This box plot shows the distribution of wind speeds measured near an oil rig.Work out the value that completes the statement below.
50% of the speeds are between 36 km/h and… km/h

Hey there!

Answer:

first question= approximately 6.8 cm

second question=approximately 2.88 x 10^-28 N

Explanation:

To determine the separation distance between the charges, we can use Coulomb's law, which states that the force between two point charges is given by:

F = k * q1 * q2 / r^2

where F is the force, k is Coulomb's constant (9 x 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the separation distance between the charges.

In this case, we have q1 = 5.0 x 10^-6 C, q2 = -6.0 x 10^-6 C, and F = -0.72 N. Plugging in these values and solving for r, we get:

-0.72 N = (9 x 10^9 N m^2/C^2) * (5.0 x 10^-6 C) * (-6.0 x 10^-6 C) / r^2

Solving for r, we get:

r = sqrt[(9 x 10^9 N m^2/C^2) * (5.0 x 10^-6 C) * (-6.0 x 10^-6 C) / (-0.72 N)]

r ≈ 0.068 m or 6.8 cm

Therefore, the separation distance between the charges is approximately 6.8 cm.

For the second question, we can use the same formula, Coulomb's law, to find the force between the charges:

F = k * q1 * q2 / r^2

Plugging in the values, we get:

F = (9 x 10^9 N m^2/C^2) * (1.6 x 10^-19 C) * (3.2 x 10^-19 C) / (0.02 m)^2

F ≈ 2.88 x 10^-28 N

Therefore, the force between the charges is approximately 2.88 x 10^-28 N.

Hope this helps!

The lowest frequency of light that can exist is zero hertz (Hz), which is also known as direct current (DC).

This is because light is a type of electromagnetic radiation that consists of oscillating electric and magnetic fields. These fields oscillate at a certain frequency, and the frequency determines the energy and properties of the light.

However, in the absence of any oscillation, there is no frequency and hence no light. In other words, the lowest frequency of light is no light at all.

It's worth noting that there are other forms of electromagnetic radiation that have frequencies lower than visible light, such as radio waves and microwaves. These types of radiation have frequencies that range from about 3 kilohertz (kHz) to several gigahertz (GHz).

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The branch of science that studies atoms is called atomic physics.

Atomic physics is the branch of physics that studies the structure of atoms and the interactions between them. It also covers the theories and principles behind the behaviour of atomic particles, such as electrons and protons. Atomic physics has many applications in fields such as chemistry, engineering, and medicine.Atomic physics is the study of atoms, their structure, and their interactions with other particles and fields. It is a sub-discipline of physics that deals with the behavior and properties of atoms. Atomic physics is concerned with the arrangement of electrons around the nucleus, the forces that hold them together, the energy levels of the different types of atoms, and the way in which they interact with light and other particles.

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The magnitude of the electrostatic force on sphere B due to sphere A is also 2.4 N, because the forces are equal in magnitude but opposite in direction as they form an action-reaction pair.

First by Coulomb's Law, the electrostatic force F between two point charges Q1 and Q2, separated by a distance r, is given by

F = k * (Q1 * Q2) / r^2

Where k is the Coulomb constant, which has a value of 9 × 10^9 N·m^2/C^2.

In this case, we have two spheres A and B, with charges +2 * 10^-6 C and +1 * 10^-6 C, respectively. The electrostatic force on A due to B is given as 2.4 N.

To find the electrostatic force on B due to A, we can use Coulomb's Law and the fact that the force between the two spheres is an action-reaction pair, meaning that the forces on A and B are equal in magnitude but opposite in direction. Therefore, the magnitude of the electrostatic force on B due to A is also 2.4 N.

We can see this by rearranging Coulomb's Law as:

F = k * (Q1 * Q2) / r^2

=> Q2 = (F * r^2) / (k * Q1)

where

Substituting the values given, we get:

Q2 = (2.4 N * (1 m)^2) / (9 × 10^9 N·m^2/C^2 * 2 × 10^-6 C) = 0.133 C

Therefore, the magnitude of the electrostatic force on sphere B due to sphere A is also 2.4 N, because the forces are equal in magnitude but opposite in direction as they form an action-reaction pair.

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So the answer with two significant figures and appropriate units is Kinetic energy at second point is 3.7 x 10^6 J or 3.7 MJ.

