The speed of the charged particle q after accelerating through a potential difference of 4V is given by sqrt(8qV/m).
The kinetic energy gained by a charged particle q accelerated through a potential difference V is given by:
K = qV
If the potential difference is increased to 4V, the kinetic energy gained by the particle will be:
K' = q(4V) = 4qV
Since the particle starts from rest, all the energy gained is converted to kinetic energy. Therefore, equating K' to the kinetic energy of the particle, we get:
K' = 1/2 mv^2
where m is the mass of the particle and v is the final speed of the particle.
Equating the two equations, we get:
4qV = 1/2 mv^2
Solving for v, we get:
v = sqrt(8qV/m)
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The given question is incomplete, the complete question is:
Charge q is accelerated starting from rest up to speed v through the potential difference V. What speed will charge q have after accelerating through potential difference 4V?
A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 57 J of kinetic energy?
The distance the block will move to have a kinetic energy of 57 J is 8.14 meters.
What is work?The work is defined as the amount of energy. The work in physics is the product of the force and the displacement.
Given that a 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. The total kinetic energy possessed by the block is 57 J.
The distance will be calculated as:-
W = F x D
W = 7 x 2
W = 14 J
The distance is,
W₁ / W₁ = D₂ / D₁
14 / 57 = 2 / D₂
D₂ = ( 57 x 2 ) / 14
D₂ = 8.14 meters
Therefore, the distance the block will move to have a kinetic energy of 57 J is 8.14 meters.
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determine the resultant force that water exerts on the overhang sea wall along abc. the wall is 2 m wide.
The resultant force that water exerts on the overhang sea wall along abc is 179 kN.
What is force?Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.
Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.
(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.
Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,
Aabefa=1.5m(2.5m)=3.75m2and
2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,
Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N
Therefore,
Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN
FR² =(Fbc)²H2+[Fab+(Fbc)v]²
==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]
=178.6(10³)N = 179 kN.
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Terry kicks a soccer ball that is sitting motionless on the field. What is the best description of the energy transfer?(1 point).
When Terry kicks a soccer ball that is sitting motionless on the field, the energy transfer that occurs is from Terry's foot to the soccer ball. The transfer of energy can be described as kinetic energy, which is the energy an object possesses due to its motion.
What is kinetic energy?Kinetic energy is the energy that an object possesses due to its motion. It is defined as the energy an object has because of its mass and velocity.
Here,
With the ball being set in motion. This transfer of energy can be described as a transfer of kinetic energy. As the ball moves, it gains kinetic energy, which is the energy an object possesses by virtue of its motion. At the same time, Terry's foot loses kinetic energy. This is due to the conservation of energy, which states that energy can neither be created nor destroyed, only transferred or converted from one form to another. In this case, the energy that was initially in Terry's foot has been transferred to the ball in the form of kinetic energy, causing the ball to move.
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Heptane gas reacts with oxygen gas to give carbon dioxide gas and water vapor (gas). If you mix heptane and oxygen in the correct stoichiometric ratio, and if the total pressure of the mixture is 300 mm hg, what are the partial pressures of heptane.
The partial pressures of heptane is zero
The balanced chemical equation for the reaction between heptane and oxygen is:
C7H16 + 11O2 → 7CO2 + 8H2O
From the equation, we can see that for every mole of heptane that reacts, we need 11 moles of oxygen. Therefore, if we mix heptane and oxygen in the correct stoichiometric ratio, all the heptane will react, and none will be left over. This means that the partial pressure of heptane in the mixture will be zero.
The total pressure of the mixture is given as 300 mmHg. According to Dalton's law of partial pressures, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases in the mixture. Therefore, if the partial pressure of heptane is zero
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A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 57 J of kinetic energy?
Answer:
Explanation: Kinetic energy generated = work done by force = force x displacement
= 3 x 7 = 21 J
can i get brainlest pls (:
A force of 500 N acts on a rocket for 600 s, causing the rocket's velocity to increase. By how much does the rocket's momentum increase?
Please give detailed answer and explanation
Answer:
The change in momentum of an object is equal to the impulse applied to it. Impulse is the product of force and time, or J = FΔt.
In this case, the force acting on the rocket is 500 N, and the time it is applied is 600 s, so the impulse is:
J = FΔt = (500 N) * (600 s) = 300000 Ns
The impulse applied to the rocket causes a change in momentum, which is given by the formula:
Δp = J
So the change in momentum of the rocket is 300000 Ns.
