ginny and carter are learning about probability and their teacher hands them a bag with 18 red marbles and 10 green marbles. ginny draws 2 red marbles and keeps them on her desk. carter wants to draw green marbles on his turn. how did the probability of drawing a green marble change from when ginny drew her marbles to when carter will draw?

The term for the probability that a value falling outside the control limits is still due to normal variation is called the Type I error or the alpha error.

The term for the probability that a value falling outside the control limits is still due to normal variation is called the Type I error or alpha error.

It refers to the probability of rejecting a true null hypothesis (in this case, the process is in control) when it should not be rejected. In other words, it is the probability of concluding that there is a problem with the process when there is actually no problem, and the observed value is simply a result of random variation.

This means that the value appears to be abnormal, but it is actually just a result of the natural variation in the process. It is important to minimize the risk of Type I errors to ensure that only truly abnormal values are addressed and corrected.

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According to simple interest, Sally initially put $1,150 into the savings account.

To solve this problem, we need to use the formula for simple interest, which is:

Simple Interest = Principal x Rate x Time

We know that the interest earned is $745.20, the rate is 7.2%, and the time is 9 years. We can plug these values into the formula and solve for the principal:

$745.20 = Principal x 0.072 x 9

$745.20 = 0.648 x Principal

Principal = $1,150

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Answer: the exact value of tan(13π/12) is √3 + 2.

Step-by-step explanation: The trigonometric equation demonstrating the equality between the tangent of 13π/12 and the tangent of 3π/4 added to π/3 may be expressed in the formal and technical tone often employed in academic writing as follows: tan(13π/12) = tan(3π/4 + π/3).

Through utilization of the identity, tan(a+b) = (tan(a) + tan(b)) / (1 - tan(a)*tan(b)), the given expression may be rendered more concise.

The trigonometric expression tan(13π/12) can be represented as (tan(3π/4) + tan(π/3)) divided by (1 - tan(3π/4) multiplied by tan(π/3)).

It is established that:

it can be observed that the value of the trigonometric function of tan(3π/4) is -1.

The mathematical expression "tan(π/3) = √3" signifies that the trigonometric tangent function of the angle π/3 is equivalent to the square root of three.

Upon substitution of the aforementioned values, the resulting output is obtained.

The trigonometric function of tan(13π/12) can be expressed as a quotient between two real numbers. Specifically, it can be represented in the form (-1 + √3) / (1 + (-1) * √3).

By utilizing the conjugate of the denominator and performing the operation of multiplication on both the numerator and denominator, the resulting expression is obtained:

The trigonometric function of tangent evaluated at 13π/12 is expressed as the product of two fractions. The numerator of the first fraction is comprised of the difference of the values -1 and the positive square root of 3, while the denominator is the sum of the value 1 and the product of -1 and the square root of 3. The numerator of the second fraction is the sum of the values 1 and the positive square root of 3, while the denominator is the sum of the same values.

The trigonometric identity expressed as tan(13π/12) has been rendered in symbolic form, wherein the numerator is the summation of -1, √3, √3, and -3. The denominator is the product of (1 + √3) and (1 - √3).

The mathematical expression tan(13π/12) can be represented as (-2√3 - 4) / (-2).

The mathematical expression tan(13π/12) is equivalent to the value of √3 + 2.

Your answer is option b)

The time at which a star rises shifts approximately 4 minutes earlier each day, due to Earth's orbit around the Sun. Since there are roughly 30 days in a month, we can calculate the change in the rise time of Aldebaran over the course of a month.

Step 1: Calculate the time change over one month
30 days * 4 minutes per day = 120 minutes

Step 2: Convert minutes to hours
120 minutes ÷ 60 minutes per hour = 2 hours

Step 3: Subtract the time change from the current rise time
2:00 am - 2 hours = 12:00 am (midnight)

Therefore, you can expect Aldebaran to rise next month at midnight. The correct answer is b) midnight.

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The equation b = 12 - (-3) would help to answer question C, "The temperature was -3 degrees and rose to 12 degrees. How much did the temperature change?"

