When J.J. Thomson discovered the electron, the physical property he measured was B) its charge-to-mass ratio, e/m.
He did this by conducting experiments using a cathode ray tube, which allowed him to observe the behavior of electrons in the presence of electric and magnetic fields. By analyzing the deflection of the electron beam, Thomson was able to determine the charge-to-mass ratio of the electron.This ratio was determined through experiments involving the discharge of electricity through a vacuum tube, the deflection of cathode rays by electric and magnetic fields, and the measurement of the radius of the cathode rays. From these experiments, Thomson was able to calculate the charge-to-mass ratio of the electron.
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A power supply delivers a sinusoidal voltage of root mean square value Voto a capacitor Cindependent of frequency f. The average power dissipated in the capacitor is closest to: A) V7wC. B) V7wC/2. C)V2/WC. D) V2/40C E) zero
The correct answer is E) zero. Since the voltage is sinusoidal and the capacitor is independent of frequency, the capacitor will act as an open circuit to the AC signal.
This means that no current will flow through the capacitor and therefore no power will be dissipated. The formula for power dissipation in a capacitor is [tex]P = V^2 / XC[/tex], where V is the voltage, XC is the capacitive reactance (which is inversely proportional to frequency), and C is the capacitance. Since the capacitor is independent of frequency, XC is infinite, making the power dissipation zero. Therefore, the answer is E) zero.
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an object is traveling on a level surface at 30 mph when the surface becomes a ramp with an angle of 30 degrees with the horizontal. the object goes up the ramp. how long (in seconds) does the object to come to rest?
It takes approximately 2.734 seconds for the object to come to rest as it travels up the ramp if speed at surface level is 30km/h.
we'll first need to determine the component of acceleration acting against the object's motion as it travels up the ramp.
Then, we'll use that information to calculate the time it takes for the object to come to rest.
Step 1: Calculate the acceleration due to gravity acting parallel to the rampThe acceleration due to gravity (g) is 9.81 m/s^2. To find the component of gravity acting along the ramp, we'll use the formula:a_parallel = g * sin(angle)where angle is 30 degrees. First, convert 30 degrees to radians:angle (in radians) = (30 * π) / 180 ≈ 0.524 radians
Now, find the parallel acceleration:
a(parallel) = 9.81 * sin(0.524) ≈ 4.905 m/s^2
Step 2: Convert the object's initial speed to meters per secondThe object is initially traveling at 30 mph.
To convert this to meters per second (m/s), use the conversion factor 1 mph ≈ 0.44704 m/s:
initial speed (in m/s) = 30 * 0.44704 ≈ 13.411 m/s
Step 3: Calculate the time it takes for the object to come to rest
Now we'll use the formula:
final speed = initial speed + (acceleration * time)Since the object comes to rest, its final speed is 0 m/s. We can now solve for time:0 = 13.411 - (4.905 * time)time ≈ 2.734 seconds
So, it takes approximately 2.734 seconds for the object to come to rest as it travels up the ramp.
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An aircraft A is flying at a constant speed of 270 m/s at a constant height of100 m above the surface of the earthThe aircraft directs a radar beam of wavelength 1.0 cm at a target T on the Earth's surface. After 90 us, an echo from the target is detected on the aircraft the frequency of the radar waves is 3 x 10^10Hz, find
(a) the speed of the radar waves
(b) the distance AT between aircraft and target
(c) the time which elapses before A is vertically above T.
A) The speed of the radar waves = 3 x 10^8 m/s
B) The distance between the aircraft and the target is 27 km.
C) It takes 100 seconds for the aircraft to be vertically above the target.
Radar wave speed, distance and time(a) The speed of the radar waves can be found using the formula:
speed of light = frequency x wavelength
Since radar waves are a type of electromagnetic waves and travel at the speed of light, we can use the above formula to find the speed of the radar waves:
speed of radar waves = speed of light = 3 x 10^8 m/s
(b) To find the distance AT between the aircraft and the target, we can use the formula:
distance = (speed x time) / 2
where speed is the speed of the radar waves (which we found to be 3 x 10^8 m/s), and time is the time taken for the radar waves to travel to the target and back (which is twice the time it took for the echo to be detected on the aircraft).
time taken for radar waves to travel to target and back = 2 x 90 us = 180 us = 1.8 x 10^-4 s
So, the distance between the aircraft and the target can be calculated as:
distance AT = (speed of radar waves x time taken for radar waves to travel to target and back) / 2
= (3 x 10^8 m/s x 1.8 x 10^-4 s) / 2
= 27 km
Therefore, the distance between the aircraft and the target is 27 km.