Kinetic energy is a form of energy that an object possesses by virtue of its motion. It is defined as the energy that an object has due to its mass and velocity. The formula shows that the kinetic energy of an object increases as its mass and velocity increase. For example, a heavy truck traveling at a high speed has a higher kinetic energy than a small car traveling at the same speed. The concept of kinetic energy is important in physics, as it is used to explain many phenomena, such as collisions, projectile motion, and the behavior of waves. It is also useful in engineering and other fields, as it helps to quantify the energy required for different types of motion, such as in machines or vehicles.

Here,

According to the law of conservation of energy, the total mechanical energy of a system remains constant if there are no external forces acting on the system. In the case of a satellite in an elliptical orbit around the Earth, the total mechanical energy is the sum of its kinetic energy and gravitational potential energy.

We can use this principle to solve for the kinetic energy of the satellite when its potential energy is 5600 MJ. We know that the total mechanical energy is conserved, so:

Total mechanical energy at first point = Total mechanical energy at second point

(KE + PE)1 = (KE + PE)2

Substituting the given values:

4100 MJ + 5200 MJ = KE2 + 5600 MJ

Simplifying:

KE2 = (4100 MJ + 5200 MJ - 5600 MJ)

KE2 = 3700 MJ

Therefore, the kinetic energy of the satellite at the second point is 3700 MJ. It's important to note that the units for energy are Joules (J), and mega-Joules (MJ) are equal to 1,000,000 Joules.

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Non-metals are elements that often acquire electrons during chemical processes to generate anions. These substances are electronegative ones.

As they are ineffective electrical conductors, glass and plastic are examples of insulators. They are used to stop electricity from entering parts of our body that are dangerous or useless. We can handle cables safely because of their plastic coating.

The fact that copper is widely used in all types of electrical wiring might indicate that metal is an excellent conductor of electricity. Copper contains a lot of free electrons that can conduct electricity, which is why metal is an excellent conductor of electricity.

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The electric field E(→r) inside the sphere is: E(→r) = (ρ × r) / (3ε₀), where ρ is the uniform volume charge density, r is the distance from the origin, and ε₀ is the electric constant.

To find the electric field E(→r) inside the sphere with a uniform volume charge density ρ, we can use Gauss's law.

First, we choose a spherical Gaussian surface of radius r < a, centered at the origin. The electric field is radial and has the same magnitude at every point on the surface due to the symmetry of the charge distribution.

By Gauss's law, the electric flux through the surface is given by:

Φ_E = E(→r) × 4πr²

where Φ_E is the electric flux through the surface and E(→r) is the electric field at every point on the surface.

The total charge enclosed by the surface is given by:

Q_enc = (4/3) × πr³ × ρ

where Q_enc is the total charge enclosed by the surface and ρ is the charge density.

By Gauss's law, the electric flux through the surface is also related to the total enclosed charge by:

Φ_E = Q_enc / ε₀

where ε_0 is the electric constant.

Combining these equations, we have:

E(→r) × 4πr² = (4/3) × πr³ ρ / ε_0

Solving for E(→r), we get:

E(→r) = (ρ × r) / (3ε₀)

Therefore, the electric field E(→r) inside the sphere is directly proportional to the distance from the origin and the charge density, and is independent of the choice of direction.

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The gas constant "R" is a physical constant that relates the properties of an ideal gas to the amount of the gas present, its pressure, volume and temperature.

The value of R depends on the units used for pressure, volume, and temperature.When pressure is measured in atmospheres (atm), volume is measured in liters (L), and temperature is measured in kelvin (K), the value of the gas constant is approximately 0.0821 L·atm/(mol·K).

The exact value of the gas constant R depends on the unit system used. For example, if pressure is measured in pascals (Pa), volume is measured in cubic meters (m³), and temperature is measured in kelvin (K), then the value of R is 8.314 J/(mol·K).

Similarly, if pressure is measured in pounds per square inch (psi), volume is measured in cubic feet (ft³), and temperature is measured in Rankine (R), then the value of R is 10.73 (ft·lbf)/(mol·R).

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103 F 103 F is therefore identical to 39 C 39 C.Celsius to Fahrenheit Conversion: 103 °F.Starting from 103, subtract 32 to convert to Fahrenheit. To get 39.444 degrees Celsius, multiply 71 by 5 over 9.

