Answer:
11.502
Step-by-step explanation:
If you get paid $520 for 2 weeks at $13 per hour, how many hours did you
work each week?
O 40
O 30
O 20
O 10
Answer:
20 hours
Step-by-step explanation:
for 1 week 560/2
=260
calculation for working hours
Total wage=Rate per hour × actual time spend on working.
Let actual working hours be (x)
260=13×X
260/13=X
20=X
20 hours
Jazmin and Justine went shopping for back to chool clothes. Jazmin purchasrd three shirts and one pair of shorts ans spent $38. 0. Justine bought four shirts and three pairs of shorts and spent $71. 50.
Part A: Assumibg all the shirts cost the same amount and all the shorts cost the same amount, write a system os equations to represent each girl's shoppins spree
Part B: Use the elimination method to solve for the price of one pair of shorts
The equations to represent each girl's shoppins spree is 3x + y = 38.0 and 4x + 3y = 71.50. Price of one shirt costs $8.50 and price of one pair of shorts costs $12.50.
Let x be the price of one shirt, and y be the price of one pair of shorts. Then, we can write the following system of equations
For Jazmin
3x + y = 38.0
For Justine
4x + 3y = 71.50
To solve for the price of one pair of shorts using elimination method, we need to eliminate one of the variables. We can do this by multiplying the first equation by 3 and the second equation by -1, and then adding them together
9x + 3y = 114.0
-4x - 3y = -71.50
5x = 42.50
x = 8.50
So, one shirt costs $8.50.
To find the price of one pair of shorts, we can substitute the value of x into either of the original equations and solve for y. Using the first equation
3(8.50) + y = 38.0
25.50 + y = 38.0
y = 12.50
Therefore, one pair of shorts costs $12.50.
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Find an equation for the perpendicular bisector of the line segment whose endpoints
are(-1, , -8) and (5, 4).
An equation in slope-intercept form for the perpendicular bisector of the line segment with endpoints (-1, -8) and K (5, 4) is y = 2x - 6.
How to determine an equation of this line?In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):
y - y₁ = m(x - x₁)
Where:
m represent the slope.x and y represent the points.First of all, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (4 + 8)/(5 + 1)
Slope (m) = 12/6
Slope (m) = 2.
At data point (-1, -8) and a slope of 2, a linear equation in slope-intercept form for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - (-8) = 2(x - (-1))
y + 8 = 2x + 2
y = 2x - 6.
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PLEASE is due very soon please explain
Answer:
1) The image of the line has the same slope as the pre-image but a different y-intercept.
hope this helps ;)
In Problems 55–62 write each function in terms of unit step functions. Find the Laplace transform of the given function. = {0, 0<_t<1 f(t) = {t^(2) t>_ 1
The Laplace transform of the given function f(t) = {0, 0 < t < 1, t², t ≥ 1} is 2s⁻³.
Given the function f(t) = {0, 0 < t < 1, t², t ≥ 1}, we need to find its Laplace transform. The Laplace transform of a function f(t) is denoted by F(s) and is defined as follows:
F(s) = L{f(t)} = ∫[0,∞) f(t)e⁻ᵃˣdt,
where s is a complex variable.
To find the Laplace transform of the given function, we need to split the function into two parts: one for 0 < t < 1 and another for t ≥ 1. For 0 < t < 1, f(t) = 0, so the integral becomes:
L{0} = ∫ 0e⁻ᵃˣdt = 0.
For t ≥ 1, f(t) = t², so the integral becomes:
L{t²} = ∫ t²e⁻ᵃˣdt.
To evaluate this integral, we can use integration by parts. Let u = t² and dv = e⁻ᵃˣdt, then du/dt = 2t and v = (-1/s) e⁻ᵃˣ. Using the integration by parts formula, we get:
L{t²} = ∫ t²e⁻ᵃˣdt = (-t²/s)e⁻ᵃˣ∣∣∣[0,∞) + (2/s)∫[0,∞) te⁻ᵃˣdt.
The first term in the above equation evaluates to zero because e⁻ᵃˣapproaches zero as t approaches infinity. Using integration by parts again for the second term, we get:
L{t²} = (-t²/s)e⁻ᵃˣ∣∣∣[0,∞) + (2/s)(-t/s)e⁻ᵃˣ∣∣∣[0,∞) + (2/s²)∫[0,∞) e⁻ᵃˣdt.