(c) To find the time which elapses before A is vertically above T, we can use the formula:
time = distance / speed
where distance is the horizontal distance between the aircraft and the target (which we found to be 27 km), and speed is the speed of the aircraft (which we were not given, but we can assume is constant).
Since the aircraft is flying at a constant speed, the time it takes to travel the horizontal distance between the aircraft and the target is the same as the time it takes for the aircraft to be vertically above the target. Therefore, the time which elapses before A is vertically above T is:
time = distance / speed
= 27 km / (270 m/s)
= 100 s
Therefore, it takes 100 seconds for the aircraft to be vertically above the target.
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51. How far did the bicycle travel during the 5.0 seconds of braking?
A) 1.8 m
B) 8.8 m
C) 22 m
D) 42 m
E) 44 m
The distance of the bicycle that traveled during the 5.0 seconds of braking is 2.98 m (there is no a correct option)
To determine how far the bicycle traveled during the 5.0 seconds of braking, we need to use the formula:
distance = initial velocity x time + 1/2 x acceleration x time²
Since the bicycle is braking, its initial velocity is its speed before braking, which we don't know. However, we know that the bicycle comes to a stop after 5 seconds of braking, so its final velocity is 0 m/s. We also know that the acceleration due to braking is -3.5 m/s².
Therefore, we can rearrange the formula to solve for distance:
distance = (final velocity - initial velocity) x time / 2 x acceleration
distance = (0 m/s - initial velocity) x 5 s / 2 x (-3.5 m/s²)
distance = (initial velocity) x 5 s / 7 m/s²
Now we need to estimate the initial velocity of the bicycle before braking. Assuming a typical bicycle traveling at a moderate speed of 15 km/h (4.17 m/s), it would take about 5-6 seconds to come to a complete stop under braking. Therefore, we can estimate that the initial velocity of the bicycle was around 4.17 m/s.
Plugging this value into the formula, we get:
distance = 4.17 m/s x 5 s / 7 m/s²
distance = 2.98 m
Therefore, the bicycle traveled during the 5.0 seconds of braking is 2.98 m.
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To find the correction factor for situation where four or more current carrying conductors are bundled together, consult Table _____.
To find the correction factor for a situation where four or more current carrying conductors are bundled together, consult Table 310.15(B)(3)(a) in the National Electrical Code (NEC).
This table provides adjustment factors for ambient temperature, conductor size, and number of conductors in a raceway or cable. The correction factor is used to adjust the ampacity of the conductors to account for the increased heat generated by the bundled conductors.
To find the correction factor for a situation where four or more current-carrying conductors are bundled together, consult Table 310.15(B)(3)(a).
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Question 26
What statement concerning ozone is incorrect?
a. Ozone residual can last several hours
b. Ozone is faster disinfectant than chlorine
c. Ozone is more expensive than chlorine
d. All statements are correct
Regarding ozone, option D: all statements are correct as it is a faster disinfectant than Chlorine, more expensive and also its residuals can last more than several hours.
In the upper stratosphere of the atmosphere, UV rays split oxygen into separate oxygen or nascent oxygen. Other oxygen molecules combine with these nascent oxygen atoms to form ozone. Ozone forms a protective layer of earth that protects us from harmful UV radiations. Hence, it is necessary to maintain the ozone layer. The reaction occurs as follows:
O₂ + UV rays → 2O
O₂ + O → O₃
Ozone layer is thermodynamically unstable and hence decomposes to molecular oxygen. CFCs or freons, non-organic molecules are known responsible for its depletion. It is obviously more expensive and a better disinfectant than chlorine.
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What is the total internal energy of a monoatomic ideal gas? Diatomic ideal gas? Non-linear?
The total internal energy of an ideal gas, monoatomic or diatomic, is a measure of the energy contained within the gas due to its molecular motion.
For a monoatomic ideal gas, the internal energy is proportional to the temperature of the gas and is given by the equation
U = (3/2) nRT
where U is the internal energy, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
This equation reflects the fact that each molecule of a monoatomic ideal gas has three degrees of freedom for translational motion, and thus contributes (1/2)kT to the internal energy of the gas, where k is Boltzmann's constant.
