that, there's no other thing to be corrected in your program.
Use another compiler to compile your program is you are not getting the required output.
Write a program, weeklypay.m, that asks an employee to enter their hourly rate and the number of hours they worked for the week. Then have the program calculate and display their weekly pay. pay
Answer:
Follows are the code to this question:
def weeklypay(hour_rate,hour ):#defining a method weeklypay that accepts two parameters
pay=hour_rate* hour#defining variable pay that calculate payable amount
return pay#return pay value
hour_rate=float(input("Enter your hour rate $: "))#defining variable hour_rate that accepts rate vlue
hour=int(input("Enter total hours: "))#defining hour variable that accepts hour value
print('The total amount you will get $: ',weeklypay(hour_rate,hour))#call method and print return value
Output:
Enter your hour rate $: 300
Enter total hours: 3
The total amount you will get $: 900.0
Explanation:
In the above-given code, a method "weeklypay" is declared, which holds two value "hour_rate and hour" in its parameter, inside a method a "pay" variable is declared, that calculate the total payable amount of the given inputs and return its value.
In the next step, the above variable is used to input the value from the user-end and uses the print method to call the "weeklypay" method and print its return value.
My Mac is stuck on this screen? How to fix?
Answer:
Press and hold the power button for up to 10 seconds, until your Mac turns off. If that doesn't work, try using a cellular device to contact Apple Support.
Explanation:
If that also doesn't work try click the following keys altogether:
(press Command-Control-Eject on your keyboard)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
This makes the laptop (macOS) instruct to restart immediately.
Hopefully this helps! If you need any additional help, feel free and don't hesitate to comment here or private message me!. Have a nice day/night! :))))
Another Tip:
(Press the shift, control, and option keys at the same time. While you are pressing those keys, also hold the power button along with that.)
(For at least 10 seconds)
If the propagation delay through a full-adder (FA) is 150 nsec, what is the total propagation delay in nsec of an 8-bit ripple-carry adder
Answer:
270 nsec
Explanation:
Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.
Formula to calculate the delay of a ripple-carry adder is;
= 2( n + 1 ) x D
delay in a full-adder = 150 nsec.
number of full-adders = number of ripple-carry bits = 8
= 2 ( 8 + 1 ) x 150
= 18 x 150
= 270 nsec
Using the Multiple-Alternative IFTHENELSE Control structure write the pseudocode to solve the following problem to prepare a contract labor report for heavy equipment operators: The input will contain the employee name, job performed, hours worked per day, and a code. Journeyman employees have a code of J, apprentices a code of A, and casual labor a code of C. The output consists of the employee name, job performed, hours worked, and calculated pay. Journeyman employees receive $20.00 per hour. Apprentices receive $15.00 per hour. Casual Labor receives $10.00 per hour.
Answer:
1. Start
2. Input Name, Jobs, Hours, Code
3. If Code == 'J' then
3.1 Pay = 20.00 * Hours
4. Else if Code == 'C' then
4.1 Pay = 15.00 * Hours
5. Else if Code == 'A' then
5.1 Pay = 10.00 * Hours
6. Output Name, Job, Hours, Pay
Explanation
This line starts the Pseudocode
1. Start
This line gets user inputs
2. Input Name, Jobs, Hours, Code
The following if and else statement determine the pay
3. If Code == 'J' then
3.1 Pay = 20.00 * Hours
4. Else if Code == 'C' then
4.1 Pay = 15.00 * Hours
5. Else if Code == 'A' then
5.1 Pay = 10.00 * Hours
This line prints the required output
6. Output Name, Job, Hours, Pay
Explaim Why the shape of a cell is hexagonal
Which type of chart or graph uses vertical bars to compare data?
Column chart
Line graph
Pie chart
Scatter chart
Answer:
Colunm Chart
Explanation:
Trust me
Compare and contrast between flowcharts that involve:
-simple logic flow and
-simple logic flow with a two way branch
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The solution to this question is given in the attached word file.