The first two terms in the above equation evaluate to zero for the same reason as before. The integral in the last term evaluates to (1/s²), so we get:
L{t²} = 2/s³.
Therefore, the Laplace transform of the given function f(t) is:
L{f(t)} = L{0} + L{t²} = 0 + 2/s³ = 2s⁻³.
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suppose the heights of professional horse jockeys are normally distributed with a mean of 62 in. and a standard deviation of 2 in. which group describes 16% of the population of horse jockeys?
The groups that describes 16% of the population of horse jockeys are option (c) jockeys who are shorter than 60 in. and (d) jockeys who are between 60 in. and 64 in.
To solve this problem, we need to use the standard normal distribution, where we can find the z-score associated with the given percentages using a z-table or calculator. The z-score tells us how many standard deviations a value is from the mean.
First, we can standardize the values using the formula
z = (x - μ) / σ
where z is the z-score, x is the value we want to standardize, μ is the mean, and σ is the standard deviation.
a) To find the jockeys who are shorter than 58 in., we can standardize the value as
z = (58 - 62) / 2 = -2
Using a z-table, we can find that the percentage of values below z = -2 is approximately 0.0228, which is less than 16%. Therefore, a) is not correct.
b) To find the jockeys who are taller than 64 in., we can standardize the value as
z = (64 - 62) / 2 = 1
Using a z-table, we can find that the percentage of values above z = 1 is approximately 0.1587, which is also less than 16%. Therefore, b) is not correct.
c) To find the jockeys who are shorter than 60 in., we can standardize the value as
z = (60 - 62) / 2 = -1
Using a z-table, we can find that the percentage of values below z = -1 is approximately 0.1587, which is less than 16%. Therefore, c) is correct.
d) To find the jockeys who are between 60 in. and 64 in., we can standardize the values as
z1 = (60 - 62) / 2 = -1
z2 = (64 - 62) / 2 = 1
Using a z-table, we can find the percentage between z1 and z2, which is approximately 0.6826. Therefore, d) is also correct.
Therefore, the correct answers are (c) jockeys who are shorter than 60 in. and (d) jockeys who are between 60 in. and 64 in.
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The given question is incomplete, the complete question is:
Suppose the heights of professional horse jockeys are normally distributed with a mean of 62 in. and a standard deviation of 2 in.
Which group describes 16% of the population of horse jockeys?
Select each correct answer.
a) jockeys who are shorter than 58 in.
b) jockeys who are taller than 64 in.
c) jockeys who are shorter than 60 in.
d) jockeys who are between 60 in. and 64 in.
a coach is interested in knowing if there is a difference in 40 yard dash times between collegiate soccer, football, and cross-country players. the independent variable in a study examining this difference is
The independent variable in the study examining the difference in 40 yard dash times between collegiate soccer, football, and cross-country players is the type of sport played by the athletes.
The coach is interested in comparing the 40 yard dash times of athletes from three different sports: soccer, football, and cross-country.
In this study, the independent variable is manipulated by selecting participants from each of the three sports. The athletes' 40 yard dash times will be the dependent variable, which is expected to vary based on the independent variable (i.e., the type of sport played by the athletes).
By comparing the 40 yard dash times of athletes from different sports, the coach can gain insights into how different types of athletic training and conditioning may affect speed and agility.
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a study timed left-handed and right-handed people to see how long it took them to hit a buzzer. the data is shown below: the forty two right handed people had an average of 1.7 s and a standard deviation of 1.4 s. the forty seven left handed people had an average of 1.1 s and a standard deviation of 0.4 s. the difference is 0.6 s, and the standard deviation of the matched pairs differences is 0.1 s. find an 82% confidence interval for the difference in left-handed or right-handed people. what z or t score should you use?
We can say with 82% confidence that the true difference in mean times for left-handed and right-handed people is between -0.978 s and -0.222 s and t-distribution is used.