For a diatomic ideal gas, the internal energy is slightly more complex due to the additional degrees of freedom associated with molecular rotation. At low temperatures, the diatomic molecules cannot rotate and the internal energy is given by U = (5/2) nRT, which includes the three degrees of freedom for translational motion and two degrees of freedom for vibration.
At higher temperatures, the diatomic molecules can rotate and the internal energy is given by U = (7/2) nRT, which includes the additional two degrees of freedom for rotation.
For a non-linear ideal gas, the internal energy depends on the specific molecular structure and the number of degrees of freedom associated with molecular motion. In general, the internal energy is given by
U = (f/2) nRT
where f is the total number of degrees of freedom for motion.
For example, a triatomic gas molecule has six degrees of freedom: three for translational motion, two for vibration, and one for rotation about a specific axis.
Therefore, its internal energy would be
U = (6/2) nRT = 3nRT.
In conclusion, the total internal energy of an ideal gas depends on its molecular structure and the number of degrees of freedom for molecular motion, with monoatomic, diatomic, and non-linear gases each having a distinct formula for their internal energy.
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on a hot summer day a girl has one foot in the grass and one foot on the cement right next to it. Explain why the cement feels so much warmer
The concrete will seem much warmer because of how it holds and radiates heat when the female has one foot in the grass and one foot on it. The reason for this is difference in specific heat.
Why the cement feels so much warmer?The concrete will seem much warmer because of how it holds and radiates heat when the female has one foot in the grass and one foot on it. Concrete absorbs heat more rapidly and easily than grass because it is porous and a good conductor of heat. Grass will stay cooler because it has a higher insulation value, which traps heat and prevents it from transferring as quickly. The dense, paved surfaces like concrete and asphalt absorb more heat from the sun than natural surfaces like grass or dirt, leading to the phenomenon known as the urban heat island effect. As a result, on a hot summer day, the concrete will seem much warmer than the grass.
What is Specific Heat?Also known as specific heat, this is the quantity of energy required to increase a substance's temperature by one degree Celsius in one gram. The units of specific heat are typically calories or joules per gram per degree Celsius. As an illustration, the specific heat of water is 1 calorie (4.186 joules) per gram per degree Celsius. Joseph Black, a Scottish scientist, discovered that equivalent masses of various substances required different amounts of heat to elevate them over the same temperature range, which led him to establish the concept of specific heat.
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What will be the net charge on an object which attracts neutral pieces of paper but repels a negatively charged balloon?
The object must have a neutral net charge. It attracts neutral pieces of paper because of electrostatic forces, but it repels a negatively charged balloon because of the principle of electric charge. If the object had a positive net charge, it would attract the negatively charged balloon, not repel it.
The only possibility is that the object has a neutral net charge. Based on your question, the net charge on the object is positive. The object attracts neutral pieces of paper. When an object is charged, it can induce a temporary charge on a neutral object like the pieces of paper and attract it. The object repels a negatively charged balloon. According to Coulomb's Law, like charges repel each other. Since the negatively charged balloon is repelled, the object must have a negative charge too. Considering both observations, the object has a net positive charge because it attracts neutral objects and repels negatively charged ones.
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a circular loop of wire lies flat on a level table top. a bar magnet is held stationary above the circular loop with its north pole point downward. as viewed from above, in what direction does the induced current flow in the loop of wire? a circular loop of wire lies flat on a level table top. a bar magnet is held stationary above the circular loop with its north pole point downward. as viewed from above, in what direction does the induced current flow in the loop of wire? an induced current flows clockwise in the loop of wire. an induced current flows counterclockwise in the loop of wire. no current is induced in the loop of wire. the direction of the induced current cannot be determined from the given information.
The induced current flows clockwise in the loop of wire. When a bar magnet is held stationary above a circular loop of wire with its north pole pointing downward, as viewed from above, the induced current in the loop of wire will flow counter clockwise.
This is due to Lenz's law, which states that the direction of the induced current flows clockwise in the loop of wire. current will be such that it opposes the change in magnetic flux that is producing it. In this case, the counterclockwise current creates a magnetic field opposing the downward magnetic field of the north pole of the bar magnet. the direction of the magnetic field will be down in the plane at the center. The magnetic field produced by a current-carrying wire loop will be in a single direction at the center. The direction of magnetic field at the center of a current-carrying circular loop is perpendicular to the plane of the loop.