People who have fevers of 103 F (39.4 C) or above typically appear and act poorly. Your comfort and ability to sleep are the key goals of treatment. We employ conversion formulas that are similar to those found in most textbooks. Add 32 and multiply by.5556 (or 5/9) to convert temperatures from degrees Fahrenheit to degrees Celsius. Add 32 and multiply by 1.8 (or 9/5) to convert temperatures from degrees Celsius to Fahrenheit. 40 degrees Celsius, or 104 degrees Fahrenheit, is the corresponding temperature in Celsius.When a child has an oral or rectal temperature of 38.2 Celsius (100.7 Fahrenheit) or above, the child is said to have a fever.When a child has an oral or rectal temperature of 38.2 Celsius (100.7 Fahrenheit) or above, the child is said to have a fever.

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The factors that influence the strength of gravity between two objects are their mass and their distance apart.

Gravity is a force that exists between any two objects with mass, pulling them towards each other. The strength of this force depends on the masses of the two objects and the distance between them. The greater the mass of the objects, the stronger the gravitational force between them.

However, the gravitational force weakens as the distance between the two objects increases. This relationship is described by the inverse square law, which states that the force of gravity is inversely proportional to the square of the distance between the two objects.

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Onchocerca volvulus microfilaria

The only microfilarial option without a sheath that is frequently found in nodule biopsies is Onchocerca volvulus.

Infected people may have trypanosoma trypomastigotes, which measure 15-20 m, in their blood, lymphatic fluid, or CSF.A pseudoparasite is a false identification of something that could be mistaken for a parasite. Comparing Wuchereria bancrofti microfilaria to Onchocera microfilaria, they are sheathed and a little bit smaller in size. The lymphatic tissues, particularly those in the lower limbs, are home to W. bancrofti microfilaria. The lifetime risk of thyroid cancer is 1.1% for the population of the United States. A fine needle aspiration biopsy is typically the next step when a thyroid nodule is worrisome, meaning it exhibits traits that could indicate thyroid cancer (FNAB) . When a follicular or hurtle cell induced lesion is the diagnosis, a thyroid biopsy is considered "suspicious." Normal thyroid cells include follicular and hurtle cells. The current analysis of thyroid biopsy data cannot distinguish between noncancerous adenomas and follicular or hurtle cell carcinoma.

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Answer:

Explanation:

Power is defined as the rate at which work is done

Power = work/time and is measured in Watts

The vector A carries you 222.487 units to the right, vector B carries you 86.424 units to the left, and vector C carries you 42.324 units to the left in the x-direction

To determine the x-direction component of each vector, we need to use trigonometry. We can use the cosine function to find the x-component of each vector since cosine gives the adjacent side length of a right triangle.

For vector A:

The length of the adjacent side (x-component) is given by: cos(15°) = 0.9659

The x-component of vector A is therefore: 230 x 0.9659 = 222.487

For vector B:

The length of the adjacent side (x-component) is given by: cos(237°) = -0.7252 (since cosine is negative in the second and third quadrants)

The x-component of vector B is therefore: 120 x -0.7252 = -86.424

For vector C:

The length of the adjacent side (x-component) is given by: cos(188°) = -0.1997 (since cosine is negative in the second and third quadrants)

The x-component of vector C is therefore: 212 x -0.1997 = -42.324

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Here, both the momentum and kinetic energy of he ball are conserved. There is no change in the magnitude of the speed thus, its kinetic energy is conserved.

The kinetic energy of an object is the energy generated by virtue  of its motion. It is related to its mass and velocity by the expression written below:

Ke = 1/2 mv²

The momentum of an object is the product of its mass and velocity. For an elastic collision both momentum and kinetic energy is conserved. But in the case of an inelastic collision, there is some energy loss and the kinetic energy is not conserved but momentum is conserved.

Here, the ball bounces by colliding with the floor, where its direction is changing but not the magnitude of speed. Hence, both the momentum and kinetic energy are conserved.

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Ranking the objects from smallest to largest circular velocity, we have:

c. a 15-kg object orbiting Earth at the same distance as the Moon (1,022 m/s).

a. a 5-kg object orbiting Earth halfway to the moon (1,681 m/s).

b. a 10-kg object orbiting Earth just above Earth's surface (7,905 m/s).