To calculate the certainty interim for the contrast between left-handed and right-handed individuals, we are able to utilize the taking-after equation:
CI = (x1 - x2) ± t*SE
where:
x1 = the meantime for left-handed people
x2 = the meantime for right-handed people
t = the critical value for the t-distribution with n1+n2-2 degrees of freedom and the desired confidence level (in this case, 82%)
SE = the standard error of the difference in means, which is calculated as:
[tex]SE = sqrt((s1^2/n1) + (s2^2/n2))[/tex]
where:
s1 = the standard deviation for left-handed people
s2 = the standard deviation for right-handed people
n1 = the sample size for left-handed people
n2 = the sample size for right-handed people
Plugging in the given values, we get:
x1 - x2 = 1.1 - 1.7 = -0.6
s1 = 0.4
s2 = 1.4
n1 = 47
n2 = 42
[tex]SE = sqrt((0.4^2/47) + (1.4^2/42)) = 0.261[/tex]
To find the critical value for the t-distribution, we can use a t-table or a calculator. With n1+n2-2 = 87 degrees of freedom and an 82% confidence level, the critical value is approximately 1.360.
Thus, the 82% confidence interval for the difference in left-handed or right-handed people is:
CI = (-0.6) ± (1.360*0.261) = (-0.978, -0.222)
hence, we can say with 82% confidence that the true difference in mean times for left-handed and right-handed people is between -0.978 s and -0.222 s.
Note that we used the t-distribution because the sample sizes for both groups are relatively small (n1 = 47, n2 = 42).
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what is 55/63 in simplest form
55/63 is already in its simplified form.
To simplify 55/63, we can divide both the numerator and denominator by their greatest common factor (GCF). To find the GCF of 55 and 63, we can use prime factorization:
55 = 5 × 11
63 = 3 × 3 × 7
The common factors of 55 and 63 are 1, so the GCF is 1. We can divide both the numerator and denominator by 1:
55/1/63/1
Therefore, 55/63 in simplest form is 55/63.
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While Brian traveled, the pilot taught him
O how to steer a Cessna 406
O how to fill the gas tank on the Cessna 406
O how to read the instrument panel on the Cessna 406
While Brian traveled, the pilot taught him A. how to steer a Cessna 406.
What is a Cessna 406?The Cessna 406 is a twin-engine aircraft that is commonly used for various purposes, such as air ambulance services, freight transport, and surveillance operations. Steering the aircraft is an essential skill that any pilot must learn in order to control the aircraft's direction of flight.
Learning how to steer a Cessna 406 would be an important skill for Brian to acquire if he was planning to become a pilot or work in the aviation industry.
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Given a quadratic equation in vertex form, find the vertex, axis of symmetry, whether the graph
opens up or down, the maximum or minimum, and the y-intercept. Graph it!
16. y = -2(x + 2)² +4
Vertex:
Axis of symmetry:
Opens: up
Maximum
down
Minimum
X=h A must write
x=
Max/Min Value:
The key features of the given quadratic equation include the following:
Vertex = (-2, 4)
Axis of symmetry: x = -2.
Direction of opening: downward.
There is a maximum (max) at 4.
y-intercept = (0, 0).
roots: x = -4 and x = 0.
What is the vertex form of a quadratic equation?In Mathematics and Geometry, the vertex form of a quadratic equation is modeled by this formula:
f(x) = a(x - h)² + k
Where:
h and k represents the vertex of the graph.a represents the leading coefficient.Based on the information provided about the graph of this quadratic equation, we can reasonably infer and logically deduce that its vertex can be determined as follows:
y = -2(x + 2)² +4
Vertex, (h, k) = (-2, 4)
Axis of symmetry, Xmax = -2.
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suppose that ann selects a ball by first picking one of two boxes at random and then selecting a ball from this box. the first box contains three orange balls and four black balls, and the second box contains seven orange balls and four black balls. what is the probability that ann picked a ball from the second box if she has selected an orange ball? (enter the value of the probability in decimal format and round the final answer to two decimal places.)
The probability that Ann picked a ball from the second box given that she selected an orange ball is 0.56 or 56% (rounded to two decimal places).
We can use Bayes' theorem to calculate the probability that Ann picked a ball from the second box given that she selected an orange ball.
Let A be the event that Ann selected an orange ball, and B be the event that Ann picked a ball from the second box. We want to find P(B|A), the probability that Ann picked a ball from the second box given that she selected an orange ball.
