Write 7.725666118 as a percentage
please show the method too.

Answer:

below

Step-by-step explanation:

1.

[tex] \sqrt{80 } = 4 \sqrt5[/tex]

[tex]5 \sqrt{45} = 15 \sqrt{5} [/tex]

[tex]4 \sqrt{5} + 15 \sqrt{5} = 19 \sqrt{5} [/tex]

2.

[tex]2 \sqrt{72} = 12 \sqrt{2} [/tex]

[tex]3 \sqrt{50} = 15 \sqrt{2} [/tex]

[tex]12 \sqrt{2} - 15 \sqrt{2} = - 3 \sqrt{2} [/tex]

The digit 5 in 89.059 is greater than the digit 5 in 78.365.

To compare the digit 5 in the numbers 89.059 and 78.365, we need to look at the place value of the digit 5 in both numbers. In 89.059, the digit 5 is in the thousandth place, while in 78.365, the digit 5 is in the hundredth place.

Since the digit 5 in the thousandth place has a greater place value than the digit 5 in the hundredth place, it means that the digit 5 in 89.059 is greater than the digit 5 in 78.365.

To understand this concept better, consider the place value system of decimal numbers, where each digit represents a specific place value. The rightmost digit represents the units, the next digit to the left represents the tens, and so on.

Moving leftwards, each digit's place value increases by a factor of 10. Thus, the digit 5 in the thousandth place has a place value of 0.001, which is greater than the place value of the digit 5 in the hundredth place, which is 0.01. Therefore, the digit 5 in 89.059 is greater than the digit 5 in 78.365.

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Answer:

I found a video that provides the answer key for the Ankara Güçlendiren

Step-by-step explanation:

Roehr Corporation Additional Paid-in Capital--Common account will increase by $110,000 by issuing 20,000 shares of $0.50 par common stock for $6 per share.

When a corporation issues common stock, the par value of the stock is recorded in the Common Stock account, and any amount received above the par value is recorded in the Additional Paid-in Capital--Common account. In this case, Roehr Corporation The par value of the common stock is

Total par value = Par value per share x Number of shares

= $0.50 x 20,000

= $10,000

The total amount received from issuing the stock is $6 per share x 20,000 shares = $120,000.

The additional paid-in capital is calculated as the difference between the total amount received and the total par value:

Additional paid-in capital = Total amount received - Total par value

= $120,000 - $10,000

= $110,000

Therefore, the answer is (B) $110,000.

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we cannot simply write equation 5c + 3d as 8c, 8d, or 8cd.

A variable in mathematics is a symbol or letter that is used to indicate a quantity in a mathematical statement or equation that can have many values. It is a symbol that may be used to represent an arbitrary or undefined integer in algebraic expressions and equations.

In the equation 5c + 3c = 8c, we can combine the two terms on the left side because they have the same variable (c) and the same exponent (1).

However, in the expression 5c + 3d, the two terms have different variables (c and d) and cannot be combined in the same way. Therefore, we cannot simply write 5c + 3d as 8c, 8d, or 8cd.

If we want to simplify the expression 5c + 3d, we can only write it in its simplest form or factor it further if possible.

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Answer:

  5 meters

Step-by-step explanation:

You want to know the width of a rectangular living room that is 12 m along one side and 13 m along the diagonal.

The diagonal of a rectangle is the hypotenuse of each of the right triangles it creates by dividing the rectangle in half. If one side length is 12 and the diagonal is 13, these measures are part of the {5, 12, 13} Pythagorean triple.

The width of the living room is 5 meters.

__

Additional comment

You can use the Pythagorean theorem to find the missing length:

  13² = 12² +w²

  169 -144 = w²

  w = √25 = 5

The width of the living room is 5 meters.

Other Pythagorean triples you see in algebra, trig, and geometry problems are {3, 4, 5}, {7, 24, 25}, {8, 15, 17}, {9, 40, 41} and their multiples.