The voltage across a disconnected charged plate capacitor increases when the plates are pulled apart
a. True
b. False
5. A schoolyard teeter-totter with a total length of 5.2 m and a mass of 38 kg is pivoted at its center. A 19kg child sits on one end of the teeter-totterWhere should a parent push vertically downward with a force of 210 N in order to hold the teeter-totter level?
The parent should push vertically downward at a distance of 4.66 m from the pivot point in order to hold teeter-totter level.
What is force?Force can be a push or a pull that is always with magnitude and direction.
As, Fp × x - Mg × d - mc × (L - x) = 0
Fp is force applied by the parent, x is distance from the pivot point to the point where the parent applies force, Mg is weight of the teeter-totter, mc is the weight of the child, and L is length of the teeter-totter.
Fp × x - (38 kg × 9.81 m/s²) × 2.6 m - (19 kg × 9.81 m/s²) × (5.2 m - x) = 0
Fp × x - 976.68 N × m - 185.58 N × m + 183.39 N × m = 0
Fp × x = 978.87 N × m
x = 978.87 N × m / Fp
So, x = 978.87 N × m / 210 N = 4.66 m
Therefore, the parent should push vertically downward at a distance of 4.66 m from the pivot point in order to hold the teeter-totter level.
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I need pls with this work pls
The missing part of the question have been filled below on Continental drift
What did Wegener do?
In the early part of the 20th century, a German scientist named Alfred Wegener, proposed the theory of continental drift which suggested the continents move and started out in different positions from what they are currently. In the 1960s, scientists discovered the spreading apart of areas of the sea floor. This in turn led to the theory of plate tectonics. The lithosphere is made of plates which float on a "plastic-like" undersurface called the mantle. Where these plates come together at boundaries, changes take place in the crust and its feature.
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The displacement of a standing wave on a string is given by D=3.6sin(0.60x)cos(48t) , where x and D are in centimeters and t is in seconds.
Part A
What is the distance (cm ) between nodes?
Part B
Give the amplitude of each of the component waves.
Part C
Give the frequency of each of the component waves.
Part D
Give the speed of each of the component waves.
Part E
Find the speed of a particle of the string at x=3.00cm when t=2.2s .
The answers to the questions are given in parts respectively.
Part A
The distance between nodes is given by the wavelength of the standing wave, which can be found using the equation:
λ = 2π/k
Where k is the wave number, given by:
k = 0.60
Plugging this into the equation for λ gives:
λ = 2π/0.60
λ = 10.47 cm
Therefore, the distance between nodes is 10.47 cm.
Part B
The amplitude of each of the component waves is given by the coefficient of the sine or cosine term in the equation for the displacement of the standing wave. In this case, the amplitude of each of the component waves is 3.6 cm.
Part C
The frequency of each of the component waves is given by the coefficient of the time term in the equation for the displacement of the standing wave. In this case, the frequency of each of the component waves is 48 Hz.
Part D
The speed of each of the component waves can be found using the equation:
v = λf
Where λ is the wavelength and f is the frequency. Plugging in the values for λ and f from Parts A and C gives:
v = (10.47 cm)(48 Hz)
v = 502.56 cm/s
Therefore, the speed of each of the component waves is 502.56 cm/s.
Part E
The speed of a particle of the string at a given position and time can be found by taking the derivative of the displacement equation with respect to time. This gives:
v = -3.6sin(0.60x)(48)sin(48t)
Plugging in the values for x and t gives:
v = -3.6sin(0.60(3.00 cm))(48)sin(48(2.2 s))
v = -3.6sin(1.8)(48)sin(105.6)
v = -164.81 cm/s
Therefore, the speed of a particle of the string at x=3.00 cm when t=2.2 s is -164.81 cm/s.
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The speed limit on a highway in lower slovakia was given as 120,000 furlongs per fortnight. How many miles per hour is this? one furlong is 1/8 mile and a fortnight is 14 days. A furlong originally referred to the length of a plowed furrow.
The required speed limit on a highway in lower slovakia is 20,000 furlongs per fortnight. And its value in miles per hour is 44.64 miles per hour.
The speed limit is given as 120000 furlongs per fortnight.
1 furlong is given as 1/8 miles.
120000 furlongs is equal to 120000/8 = 15000 miles per fortnight
Let us convert miles per fortnight to miles per hour.