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Question 81
The siting of nuclear facilities is subject to extensive regulation and licensing by the a. Federal health department
b. National environmental protection agency
c. Nuclear regulatory commission
d. Consumer product safety commission
The siting of nuclear facilities is subject to extensive regulation and licensing by the c. Nuclear Regulatory Commission.
The siting of nuclear facilities is subject to extensive regulation and licensing by the Nuclear Regulatory Commission to ensure the safety and protection of the public and the environment from potential nuclear hazards. The Nuclear Regulatory Commission regulates commercial nuclear power plants and other uses of nuclear material. The NRC licenses and regulates the Nation's civilian use of radioactive materials to protect public health and safety, promote common defense and security, and protect the environment.
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a proton is not the only nucleus that has a magnetic dipole moment. another is the nucleus of the isotope 15n , which is sometimes imaged in mri. the gyromagnetic ratio of a 15n nucleus is 10.1% that of a proton. part a what is the precession frequency of a 15n nucleus in a 1.50 t mri machine? express your answer with the appropriate units.
Therefore, the precession frequency of a 15n nucleus in a 1.50 T MRI machine is 6.45 MHz. The appropriate units are megahertz (MHz).
The precession frequency of a 15n nucleus can be calculated using the formula:
frequency = gyromagnetic ratio x magnetic field strength
In this case, the gyromagnetic ratio of a 15n nucleus is 10.1% that of a proton, so we can write:
gyromagnetic ratio = 0.101 x gyromagnetic ratio of a proton
The gyromagnetic ratio of a proton is approximately 42.58 MHz/T, so the gyromagnetic ratio of a 15n nucleus is:
gyromagnetic ratio = 0.101 x 42.58 MHz/T = 4.30 MHz/T
The magnetic field strength of a 1.50 T MRI machine is 1.50 T, so the precession frequency of a 15n nucleus in this machine is:
frequency = 4.30 MHz/T x 1.50 T = 6.45 MHz
Therefore, the precession frequency of a 15n nucleus in a 1.50 T MRI machine is 6.45 MHz. The appropriate units are megahertz (MHz).
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how did the ancient greeks attempt to explain the motion of the planets?
The ancient Greeks were some of the first to attempt to explain the motion of the planets. They believed that the planets, including the sun and the moon, revolved around the Earth. They also believed that the planets moved in circular orbits, which was known as the geocentric model. This theory was proposed by the famous astronomer Ptolemy in the 2nd century CE.
The ancient Greeks also believed that the motion of the planets was influenced by the gods and that their movements could predict future events. Although the geocentric model was eventually disproven by scientists such as Galileo and Copernicus, the work of the ancient Greeks laid the foundation for modern astronomy.
To account for the irregularities in the motion of the planets, the Greeks added epicycles, small circular orbits that were superimposed on the larger circular paths of the planets. By adjusting the size and speed of these epicycles, the Greeks were able to predict the positions of the planets with reasonable accuracy.
This geocentric model was widely accepted in ancient Greece and remained the dominant model of the universe for many centuries. However, it was eventually replaced by the heliocentric model proposed by Nicolaus Copernicus in the 16th century, which placed the Sun at the center of the universe and explained the motion of the planets in a simpler, more elegant way.
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The ancient Greeks attempted to explain the motion of the planets through a geocentric model, which held that the Earth was at the center of the universe and that the planets, the sun, and the stars revolved around it.
This model was first proposed by the philosopher Aristotle in the 4th century BCE, and was later elaborated by the astronomer Ptolemy in the 2nd century CE.
According to the geocentric model, each planet moved in a perfect circle, called an epicycle, around a point called a deferent, which itself moved in a circle around the Earth.
The speed of the planet was not constant, but varied as it moved around its epicycle.
The geocentric model was consistent with observations of the motions of the planets and stars, and was widely accepted in the ancient world.
However, it had some inconsistencies and could not account for all observations accurately.
In the 16th century, the Polish astronomer Nicolaus Copernicus proposed a heliocentric model, which held that the Sun, not the Earth, was at the center of the universe, and the planets revolved around it.
This model provided a more accurate explanation of the motions of the planets, and eventually became widely accepted.
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The following table gives the angular speed of a rotating fan blade at various times as it slows to a stop.
Time (s) Angular speed (rad/s)
0 5. 0
2. 0 4. 1
4. 0 3. 0
Part A
Find the average angular acceleration for the times t=0 to t=2. 0s
Part B
Find the average angular acceleration for the times t=0 to t=4. 0s.