This is because the equation b = 12 - (-3) simplifies to b = 12 + 3, which gives us the value of b (the temperature change) when the starting temperature was -3 degrees and the final temperature was 12 degrees.

The subtraction of a negative number (i.e., -3) is the same as adding its absolute value (i.e., 3), so the equation can be rewritten as b = 12 + 3. Therefore, the value of b is 15, which represents the temperature change from -3 degrees to 12 degrees.

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Using circle theorems CD =  9.17

Circle theorems are theorems that govern circle properties.

Given that form the figure EF = 8, ON = 3 and OM = 2, we need to find CD.

From the figure using Pythagoras' theorem

OE² = ON² + EN²

= ON² + (EF/2)²

= 3² + (8/2)²

= 3² + 4²

= 9 + 16

= 25

OE = √25

= 5

Also, OD² = OM² + DM²

Making DM subject of the formula, we have that

DM² = OD² - OM²

DM = √(OD² - OM²)

Now OD = OE = 5

So, we have that

= √(OD² - OM²)

= √(OE² - OM²)

= √(5² - 2²)

= √(25 - 4)

= √(25 - 4)

= √21

= 4.58

Now CD = 2DM

= 2 × 4.58

= 9.17

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Answer:48

Step-by-step explanation:

The length or value of d is 3m

What is meant by length?

Length is a measurement of how long something is, typically referring to the longest dimension of an object or space. It is a fundamental physical quantity and can be measured in various units, such as meters, feet, or inches. Length is important in many fields, including mathematics, science, and engineering.

According to the given information

In a right-angled triangle, the side opposite to the 90-degree angle is called the hypotenuse. The side opposite to the 60-degree angle is equal to the hypotenuse multiplied by the square root of 3 divided by 2. Since AC is the hypotenuse and its length is given as 2*(√(3))m, we can find the length of BC (d) as follows:

d = (AC * √(3)) / 2 d = (2 * √(3) * √(3)) / 2

d = 3m

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the value of c is 11.165 lbs. This was calculated using the z-score formula, assuming a normal distribution with a mean weight of 10 lbs and a standard deviation of 0.5 lbs. This ensures that 99% of all parcels are at least 1 lb under the surcharge weight.

To find the value of c, we need to use the standard normal distribution and the z-score formula. Since we know that 99% of all parcels are at least 1 lb under the surcharge weight, we can use the z-score associated with the 99th percentile, which is 2.33 (from a z-score table).

The formula for the z-score is:

z = (x - μ) / σ

where x is the weight of the parcel, μ is the mean weight, and σ is the standard deviation.

In this case, we want to find the weight of the parcel that is at the 99th percentile, which is 1 lb under the surcharge weight. Let's call this weight x. We know that the surcharge weight is c, so the weight of the parcel that is 1 lb under the surcharge weight is (c - 1).

Using the z-score formula and substituting the values we know, we get:

2.33 = ((c - 1) - μ) / σ

We want to solve for c, so we need to rearrange the equation:

c - 1 = 2.33σ + μ
c = 2.33σ + μ + 1

We don't know the values of μ and σ, but we can use the fact that the distribution is normal to estimate them. We can assume that the distribution is centered at the mean weight of all parcels, and that the standard deviation is equal to the average difference between the weight of each parcel and the mean weight.

Let's say that the mean weight is 10 lbs, and the standard deviation is 0.5 lbs. Then, we can plug these values into the equation for c:

c = 2.33(0.5) + 10 + 1
c = 11.165

So, the value of c that ensures that 99% of all parcels are at least 1 lb under the surcharge weight is approximately 11.165 lbs.

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Answer:

62.5%

Step-by-step explanation:

The number of states do not use nuclear: 20 + 12 = 32

The number of states that do not use nuclear and use coal: 20

so 20/32 = 5/8 = 62.5%

After Jenny invested the $1900 in a 5-year CD,

A) Given principal money (P) = $1900

Rate of interest (r) = 1.47% / 100 = 0.047

number of times interest compounded per year (n) = 4

number of years (t) = 5

Amount Jenny will have after 5-years (A) = [tex]p(1+r/n)^{nt}[/tex]

A = [tex]1900(1+0.047/4)^{4*5}[/tex]

A = [tex]1900(1 + 0.01175)^{20}[/tex]

A = [tex]1900(1.01175)^{20}[/tex]

A = 1900(1.2631) ≅ $2400

B) Interest earned after 5 years = $2400 - $1900 = $500.