1 fortnight is known to be 14 days
1 day = 24 hours
14 day = 24 × 14 = 336 hours
15000 miles per fortnight = 15000/336 = 44.64 miles per hour
Thus, 120,000 furlongs per fortnight is nothing but 44.64 miles per hour.
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An infinitely long wire carries a current of I = 185 A. Randomized Variables [ I=185A 50% Part (a) Consider a circle with a radius r and centered on the wire. Determine the magnitude of the magnetic field B at points along the circle in terms of I and r. 50% Part (b) If r = 022 m, calculate the numerical value of B in tesla.
The magnitude of the magnetic field B at points along the circle can be determined using Ampere's law.
According to Ampere's law, the integral of the magnetic field B along a closed path is equal to the current I enclosed by that path.
Mathematically, this can be expressed as ∫B * Δl = μ0I where μ0 is the permeability of free space, B is the magnetic field, dl is an infinitesimal element of the path, and I is the current enclosed by the path
So, in part (a): The magnitude of the magnetic field, B, at points along the circle in terms of I and r can be found using the formula B = μ0*I/2π*r, where μ0 is the permeability of free space and r is the radius of the circle.
Whereas, the magnitude of the magnetic field, in T, when the radius of the circle r = 0.22 m, is equal to
B = (4π x 10-7)*(185 A) / (2π*0.22 m) = 0.667 T.
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An object weighing 300 N in air is immersed in water after being tied to a string connected to a balance. The scale now reads 262 N. Immersed in oil, the object appears to weigh 273 N. Find the density of the object. Answer in units of kg/m^3.
The density of the object is:
rho object = m / V = 300 / 720 = [tex]0.4167 kg/m^3[/tex]
What best defines the density of an object?When an object is immersed in liquid, it appears to lose weight equal to the weight of the liquid displaced. Apparent weight loss is caused by an upwardly acting buoyant force that balances the weight of the object.
This problem can be solved using Archimedes' principle that the buoyant force on an object is equal to the weight of the liquid displaced by the object.
First, let's calculate the volume of the object. An object in air weighs 300 N. When immersed in water, the weight is reduced to 262 N. This means that the buoyant force acting on the object is 300 - 262 = 38 N.
Buoyancy is equal to the weight of water displaced by an object. Therefore, the volume of the object is:
[tex]V = m\ water / rho\ water = F\ buoyant / g / rho\ water[/tex]
where m water is the mass of water displaced by the object, rho water is the density of the water, F buoyancy is the buoyant force acting on the object, and g is the acceleration is respect of gravity.
Inserting the given value will result in:
[tex]V = 38 / 9.81 / 1000 = 0.00387 m^3[/tex]
Now let's calculate the density of an object when submerged in oil.
The object immersed in oil weighs 273 N. The buoyant force acting is:
F buoyancy = 300 - 273 = 27 N
The buoyant force is same to the weight of oil displaced by the object. So the volume of the object is:
V = m oil / rho oil = F buoyant / g / rho oil
where m oil is the mass of oil displaced by the object, rho oil is the density of the oil, F is the buoyant force acting on the object, and g is the acceleration due to gravity.
Inserting the given value will result in:
V = 27 / 9.81 / rho oil
We know that the volume of this object is 0.00387 [tex]m^3[/tex]. After inserting this value:
0.00387 = 27 / 9.81 / low oil
Solving Rho Oil gives:
Rho oil = 720 kg/
So the object density is:
Raw object = m / V = 300 / 720 =
0.4167/[tex]m^3[/tex]
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A 6.0-kg rock is dropped from a height of 9.0 m. At what height is the rock's kinetic energy twice its potential energy?
At a height of 4.48 meters, a rock's kinetic energy is twice its potential energy.
What are kinetic energy and potential energy?Potential energy is the energy stored in any object or system due to the position or arrangement of its parts. It is, however, unaffected by factors outside of the object or system, such as air or height. Kinetic energy, on the other hand, is the energy of moving particles in an object or system.
Given that a 6.0-kg rock is dropped from a height of 9.0 m.