Answer: 2/3

Step-by-step explanation: 1/2 converted to 6ths is 3/6 add them together and it’s 4/6 simplify that and it’s 2/3

The calculated volume of the figure is 761.97 cubic inches

From the question, we have the following parameters that can be used in our computation:

The volume of the figure is calculated as

Volume = Cylinder + Cone - Hollow cylinder

So, we have

Volume = 3.14 * (8/2)^2 * 18 + 1/3 * 3.14 * (8/2)^2 * 5 - 3.14 * (2)^2 * 18

Evaluate

Volume = 761.97

Hence, the volume is 761.97 cubic inches

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The function that possesses a period of 16 units, a midline at y=3, and a maximum at y=8 is f(x) = 5 sin(π/8 x) + 3

The sine function with a period of 16 units, a midline at y=3, and a maximum at y=8 can be written in the form:

y = A sin(Bx) + C

where A is the amplitude, B is the frequency (related to the period), and C is the vertical shift (related to the midline).

The frequency is related to the period by the formula: B = 2π/period.

So, in this case,

B = 2π/16 = π/8.

So, we have

y = A sin(π/8x) + C

Using the list of options as a guide the sine function that satisfies these conditions is f(x) = 5 sin(π/8 x) + 3

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The amount of fluid that a person should drink per day can vary depending on factors such as their age, sex, weight, activity level, and climate.

The Institute of Medicine recommends that men should consume about 3.7 liters (125 ounces) of fluid per day, while women should consume about 2.7 liters (91 ounces) of fluid per day. This includes fluid from all sources, including water, other beverages, and food.

It is important to note that individual fluid needs may vary and may be influenced by factors such as health conditions, medications, and pregnancy or breastfeeding. It is always a good idea to consult with a healthcare professional to determine the appropriate amount of fluid intake for your specific needs.

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A client's daily fluid intake should be around 3,700 ml for men and 2,700 ml for women, keeping in mind that individual needs may vary.

Remember to round to the nearest whole number if necessary.

As a concise answer bot, I cannot provide a 200-word response.

How many ml of fluid a client should drink per day, we need to consider general guidelines for daily fluid intake.
The general recommendation for daily fluid intake is approximately:
- For men: 3,700 ml (about 13 cups)
- For women: 2,700 ml (about 9 cups)
These amounts include fluids from all sources, such as water, beverages, and food.

Please note that individual needs may vary depending on factors such as age, activity level, and climate.

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The polynomials that are equivalent to  (x-3y+72)2 are

A polynomial is described as an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables.

A polynomial equation in two variables is an equation of the form

p(x, y) = q(x, y) where both p(x, y) and q(x, y) are polynomials in two variables.

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The weight of the plane if it is carrying gallons of fuel is 2336 pounds, under the condition of when carrying 10 gallons, and 45 gallons he airplane weighs 2056  and 2252 pounds.
We can utilize the two given points to create two linear equations

y = mx + b
2056 = 10m + b
2252 = 45m + b

We can find m and b by subtracting the first equation from the second equation:

(45m + b) - (10m + b) = 2252 - 2056
35m = 196
m = 5.6

For finding b by substituting m into one of the original equations:

2056 = 10(5.6) + b
b = 2000

The equation is

y = 5.6x + 2000

To evaluate  how much the airplane weighs when carrying 60 gallons of fuel,  now lets substitute x into the equation

y = 5.6(60) + 2000
y = 336 + 2000
y = 2336

The weight of the plane if it is carrying gallons of fuel is 2336 pounds, under the condition of when carrying 10 gallons, and 45 gallons he airplane weighs 2056  and 2252 pounds.

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The complete question is
Suppose that the weight (in pounds) of an airplane is a linear... Suppose that the weight (in pounds) of an airplane is a linear function of the amount of fuel (in gallons) in its tank. When carrying 10 gallons of fuel, the airplane weighs 2056 pounds. When carrying 45 gallons of fuel, it weighs 2252 pounds. How much does the airplane weigh if it is carrying 60 gallons of fuel?

The length and width of the square picture frame are both approximately 7.08 inches. The dimensions of the picture that would fit inside the frame are approximately 6.5 inches.

In a square, the diagonal is a line segment that connects opposite corners of the square. Since a square has four congruent sides, we can use the Pythagorean theorem to find the length of the diagonal "d" in terms of the length "s" of the sides. The formula used is given by

=> d² = s² + s²

Here we have

The diagonal of the frame is 10 inches

Let's assume that the length and width of the square picture frame are both "x" inches.