Part C
Find the average angular acceleration for the times t=2. 0s to t=4. 0s
The angular speed of a rotating fan blade at various times as it slows to a stop. Time (s) Angular speed (rad/s)
0 5. 0
2. 0 4. 1
4. 0 3. 0
Part A. The average angular acceleration for the times t=0 to t=2.0s is -0.45 rad/[tex]s^{2}[/tex].
Part B. The average angular acceleration for the times t=0 to t=4.0s is -0.5 rad/[tex]s^{2}[/tex].
Part C. The average angular acceleration for the times t=2.0s to t=4.0s is -0.55 rad/[tex]s^{2}[/tex].
Part A
The change in angular speed during the first 2.0 seconds is
Δω = ωf - ωi = 4.1 rad/s - 5.0 rad/s = -0.9 rad/s
The average angular acceleration during this time interval is
α = Δω / Δt = (-0.9 rad/s) / (2.0 s) = -0.45 rad/[tex]s^{2}[/tex]
Therefore, the average angular acceleration for the times t=0 to t=2.0s is -0.45 rad/[tex]s^{2}[/tex].
Part B
The change in angular speed during the first 4.0 seconds is
Δω = ωf - ωi = 3.0 rad/s - 5.0 rad/s = -2.0 rad/s
The average angular acceleration during this time interval is
α = Δω / Δt = (-2.0 rad/s) / (4.0 s) = -0.5 rad/[tex]s^{2}[/tex]
Therefore, the average angular acceleration for the times t=0 to t=4.0s is -0.5 rad/[tex]s^{2}[/tex].
Part C
The change in angular speed during the time interval t=2.0s to t=4.0s is
Δω = ωf - ωi = 3.0 rad/s - 4.1 rad/s = -1.1 rad/s
The average angular acceleration during this time interval is
α = Δω / Δt = (-1.1 rad/s) / (2.0 s) = -0.55 rad/[tex]s^{2}[/tex]
Therefore, the average angular acceleration for the times t=2.0s to t=4.0s is -0.55 rad/[tex]s^{2}[/tex].
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a parallel-plate capacitor in air has circular plates of radius 2.9 cm separated by 1.1 mm. charge is flowing onto the upper plate and off the lower plate at a rate of 6 a. find the time rate of change of the electric field between the plates.
The time rate of change of the electric field between the plates of the parallel-plate capacitor in air is 8.20 x 10^7 N/C/s.
A parallel-plate capacitor with circular plates of radius 2.9 cm and a separation of 1.1 mm has charge flowing onto the upper plate and off the lower plate at a rate of 6 A.
To find the time rate of change of the electric field between the plates, we can use the formula:
dE/dt = (dQ/dt) / (ε₀ * A)
Where dE/dt is the time rate of change of the electric field, dQ/dt is the rate of charge flow (6 A), ε₀ is the vacuum permittivity (8.85 × 10⁻¹² F/m), and A is the area of the circular plates.
First, calculate the area of the circular plates:
To find the time rate of change of the electric field between the plates of the parallel-plate capacitor in air, we can use the formula:
dE/dt = (I/Aε0)
Where dE/dt is the time rate of change of the electric field, I is the current flowing onto the upper plate and off the lower plate (which is given as 6 A), A is the area of the plates (which is πr^2, where r is the radius of the plates), and ε0 is the permittivity of free space (which is a constant value of 8.85 x 10^-12 C^2/Nm^2).
Substituting the given values, we get:
dE/dt = (6/(π(0.029)^2)(8.85 x 10^-12)
Simplifying this expression, we get:
dE/dt = 8.20 x 10^7 N/C/s
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two forces are acting on an object F1 = 78 N upward and F2 = 26 N downward. What third force will cause the object to be in equilibrium?52 N pointing down52 N pointing up82 N pointing down82 N pointing up
To find the third force that will cause the object to be in equilibrium, we need to calculate the net force acting on the object. Net force is the sum of all the forces acting on the object. In this case, we have two forces, F1 = 78 N upward and F2 = 26 N downward. To calculate the net force, we subtract the smaller force from the larger force. So, in this case, the net force is 78 N - 26 N = 52 N upward.
Therefore, to keep the object in equilibrium, we need a third force that is equal in magnitude but opposite in direction to the net force. That means we need a force of 52 N pointing downward. Any other force that is equal in magnitude but in the opposite direction would also work. For example, a force of 82 N pointing upward would also keep the object in equilibrium.