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The average rate of change in revenue as the number of bluetooth speakers sold increases from 20 to 40 units is $34.50 per unit.

To find the average rate of change in revenue, we need to calculate the change in revenue over the change in units sold.

First, let's calculate the revenue for 20 and 40 units sold:

R(20) = 35(20) - 0.01(20)^2 = $670

R(40) = 35(40) - 0.01(40)^2 = $1360

Now we can calculate the change in revenue:

ΔR = R(40) - R(20) = $1360 - $670 = $690

And the change in units sold:

Δx = 40 - 20 = 20

Finally, we can calculate the average rate of change in revenue:

ΔR/Δx = $690/20 = $34.50

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Answer: 3.610^5+4.810^4 in scientific notation is 4.08*10^5.

Step-by-step explanation: The initial step to convert 3.610^5+4.810^4 into scientific notation is to combine the two values.

The sum of 3610 multiplied by 10 to the power of 5 and 4810 multiplied by 10 to the power of 4 is equal to adding 3610 multiplied by 10 to the power of 4 and 4810 multiplied by 10 to the power of 4, resulting in 40.8 multiplied by 10 to the power of 4.

We can convert 40.8*10^4 to scientific notation by shifting the decimal point to the left until there is only one non-zero digit to the left of the decimal, and denoting the number of decimal places moved with a 10 exponent.

Rewording: When you raise 40.810 to the power of 4, the result is 4.0810 to the power of 5 when you add 1 to the exponent. This is equivalent to multiplying 4.08 by 10 and raising it to the power of 5.

The distance between Thomas St and Denny Way on Broad St is approximately 0.2 miles (rounded to the nearest tenth of a mile).

To determine the distance between Thomas St and Denny Way on Broad St, we can use the Pythagorean theorem.

Let x be the distance between Thomas St and Denny Way on Broad St. We can draw a right triangle where the hypotenuse is 0.2 miles (the distance between Thomas St and Denny Way on Aurora Ave), and one leg is x (the distance between Thomas St and Denny Way on Broad St). The other leg is the distance between Aurora Ave and Broad St.

Using the Pythagorean theorem, we have:

[tex]0.2^2 = x^2 + d^2[/tex]

where d is the distance between Aurora Ave and Broad St.

Assuming d is negligible, we can solve for x:

[tex]x^2 = 0.2^2 - d^2x^2 = 0.2^2x = sqrt(0.2^2) = 0.2[/tex]

Therefore, the distance between Thomas St and Denny Way on Broad St is approximately 0.2 miles (rounded to the nearest tenth of a mile).

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The difference between the high and low prices on October 20 is $3.33  

On October 27, the actual volume of discovery group shares posted is 2360000

The price that Discovery group clothes on October 19 is $36.94

The difference in the prices as a percent increase is 0.76%

The number change from October 20 to October 21 as a percent rounded to the nearest tenth of a percentage is -16.9%

The net change from October 27 to October 28 as a percent, rounded to the nearest tenth of a percent is 14.8%

The reason why 52 week high and 52 week low numbers are the same in both charts is that there was no price higher than $76.19 or lower than $22.78 for those weeks.

The closing price one year earlier is $54.60

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The ratio of the areas of the bases of the two similar prisms is approximately 26 to 1.

What is the scale factor?

A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).

Let h1 and h2 be the heights of the two similar prisms, and let A1 and A2 be the areas of their respective bases.