Then, using the Pythagorean theorem, we can express the length of the diagonal (d) of the square picture frame in terms of "x":

=> d² = x² + x²  

Simplifying this equation, we get:

=> d² = 2x²

We know that the length of the diagonal is 10 inches, so we can write:

=> 100 = 2x²

Solving for "x", we get:

=> x² = 50

=> x = 5√2

=> x = 7.071 inches

Therefore,

The length and width of the square picture frame are both approximately 7.08 inches.

To find the dimensions of the picture that would fit inside the frame, we can simply subtract a margin of, say, 0.5 inches from each dimension to allow for the picture to fit comfortably within the frame.

So, the dimensions of the picture that would fit inside the frame are approximately 6.5 inches by 6.5 inches.

Therefore,

The length and width of the square picture frame are both approximately 7.08 inches. The dimensions of the picture that would fit inside the frame are approximately 6.5 inches.

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Answer:

425.2

Step-by-step explanation:

v = 1/3[tex]\pi r^{2} h[/tex]  If the diameter is 12,  then the radius is 6

v = [tex]\frac{3.14(6^{2})12 }{3}[/tex]

v = [tex]\frac{3.14(36)(12)}{3}[/tex]

v = 452.16

Helping in the name of Jesus.

There are almost 8 different dessert options that can be served.

Given that there are four fruit alternatives (watermelon, cantaloupe, pineapple and mango) and two ice cream selections (lemon or piquin chilli), the question asks how many different dessert options are offered. We can utilise the multiplication principle of counting. In this case, there are 4 ways to choose a fruit and 2 ways to choose an ice cream flavor. Using the multiplication principle, we can multiply these choices to find the total number of dessert options:

4 (fruit options) x 2 (ice cream options) = 8

Therefore, there are 8 different dessert options that can be served.

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--The complete Question is, Today's dessert is any of these fruits: watermelon, cantaloupe, pineapple or mango, accompanied by lemon or piquin chili ice cream. How many different desserts can be served? --

Answer:

Let's use a system of equations to solve the problem.

Let x be the number of regular admission tickets sold, and y be the number of fast pass tickets sold.

From the problem, we know that:

x + y = 104 (equation 1)

and

8x + 22y = 1280 (equation 2)

We can use equation 1 to solve for x in terms of y:

x = 104 - y

Substituting this expression for x into equation 2, we get:

8(104 - y) + 22y = 1280

Simplifying and solving for y, we get:

832 - 8y + 22y = 1280

14y = 448

y = 32

So the student sold 32 fast pass tickets.

To find the number of regular admission tickets sold, we can substitute y = 32 into equation 1 and solve for x:

x + 32 = 104

x = 72

So the student sold 72 regular admission tickets.

Therefore, the student sold 72 regular admission tickets and 32 fast pass tickets.

Answer:

Rounding to the nearest whole number, we predict that the Star Wars Lego Death Star set has approximately 80 pieces. However, it's important to note that this prediction is based solely on the given model and may not necessarily reflect the actual number of pieces in the set.

Step-by-step explanation:

The given equation for the model is y = 0.16x, where y represents the number of pieces in a Lego set and x represents the cost of the set in dollars.

To use this model to predict the number of pieces in the Star Wars Lego Death Star set that costs $499.99, we substitute x = 499.99 into the equation and solve for y:

y = 0.16x

y = 0.16(499.99)

y = 79.9984

The function has a minimum value of -2 that occurrs at x = -1

Given that

g(x) = 2x^2 + 4x

This is a quadratic function with a positive leading coefficient (2), which means that it opens upward and so it has a minimum value.

We can find the vertex of the parabola (the point where it changes direction) by using the formula:

x = -b/2a

where a and b are the coefficients of the quadratic function.

In this case, a = 2 and b = 4, so:

x = -4/(2*2) = -1

To find the corresponding y-value (the minimum value of the function), we substitute x = -1 into the function:

g(-1) = 2(-1)^2 + 4(-1) = -2

Therefore, the minimum of the parabola is at the point (-1, -2).