We know that there are two boxes, each with a probability of 1/2 of being selected. The probability of selecting an orange ball from the first box is 3/7, and the probability of selecting an orange ball from the second box is 7/11. Therefore, the probability of selecting an orange ball overall is:
P(A) = P(A|B)P(B) + P(A|B')P(B')
= (7/11)(1/2) + (3/7)(1/2)
= 25/42
Now we can use Bayes' theorem:
P(B|A) = P(A|B)P(B)/P(A)
= (7/11)(1/2)/(25/42)
= 14/25
Therefore, the probability that Ann picked a ball from the second box given that she selected an orange ball is 0.56 or 56% (rounded to two decimal places).
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in which one of the four scenarios would you consider a non-parametric test? group of answer choices when we are dealing with time series when we have numeric data and want to plot a regression line when we want to perform multiple regression when we only have ordered data
Non-parametric tests are statistical tests that do not require specific assumptions about the population distribution, such as normality or equal variances. They are useful in situations where the data does not meet the assumptions of parametric tests, or when the variables are ordinal or categorical.
There are some additional examples of non-parametric tests.
When the data is skewed or has outliers: If the data is not normally distributed, non-parametric tests such as the Wilcoxon rank-sum test or the Kruskal-Wallis test can be used instead of the t-test or ANOVA.When the sample size is small: If the sample size is small, it may be difficult to determine if the data is normally distributed or if variances are equal. In this case, non-parametric tests such as the Mann-Whitney U test or the Wilcoxon signed-rank test may be more appropriate.When the data is categorical or ordinal: If the data is categorical or ordinal, non-parametric tests such as the Chi-square test or Spearman's rank correlation coefficient can be used instead of parametric tests.When the data violates assumptions of independence: If the data is not independent, non-parametric tests such as the Friedman test or the McNemar's test may be used.Hence, non-parametric tests offer a flexible alternative to traditional parametric tests and can be useful in a variety of situations.
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how many mpg? ............
The fuel efficiency of the vehicle with the greatest weight which is around 2375kg on this scatter-plot showing vehicle weights & fuel efficiency is 16 mpg.
What is a scatter-plot?The relationships between two variables in a data set are represented by graphs or scatter plots. It displays data points on a Cartesian system or a two-dimensional plane. The dependent variable is represented or plotted on the Y-axis, while the independent variable or attribute is plotted or represented on the X-axis. The scatter plot's objective is to show what happens to one variable when another variable is modified. A theory that the two variables are connected is tested using the scatter plot.
The scatter plot shows the vehicle weights & fuel efficiency.
Data represented on X-axis(independent variable) : weights of vehicle
Data represented on Y-axis(dependent variable) : fuel efficiency.
Lowest weight of vehicle=1125 kg(approx)
Greatest weight of the vehicle=2375 kg(approx)
Lowest fuel efficiencies of surveyed vehicles=16 mpg.
Greatest fuel efficiency of surveyed vehicles=30 mpg.
∴The fuel efficiency of the heaviest vehicle=16 mpg.
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50.12 in word form
PLEASE HELP ME I WILL DO WHATEVER
Kiera had 1 1/3 cups of coffee in the morning and 1 1/4 cups of coffee in the afternoon. She wants to add the fractions 1 1/3+ 1 1/4 to find how much coffee she drank in all.
She can add the whole numbers, but before she can add the fractions she must find the common denominator. Drag and drop the numbers into the boxes to make the statement true.
Picture attached to
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
To add and Kiera found the common denominator is Response area. Before adding the fractions together she wrote the numerator of the first fraction as Response area and the numerator of the second fraction as Response area.
For given problem, The common denominator is 12 and Before adding the fractions the numerator of first fraction was 16 and numerator of second fraction was 15.
What are fractions?The representation of sections or portions of a whole using fractions is common. It consists of Numerator and the denominator reflects the total number of equally sized pieces that make up the whole, whereas the numerator represents the number of components we have.
For example, in the fraction 5/4, 4 is the denominator and 5 is the numerator.
Now for given problem,
Kiera had [tex]1\frac{1}{3}[/tex] cups of coffee in the morning, equivalent to [tex](4/3)[/tex] cups of coffee.
Kiera also had[tex]1 \frac{1}{4}[/tex] cups of coffee in the afternoon, equivalent to [tex](5/4)[/tex] cups of coffee.
