zhangjin xu the jet engine of an airplane takes in 120 kg of air per second, which is burned with 4.2 kg of fuel per second. the burned gases leave the plane at a speed of 550 m/s (relative to the plane). If the plane is traveling 270 m/s (600 mi/h ), determine the following quantities. Part A - The thrust due to ejected fuel. Part B - The thrust due to accelerated air passing through the engine. Express your answer using two significant figures. Part C - The power (hp) delivered. Express your answer using two significant figures.

Answers

Answer 1

Therefore, the thrust due to ejected fuel is 2310 N, the thrust due to accelerated air passing through the engine is 98340 N, and the power delivered is 3260 hp.

What is acceleration?

Acceleration is the rate of change of velocity of an object with respect to time. It is a vector quantity, meaning that it has both magnitude and direction. Acceleration occurs when an object changes its speed, its direction, or both. A positive acceleration means that the speed of an object is increasing, while a negative acceleration (also called deceleration) means that the speed of an object is decreasing. The standard unit of acceleration is meters per second squared.

Here,

To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system is conserved when there are no external forces acting on it. In this case, we can assume that the airplane and the burned gases form a closed system, so the total momentum of the system is conserved.

Part A: To find the thrust due to ejected fuel, we can use the equation:

Thrust = (mass flow rate of fuel) x (exit velocity of burned gases)

Thrust = (4.2 kg/s) x (550 m/s) = 2310 N

Part B: To find the thrust due to accelerated air passing through the engine, we can use the equation:

Thrust = (mass flow rate of air) x (exit velocity of air) + (mass flow rate of fuel) x (exit velocity of burned gases)

The mass flow rate of air is 120 kg/s, and the exit velocity of air is the sum of the speed of the airplane and the speed of the air relative to the airplane. We can use the formula for the velocity addition to find the exit velocity of air:

exit velocity of air = speed of airplane + speed of air relative to airplane

exit velocity of air = 270 m/s + 550 m/s = 820 m/s

Now we can substitute the values into the equation:

Thrust = (120 kg/s) x (820 m/s) + (4.2 kg/s) x (550 m/s)

Thrust = 98340 N

Part C: To find the power delivered by the engine, we can use the equation:

Power = Thrust x Velocity

We can use the speed of the airplane as the velocity, since this is the speed at which the engine is delivering thrust to the airplane. The speed of the airplane is 270 m/s, which is equivalent to 603 mi/h. To convert the thrust from Newtons to pounds-force (lbf), we can divide by the conversion factor 4.448 N/lbf. Then we can use the following formula to convert the power from watts to horsepower:

1 hp = 746 W

Substituting the values into the equation, we get:

Power = (98340 N / 4.448 N/lbf) x (603 mi/h) / (3600 s/h) x (1 hp / 746 W)

Power = 3260 hp

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Related Questions

A 12-foot ladder is leaning against a wall. The bottom of the ladder is 5 feet away from the bottom of the wall. Approximately how high up the wall does the top of the ladder reach? responses 2. 4 feet 2. 4 feet 7. 0 feet 7. 0 feet 10. 9 feet 10. 9 feet 13. 0 feet.

Answers

The ladder's top extends around 10.9 feet up the wall. Solution is option d.

Using the Pythagorean theorem, we can determine the height up the wall that the top of the ladder reaches,

c^2 = a^2 + b^2

where c is the length of the ladder, a is the distance from the bottom of the ladder to the wall, and b is the height up the wall that the top of the ladder reaches.

In this case,

c = 12 feet

a = 5 feet

Plugging these values into the equation,

b^2 = c^2 - a^2 = 12^2 - 5^2 = 144 - 25 = 119

b = sqrt(119) = 10.9 feet (approximately)

Therefore, the top of the ladder reaches approximately 10.9 feet up the wall. Answer is option d.

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--The complete question is, A 12-foot ladder is leaning against a wall. The bottom of the ladder is 5 feet away from the bottom of the wall. Approximately how high up the wall does the top of the ladder reach?

a. 2.4 feet

b. 7.0 feet

c. 0.9 feet

d. 10.9 feet

e. 13.0 feet.--

A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 280. 5 m from the wall and the sound of her voice travels at 340. 0 m/s at that location. How long after she shouts will she hear her echo.