The circular velocity of an object in orbit depends on its mass, the mass of the central body, and the distance between them. The formula for the circular velocity is V = sqrt(GM/R), where G is the gravitational constant, M is the mass of the central body, and R is the distance between the two objects.

a. The distance between the 5-kg object and Earth is halfway to the Moon, which is about 384,400 km. Therefore, the distance between the object and Earth is 384,400/2 = 192,200 km. Using the formula above, the circular velocity of the object is V = sqrt((6.67x10^-11 m^3/kg/s^2) x (5.97x10^24 kg) / (1.92x10^8 m)) = 1,681 m/s.

b. The distance between the 10-kg object and Earth is just above Earth's surface, which is about 6,378 km. Using the formula above, the circular velocity of the object is V = sqrt((6.67x10^-11 m^3/kg/s^2) x (5.97x10^24 kg) / (6.38x10^6 m)) = 7,905 m/s.

c. The distance between the 15-kg object and Earth is the same as the Moon's distance, which is about 384,400 km. Using the formula above, the circular velocity of the object is V = sqrt((6.67x10^-11 m^3/kg/s^2) x (5.97x10^24 kg) / (3.84x10^8 m)) = 1,022 m/s.

The given question is incomplete, the complete question is

Rank the following objects, in order of their circular velocities, from smallest to largest

a. a 5-kg object orbiting Earth halfway to the moon

b. a 10-kg object orbiting Earth just above Earth's surface

c. a 15-kg object orbiting Earth at the same distance as the Moon

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The velocity of the other pool ball is (3, -1) m/s.

We can solve this problem using the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.

Let the initial velocity of the stationary pool bar be (0,0) m/s. The initial momentum of the system is:

p_initial = m1 * v1 + m2 * v2

where m1 and m2 are the masses of the pool balls, and v1 and v2 are their initial velocities.

Substituting the given values, we have:

p_initial = 0.1 kg * (5, -4) m/s + 0.1 kg * (0,0) m/s

= (0.5, -0.4) kg m/s

After the collision, the total momentum of the system is still conserved, but now we have one ball at rest and the other moving with a velocity of (2, -3) m/s. Let the velocity of the other pool ball be (vx, vy) m/s. Then we have:

p_final = m1 * (2, -3) m/s + m2 * (vx, vy) m/s

where m1 and m2 are still the masses of the pool balls.

Setting the initial and final momenta equal and solving for (vx, vy), we get:

p_initial = p_final

0.5, -0.4 = 0.1 * (2, -3) + 0.1 * (vx, vy)

0.5, -0.4 = (0.2, -0.3) + (0.1vx, 0.1vy)

0.5 - 0.2 = 0.1vx

-0.4 + 0.3 = 0.1vy

vx = 3 m/s

vy = -1 m/s

Therefore, the velocity of the other pool ball is (3, -1) m/s.

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Answer:

He collected many specimens of the finches on the Galapagos Islands. These specimens and his notebooks provided Darwin with a record of his observations as he developed the theory of evolution through natural selection.

The larger piston can exert about 9.69 times more force than the force applied to the smaller piston.

Force exerted by a piston is directly proportional to pressure applied and the surface area of piston. Since the hydraulic system is connected, pressure is same in both vessels.

Surface area of small piston is:

A_small = πr_small² = π(0.9 cm)² ≈ 2.54 cm²

Surface area of the large piston is:

A_large = πr_large² = π(2.8 cm)² ≈ 24.62 cm²

Force exerted by small piston is:

F_small = P × A_small

P is pressure and A_small is surface area of small piston.

Force exerted by large piston is:

F_large = P × A_large

P is pressure and A_large is the surface area of large piston.

F_large/F_small = (P × A_large)/(P × A_small) = A_large/A_small

F_large/F_small = 24.62 cm² / 2.54 cm² ≈ 9.69

This means that larger piston can exert about 9.69 times more force than the force applied to the smaller piston.

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25 °C is equivalent to 298.15 K. The formula to convert Celsius (°C) to Kelvin (K) is 0°C + 273.15 = 273.15K.

To convert 25 degrees Celsius (°C) to Kelvin (K), you can use the following formula:

0°C + 273.15 = 273.15K

Plugging in the given value of 25 °C, we get:

K = 25 + 273.15 = 298.15 K

Therefore, 25 °C is equivalent to 298.15 K.