Now we can add the two fractions together:
[tex](4/3) + (5/4)[/tex]
To find common Denominator;
(LCM) of 3 and 4 is 12
Making denominator of both fraction 12;
[tex](4/3) * (4/4) + (5/4) * (3/3)[/tex]
[tex](16/12) + (15/12)[/tex]
[tex]16/12 + 15/12 = (16 + 15)/12 = 31/12[/tex]
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The legs of a right triangle measure 39 and 80 units. What is the measure of the
hypotenuse? Answer as a number only.
Answer: probably 89
Step-by-step explanation: looked it up "you have the wrong picture up"
The hypotenuse of the given right-angled triangle is 89 units.
From the below figure, the base of the triangle AB = 39 units
The height of the triangle AC = 80 units
To know the hypotenuse of the given triangle we have to use the Pythagoras theorem as shown below,
From the given figure,
BC² = AB² + AC²
BC² = 39² + 80²
BC² = 1521 + 6400
BC² = 7921
BC = √7921
BC = 89.
From the above analysis, we can conclude that the hypotenuse of the given right-angled triangle is 89 units.
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Given question is having the wrong picture. I am attaching required correct picture as below,
what are the major differences between vertical and horizontal text sets? hypothesize and explain an example of a situation where one type of text set may be more beneficial than the other.
Answer: Vertical text sets are arranged in columns from top to bottom, while horizontal text sets are arranged in rows from left to right. The major differences between the two include:
Readability: Vertical text sets may be more difficult to read for individuals who are accustomed to reading horizontally, while horizontal text sets may be more natural for them to read.
Space utilization: Vertical text sets can utilize space more efficiently, especially in situations where vertical space is available, such as in tall and narrow posters or banners. Horizontal text sets, on the other hand, can utilize space more efficiently in situations where horizontal space is available, such as in wide-screen displays or landscape-oriented documents.
Cultural conventions: In some cultures, such as Japan and China, vertical text sets are traditionally used for writing, while in other cultures, such as the United States, horizontal text sets are the norm. Thus, the use of one or the other may depend on cultural context.
One situation where vertical text sets may be more beneficial is in designing a tall and narrow billboard. In this case, a horizontal text set may be difficult to read from afar, while a vertical text set can make use of the available space and be easily read from a distance. On the other hand, in designing a website, horizontal text sets may be more beneficial as they can utilize the full width of the screen and provide more space for additional content.
Step-by-step explanation:
Area use a 7. 2 pans of blue pink and white paint to paint her bedroom walls 1/4 of this month is blue pants and the rest is wipe it how many pensive white paint did you use to paint her bedroom walls
If 1/4 of this amount is blue paint, and the rest is white paint, Area used 5.4 pints of white paint to paint her bedroom walls.
Given that Area used a total of 7.2 pints of blue and white paint to paint her bedroom walls. And 1/4 of the amount is blue paint, then the remaining 3/4 of the amount must be white paint.
To find the amount of white paint used, we can use the following formula:
Amount of white paint = Total amount of paint - Amount of blue paint
Since we know that the total amount of paint used is 7.2 pints and 1/4 of that amount is blue paint, we can calculate the amount of blue paint as:
Amount of blue paint = (1/4) x 7.2 = 1.8 pints
Now we can substitute these values in the formula to find the amount of white paint used:
Amount of white paint = 7.2 - 1.8 = 5.4 pints
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Central Limit Theorem forms the foundation for the ___ branch of statistics
Central Limit Theorem forms the foundation for the inferential statistics branch of statistics
The Central Limit Theorem is a statistical concept that describes the behavior of the mean of a sufficiently large sample size drawn from any population with a finite mean and variance.
The Central Limit Theorem is a fundamental concept in statistics that states that, under certain conditions, the distribution of sample means approaches a normal distribution regardless of the shape of the population distribution. This theorem provides a basis for inferential statistics, which involves making inferences about a population based on a sample.
It allows us to use sample statistics to estimate population parameters with a certain level of confidence. This theorem has practical applications in many areas of research, such as in quality control, social sciences, and healthcare.
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Charlie jumped a distance of 81/feet. His younger 1 brother jumped a distance of 35/L feet and then jumped 21 feet Who jumped farther? How much farther? Explain how you found your answer.
Charlie jumped farther than his younger brother, by a distance of (60L + 35)/L - 81 feet.
To compare the distances that Charlie and his younger brother jumped, we need to find a common unit of measurement. We can convert the mixed numbers into improper fractions to make the calculation easier.
Charlie jumped 81/1 feet, which is the same as 81 feet.