Answers

The hiker will hear her echo 1.65 seconds after she shouts.

To determine how long it takes for the hiker to hear her echo, we need to calculate the time it takes for the sound to travel from the hiker to the canyon wall, reflect off the wall, and travel back to the hiker.

Let's start by calculating the time it takes for the sound to travel from the hiker to the canyon wall. We can use the formula:

Time = distance / speed

where distance is the distance between the hiker and the canyon wall, and speed is the speed of sound.

Plugging in the given values, we get:

Time = 280.5 m / 340.0 m/s = 0.825 s

So it takes 0.825 s for the sound to travel from the hiker to the canyon wall.

Now we need to calculate the time it takes for the sound to travel from the canyon wall back to the hiker. This time will be the same as the time it took for the sound to travel from the hiker to the canyon wall, since the distance is the same and the speed of sound is constant.

Therefore, the total time it takes for the hiker to hear her echo is:

total time = 2 x time = 2 x 0.825 s = 1.65 s

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Jaycie wants to increase her upper body strength by doing push-ups. She does one push-up by applying a force of 10 n to raise her center of gravity 2 m. How many push-ups must jaycie complete to do 200 j of work?.

Answers

Jaycie would need to complete 10 push-ups to do 200 J of work, assuming that the force and displacement are the same for each push-up.

The work done by Jaycie to do one push-up is equal to the product of the force applied and the displacement of her center of gravity:

Work = Force x Displacement x cos(theta)

where theta is the angle between the force vector and the displacement vector. In this case, we can assume that the angle is 0 degrees, since the force is applied vertically upward and the displacement is vertically upward as well.

So the work done by Jaycie to do one push-up is:

Work = Force x Displacement = 10 N x 2 m = 20 J

To do 200 J of work, Jaycie would need to do:

Number of push-ups = Total work ÷ Work per push-up = 200 J ÷ 20 J/push-up = 10 push-ups

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Using the diagram belows. Which of the following statements is correct?

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Using the diagram belows. Point A is directly above Point C statements is correct.

What is diagram?

A diagram is a visual representation of information or data. It is used to help people better understand complex or abstract concepts, or to compare and contrast various elements. Diagrams are often used to provide an overall picture of a process, such as a flow chart, or a visual representation of the components of a system, such as a circuit diagram. Diagrams may also be used to explain the relationships between objects, such as in a Venn diagram. Diagrams are most commonly used in the fields of mathematics, engineering and science to illustrate concepts, but are also used in other disciplines such as business and art.

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Complete Question

Using the diagram belows. Which of the following statements is correct?

A. Point B is directly to the right of Point C.

B. Point A is directly above Point C.

C. Point D is directly below Point B.

D. Point A is directly to the left of Point D.

Polar coordinates are used for planes. Extending this system into three dimensions in the simplest way results in a cylindrical coordinate system. A cylindrical coordinate system uses the same r and as in polar coordinates, with an added dimension along to the z-axis. The three coordinates that define a point in a cylindrical coordinate system is the triple (r, , z). Consider a point in the three-dimensional Cartesian coordinate system, (3, −4, 6) cm. Dacia and Katarina compute the corresponding point in a cylindrical coordinate system, whose origin corresponds to the origin in the Cartesian system. Which point do they find?

Answers

Answer:

Explanation:

Cartesian coordinates Cylindrical coordinate

What is the power consumed across AB?

Answers

The power consumed across AB would be 4W.

What Is a Resistor?

A passive electrical component called a resistor prevents the flow of electric current by introducing resistance. They are prevalent in practically all electrical networks and electronic circuits. Ohms () are used to measure resistance. An ohm is the resistance that develops when a resistor has a one-volt (V) drop between its terminals and a one-ampere (A) current flows through it.

Five resistors in total are positioned at various points in the terminal AB in the preceding diagram. We must now determine the five resistors' equivalent resistance.

Let's split it into two sections. Two resistors make up the part below and three resistors make up the part above.

Now, we must determine the part's actual resistance.

Req=(r1r2/ r1+r2)×r3 * (r1r2/ r1+r2+r3)⇒Req=7×721∴Req=7/3

The obtained resistance is then parallel to the below traitor and in series with the neighboring resistor.