Roger's camera battery had a short circuit, which caused a fire at his home. What could he have done to prevent this from happening? A left batteries in camera when not in use B. stored batteries with other metal objects c. kept batteries near a magnetic field D. removed the batteries from the camera
Answer: D
Explanation: Because if he took the battery out it would not have short circuited.
Return to the Product Mix worksheet. Benicio wants to provide a visual way to compare the scenarios. Use the Scenario Manager as follows to create a PivotTable that compares the profit per unit in each scenario as follows:
a. Create a Scenario PivotTable report using the profit per unit sold (range B17:F17) as the result cells.
b. Remove the Filter field from the PivotTable.
c. Change the number format of the value fields to Currency with 2 decimal places and the $ symbol.
Answer:
To create a pivot table, select the columns to pivot and click on the insert option, click on the pivot table option and select the data columns for the pivot, verify the table range, select the location for the pivot and click ok. To format a column, select the columns and click the number option on the home tab, select the currency option and click on the number of decimal places
Explanation:
Microsoft Excel is a great tool for data analysis and visualization. It has several mathematical, engineering, statistical, and graphical tools for working with data.
A pivot-table is an essential tool for describing and comparing data of different types.
The steps to follow in order to produce a Pivot table would be as mentioned below:
Opting the columns for a pivot table. Now, make a click on the insert option. This click is followed by opting for the pivot table and the data columns that are available in it.After this, the verification of the range of the table is made and then, the location for the pivot table has opted. After this, the column is formatted and the number option is selected followed by the currency option, and the quantity of decimal places. A Pivot table allows one to establish a comparison between data of distinct categories(graphic, statistical, mathematical) and elaborate them.Learn more about 'Pivot Table' here:
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Plz answer me will mark as brainliest
Answer:
True
Operating System
Booting
A____server translates back and forth between domain names and IP addresses.
O wWeb
O email
O mesh
O DNS
Answer:
DNS
Explanation:
Hope this helps
7. While an adjacency matrix is typically easier to code than an adjacency list, it is not always a better solution. Explain when an adjacency list is a clear winner in the efficiency of your algorithm
Answer:
The answer is below
Explanation:
Adjacency list is a technique in a computer science that is used for representing graph. It deals with a gathering of unorganized lists utilized to illustrate a limited graph. In this method, each list depicts the group of data of a peak in the graph
Adjacency List are most preferred to Adjacency Matrix in some cases which are:
1. When the graph to is required to be sparsely.
2. For iterability, Adjacent List is more preferable
Suppose one machine, A, executes a program with an average CPI of 1.9. Suppose another machine, B (with the same instruction set and an enhanced compiler), executes the same program with 20% less instructions and with a CPI of 1.1 at 800MHz. In order for the two machines to have the same performance, what does the clock rate of the first machine need to be
Answer:
the clock rate of the first machine need to be 1.7 GHz
Explanation:
Given:
CPI of A = 1.9
CPI of B = 1.1
machine, B executes the same program with 20% less instructions and with a CPI of 1.1 at 800MHz
To find:
In order for the two machines to have the same performance, what does the clock rate of the first machine need to be
Solution:
CPU execution time = Instruction Count * Cycles per Instruction/ clock rate
CPU execution time = (IC * CPI) / clock rate
(IC * CPI) (A) / clock rate(A) = (IC * CPI)B / clock rate(B)
(IC * 1.9) (A) / clock rate(A) = (IC * (1.1 * (1.0 - 0.20)))(B) / 800 * 10⁶ (B)
Notice that 0.20 is basically from 20% less instructions
(IC * 1.9) / clock rate = (IC * (1.1 * (1.0 - 0.20))) / 800 * 10⁶
(IC * 1.9) / clock rate = (IC*(1.1 * ( 0.8))/800 * 10⁶