It's important to note that in order for the object to be in equilibrium, the net force acting on it must be zero. This means that the sum of all the forces acting on the object must be equal to zero. In this case, we have two forces with opposite directions, so they cancel each other out, resulting in a net force of zero.
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52 N pointing downward third force will cause the object to be in equilibrium.
In order for an object to be in equilibrium, the net force acting on it must be zero. This means that the sum of all the forces acting on the object must be equal to zero. In this case, we have two forces acting on the object, F1 = 78 N upward and F2 = 26 N downward.
To find the third force that will cause the object to be in equilibrium, we need to find a force that will balance out the two existing forces. Since F1 is pointing upward and F2 is pointing downward, we know that the third force must also be pointing upward.
To balance out the two forces, we need to find a force that is equal in magnitude to the sum of F1 and F2, but pointing in the opposite direction. The sum of F1 and F2 is 78 N - 26 N = 52 N upward. Therefore, the third force that will cause the object to be in equilibrium is 52 N pointing downward.
In summary, the answer is: 52 N pointing downward.
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(Table 310-15(a)(16)):What is the ampacity of No. 8 THHN conductors when installed in a walk in cooler if the ambient temperature is 50F?
According to Table 310-15(a)(16) of the National Electrical Code (NEC), the ampacity of No. 8 THHN conductors for a temperature of 50°F is 50 amperes.
However, the ampacity of the conductors depends on other factors as well, such as the length of the conductors, the type of insulation used, the number of conductors in the conduit, and the ambient temperature of the location where the conductors are installed. It is important to properly size the conductors based on all these factors to ensure safe and efficient operation of the electrical system.
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13) What do we mean by a protogalactic cloud? A) a cloud of hydrogen and helium that contracts to become a galaxy B) a term once used historically to refer to any galaxy C) the cloud-like halo that surrounds the disks of spiral galaxies D) a cloud of gas that was once a galaxy
A protogalactic cloud refers to option A) a cloud of hydrogen and helium that contracts to become a galaxy.
It is an early stage in the formation of a galaxy where gas and dust come together under the influence of gravity, eventually leading to the development of a fully formed galaxy.A protogalactic cloud is a cloud of gas and dust that is in the process of collapsing to form a new galaxy. These clouds are typically composed of hydrogen, helium, and other elements, and contain the seeds of stars and planets that will form within the newly forming galaxy. Protogalactic clouds are believed to be the birthplace of galaxies and are thought to be the sites of the earliest star formation in the universe.
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an outboard motor for a boat is rated at 55 hp. if it can move a particular boat at a steady speed of 35 km/h, what is the total force resisting the motion of the boat?
To calculate the total force resisting the motor of the boat, we can use the equation. Total Force = 0.5 x Density of Water x Cross-Sectional Area of the Boat x Drag Coefficient x [tex]velocity^{2}[/tex] + Weight of the Boat Since we are given.
The boat is moving at a steady speed of 35 km/h, we need to convert this to meters per second. 35 km/h = 9.72 m/s We are also given that the motor is rated at 55 hp, but we don't need to use this information to calculate the total force. Now, we need to estimate some values for the other variables in the equation. The density of water is approximately 1000 kg/[tex]m^{2}[/tex], the cross-sectional area of the boat is not given, and the drag coefficient varies depending on the shape of the boat. Let's assume a cross-sectional area of 10 [tex]m^{2}[/tex]and a drag coefficient of 0.5 which is typical for a boat of this size and shape. Using these values, we can calculate the total force as Total Force = 0.5 x 1000 kg/[tex]m^{2}[/tex] x 10 [tex]m^{2}[/tex] x 0.5 x 9.72 m/[tex]s^{2}[/tex] + Weight of the Boat We don't know the weight of the boat, but we can still solve for the total force. Simplifying the equation gives Total Force = 1182.2 N/[tex]m^{2}[/tex] x Weight of the Boat So, the total force resisting the motion of the boat depends on the weight of the boat. If we had that information, we could use the equation above to calculate the total force.
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What is the wavelength of a radio wave traveling in a vacuum that has a frequency of 7.80x10^7Hz?
The wavelength of the radio wave with a frequency of 7.80×10⁷ Hz is 3.846 m.
The wavelength and frequency are inversely proportional to each other. The frequency of the wave gives the number of oscillations per unit of time.
The wavelength is defined as the distance between crests and troughs and the unit of wavelength is a meter.