The net effective resistance will therefore be b,

Req=7/3+7=28/3\s⇒Reff=28/3×7/49/3∴Reff=4Ω

As a result, the power through terminal AB will be as follows:

P=1×4=4W.

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A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 57 J of kinetic energy?

Answers

The work-energy theorem states that an object's kinetic energy changes as a result of the net work done on it.

Describe energy?

Energy is referred to by scientists as the capacity for work. Energy is the force that moves things, and since people have figured out how to convert it from one form to another and use it to do labour, modern civilization is possible. Potential energy and kinetic energy are the two categories of energy.

Describe a force?

An object can be made to move by force. It is applied to an item in the same manner as addition—adding one thing to another. Magnitude: A force's strength is typically described by its magnitude

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fill in the blanks waves can travel through ____ .air granite rock molten magma water sandstone mudstone

Answers

Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.

What is a wave?

In physics, a wave is a disturbance that travels through space and time, usually accompanied by the transfer of energy. Waves can be characterized by their amplitude, wavelength, frequency, and speed.

Here,

Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.

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find the acceleration of the elevator (magnitude and direction).express your answer with the appropriate units. enter positive value if the direction of the acceleration is upward and negative value if the direction of the acceleration is downward.

Answers

The acceleration of the elevator is -2.2 m/s2 downwards.

What is Acceleration?

Acceleration is a vector quantity that describes the rate of change of an object's velocity over a period of time. It is measured in metres per second squared (m/s2). Acceleration is not the same as speed, which is the rate at which an object moves in a particular direction. Acceleration can be either positive (speeding up) or negative (slowing down) and is caused by an applied force, such as friction or gravity. The acceleration of an object changes with time and is dependent on the object's mass, drag, and the force that is applied to it.

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please answer this question!!

Answers

Answer:

Explanation:

difícil

Describe the magnetic poles and magnetic field

Answers

The magnetic pole is referred to as the region at each end of a magnet where the external magnetic field is strongest while a magnetic field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.

What is a Magnetic field?

This is referred to as a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A bar magnet suspended in Earth's magnetic field orients itself in a north–south direction and is referred to as a magnetic pole which has magnetic field present in the region also.

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60. A friction block consists of a piece of wood with slotted masses on top of it. If you double the total mass of the block plus slotted masses, how does the coefficient of static friction between the friction block and concrete change?

Answers

The change in the coefficient of static friction between the friction block and concrete change would be Zero which means it will not change.

How does mass affect the coefficient of static friction?

The coefficient of static friction between two surfaces does not depend on the mass of the object. Therefore, doubling the total mass of the friction block and slotted masses would not change the coefficient of static friction between the block and the concrete.

The coefficient of static friction is a property of the two surfaces in contact and is affected by factors such as the roughness of the surfaces, the materials they are made of, and the amount of force pressing the surfaces together.

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An object weighing 300 N in air is immersed in water after being tied to a string connected to a balance. The scale now reads 262 N. Immersed in oil, the object appears to weigh 273 N. Find the density of the oil.

Answers

Answer:

Approximately [tex]711\; {\rm kg \cdot m^{-3}}[/tex], (approximately [tex]0.711\; {\rm g \cdot cm^{-3}}[/tex],) assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].

Explanation:

The density of water is [tex]\rho(\text{water}) =10^{3}\; {\rm kg \cdot m^{-3}}[/tex].

The buoyancy force on an object immersed in a liquid is equal to the weight of the liquid that object displaces.

While in water, the buoyancy force on the object in this question is [tex](300 - 262)\; {\rm N} = 38\; {\rm N}[/tex]. In other words, this object displaces [tex]38\; {\rm N}[/tex] of water. Divide weight by [tex]g[/tex] to find mass:

[tex]\begin{aligned}m(\text{water displaced}) &= \frac{38\; {\rm N}}{9.81\; {\rm N\cdot kg^{-1}}} \approx 3.8736\; {\rm kg} \end{aligned}[/tex].

Since the object is fully immersed, the volume of water displaced would be equal to the volume of the object. Divide the mass of the water displaced by the density of water to find this volume:

[tex]\begin{aligned}V(\text{water displaced}) &= \frac{m(\text{water displaced})}{\rho(\text{water})} \\ &\approx \frac{3.8736\; {\rm kg}}{10^{3}\; {\rm kg \cdot m^{-3}}} \\ &= 3.8736 \times 10^{-3}\; {\rm m^{3}}\end{aligned}[/tex].