(IC * 1.9) / clock rate = (IC * 0.88) / 800 * 10⁶
clock rate (A) = (IC * 1.9) / (IC * 0.88) / 800 * 10⁶
clock rate (A) = (IC * 1.9) (800 * 10⁶) / (IC * 0.88)
clock rate (A) = 1.9(800)(1000000) / 0.88
clock rate (A) = (1.9)(800000000) / 0.88
clock rate (A) = 1520000000 / 0.88
clock rate (A) = 1727272727.272727
clock rate (A) = 1.7 GHz
The code below is supposed to display the name and score for the student with the highest score one time before the program ends. It is displaying Jim as the student with the highest score. It is displaying the highest score of 95. Unfortunately, Jim does not have a score of 95. Correct the following code:
Declare String students[SIZES] = {"Jen", "Jon", "Jan", "Joe", "Jim"}
Declare Integer scores[SIZES] = 70, 85, 72, 95, 90
Declare Integer index Declare Integer highest = scores[0]
Declare Integer highest Name = " " For index = 0
To SIZES //Assume that this translates to For (index = 0; index <= SIZES, index ++)
If scores[index] > highest then highest = scores[index]
End Of highestName = students[index]
End For Display "
The name of the student with the highest score is ", highest Name Display "The highest score is ", highest
Answer:
Modify
If scores[index] > highest then highest = scores[index]
End Of highest
Name = students[index]
End For Display
to
If scores[index] > highest then highest = scores[index]
Name = students[index]
End Of highest
End For Display
Explanation:
In the code, you posted the code segment that gets the name of the student with the highest score is outside the if condition that determines the highest.
To make correction, we only need to bring this code segment into the loop.
See Answer
Create a class named Invoicing that includes three overloaded computeInvoice() methods for a book store: see pages 196 for examples… The 8% tax should be defined as a constant.
1. When computeInvoice() receives a single parameter, it represents the price of one book ordered. Add 8% tax and display the total due.
2. When computeInvoice() receives two parameters, they represent the price of a book and the quantity ordered. Multiply the two values, add 8% tax, and display the total due.
3. When computeInvoice() receives three parameters, they represent the price of a book, the quantity ordered, and a coupon value. Multiply the quantity and price, reduce the result by the coupon value, and then add 8% tax and display the total due.
Create a driver class named TestInvoice with a main() method that tests all three overloaded methods using the following data: Price $24.95 Price, $17.50, quantity 4, Price $10.00, quantity 6, coupon $20.00 Output printed to Eclipse Console:
Price $26.95
Price $76.95
Price $43.20
Answer:
Follows are the method to this question:
class Invoicing //defining a class Invoicing
{
public static final double Tax = 8.0; //defining static variable Tax that holds a value
public static double Total;//defining a double variable Total
public void computeInvoice(double p1)//defining method computeInvoice that take double parameter
{
Total = p1 + p1 * (Tax / 100);//defining double variable Total that holds Price value
System.out.printf("Price $%.2f\n" , Total);//print calculated value
}
public void computeInvoice(double p2, int q)//defining method computeInvoice that takes integer and double parameter
{
Total = p2 * q;//use Total variable that calculate Price with Tax
Total = Total + (Total * (Tax/ 100));//calculate taxes on Total
System.out.printf("Price $%.2f\n" , Total);//print calculated value
}
public void computeInvoice(double p3, int q, double c)//defining method computeInvoice that takes one integer and two-double parameter
{
Total = p3 * q;//use Total to calculate Total price
Total = Total - c;//remove coupon amount from Total amount
Total = Total + (Total * (Tax/ 100));//calculate taxes on Total
System.out.printf("Price $%.2f\n" , Total);//print calculated value
}
}
public class TestInvoice //defining Main class TestInvoice
{
public static void main(String[] ar)//defining main method
{
Invoicing obm = new Invoicing ();//creating Invoicing class object obm
obm.computeInvoice(24.95);//calling method computeInvoice
obm.computeInvoice(17.5, 4);//calling method computeInvoice
obm.computeInvoice(10, 6, 20);//calling method computeInvoice
}
}
Output:
please find attached file.