Also, let k be the scale factor that relates the smaller prism to the larger prism.

a. We know that the volumes of the two similar prisms are proportional to the cubes of their corresponding side lengths, so we have:

(kh1)³ / (kh2)³ = 135 / 5000

Simplifying this expression, we get:

h1³ / h2³ = 135 / 5000

Taking the cube root of both sides, we get:

[tex]h1 / h2 = (135 / 5000)^{(1/3)}[/tex]

Using a calculator, we find:

h1 / h2 ≈ 0.405

Therefore, the ratio of the heights of the two similar prisms is approximately 0.405 to 1.

b. The ratio of the areas of the bases of two similar prisms is equal to the square of the scale factor. That is:

A1 / A2 = k²

To find the scale factor k, we can use the fact that the volumes of the two prisms are proportional to k³. Therefore:

k³ = 5000 / 135

k ≈ 5.091

Using this value of k, we get:

A1 / A2 = k² = (5.091)² ≈ 26

Therefore, the ratio of the areas of the bases of the two similar prisms is approximately 26 to 1.

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Answer:

the two-digit number is 65.

Step-by-step explanation:

Let's assume that the tens and units digits of the two-digit number are x and y, respectively.

According to the given condition,

10x + y < 6(x + y) - 1 (less than 6 times the sum of its digits by 1)

Simplifying the above equation, we get:

4x - 5y < -1 (dividing both sides by 2)

Also, it is given that the difference between the digits is 1, so we can write:

x - y = 1 (difference between the digits is 1)

Now, we need to solve these two equations to find the values of x and y.

Multiplying the second equation by 4, we get:

4x - 4y = 4

Adding this equation to the first equation, we get:

4x - 5y + 4x - 4y = 3

Simplifying the above equation, we get:

8x - 9y = 3

Now, we can solve these two equations simultaneously to find the values of x and y.

Multiplying the second equation by 8, we get:

8x - 8y = 8

Subtracting this equation from the previous equation, we get:

y = 5

Substituting this value of y in the equation x - y = 1, we get:

x - 5 = 1

x = 6

Therefore, the two-digit number is 65.

The volume of the given cone with a height of 17.3 and a diameter of 10.4 is  489.87 cubic cm

The volume of any cone can easily be determined by the formula (pi*r*r)*(h/3) where pi has the value of 3.14, 'r' is the radius of the cone, and 'h' is the given height of the cone.

Here in the given question, we can see that the height(h) given here is 17.3cm and the diameter is 10.4cm with which we can find the radius because we know the radius is the half of diameter so 'r' will be 5.2cm.

Now just putting the values of 'h' and 'r' in the given formula (pi*r*r)*(h/3)  we get the volume of the cone which is 489.87 cubic cm.

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Answer:

Step-by-step explanation:

here,

height h= 17.3cm

diameter= 10.4cm

therefore, radius r will be 5.2cm

pi= 3.14

solution:

volume v of cone= 1/3*pi*r2*h

= 1/3*3.14*5.2*5.2*17.3 cm3

= 489.7 cm3

explanation:

here, it is given that the height is 17.3cm and the radius is 5.2cm. we know that the formula for finding the volume of a cone is 1/3*pi*r2*h.

Answer: 1,200

Step-by-step explanation: 1,300 - 100 = 1,200

From the defined functions in problem, the functions that are mapped from z to z, and onto functions are f(n) = n - 1, [tex] f( n) = [\frac{n}{2}] [/tex]. So, option(a) and option(d) are right choice.

Onto functions work on the codomain. Here we want to check if it contains elements not associated with any element in the domain. Definition: A function f: A→B is onto if, for every element b∈B, there exists an element a∈A such that f(a)=b. An onto function is also called surjective. We have a number of functions that are mapped from Z to Z and we will identify which is onto function or not. Let's consider each one by one

a) f : Z→Z such that f( n) = n - 1

For all m∈Z( Co-domain) and consider (m - 1)∈Z( domain) s.t f( m) = m - 1 = m -1 i.,e., f(a) = b. So, it is an onto function.

b) f : Z→Z such that f( n) = n² + 1

For all m∈Z( Co-domain) and consider (m - 1)∈Z( domain) s.t f( m) = m² + 1 i.,e., two values of m exist and f(a) ≠ b.So, it is not onto function.