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The elements of the given relations in the set P = {(x, y) : y = 3x - 1, x ≤ 4, x ∈ N} are: (a) y = x: {(1, 1), (2, 2), (3, 3), (4, 4)}

(b) y = 4x: {(1, 4), (2, 8), (3, 12), (4, 16)}

(c) x + y: {(1, 3), (2, 7), (3, 11), (4, 15)}

(d) x + y ≥ 20: {(3, 8), (4, 11)}

To find the elements of the given relations in the set P = {(x, y) : y = 3x - 1, x ≤ 4, x ∈ N}, we substitute the x-values from the set P into the corresponding equations.

(a) y = x:

In this relation, the y-values will be the same as the x-values.

Substituting the x-values from the set P into the equation, we get:

(1, 2), (2, 5), (3, 8), (4, 11)

So, the elements of the relation y = x in the set P are:

{(1, 1), (2, 2), (3, 3), (4, 4)}

(b) y = 4x:

Substituting the x-values from the set P into the equation, we get:

(1, 4), (2, 8), (3, 12), (4, 16)

So, the elements of the relation y = 4x in the set P are:

{(1, 4), (2, 8), (3, 12), (4, 16)}

(c) x + y:

Substituting the x-values from the set P into the equation, we get:

(1, 2), (2, 5), (3, 8), (4, 11)

So, the elements of the relation x + y in the set P are:

{(1, 3), (2, 7), (3, 11), (4, 15)}

(d) x + y ≥ 20:

Substituting the x-values from the set P into the inequality, we get:

(1, 2), (2, 5), (3, 8), (4, 11)

So, the elements of the relation x + y ≥ 20 in the set P are:

{(3, 8), (4, 11)}

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(a) Total number of trips = 270

(b) There are 33 different visits that could make.

We have the information:

There are 18 major sea islands in the queen Elizabeth islands of Canada. There are 15 major lakes in Saskatchewan, Canada.

Let us say that A indicates the major sea Islands and B indicates the major lakes.

Taking both the cases as events, we will use multiplication principle.

Based on the information, the event A occurs in m ways and the event B will occur in n ways. So, the two events will occur in m×n ways.

(a) A × B = 18 × 15

Total number of trips = 270

(b) |A| = 18

|B| = 15

A ∩B = θ         (as we cannot visit both an island and lake)

Addition Principle: There are |A| + |B| ways to choose an element form

A ∪ B , when A and B are the finite sets with A ∩B = θ

|A ∪ B| = |A| + |B| = 18 + 15 = 33

Thus, There are 33 different visits that could make.

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A graph of four points with integer coordinates that are each 3 units away from (2, 3) is shown in the image attached below.

In Mathematics and Geometry, the translation of a graph to the left simply means subtracting a digit from the value on the x-coordinate of the pre-image while the translation of a graph downward simply means subtracting a digit from the value on the y-coordinate (y-axis) of the pre-image.

In Mathematics and Geometry, a horizontal translation to the left is modeled by this mathematical equation g(x) = f(x + N).

Where:

In order to write an equation that models the four points with integer coordinates that are each 3 units away from (2, 3), we would have to apply a set of translation to f(x) by 3 units:

A (5, 3)

B (-1, 3)

C (2, 6)

D (2, 0)

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The graph of the solution set can be seen in the image at the end.

Here we have the inequality:

-(6 + 1/2)y + 9 > -17

First, we need to isolate the variable y, then we will get:

9 + 17 > (6 + 1/2)y

26 > 6.5y

26/6.5 > y

4 > y

The graph of this will be an open circle at y = 4, and an arrow that goes to the left, the graph can be seen in the image at the end.

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For a survey to put an estimate the proportion of voters who support gun control, the minimum sample size is 752 that is minimum 752 people need to be included in the sample.

We have a survey which is planned to estimate the proportion of voters who support gun control. Margin of error, MOE = 3% = 0.03

Confidence level = 90% = 0.90

No information about the proportion of the voters that is p,so let's assume, p= 0.5

Level of significance, α = 1 - CI

= 1 - 0.90 = 0.10

We have to determine the sample size of people. Using the following formula for computes minimum sample size required to estimate population proportion within the required margin of error, [tex]n ≥ p( 1-p) (\frac{z_c}{MOE})²[/tex]

where, n --> sample size

[tex]z_c[/tex]--> critical value of z

using the Z-distribution table, the value of z for 90% confidence interval is 1.64.

Substitute all known values in above formula, [tex]n ≥ 0.5( 1- 0.5) (\frac{1.64}{0.03})²[/tex]

= 751.54 ~ 752( people must be a integer no.)