Explanation:
In the above-given code, a class "Invoicing" is defined, inside the class two static double variable "Total and Tax" is defined, in which the Tax variable holds a value that is "8.0".
In class three same method, "computeInvoice" is used that accepts a different parameter for providing method overloading, which can be defined as follows:
In the first method, it accepts a single double parameter "p1", and inside the method, it uses the "Total" variable to calculate price value.In the second method, it accepts one integer and one double parameter "q and p2", and inside the method, it uses the "Total" variable is used to calculate the price with tax and print its value.In the third method, it accepts one integer and two double parameters "q, p3, and c", and inside the method, it uses the "Total" variable is used to calculate the price with tax and include tax and print its value.In the next step, the main class "TestInvoice" is defined inside the main method, Invoicing object is created and call its method.Which function is used to display a string value to the screen?
main[]
print()
run=
SHOW!
Answer:
The correct answer to this question is given below in the explanation section.
Explanation:
in most programming languages, the print() function is used to display a string value to the screen. Because, the print function prints all the string given in it as a parameter.
for example: to print hello world.
we use the function to print hello world as print("hello world").
However, it noted that other options are not correct because the main() function is an entry point of a program and it does not print string value to the screen. while run and show function do not print string value of screen also.
Answer:
in python print()
Which of the following domestic appliances does not use a magnet?
A. Fridge
B. Pressing iron
C. Radio
D. Fan
A _____ is a smaller image of a slide.
template
toolbar
thumbnail
pane
Which of the following is NOT a period of the Middle Ages?
Early Middle Ages
O Late Middle Ages
O High Middle Ages
O New Middle Ages
allowing is NOT an artifact of the Information Age?
The one that is not a period of the Middle Ages is the High Middle Ages. The correct option is c.
What are different ages?The Middle Ages, which roughly correspond to the years 500 to 1400–1500 BCE, is the term used to describe this time of European history. The phrase was initially used by academics in the 15th century to refer to the time frame between their own era and the dissolution of the Western Roman Empire.
The period between the fall of Imperial Rome and the start of Early Modern Europe is referred to as the “Middle Ages” for this reason. The reason the Middle Ages are known as the Dark Ages is that life was hard and brief in Europe, and contrasted with the orderliness of classical antiquity.
The time period in European history from roughly 500 AD to 1500 AD. This time period's early years are commonly referred to as the Dark Ages.
Therefore, the correct option is c, High Middle Ages.
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Which of the following is NOT solely an Internet-based company?
Netflix®
Amazon®
Pandora®
CNN®
Answer:
I think it's Pandora, though I am familiar with others
Answer:
CNN
Explanation:
c Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in an expression.
Answer:
maxSum = FindMax(numA, numB) + FindMax(numY, numZ);
Explanation:
In the statement, maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using which are found by calling the FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS + sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum. The screenshot of program along with its output is attached.
What is a small device that connects to a computer and acts as a modem
Answer:
Dongle
Explanation:
a small device that connects to a computer and acts as a modem. broadband. internet connection with fast data-transfer speeds and an always-on connection. cable internet service.
What is the missing line of code? >>> sentence = "Programming is fun!" 'gr O sentence[2:6] sentence[3:5] sentence[3:6] sentence[2:5]
Answer: not sentence [3:6]
I hope this helps
Explanation:
In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation during its current time quantum? The process will terminate itself. The process will be terminated by the operating system. The process's state will be changed from running to blocked. None of the mentioned.
Answer:
B. The process will be terminated by the operating system.
Explanation:
When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.
So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.
Based on the information given regarding CPU scheduling, the correct option is C. The process's state will be changed from running to blocked.
It should be noted that in a system where Round Robin is used for CPU scheduling, when a process cannot finish its computation during its current time quantum, the process's state will be changed from running to blocked.
It should be noted that a prices transition to a blocked state occurs when it's waiting for some events like a particular resource becoming available.