Calculate the total potential energy at the initial point,
PE = mgh
PE = 6 x 9.81 x 9
PE = 530.74 J
At the zero height, the kinetic energy will be maximum and is equal to the total energy,
KE = 530.75 J
1/2 mv² = 530.75
v² = 175.85
The height at which the kinetic energy is two times the potential energy is calculated as:-
1 /2 x mv² = 2 x mgh
h = ( 4 v²) / ( 4 x 9.81 )
h = 4 ( 175.82 ) / ( 4 x 9.81 )
h = 4.48 meters
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How does light block?
When light encounters an obstacle such as a wall, it can be either absorbed, transmitted, reflected, or refracted. The way in which light is blocked depends on the characteristics of the obstacle and the properties of the light.
For example, a solid object such as a wall absorbs light, meaning that the energy of the light is transferred to the object, causing the object to heat up. This can result in the object becoming warmer, such as a wall or floor in direct sunlight, or it can result in the object changing its chemical properties, such as with photosensitive materials like photographic film.
Reflection occurs when light bounces off an object, changing the direction of the light. This can result in a mirror image or a diffuse reflection, depending on the characteristics of the object.
Refraction occurs when light passes through an object, changing the direction of the light. This can occur when light passes through transparent materials such as water or glass.
Finally, light can also be blocked by scattering, which occurs when light is dispersed in many different directions as it encounters small particles in the atmosphere, such as dust or water droplets. This is why the sky appears blue during the day, as the shorter blue wavelengths of light are scattered more than the longer wavelengths of red and orange light.
A solid object labeled A weighs more than another solid object labeled B. Which of the following are true?
Answer
A occupies more volume than B.
A has a greater weight density than B.
A has a greater specific gravity than B.
A has greater volume but lesser weight density than B.
none of the above.
Answer:
None of the above.
Mass = Mass / Volume * Volume
W(eight) = Mass * 9.80 m/s^2 = Mass * Acceleration due to gravity
One needs to know specific values to make required comparisons.
None of the statements can be determined weighs as true without additional information.
What is the gravitational force?The gravitational force pulls any two things in the cosmos, regardless of whether their masses are equal or not.
The weight of an object depends on its mass and the gravitational force acting on it. Therefore, if two objects have different weights, it does not necessarily mean that one object has a greater volume or weight density than the other.
For example, object A could be made of a denser material than object B, even though it weighs more, so it would occupy less volume. Similarly, object A could have a lower volume but a greater weight density than object B. Specific gravity also depends on the density of the object and the density of the reference material, so it cannot be determined without additional information.
Therefore, none of the statements can be determined as true without additional information.
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Complete equation Fᵧ/Fₓ = _________.
Answer:
Yx
Explanation:
..............................
13 A string of length 1.25m fixed at both ends resonates at a maximum frequency of 800Hz. Find the velocity of sound in air.
To solve for the velocity of sound in air, we can use the formula:
v = fλ
where:
v = velocity of sound
f = frequency of the wave
λ = wavelength of the wave
In this problem, we are given the frequency and the length of the string, but we need to find the wavelength. For a string fixed at both ends, the wavelength is given by:
λ = 2L/n
where:
L = length of the string
n = harmonic number
In this case, the string is fixed at both ends, so the harmonic number will be an odd number:
n = 1, 3, 5, ...
We are given that the maximum frequency is 800 Hz, which corresponds to the fundamental frequency (n = 1). Therefore:
λ = 2L/n = 2(1.25 m)/1 = 2.5 m
Now we can substitute the values into the formula for the velocity of sound:
v = fλ = (800 Hz)(2.5 m) = 2000 m/s
Therefore, the velocity of sound in air is 2000 m/s.
Wind farms are a source of renewable energy found around the world. The power p (in kilowatts) generated by a wind turbine varies directly as the cube of the wind speed v (in meters per second). If a turbine generates 600kw in a 13 m/s wind, how much power does it generate in a 14 m/s wind?.
The turbine generates approximately 781.78 kW of power in a 14 m/s wind.
The power generated by a wind turbine is directly proportional to the cube of the wind speed. Therefore, we can write:
p ∝ [tex]v^3[/tex]
where "p" is the power generated in kilowatts (kW) and "v" is the wind speed in meters per second (m/s). We can also introduce a constant of proportionality "k" to get:
p = k [tex]v^3[/tex]
To find the value of "k", we can use the given information that the turbine generates 600 kW in a 13 m/s wind. Thus:
600 = k x [tex]13^3[/tex]
Solving for "k", we get:
k = 600 / [tex]13^3[/tex]
k = 0.270270...