[tex]V(\text{object}) = V(\text{water displaced}) \approx 3.8736 \times 10^{-3}}\; {\rm m^{3}}[/tex].

When the object is immersed in oil, the volume of oil displaced would also be equal to the volume of this object:

[tex]V(\text{oil displaced}) = V(\text{object}) \approx 3.8736 \times 10^{-3}}\; {\rm m^{3}}[/tex].

It is given that the buoyancy force on this object is [tex](300 -273)\; {\rm N} =27\; {\rm N}[/tex] when immersed in oil. Similar to the case when the object is in water, the object would displace [tex]27\; {\rm N}[/tex] of oil. The mass of that much oil would be:

[tex]\begin{aligned}m(\text{oil displaced}) &= \frac{27\; {\rm N}}{9.81\; {\rm N\cdot kg^{-1}}} \approx 2.7523\; {\rm kg} \end{aligned}[/tex].

Divide mass of the oil displaced by volume to find density:

[tex]\begin{aligned}\rho(\text{oil}) &= \frac{m(\text{oil displaced})}{V(\text{oil displaced})} \\ &\approx \frac{2.7523\; {\rm kg}}{3.8736 \times 10^{-3}\; {\rm m^{3}}} \\ &\approx 711\; {\rm kg\cdot m^{-3}}\end{aligned}[/tex].

The average atomic mass of element a is 63. 6 atomic mass units. The only naturally occurring isotopes of element a are a-63 and a-65. What is the percent abundance of a-63 in a naturally occurring sample of element a to the nearest whole number percentage?.

Answers

The percent abundance of a-63 in a naturally occurring sample of element a is 70% if we have data of atomic mass

The percent abundance of a-63 in a naturally occurring sample of element a can be calculated using the formula:

percent abundance of a-63 = (mass of a-63 / average atomic mass) x 100%

Since there are only two naturally occurring isotopes of element a, we can write the average atomic mass as a weighted average of the masses of a-63 and a-65, where the weighting factor is the percent abundance of each isotope. Let x be the percent abundance of a-63. Then:

average atomic mass = (mass of a-63 x percent abundance of a-63 + mass of a-65 x percent abundance of a-65) / 100

Substituting:

[tex]63.6 = (63 * x + 65 * (100 - x)) / 100[/tex]

Multiply sides by 100:

[tex]6360 = 63x + 65(100 - x)[/tex]

Expanding brackets:

[tex]6360 = 63x + 6500 - 65x[/tex]

Simplify:

-140 = -2x

x = 70

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In a shipping company distribution center, an open cart of mass 50.0 kg is rolling to the left at a speed of 5.00 m/s. You can ignore friction between the cart and the floor. A 15.0 kg package slides down a chute that is inclined at 37º from the horizontal and leaves at the end of the chute with a speed of 3.00 m/s. The package lands in the cart and they roll off together. If the lower end of the chute is a vertical distance of 4.00 m above the bottom of the cart, what are (a) the speed of the package just before it lands in the cart (b) the final velocity of the cart?

Answers

An open cart with a mass of 50.0 kg is moving to the left at the a speed of 5.00 m/s at a freight company distribution centre. Don't think about the cart's contact with the floor

Fast speed test: What is it?

Your current Web speed can be estimated with the FAST.com speed test. For users who are accessing content online, download speed is extremely important, and we want Suitable for the target market to be an incredibly easy and quick speed test. Your download speed and link latency can be seen when you select.

What is an object's speed?

The speed that an object travels a distance can be conceived of as its speed. A slow-moving object travels a relatively short distance in a given length of time, whereas a fast-moving object travels a big distance in a short amount of time.

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kinetic energy of an object whose mass is 1Kg and it is moving at a velocity of 5m/s.

Answers

The kinetic energy of the object is: KE = 0.5 x 1 kg x (5 m/s)2

 = 12.5 J

What is kinetic energy?