Hence, required minimum sample size is 752.

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Answer: Luis will spend a total of $22,868.48 on his lease.

Step-by-step explanation: To calculate the total cost of Luis's lease, we need to multiply the monthly cost by the number of months in the lease:

Total cost = monthly cost x number of months

The number of months in 4 years is 4 x 12 = 48 months.

Therefore, the total cost of Luis's lease is:

Total cost = $475.86/month x 48 months

Total cost = $22,868.48

So Luis will spend a total of $22,868.48 on his lease.

The equation in the interval [0, 2π) 3csc^2x=4 are: x = π/3 and x = 2π/3.

We can start solving the equation by isolating the csc^2(x) term, using the fact that csc^2(x) = 1/sin^2(x):

3csc^2(x) = 4

csc^2(x) = 4/3

1/sin^2(x) = 4/3

sin^2(x) = 3/4

Taking the square root of both sides, we get:

sin(x) = ±√(3/4) = ±(√3)/2

Since we are looking for solutions in the interval [0, 2π), we need to determine the angles in this interval whose sine is equal to ±(√3)/2. These angles are π/3 and 2π/3, since sin(π/3) = √3/2 and sin(2π/3) = √3/2.

Therefore, the solutions in the interval [0, 2π) are:

x = π/3 and x = 2π/3.

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The width of the rectangle is x + 4

Since the area of the rectangle is x^2 + 15x + 44, the product that give the value can be solved by factorization

To factorize the expression x^2 + 15x + 44, we need to find two numbers whose product is 44 and whose sum is 15. These numbers are 11 and 4, because 11 times 4 is 44 and 11 plus 4 is 15.

Now we can write the expression as:

x^2 + 11x + 4x + 44

Grouping the terms in pairs:

(x^2 + 11x) + (4x + 44)

Factoring out the greatest common factor from each pair:

x(x + 11) + 4(x + 11)

Now we can see that we have a common factor of (x + 11):

(x + 11)(x + 4)

Therefore, the factored form of x^2 + 15x + 44 is:

(x + 11)(x + 4)

the width of the rectangle is x + 4

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A) Let the side length of the square base be x, and the height of the box be h. Then, the volume of the box is given by:

V = [tex]x^2[/tex] * h = 8500

Solving for h, we get:

h = 8500 / [tex]x^2[/tex]

The surface area of the box can be expressed as:

S = 2x^2 + 4xh

Substituting the value of h obtained above, we get:

S = [tex]2x^2[/tex] + 4x(8500 / [tex]x^2[/tex]) = 2[tex]x^2[/tex]+ 34000 / x

Thus, the surface area of the box can be expressed as a function of x.

B) To graph the function, plot the surface area (S) on the y-axis and the side length of the square base (x) on the x-axis. Since x cannot be negative, the domain of the function is (0, infinity). As x gets very large or very small, the surface area approaches infinity, so we should only graph the function for values of x that make sense in the context of the problem.

C) The minimum amount of cardboard required to construct the box is equal to the surface area of the box. To find the minimum surface area, we need to find the minimum of the function S(x) obtained in part A.

D) To find the dimensions of the box that minimize the surface area, we need to find the value of x that minimizes the function S(x). We can do this by taking the derivative of S(x) with respect to x, setting it equal to zero, and solving for x. This gives us:

dS/dx = 4x - 34000/[tex]x^2[/tex] = 0

Multiplying both sides by [tex]x^2[/tex] and solving for x, we get:

x = (8500/2[tex])^(1/3)[/tex] ≈ 18.3

Therefore, the dimensions of the box that minimize the surface area are a square base with side length of approximately 18.3 inches, and a height of:

h = 8500 / [tex]x^2[/tex] ≈ 26.2 inches

E) UPS might be interested in designing a box that minimizes the surface area because it can reduce the amount of cardboard used in each box, resulting in cost savings and a reduced environmental impact. Additionally, minimizing the surface area of a box can make it more efficient to stack and transport, reducing shipping costs and making the overall process more sustainable.

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A) The Surface Area = [tex]X^2 + 34000/X[/tex]

B) The y-axis and the side length X on the x-axis.

C) The minimum amount of cardboard required to construct the box is approximately 1649.39 square inches.