Now we can use this value of "k" to find the power generated by the turbine in a 14 m/s wind. Thus:
p = 0.270270... x [tex]14^3[/tex]
p ≈ 781.78 kW
Therefore, the turbine generates approximately 781.78 kW of power in a 14 m/s wind.
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If a force is applied when using a lever over 2 meters to move the object 1 meter, the distance over which the force is applied is called the _____.
The distance over which the force is applied when using a lever is called the effort distance.
What is force?Force is defined as the rate of change of momentum.
Here,
The distance over which the force is applied when using a lever is called the effort distance. It refers to the distance between the point where the effort is applied and the fulcrum of the lever. In the case we described, where a force is applied when using a lever over 2 meters to move an object 1 meter, the effort distance would be 2 meters. The load distance, on the other hand, refers to the distance between the fulcrum and the point where the load is applied. Understanding the relationship between the effort and load distances is crucial to determining the mechanical advantage of a lever system.
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what is the net electric potential at the origin due to the circular arc of charge Q1 = +7.21 pC and the two particles of charges Q2 = 4.00Q1 and Q3 = −2.00Q1? The arc's center of curvature is at the origin and its radius is R=2.00 m; the angle indicated is θ=20.0∘
The net electric potential at the origin due to the circular arc of charge Q1, and the two particles of charges Q2 and Q3 can be calculated by using the formula for electric potential due to a point charge:
V = (kQ)/r
Where V is the electric potential, k is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the point of charge to the point where we want to calculate the electric potential.
For the circular arc of charge Q1, the electric potential at the origin is:
V1 = (kQ1)/R = (8.99 x 10^9 Nm^2/C^2)(7.21 x 10^-12 C)/(2.00 m) = 1.62 x 10^-2 V
For the particle of charge Q2, the electric potential at the origin is:
V2 = (kQ2)/R = (8.99 x 10^9 Nm^2/C^2)(4.00Q1)/(2.00 m) = 4.00V1 = 6.48 x 10^-2 V
For the particle of charge Q3, the electric potential at the origin is:
V3 = (kQ3)/R = (8.99 x 10^9 Nm^2/C^2)(-2.00Q1)/(2.00 m) = -2.00V1 = -3.24 x 10^-2 V
The net electric potential at the origin is the sum of the electric potentials due to each charge:
Vnet = V1 + V2 + V3 = 1.62 x 10^-2 V + 6.48 x 10^-2 V - 3.24 x 10^-2 V
Vnet = 4.86 x 10^-2 V
Therefore, the net electric potential at the origin due to the circular arc of charge Q1 and the two particles of charges Q2 and Q3 is 4.86 x 10^-2 V.
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Which of the following correctly explain why the pressure of a gas in a rigid container increases with increasing temperature? SELECT TWO ANSWERS The average molecular speed increases with temperature, so the molecules collide with the walls of the container more frequently. The average molecular kinetic energy increases with temperature, so the molecules exert a larger average force on the walls of the container when they collide with the walls of the container. The average molecular kinetic energy increases with temperature, so the molecules exert a larger average force on each other when they collide with each other. The average molecular speed increases with temperature, so the molecules collide with each other more frequently.
A 50 kg student holding a 7 kg backpack rides a 4 kg skateboard down the sidewalk at 3 m/s. What is the total momentum of the student, backpack, and skateboard in units of kg*m/s?.
Answer:
Below
Explanation:
Total mass = ( 50 + 7 + 4) = 61 kg
momentum = m * v
= 61 kg * 3 m/s = 183 kg m/s
Assuming that autografts and isografts are not possible what is the next most successful graft type and what is the source
The next most successful graft type and what is the source of killer t cells and macrophages energy. if Assuming that autografts and isografts are not possible.
What is the source of macrophage?CCR2− macrophages are largely derived from embryonic progenitors, including contributions from yolk sac macrophages, and are primarily autonomous from blood monocytes. energy, in physics, is the capacity to do work. In contrast, resident cardiac CCR2+ macrophages are derived entirely from definitive HSCs and are replaced slowly by blood monocytes.
Are macrophages in urine?energy is the ability to do work. T cells and macrophages appear in the urine of patients with glomerulonephritis (GN), accompanied by active cellular infiltration such as cellular crescent formation and diffuse interstitial cell infiltration, but not in the urine of patients with GN without the active inflammatory lesions.