Kinetic energy is the energy of motion. It is the energy an object has due to its motion. Kinetic energy can be defined as the energy an object has due to its mass and its velocity. Kinetic energy is measured in Joules (J). Kinetic energy increases with increasing mass and velocity of an object. When an object is at rest, it has zero kinetic energy. When an object is in motion, it has kinetic energy. Kinetic energy is a form of energy that is associated with the motion of an object. It is the energy that is stored in the movement of an object. Kinetic energy is one of the fundamental forms of energy, along with potential energy.

Kinetic energy is the energy possessed by an object due to its motion. It is a form of energy that can be calculated using the equation:

Kinetic energy (KE) = 0.5 x Mass (m) x Velocity (v)2

In this case, the mass of the object is 1 kg and its velocity is 5 m/s.

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PLEAS HELP
The picture is to answer the questions and here are the questions


The Death of Georgi Markov and the Attack on Vladimir Kostov (1978)

1. What was the delivery method of the ricin?
2. What are the symptoms of ricin poisoning?
3. How much ricin did they find in Markov?

Tylenol Tampering (1982)

1. How many people died?
2. What are the circumstances surrounding the deaths?
3. When/where did the tampering likely occur? How do they know?
4. What is the significance of this case?

Answers

I ain’t reading that all for 5 points

hich of the following is a minimal sum-of-products (SOP) equation that implements the same logic as the equation f(a, b, c) = a(b + c') + ac a. f = ab + ac b. f = ab + ac' + be c. f=a d. f = b(a + d) e. f = a(b + b)(b + c)

Answers

The minimal SOP equation that implements the same logic as the given equation is f = ab + ac.

What is SOP?

The sum of product (SOP) is a type of logic circuit used to represent a logical expression. It is also known as a canonical sum of products and is a type of canonical form. An SOP expression is composed of one or more product terms. Each product term is the logical AND of one or more literals and is separated from other product terms with a plus sign. The sum of product form of a logic expression is a sum of the product terms of the expression.

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A hydraulic system is designed to lift a maximum weight of 10,000 N. If the output piston has a diameter of 10 cm, what should be the diameter of the input piston?

Answers

In a hydraulic system, the force exerted on the output piston is equal to the force exerted on the input piston. This means that the force exerted on the output piston, which is the maximum weight of 10,000 N, is equal to the force exerted on the input piston.

The force exerted on a piston is equal to the pressure times the area of the piston. The pressure is the same on both sides of the hydraulic system, so we can set the pressures on the input and output pistons equal to each other:

pressure_input = pressure_output

The area of the output piston is given by:

A_output = πr_output^2

where r_output is the radius of the output piston, which is half the diameter of 10 cm:

r_output = 10 cm / 2 = 5 cm = 0.05 m

A_output = π(0.05 m)^2 = 0.00785 m^2

The force on the output piston is 10,000 N, so we can use the formula for the force on a piston to solve for the pressure:

F_output = P_output × A_output

P_output = F_output / A_output = 10,000 N / 0.00785 m^2 = 1,273,885 Pa

Now we can use the formula for the force on the input piston to solve for the diameter:

F_input = P_input × A_input

Since the force on the input piston is the same as the force on the output piston, we have:

F_input = F_output = 10,000 N

We also know that the pressure on the input piston is equal to the pressure on the output piston, so we can substitute the values we found for the pressure and area of the output piston:

F_input = P_output × A_input

10,000 N = 1,273,885 Pa × πr_input^2

r_input = √(10,000 N / (1,273,885 Pa × π)) = 0.128 m

The radius of the input piston is 0.128 m, so the diameter is:

d_input = 2r_input = 0.256 m = 25.6 cm (rounded to one decimal place)

Therefore, the diameter of the input piston should be approximately 25.6 cm in order to lift a maximum weight of 10,000 N in this hydraulic system.

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If the normal force exerted on the rock as it slides through its lowest point (point b) is twice the weight of the rock, how much work did friction do on the rock as it moved from a to b?.

Answers

The work done by friction as the rock moves from point a to point b is equal in magnitude to the potential energy of the rock at point a, and it is negative because it acts in the opposite direction to the displacement of the rock

To determine how much work friction did on the rock as it moved from point a to point b, we need to first consider the forces acting on the rock and the work done by each force.

At point a, the rock has only potential energy due to its position above the ground. As it slides down the slope towards point b, the potential energy is converted to kinetic energy, and the rock gains speed.