From the given,
frequency (ν) = 7.80×10⁷ Hz
wavelength (λ) =?
frequency (ν) = c / λ, where c is the velocity of light and λ is the wavelength.
λ = c/ν
= (3×10⁸ m/s) / (7.80×10⁷ Hz)
= 3.846 m
Thus, the wavelength of the radio wave is 3.846m.
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List 3 requirements that capacitance of capacitors depends on
Capacitance of capacitors depends on several factors. Here are 3 key requirements that influence capacitance: Surface Area , Distance between Plates , Dielectric Material.
1. Surface Area: Capacitance is directly proportional to the surface area of the capacitor's conductive plates. Larger surface areas allow for more charge to be stored, which increases the capacitance value.
2. Distance between Plates: Capacitance is inversely proportional to the distance between the capacitor's plates. As the distance between the plates decreases, the electric field strength between them increases, leading to a higher capacitance value.
3. Dielectric Material: Capacitance is also dependent on the dielectric material (insulator) placed between the plates. The dielectric constant of the material determines its ability to store electric charge, and a higher dielectric constant results in a higher capacitance value.
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1) If we could see our own galaxy from 2 million light-years away, it would appear
A) as a flattened disk with a central bulge and spiral arms.
B) as a faintly glowing band of light stretching all the way around the sky.
C) to fill the sky with widely spaced stars.
D) like a single, dim star.
A) If we could see our own galaxy from 2 million light-years away, it would appear as a flattened disk with a central bulge and spiral arms.
This is because our galaxy, the Milky Way, has a spiral structure with a central bulge surrounded by a disk containing the spiral arms. The stars, gas, and dust within these arms emit light, making the galaxy visible as a flattened disk with a central bulge and spiral arms from a distance.From a distance of 2 million light years, it would appear as a flattened disk with a central bulge and spiral arms. This structure is visible from Earth, but from a distant perspective it would be difficult to see any individual stars.
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You push with a steady force of 19 N on a 46-kg desk fitted with casters (wheels that swivel) on its four feet.
How long does it take you to move the desk 5.1 m across a warehouse floor?
It would take you 12.4 seconds to move the desk 5.1 m across the warehouse floor. we need to find the time it takes to move the desk across the warehouse floor. First, we'll find the acceleration of the desk, and then use the equation of motion to find the time.
To calculate the time it takes to move the desk 5.1 m across the warehouse floor, we need to use the formula:
time = distance / speed
First, we need to find the speed of the desk. Since the force applied to the desk is steady, we can use the formula:
force = mass x acceleration
to find the acceleration of the desk.
19 N = 46 kg x acceleration
acceleration = 0.413 m/s^2
Next, we can use the formula:
speed = acceleration x time
to find the speed of the desk.
speed = 0.413 m/s^2 x time
Finally, we can plug in the distance and solve for time:
time = distance / speed
time = 5.1 m / (0.413 m/s^2 x time)
time = 12.4 seconds
Therefore, it would take you 12.4 seconds to move the desk 5.1 m across the warehouse floor.
1. Find the acceleration:
F = ma, where F is the force applied, m is the mass of the desk, and a is the acceleration.
a = F/m = 19 N / 46 kg ≈ 0.413 m/s²
2. Use the equation of motion:
s = ut + 0.5at², where s is the distance covered, u is the initial velocity (0 m/s, as the desk is initially at rest), t is the time taken, and a is the acceleration found in step 1.
5.1 m = 0 + 0.5 * 0.413 m/s² * t²
10.2 m = 0.413 m/s² * t²
t² ≈ 24.71 s²
t ≈ √24.71 ≈ 4.97 s
So, it takes you approximately 4.97 seconds to move the desk 5.1 meters across the warehouse floor with a steady force of 19 N and casters fitted on the desk.
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Place the following in sequence: A) Hubble makes his discoveries; B) Cosmic background radiation is first detected; C) Lemaitre proposes his theory
The correct sequence is:
C) Lemaitre proposes his theory --> A) Hubble makes his discoveries --> B) Cosmic background radiation is first detected.
Lemaitre proposed his theory of the expanding universe, which later became known as the Big Bang theory, in the 1920s. Hubble's observations in the 1920s and 1930s provided evidence for the expansion of the universe and the relationship between distance and recession velocity for galaxies.
The cosmic microwave background radiation, which is the afterglow of the Big Bang, was first detected in 1964 by Arno Penzias and Robert Wilson.