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Estimate the difference in oxygen concentration within the plastic across the. wall of the ... rounding the pipe shows that in steady state 0.633!mg of
3. What is the electrostatic force of attraction between a -5.8 x 10-7C charge and a 3.8 x 10-8C charge if they are separated by a distance of 4.4 meters?
Answer:
1.73 x 10-7 N
Explanation:
3. What is the electrostatic force of attraction between a -5.8 x 10-7C charge and a 3.8 x 10-8C charge if they are separated by a distance of 4.4 meters?
The electrostatic force of attraction between two charges can be calculated using Coulomb's law, which states that the force of attraction is inversely proportional to the square of the distance between them. In this case, the two charges are -5.8 x 10-7C and 3.8 x 10-8C and they are separated by a distance of 4.4 meters. Plugging these values into Coulomb's law, the electrostatic force of attraction is 1.73 x 10-7 N.
1 /B 1 B 1 1/ Q B A A space ship, initially traveling at constant velocity along a straight line, decides to switch course. It first fires it's engine at full power for a very short time in the direction perpendicular to its trajectory at point A, giving it an instantaneous large boost. Then at point B, it fires its engine continuously at a much lower power in the opposite direction until it reaches point C. Which of the following trajectories most closely represent the trajectory of the ship? R Search listening t... KWFinder: Keywor... A space ship, initially traveling at constant velocity along a straight line, decides to switch course. It first fires it's engine at full power for a very short time in the direction perpendicular to its trajectory at point A, giving it an instantaneous large boost. Then at point B, it fires its engine continuously at a much lower power in the opposite direction until it reaches point C. Which of the following trajectories most closely represent the trajectory of the ship? Pick the correct answer 0 1 g 2 O 3 o 4 o 5 Submit
The spaceship undergoes an instantaneous change in velocity at point A and then undergoes a continuous change in velocity at point B until it reaches point C. The trajectory of the spaceship is therefore curved and can be represented by one of the given options.
What is Instantaneous Velocity?
Instantaneous velocity is the velocity of an object at a specific moment in time or at a specific point in its motion. It is the limit of the average velocity as the time interval over which it is calculated approaches zero. In other words, it is the slope of the tangent to the position-time graph at a particular point.
To calculate the instantaneous velocity of an object, you need to determine the object's position at a specific moment in time and then take the derivative of the position function with respect to time. The resulting derivative gives you the object's instantaneous velocity at that specific moment in time.
Instantaneous velocity is important in physics and many other fields because it allows us to understand the behavior of objects in motion and to calculate important quantities such as acceleration, momentum, and energy.
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an object is horizontally dragged across the surface by a 100N force acting parallel to the surface.find the amount of work done by the force in movING the object through a distance of 8m
Answer:
the amount of work done by the force in moving the object through a distance of 8m is 800 Joules.
Explanation:
The work done by a force is given by the product of the force and the distance moved in the direction of the force. In this case, the force is acting parallel to the surface and causing the object to move horizontally, so the work done is:
Work = force x distance
Work = 100N x 8m
Work = 800 Joules (J)
Therefore, the amount of work done by the force in moving the object through a distance of 8m is 800 Joules.
What is viscosity ? explain with an example !
Answer:
Viscosity is the state of being thick, sticky, and semifluid, because of friction. A example is honey or syrup.
What is the best way to study physics
Studying physics can be challenging, but there are several strategies that can help you learn the subject more effectively. Here are some tips:
1. Review and understand the basics: Physics builds on foundational concepts, so it's essential to have a solid grasp of the basics before moving on to more complex material.
2. Practice problem-solving: Physics is all about solving problems, so practice is key. Work through as many problems as you can, and use a variety of resources such as textbooks, problem sets, and online resources.
Create study groups: Studying with others can be a great way to learn physics. Discussing concepts, working through problems, and teaching each other can help reinforce learning.
4. Seek help when needed: Physics can be challenging, and it's okay to ask for help. Seek assistance from your teacher, tutor, or study group when you are struggling with a concept or problem.
5. Use visual aids: Physics often deals with abstract concepts, so using visual aids such as diagrams, graphs, and videos can help to make the material more concrete and easier to understand.
6. Stay organized: Keep track of assignments, due dates, and notes in an organized way to avoid confusion and ensure that you don't fall behind.
7. Stay curious: Physics can be a fascinating subject, and cultivating a genuine interest in the subject can help motivate you to learn more and understand it better.