The Kelvin (K) scale is an absolute temperature scale where 0 K represents absolute zero, the theoretical temperature at which all matter would have zero thermal energy. On the Kelvin scale, the size of one degree is the same as that of one Celsius degree, but the Kelvin scale starts at absolute zero, while the Celsius scale starts at the freezing point of water.

To convert a temperature from Celsius to Kelvin, you simply need to add 273.15 to the Celsius temperature. This is because the size of one Kelvin degree is the same as one Celsius degree, but the Kelvin scale starts at absolute zero (which is -273.15 °C), so adding 273.15 to a temperature in Celsius converts it to Kelvin.

The Kelvin scale is used in many scientific fields, especially in physics and chemistry, where absolute zero is a critical reference point. It is also used in engineering and technology, particularly in the fields of thermal engineering and materials science

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The weight on Phobos will be 0.3135 N

We know that weight is defined as:

W = mass*gravitational acceleration.

Here we know that the mass of the person is 55 kilograms, and we also know that the gravitational acceleration on phobos is:

g = 0.0057 m/s²

Then the weight will be

W = 55kg*0.0057 m/s² = 0.3135 N

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In Fahrenheit, 35.5 degrees Celsius is equivalent to 127.9 degrees.

Use the formula below for the convert 35.5 degrees Celsius to Fahrenheit:

°F = (°C x 1.8) + 32

The process of translating a temperature from one scale to another is referred to as temperature conversion. Temperature conversions between the several regularly used temperature scales, including Celsius, Fahrenheit, and Kelvin, are frequently required.

where the temperature is expressed in degrees Fahrenheit (°F) and degrees Celsius (°C).

Plugging in 35.5 degrees Celsius yields the following results:

°F = (35.5 x 1.8) + 32 °F

=> 95.9 + 32 °F

=> 127.9

As a result, 35.5 Celsius is equivalent to 127.9 Fahrenheit.

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If we are using a reference voltage of 5 volts and analogread() gives a value of 708, then 3.5 is the appropriate voltage.

When charged electrons (current) are forced through a conducting loop by the pressure of an electrical circuit's power source, they may perform tasks like lighting a lamp. In a nutshell, voltage equals pressure and is expressed in volts (V).

Volt. The derived unit for electric potential, voltage, and electromotive force is the volt (symbol: V). The Italian physicist Alessandro Volta (1745–1827), who created the voltaic pile, arguably the first chemical battery, is honored by having his name attached to the volt.

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Each capacitor's capacitance will decrease in the following order:

C> B> A> D.

An object that stores electrical energy is a capacitor. By building up electric charges on two nearby surfaces that are isolated from one another, a capacitor is a device that stores electrical energy in an electric field.

A passive electrical component having two terminals is a capacitor. Capacitance refers to a capacitor's effect. Faraday is the SI unit for capacitance (F).

C = ε₀ K A/ d

where the capacitor's area is A, the electric permittivity is 0, and the distance between the plates is d

The capacitance is inversely proportional to the distance and directly proportional to the cross-sectional area of the plates.

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Note: the full question is

Four parallel plate capacitors are constructed using square plates, and each has a dielectric inserted between the plates.

Sort the capacitance of each capacitor from highest to lowest.

Capacitor A: long side

l, distance between plates D, dielectric constant

Capacitor B: side length l

2, the distance between the plates D 2, the dielectric constant 4k.

Capacitor C: side length 2l, distance between plates D, dielectric constant 2k.

Capacitor D: side length l, plate spacing 2D, dielectric constant 2k.

Answer:

The tempature of the room.

Explanation:

Due to the temperature of the room being above the ice freezing point, the ice will melt.

99.3°F is equivalent to 37.4°C

A temperature unit developed from the SI (International System of Units) is Celsius (symbol: °C).

Prior to the adoption of the metric system, Fahrenheit (symbol: °F) was a commonly used measurement of temperature.

To convert Fahrenheit (°F) to Celsius (°C) we have to first subtract 32 from Fahrenheit and then multiply it by .5556 or 5/9.

We have to convert 99.3 degrees Fahrenheit (°F) to Celsius (°C),

We can use the following formula:

°C = (°F - 32) x 5/9

As per the given information,

°F = 99.3

Substituting the value 99.3 for °F, we get:

°C = (99.3 - 32) x 5/9

= 67.3 x 5/9

= 37.4

Therefore, 99.3°F is equivalent to 37.4°C.