The forces acting on the rock as it slides down the slope are:

The force of gravity acting downward, with a magnitude equal to the weight of the rock (mg).

The normal force acting perpendicular to the slope, which is equal in magnitude but opposite in direction to the force of gravity (2mg at point b).

The force of friction acting parallel to the slope, in the opposite direction to the motion of the rock.

Since the rock is sliding down the slope, the force of friction must be acting in the direction opposite to the motion, which means that the work done by friction is negative.

The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. In this case, we can assume that the initial velocity of the rock at point a is zero, so its initial kinetic energy is also zero.

At point b, the rock has reached its maximum speed and all of its potential energy has been converted to kinetic energy. Therefore, the work done by gravity is equal to the change in potential energy:

[tex]mgh = (1/2)mv^2[/tex]

where m is the mass of the rock, g is the acceleration due to gravity, h is the vertical distance between points a and b, v is the speed of the rock at point b.

Solving for v, we get:

[tex]v = \sqrt{(2gh)}[/tex]

The work done by the normal force is zero, since it acts perpendicular to the displacement of the rock.

The work done by friction is given by:

[tex]W_{friction} = -f * d[/tex]

where f is the force of friction and d is the horizontal distance between points a and b.

To determine the force of friction, we can use the fact that it is equal in magnitude to the normal force multiplied by the coefficient of friction (μ):

f = μ * N

At point b, the normal force is twice the weight of the rock, so N = 2mg. The coefficient of friction is not given, so we cannot calculate the exact value of the work done by friction.

However, we can make some general observations about the work done by friction based on the information given. Since the normal force at point b is twice the weight of the rock, this implies that the slope is steeper at point b than it is at point a. This in turn implies that the force of friction at point b is greater than it is at point a. Therefore, we can conclude that the work done by friction is negative and that its magnitude is greater than zero.

Finally, we can use the work-energy principle to calculate the work done by friction:

[tex]W_{friction} = -mgh = -[(1/2)mv^2][/tex]

Substituting the expression we derived for v, we get:

[tex]W_{friction} = -mgh = -[(1/2)m(2gh)] = -mgh[/tex]

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Long wavelength visible light
will have a greater energy than

short wavelength visible light.
will have a speed that is faster than short wavelength light.
has a higher frequency than short wavelength visible light.
will appear blue in color to the average human eye.
will appear red in color to the average human eye.

Answers

Longer wavelength visible lights generally have low frequency and energy as compared to shorter wavelength visible lights. This is because the wavelength is inversely proportional to energy and frequency.

What wavelength of light is visible to the human eye?

The visible light spectrum is the segment of the electromagnetic spectrum that the human eye can view with unaided eyes. This range of wavelengths is called visible light. Typically, the human eye can easily detect wavelengths from 380 to 700 nanometers.

These wavelengths of light are perceived through the human eyes with the help of specific kinds of cells, that are known as rod and cone cells. special cells called rods and cones live in the retina. These cells are the eye's lookouts. Different rods and cones react to different wavelengths, or colors, of light.

Therefore, longer wavelength visible lights generally have low frequency and energy as compared to shorter wavelength visible lights.

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The kinetic energy of a moving object is 34j
. If the mass of the object is 6kg • Calculate its height.

Answers

The velocity of the moving object is 3.37 m/s.

What is kinetic energy?

The energy of the body due to its movement is called its kinetic energy. We can write -

E{K} = 1/2 mv²

Given is that the kinetic energy of a moving object is 34 joules. The mass of the object is 6kg.

We can write the kinetic energy as -

1/2 mv² = 34

mv² = 68

v² = 68/6

v² = 34/3

v² = 34/3

v = 3.37 m/s

Therefore, the velocity of the moving object is 3.37 m/s.

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According to newton's third law of motion, when one object exerts a force on a second object, what are the forces? question 16 options: opposite in magnitude and equal in direction equal in magnitude and opposite in direction opposite in magnitude and opposite in direction equal in magnitude and equal in direction.

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According to Newtons third law of motion when one object exerts a force on a second object, then true statement about the force is option (D) They are equal in magnitude and opposite in direction

Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on a second object, the second object exerts an equal and opposite force on the first object. This law applies to any two objects that interact with each other, and the forces they exert on each other always have the same magnitude but act in opposite directions.