His younger brother jumped 35/L feet and then 21 feet. We don't know the exact value of L, but we can still compare the distances by assuming L is a constant value. So, the total distance his younger brother jumped is:
35/L + 21 feet
We can simplify the expression by finding a common denominator:
(35 + 21L)/L feet
To compare the distances, we can subtract the distances jumped by Charlie and his younger brother:
81 - (35 + 21L)/L
To determine who jumped farther, we need to simplify this expression by finding a common denominator:
(81L - 35 - 21L)/L
Simplifying further:
(60L + 35)/L
We don't know the exact value of L, but we can say that if L is any positive value, then 60L + 35 is greater than 81. Therefore, Charlie jumped farther than his younger brother, by a distance of (60L + 35)/L - 81 feet.
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what are the best displays for bivariate categorical data
The best displays for bivariate categorical data depend on the nature of the data and the research question. Here are a few common types of displays for bivariate categorical data:
Clustered Bar Charts: This display shows the frequency of each category of two variables side-by-side.
Stacked Bar Charts: This display shows the frequency of each category of two variables stacked on top of each other.
Mosaic Plots: This display shows the relative proportion of each combination of two categorical variables by area.
Heat Maps: This display is a two-dimensional table that is color-coded to show the relationship between two categorical variables.
Tree Maps: This display shows the proportion of each category of two variables by area.
The choice of display should be guided by the nature of the data and the research question being addressed.
~~~Harsha~~~
How to calculate 1over4 to a equivalent factions with denominator?
To express 1/4 as an equivalent fraction with a different denominator, we need to find a common multiple of 4 and the desired denominator.
Let's say we want to express 1/4 as an equivalent fraction with a denominator of 12. To do this, we can multiply both the numerator and denominator of 1/4 by 3, which gives us:
1/4 x 3/3 = 3/12
So 1/4 is equivalent to 3/12 when the denominator is 12.
In general, to express a fraction a/b as an equivalent fraction with a different denominator c, we can multiply both the numerator and denominator by the same value that makes b equal to c.
This is because when we multiply both the numerator and denominator by the same value, we are essentially multiplying the fraction by 1, which does not change its value.
For example, to express 2/5 as an equivalent fraction with a denominator of 15, we can multiply both the numerator and denominator by 3, which gives us:
2/5 x 3/3 = 6/15
Therefore, 2/5 is equivalent to 6/15 when the denominator is 15.
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Find the area of the following triangle:
5
3
4
Answer
6
Step-by-step explanation:
Answer:
Step-by-step explanation:
To find the area of a triangle, we can use the formula:
Area = (1/2) × base × height
In this case, we have three sides of the triangle given: 5, 3, and 4. To use these to find the area, we need to first determine which side is the base and what the corresponding height is.
We can see that the side with length 5 is opposite the biggest angle, so this is likely the hypotenuse. The other two sides, 3 and 4, must then be the other two legs of a right triangle, with one of them being the base and the other the height.
To determine which is which, we can use the Pythagorean theorem:
c^2 = a^2 + b^2
where c is the hypotenuse and a and b are the other two sides. In this case, we have:
5^2 = 3^2 + 4^2
25 = 9 + 16
So we have confirmed that 3 and 4 are indeed the legs of a right triangle, with 5 as the hypotenuse. We can use the Pythagorean theorem again to find the height:
a^2 + b^2 = c^2
b^2 = c^2 - a^2
b = sqrt(c^2 - a^2) (taking the positive square root because b is a length)
b = sqrt(5^2 - 3^2)
b = sqrt(16)
b = 4
So the height of the triangle is 4. We can now use the formula to find the area:
Area = (1/2) × base × height
Area = (1/2) × 3 × 4
Area = 6
Therefore, the area of the triangle is 6 square units.
What is the geometric mean between 1/4 and 12?
A. √12
B. √12 1/4
C. √3
D.1/2
The geometric mean of the given number is √3.
Hence option C is correct.
Use the concept of geometric mean defined as:
The Geometric Mean (GM) in mathematics is the average value or mean that, by calculating the product of the values of the set of numbers, denotes the central tendency of the numbers.
In essence, we multiply the numbers together and calculate their nth root, where n is the total number of data values.