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Stamping your feet cleans the snow off of them because _____.
a) the heat generated by the stamping melts the snow somewhat.
b) the snow on your feet has inertia.
c) the vibration of the stamping lowers the friction between the snow and the foot.
d) the force of the stamping knocks it off.
Pls answer the question using graph and the one about identifying 50 points
Answer:
The graph is A, and the others are as follows: 18m/s = V; 16m/s/s = A; 50cm/min = V; 8mi = D; 2m = D; 20s = T; 42s = T; 122min = T; 8m/s/s = A
Explanation:
The graph shows the y-value increasing, and since the y-value represents velocity, that means that the velocity is increasing, and since we know that the velocity is getting larger at a constant rate, shown by the straight line, we know that the car is also accelerationg, therfore making the answer A.
Distance/Time is equal to velocity, therefore all questions with a distance over a time are velocity. m stands for meters, and mi stands for miles, both of which are measures of distance. s stands for seconds, and min stands for minutes, both of which are measurements of time. Lastly, m/s/s is a form of identifying acceleration.
Give the number of protons (p), neutrons (n), and electrons (e) in one atom of 238U.A) 146 p, 92 n, 92 e D) 146 p, 28 n, 146 eB) 92 p, 92 n, 92 e E) 238 p, 146 n, 238 eC) 92 p, 146 n, 92e
The correct answer is A) 146 p, 92 n, 92 e. This is because the atomic number of uranium (U) is 92, which means it has 92 protons in its nucleus.
The atomic mass of uranium is 238, which means it has a total of 238 particles in its nucleus. To find the number of neutrons, you subtract the atomic number (92) from the atomic mass (238), giving you 146 neutrons. Finally, because the atom is neutral (has no overall charge), it must have the same number of electrons as protons, so there are also 92 electrons in one atom of 238U.
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Put the following chemical elements in order from lowest number of protons in the nucleus (top) to the highest number (bottom).1. Hydrogen.2. Helium.3. Carbon.4. Oxygen.5. Iron.
1. Hydrogen: With an atomic number of 1, hydrogen has the lowest number of protons in the nucleus.
What is atomic number?Atomic number is an important property of an element and is used to classify elements. It refers to the number of protons in the nucleus of an atom of that element. Protons have a positive charge and the number of protons indicates the charge of an atom. The atomic number of an element is unique and constant, and it is always written as a subscript on the element symbol.
2. Helium: With an atomic number of 2, helium has the second lowest number of protons in the nucleus.
3. Carbon: With an atomic number of 6, carbon has the third lowest number of protons in the nucleus.
4. Oxygen: With an atomic number of 8, oxygen has the fourth lowest number of protons in the nucleus.
5. Iron: With an atomic number of 26, iron has the highest number of protons in the nucleus.
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order for our moon
When the moon first formed, it was only 14,000 above the Earth's surface outside f
Roche limit. It took only to 100
to form.
When the moon first formed, it was only 14,000 miles above the Earth's surface outside the Roche limit.
The distance between two celestial bodies which are held together with the force of gravity between them, is called the Roche limit or Roche radius.
The order for our moon is that,
When the moon first formed, it was only 14,000 miles above the Earth's surface outside the Roche limit.
It took only to 100 years to form.
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Conductors in Parallel(310-10(H)(1)(Table 250-122): What are the conductors required for a 250 ampere feeder paralleled in two raceways?
The also recommended to consult a licensed electrician and comply with any local codes and regulations that may apply to the specific installation.
Why will be the conductors required for a 250 ampere feeder paralleled?To determine the conductors required for a 250 ampere feeder that is paralleled in two raceways, we need to consult the [tex]NEC[/tex] (National Electrical Code) Table 310.16, which provides ampacity values for various types and sizes of conductors.
Assuming the raceways are located in the same area and under the same conditions, we can parallel the conductors in accordance with the [tex]NEC 310.10(H)(1)[/tex] requirements.
This means that each parallel conductor must have the same length, be the same size, and be made of the same material.
Based on [tex]NEC[/tex] Table 250.122, we can use two parallel sets of 4/0 AWG conductors, which have an ampacity of 230 amps each.
Therefore, two sets of 4/0 AWG conductors in parallel would provide a total ampacity of 460 amps, which is well above the required 250 ampere feeder size.
It is important to note that this answer assumes that the installation complies with all other applicable [tex]NEC[/tex] requirements, such as those related to raceway fill, grounding, and overcurrent protection.
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