D) The dimensions of the box that minimize the surface area are X = 20.5 inches and Y = 16.87 inches.

E)  Smaller boxes take up less space in delivery trucks and planes, allowing more packages to be shipped at once and reducing transportation costs.

A) Express the surface area of the box as a function of X:

Let the side length of the square base be X and the height of the box be Y. Then, we know that the volume of the box is 8500 cubic inches, so:

[tex]X^{2Y} = 8500[/tex]

To find the surface area of the box, we need to add up the area of each face. There are 5 faces in total (the bottom square and 4 identical rectangular sides), so:

Surface Area = [tex]X^2 + 4XY[/tex]

We can substitute the value of Y from the equation for volume, giving:

Surface Area = [tex]X^2 + 4X(8500/X^2)[/tex]

Surface Area = [tex]X^2 + 34000/X[/tex]

B) Graph the function found in part a:

To graph this function, we can plot the surface area on the y-axis and the side length X on the x-axis. The graph will have a minimum value, which we can find using calculus or by using a graphing calculator.

C) What is the minimum amount of cardboard that can be used to construct the box:

The minimum amount of cardboard required to construct the box is the surface area of the box. To find this minimum value, we need to find the minimum point on the graph in part b. From the graph or by using calculus, we can see that the minimum occurs at X = sqrt(8500/5) = 20.5 inches. Substituting this value into the equation for surface area, we get:

Surface Area = [tex]20.5^2 + 4(20.5)(8500/20.5^2)[/tex]= 1649.39 square inches

D) What are the dimensions of the box that minimize the surface area:

From part c, we know that the minimum occurs at X = sqrt(8500/5) = 20.5 inches. To find the height of the box, we can substitute this value of X into the equation for volume:

[tex]X^2Y = 8500[/tex]

[tex](20.5)^2 Y = 8500[/tex]

[tex]Y = 8500/(20.5)^2 = 16.87[/tex] inches

E) Why might UPS be interested in designing a box that minimizes the surface area:

UPS and other parcel delivery services are always looking for ways to reduce their costs and increase efficiency. By designing a box that minimizes the surface area while still containing the same volume of goods, they can reduce the amount of cardboard used for each shipment. This would save them money on materials and shipping costs, while also reducing their environmental impact. Additionally, smaller boxes take up less space in delivery trucks and planes, allowing more packages to be shipped at once and reducing transportation costs.

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Step-by-step explanation:

[tex] - 3 = \frac{3}{4} (2) + b[/tex]

[tex] - \frac{6}{2} = \frac{3}{2} + b[/tex]

[tex]b = - \frac{9}{2} [/tex]

[tex]y = \frac{3}{4} x - \frac{9}{2} [/tex]

Alternately, starting at (2, -3), go up 3 units, then right 4 units, to (6, 0). Draw a line that goes through these points.

the values of k for which the equation 2x² + x + 4k has (a) two real solutions are k < 1/32, (b) one real solution is k = 1/32, and (c) no real solutions are k > 1/32.

How to solve the question?

The given equation is 2x² + x + 4k.

(a) For the equation to have two real solutions, the discriminant b² - 4ac must be positive.

Therefore, for this equation, b² - 4ac > 0

=> 1 - 4(2)(4k) > 0

=> 1 - 32k > 0

=> k < 1/32

Hence, all values of k less than 1/32 will give the equation 2x² + x + 4k two real solutions.

(b) For the equation to have one real solution, the discriminant b² - 4ac must be zero.

Therefore, for this equation, b² - 4ac = 0

=> 1 - 4(2)(4k) = 0

=> 1 - 32k = 0

=> k = 1/32

Hence, only the value of k equal to 1/32 will give the equation 2x² + x + 4k one real solution.

(c) For the equation to have no real solutions, the discriminant b² - 4ac must be negative.

Therefore, for this equation, b² - 4ac < 0

=> 1 - 4(2)(4k) < 0

=> 1 - 32k < 0

=> k > 1/32

Hence, all values of k greater than 1/32 will give the equation 2x² + x + 4k no real solutions.

In conclusion, the values of k for which the equation 2x² + x + 4k has (a) two real solutions are k < 1/32, (b) one real solution is k = 1/32, and (c) no real solutions are k > 1/32.

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