The given numbers are,
1/4 and 12
Take a = 1/4 and b = 12
Now since we know the geometric mean of a and b = √ab
geometric mean = [tex]\sqrt{\frac{1}{4}\times 12[/tex]
geometric mean = √3
Hence,
The geometric mean for the given numbers is √3.
So option C is correct.
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The triangular prism has a base area of 38 units^2 and a height of 6.5 find its volume
The triangular prism therefore has a 123.5 cubic unit volume as by dividing its base area by its height.
what is prism ?
A prism is indeed a three-dimensional solid object in geometry made up of two bases that are parallel and congruent and are joined by a collection of rectangular faces. The kind of prism depends on the form of the bases. The prism is referred to as an n-sided prism, for instance, if the basis are triangles with n sides.
Although parallelograms and squares are also possible, a prism's faces are typically rectangular. A prism's height is determined by the mean line between its bases, and its lateral edges are those that link the corresponding base vertices.
given
The volume of a triangular prism can be calculated by multiplying the base area by the height and dividing by 2, as it is essentially a triangular pyramid extruded in the height direction. The formula for calculating the volume of a triangular prism is:
Volume = (Base Area × Height) / 2
Given that the base area is 38 units^2 and the height is 6.5 units, we can substitute these values into the formula to calculate the volume:
Volume = (38 × 6.5) / 2
Volume = 247 / 2
Volume = 123.5 units^3
So, the volume of the triangular prism is 123.5 units^3.
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Un concensario de coches rebaja a 16000 un vehiculo que valia 18300 en que porcentaje lo han rebajado?
As a car dealer lowers a vehicle that was worth 18300 to 16000 by applying the formula of change in percentage we get that by 12.569 percentage (approximately) the price gets lowered .
The initial price of the car is set at P = 18300 (units)
The price after lowering drom P becomes A= 16000 (units)
Hence the change in price (or value) of the car, that is the price of the car is lowered by, C = (initial price - lowered price) = (P - A) = (18300 - 16000) units = 2300 units.
The formula for calculating percentage change is given as follows,
Change in percentage = [(Change in value)/ ( Initial value) ]*100
⇒Change in percentage = (C/ P)*100
⇒ Change in percentage =( 2300/ 18300)*100 = 12.569% (approximately)
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Ten Pin Bowling charges a fee to rent
shoes and a cost per game. The shoe
rental costs $5.25, and each game costs
$2.50. Write the equation of this
scenario in slope-intercept
form.
Answer:
y = 2.50x + 5.25
FORMULA FOR SLOPE INTERCEPT
y = mx + b
IM SO SORRY IF THIS DOES NOT MAKE SENSE!
The population density in orange land is 18 oranges per acre exactly 792 oranges grow in orange land how many acres are there in orange light
Answer:
44 acres
Step-by-step explanation:
Population density is the number of individuals per unit area. It is a useful concept to measure how crowded or sparse a region is. For example, if we want to compare the population density of different countries, we can divide the total population by the total land area. This will give us the number of people per square kilometer or square mile.
In this case, the population density of oranges is 18 oranges per acre. This means that on average, there are 18 oranges in every acre of land that grows oranges. This can help us estimate how much land is needed to produce a certain amount of oranges. For example, if we want to know how many acres of land can produce 1000 oranges, we can divide 1000 by 18 and get 55.56 acres.
To find the area of orange land, we need to divide the total number of oranges by the population density. This will give us the number of acres that can fit 792 oranges. The formula is:
Area = Number of oranges / Population density
Plugging in the given values, we get:
Area = 792 / 18
Simplifying, we get:
Area = 44
Therefore, there are 44 acres in orange land. This means that if we have 792 oranges, we can distribute them evenly in 44 acres of land and have 18 oranges per acre.
which ones multi answer
191 cm
191 cm
162 cm
162 cm
170 cm
170 cm
152 cm
152 cm
192 cm
192 cm
168 cm
168 cm
201 cm
201 cm
205 cm
205 cm
190 cm
190 cm
161 cm
161 cm
193 cm
193 cm
195 cm
195 cm
177 cm
The heights that people had a foot size smaller than 24 centimetres would be = 162cm, 152cm, 162cm, 161cm,162cm.
How to determine the number of foot size lees than 24cm?The total number of people whose foot sizes and heights where obtained for the study = 15
The heights that had foot sizes less than 24cm= 162cm, 152cm,162cm,161cm,162cm.
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