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The conversion of 99.4 °F(Fahrenheit) is equivalent to 37.44 °C.

A temperature unit developed from the SI (International System of Units) is Celsius (symbol: °C).

Prior to the adoption of the metric system, Fahrenheit (symbol: °F) was a commonly used measurement of temperature.

To convert Fahrenheit (°F) to Celsius (°C) we have to first subtract 32 from Fahrenheit and then multiply it by .5556 or 5/9.

We have to convert 64 degrees Fahrenheit (°F) to Celsius (°C),

We can use the following formula:

°C = (°F - 32) x 5/9

As per the given information,

°F = 99.4

By placing the value 99.4 for °F, we get:

°C = (99.4 - 32) x 5/9

°C = 37.44 (rounded to two decimal places)

Therefore, 99.4 °F is equivalent to 37.44 °C.

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The soccer ball is moving at a speed of approximately 10.84 m/s just before it hits the player's chest.

The conservation of energy means that there is not any loss of energy but energy changes from one form to another.

To solve this problem, we can use the principle of conservation of energy, which states that the total energy in a system is conserved. In this case, we can assume that the system consists of only the soccer ball.

The initial energy of the soccer ball is given by its kinetic energy:

KE₁= 0.5 x m  x  v₁²

Where m is the mass of the soccer ball and v₁ is its velocity just after being kicked by the goalkeeper.

The final energy of the soccer ball just before it hits the player's chest is given by its potential energy and kinetic energy:

KE₂ + PE₂= m x  g x h₂ + 0.5 x m x v₂²

Where h₂ is the height of the player's chest above the ground, g is the acceleration due to gravity (9.81 m/s²), and v₂is the velocity of the soccer ball just before it hits the player's chest.

Since energy is conserved, we can equate the initial energy to the final energy:

KE₁ = KE₂ + PE₂

Substituting the expressions for KE₁and KE₂+ PE₂, we get:

(0.5 x m x v₁²) = (m x g x h₂) + (0.5 x m x v₂²)

Simplifying and solving for v2, we get:

v₂ = √(v₁² - 2 x g x (h₂ - 0.8))

Substituting the given values, we get:

v₂ = √((33 m/s)² - (2 x 9.81 m/s²) x (1.4 m - 0.8 m))

v₂= 10.84 m/s

Therefore, the speed of the soccer ball will be 10.84 m/s just before it hits the player's chest.

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All of the PE on charges 2q will be changed into its KE. A electric potential vtot just at square's center is determined by the equation KE of a load 2q ≈ (12 - 3*sqrt(2))*kq2/d.

The effort required to move a unit charge of one place to another within an electric field is referred to as electric potential. Although any site beyond the area of the given positive ions can be employed, Earth is usually used as the bench mark. potential power.

The effort required to convey a unit positive electrical charge from such an infinitely far away to a certain place is measured as the electromotive force at that location. Volt (V), which is also known as Joule per Coulomb, is the SI unit for electric potential.

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The crown is not made up of pure gold as its density which is calculated is observed to be less than that of the pure gold.

The formula for an object's density is ρ = m/v.

where,

m is mass

v is volume

Mass of the crown is given as 1 kg.

When submerged in water, its mass becomes 0.92 kg.

So, volume of water displaced is 0.08 L.

Density of pure gold is given as, ρ gold = 19.3 kg/L

The amount of water that is displaced has the same volume as the crown. Let us calculate the density of crown,

ρ crown = m/v = 1/0.08 = 12.5 kg/L

Comparing the above obtained value with the density of pure gold we have, ρ crown < ρ gold.

Thus, the crown is not made up of pure gold.

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According to general relativity, Earth goes around the sun rather than flying straight off into space because of the curvature of spacetime caused by the mass of the sun.

The general theory of relativity explains how gravity is actually caused by the curvature of spacetime and not by any actual force at all. The mass of the sun bends spacetime, which in the case of the Earth orbiting the sun causes the Earth to move on a curved orbit. The orbit of the Earth is visible as a curving path.

The Earth would indeed continue to move in a straight line if it weren't for the sun's mass's effect on the curvature of spacetime. But, general relativity offers a more thorough understanding of gravity and demonstrates that the Earth's and other solar system objects' motions are caused by the curvature of spacetime.

Learn more about curvature of spacetime

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