c) f : Z→Z such that f( n) = n³ ( cubic function), If f(n) = 2, where n( domain) and 2 (co-domain)

=> n³ = 2

=> n = 2⅓

So, it is not onto function.

d) f : Z→Z such that,[tex]f( n) = [\frac{n}{2}] [/tex]

For all m∈Z( Co-domain) and consider 2m∈Z( domain) s.t f( 2m) = [tex]f(2m) = [\frac{2m}{2}] [/tex]

= m

So, for every m there exits 2m such that, f(2m) = m. Hence, the onto functions are f( n) = n - 1 and [tex]f( n) = [\frac{n}{2}] [/tex].

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Answer: B symmetric

Step-by-step explanation:

Since every value in a constant-distribution has the same chance of happening, the distribution is symmetric. The mean and median are both identical to this value because there is only one value, which also makes it the mode.

The mode may or may not be equal to the mean and median for a symmetric distribution, but they are always equal. The mean is often higher than the median and the mode may be lower than the median in a positively skewed distribution. The mode may be higher than the median and the mean is often lower in a negatively skewed distribution.

A constant-probability distribution is a form of probability distribution in which the likelihood of each possible result is the same. In other words, there is an equal chance of each outcome.

Therefore , The Constant-distribution is a sort of probability distribution where the mean, median, and mode are all equal.

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The probability that a congressman selected at random supports Bill A or Bill B is 0.83.

The probability that a congressman selected at random supports Bill A but not Bill B is 0.21.

The probability that a congressman selected at random supports neither Bill A nor Bill B is 0.17.

P(Bill A or Bill B) = P(Bill A) + P(Bill B) - P(Bill A and Bill B) = 0.35 + 0.62 - 0.14 = 0.83

ii. The probability that a congressman selected at random supports Bill A but not Bill B is the probability in the Bill A circle that is not in the overlap:

P(Bill A but not Bill B) = P(Bill A) - P(Bill A and Bill B) = 0.35 - 0.14 = 0.21

iii. P(neither Bill A nor Bill B) = P(not Bill A and not Bill B) = 0.17

Therefore, the probability that a congressman selected at random supports neither Bill A nor Bill B is 0.17.

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We reject the null hypothesis and conclude that the true average temperature of COVID patients exceeds 100, with a type I error rate of 10% and a p-value of 0.0068 indicating a low probability of obtaining the observed sample mean if the null hypothesis were true.

To test if the true average temperature of COVID patients exceeds 100, we can use a one-sample z-test.

The null and alternative hypotheses are

Null hypothesis: The true average temperature of COVID patients is less than or equal to 100.

Alternative hypothesis: The true average temperature of COVID patients exceeds 100.

We can calculate the test statistic as

z = (x - μ) / (σ / sqrt(n))

where x is the sample mean, μ is the hypothesized population mean (100 in this case), σ is the population standard deviation, and n is the sample size.

Substituting the given values, we get

z = (101.2 - 100) / (6 / sqrt(56))

z = 2.47

We can find that the p-value is 0.0068. This means that if the true average temperature of COVID patients is actually 100, there is only a 0.68% chance of getting a sample mean of 101.2 or higher.

Since the alpha level is 10%, and the p-value is less than 10%, we reject the null hypothesis and conclude that the true average temperature of COVID patients exceeds 100.

The type of error that could have occurred is a type I error, which is rejecting the null hypothesis when it is actually true. The probability of a type I error is equal to the chosen alpha level, which is 10% in this case.

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I choose City Bus as mode of transport since from function rule it is clear that the per mile cost for City Bus is lesser than any other transportation.

Option 1: Let the model for Taxi be f(x) = ax + b, where f(x) is total cost and x is number of miles.

From the table of Taxi we get, f(3) = 26.95; f(6) = 28.90; f(9) = 30.85 and f(12) = 32.80.