Learn more about CPU scheduling on:
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Which of the following tabs in the PowerPoint Ribbon is unique to PowerPoint,
not found in other Microsoft Office applications?
a.
b.
Home
Animations
Insert
View
Answer:
The answer to this question is given below in the explanation section
Explanation:
The correct option for this question is Animation tab.
Animation tab in PowerPoint ribbon is a unique tab that is not found in other office applications such as in word, excel, outlook, publisher etc.
Because in PowerPoint you can use animation to make your slides animated and all animation can be managed and animation-related settings, you can find in the animation tab.
However, other tabs such as Home, Insert, and View are common in all office applications.
802.11ac provides an advantage over 802.11n by incorporating increased channel bonding capabilities. What size bonded channels does 802.11ac support?
Answer:
The 802.11ac wireless standard takes channel bonding to a higher level because it can support 20MHz, 40MHz, and 80MHz channels, with an optional use of 160MHz channels.
Explanation:
The 802.11ac is a standardized wireless protocol established and accepted by the institute of electrical and electronics engineers (IEEE). 802.11ac as a wireless local area network (WLAN) protocol, has multiple amplitude and bandwidth, thus making it to be the first standard wireless protocol to have the ability to operate on a Gigabit (Gb) network.
Generally, the 802.11ac wireless standard provides an advantage over 802.11n by incorporating increased channel bonding capabilities. The 802.11ac wireless standard takes channel bonding to a higher level because it can support 20MHz, 40MHz, and 80MHz channels, with an optional use of 160MHz channels.
On the other hand, 802.11n is a standardized wireless protocol that can support either a 20MHz or 40MHz channel.
Consider a multiprocessor CPU scheduling policy. There are 2 options: 1) a singlecommon ready queue of jobs; when a CPU becomes free, the job atthe head of the queuegoes to this free CPU. 2) a ready queue for each CPU; the arriving job joins the shortestqueue. In general, do you expect the common queue or the shortest queue policy to performbetter. Justify.
Explanation:
A ready queue is more adequate since in this method the load balancing occurs in a proper way. The goal of multiple processing is the correct distribution of load.
But in the cases when a processor is doing quicker or taking a smaller queue, it will self assign processes allotted for execution, configuring it with a constant busy state.
def build_dictionary(string):
d = dict()
for x in string:
if not d.get(x):
d[x] = 1
else:
d[x] += 1
return d
Part 2:
Create a function named build_word_counter that has the same signature as build_dictionary. This function also returns a dictionary, however, it normalizes each word such that the case of the word is ignored (i.e. case insensitive). So the words LIKE, Like, like should be considered the same word (much like a regular dictionary would). You must use the same function add_item again (so don't make any modifications to it) Normalize words by using the lower case version of the word.
Part 3:
Create a function named build_letter_distribution that has the same signature as build_dictionary. This function returns a dictionary; however, each key will be a letter and the value will be the count that represents how many times that letter was found. Essentially you will have a letter distribution over a sentence (which is a list of words). The letters should be case insensitive.
Answer:
Follows are the code to this question:
def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter
d = dict()#defining d variable as a dictionary
for x in string:#defining for loop that use string
x = x.lower()#Use lower method
if not d.get(x):#defining if block that holds value in d variable
d[x] = 1#use dictionary to hold value in 1
else:#defining else block
d[x] += 1#use dictionary to increment value by 1
return d#return dictionary
print(build_word_counter(["Like","like","LIKE"]))#use print method to call method
def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable
d = dict()#defining d variable as a dictionary
for i in string:#defining for loop to count string value
for j in i:#defining for loop to hold string as number
if not d.get(j):#defining if block that doesn't get value in dictionary
d[j] = 1#hold value in dictionary
else:#defining else block
d[j] += 1#use dictionary to increment the dictionary value
return d#return dictionary
print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value
Output:
please find the attached file.
Explanation:
In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.
In the next step, a conditional statement is used that holds value in the dictionary and count its word value.
In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.