So, 3a + b = 26.95 and 6a + b = 28.90

So, (6a + b) - (3a + b) = 28.90 - 26.95

3a = 1.95

a = 1.95/3 = 0.65

Now, f(9) = 30.85

9*0.65 + b = 30.85

5.85 + b = 30.85

b = 30.85 - 5.85 = 25

So the model is, f(x) = 0.65x + 25

Option 2: Let the model for City Bus be f(x) = cx + d, where f(x) is total cost and x is number of miles.

From the table of Taxi we get, f(2) = 0.60; f(4) = 1.20; f(6) = 1.80 and f(8) = 2.40.

So, 2a + b = 0.60 and 4a + b = 1.20

(4a + b) - (2a + b) = 1.20 - 0.60

2a = 0.60

a = 0.60/2 = 0.30

Now, f(8) = 2.40

8*0.30 + b = 2.40

2.40 + b = 2.40

b = 2.40 - 2.40 = 0

So the function rule for City Bus is, f(x) = 0.3x.

Option 3: From the graph of Light Rail we can see that for any distance travelled total cost remains same that is 15.

So the function rule for Light Rail will be a constant function is, f(x) = 15

Option 4: Let the model for Motorized Scooter be f(x) = mx + n, where f(x) is total cost and x is number of miles.

From the graph we can see that, f(0) = 5, f(1) = 6, f(3) = 8 etc.

So, n = 5

and m + n = 6

m + 5 = 6

m = 6 - 5 = 1

Hence the function rule for Motorized Scooter is, f(x) = x + 5.

Hence I choose City Bus as mode of transportation as the per mile cost for that transportation mode is less than any other.

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Answer:

- w - 24

Step-by-step explanation:

- 4(w + 6) + 3w ← multiply each term in the parenthesis by - 4

= - 4w - 24 + 3w ← collect like terms

= (- 4w + 3w) - 24

= - w - 24

The biggest effect of electing so many public officials is that it can be difficult for voters to make informed decisions.

With so many candidates to choose from, voters may not have the time or resources to thoroughly research each candidate and their qualifications. This can lead to uninformed voting, where voters may simply choose a candidate based on their name recognition, party affiliation, or other superficial factors.

Additionally, contested elections can also lead to an increase in negative campaigning and attack ads, which can further cloud voters' perceptions of the candidates and the issues at stake. Ultimately, electing a large number of public officials can make it harder for voters to feel confident in their choices and can undermine the democratic process.

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The primary condition for which a patient is receiving care is communicated to the third-party payer through a diagnosis code on the healthcare claim.

The diagnosis code is a standardized code that represents the patient's medical condition or illness as determined by the healthcare provider. These codes are typically based on the International Classification of Diseases (ICD) coding system, which is used worldwide for reporting diagnoses and medical procedures.

By including the appropriate diagnosis code on the healthcare claim, healthcare providers can communicate to third-party payers the reason for the services or procedures provided. This information is essential for processing and reimbursing healthcare claims accurately and efficiently.

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The primary condition for which a patient is receiving care is communicated to the third-party payer through a(n) ICD (International Classification of Diseases) code on the healthcare claim.

The ICD code serves as a standardized system for classifying diseases and health conditions, enabling clear

communication between healthcare providers and third-party payers.

The primary condition for which a patient is receiving care is communicated to the third-party payer through a

diagnosis code on the healthcare claim. Diagnosis  codes, also known as ICD codes (International Classification of

Diseases codes), are standardized codes that represent the specific medical condition or disease being treated by the

healthcare provider.

These codes are used to ensure accurate and timely payment for services rendered and to track healthcare utilization

and outcomes.

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Answer:

Hello thanks for submitting here is the equation commonly known for this type of thing!

Equation y = 12.50x. 2

If you need the answer let me know!

Answer:

The numbers in order from biggest to smallest are: 0.925, 0.9, 0.871, 0.87, 0.637, 0.62, 0.125, 0.012, and 0.01.

Step-by-step explanation:

To order these numbers from biggest to smallest, I compared the digits in each decimal place starting from the tenths place. For example, the number with the largest digit in the tenths place is 0.9. If two or more numbers have the same digit in the tenths place, I then compared the digits in the hundredths place and so on until I found which number was larger.