To understand this law, let's consider an example of a person pushing a wall. When a person pushes a wall, the person exerts a force on the wall, but the wall also exerts an equal and opposite force on the person. The force that the wall exerts on the person is equal magnitude but opposite in direction to the force that the person exerts on the wall. As a result, the person feels a force pushing back on them, which is why they cannot push the wall over.

Therefore, the correct option is (D) They are equal in magnitude and opposite in direction

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A hippo is dozing under water with only its small nostrils sticking out. It has a mass of 1600 kg and a volume of about 1.57 m3 after exhaling. How much force does it exert on the ground of the pool (fresh water, density 1g/cm3)?

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The concept Buoyant force is used here to determine the force which on the ground of the pool. The buoyant force is 15385.21 N.

What is Buoyant force?

The Buoyant force is defined as the upward force exerted on an object which is fully or partially immersed in a liquid. This force is also called the Upthrust. Due to this force a body immersed in a fluid appears to lose its weight.

The Buoyant force is calculated as:

F = mg × ρ fluid / ρ hippo

Density of hippo = Mass/volume

= 1600/1.57 = 1019.10 kg/m³

Density of fluid = 1 g/cm³ = 1000 kg/m³

F = 1600 × 9.8 × 1000/1019.10 = 15385.21 N

Thus the Buoyant force is 15385.21 N.

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The carnival ride from Prob 12.51 is modified so that the 80 kg riders can move up and down the inclined wall as the speed of the ride increases. Knowing that the coefficient of static friction between the wall and the platform is 0.2, determine the range of values of the constant speed v0 for which the platform will remain in the position shown.

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The range of values of the constant speed v0 for which the platform will remain in the position shown is 0 < v0 < 3.2 m/s.

What is position?

Position is the location of an object within a defined space. It is typically expressed as a set of coordinates, such as (3, 5), or as an angle, such as 30 degrees. Position can also refer to the occupation or job of a person, such as a CEO or engineer. In physics, position is the location of an object in relation to other objects or points of reference. In mathematics, position is an important concept in geometry, where shapes and angles are determined by their relative positions. In economics, position is a term used to describe a company's financial standing, such as its stocks, bonds, and other investments.

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A 0.40-kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 7.0 N for a distance of 3.5 m. How much kinetic energy does the block gain?

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Answer:

24.5 J

Explanation:

The work done on the block by the force is:

W = Fdcos(theta)

where F is the applied force, d is the distance over which the force is applied, and theta is the angle between the force and the displacement. In this case, the force is in the same direction as the displacement, so cos(theta) = 1.

W = (7.0 N)(3.5 m)(1) = 24.5 J

Since the surface is frictionless, all the work done on the block goes into increasing its kinetic energy. The kinetic energy gained by the block is therefore:

K = W = 24.5 J

So the block gains 24.5 J of kinetic energy.

in the following questions you will be asked to rank these rods. if multiple rods rank equallly use the same rank for each then exclude the intermediate ranking

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a.) From greatest to least in order of the strength of the electric field they contain:

Rod 1 (L, 3d, V)

Rod 3 (3L, 2d, 2V)

Rod 2 (2L, d, 2V)

What kind of accounting system only keeps track of transactions when money is used to pay for things and when it is used to make purchases?

Inversely proportional to the distance between the charges, the field strength is proportional to the potential difference.

As a result of its relatively small diameter and large potential difference, rod 1 has the strongest electric field. Due to its longer length, which offsets its larger diameter, Rod 3 has the second-highest electric field strength, while Rod 2 has the lowest due to its larger diameter and smaller potential difference.

b.) Ranking by current density within them (greatest to least):

Rod 2 (2L, d, 2V)

Rod 1 (L, 3d, V)

Rod 3 (3L, 2d, 2V)

Inversely proportional to the rod's length and cross-sectional area, the current density is proportional to the potential difference. Because of its smaller cross-sectional area and longer length, Rod 2 has the highest current density. This is due to its smaller diameter. Due to its smaller diameter than Rod 3, Rod 1 has the next highest current density, and Rod 3 has the lowest current density as a result of both its larger diameter and length.

c.) Ranking by drift speed of electrons through them (greatest to least):

Rod 3 (3L, 2d, 2V)

Rod 1 (L, 3d, V)

Rod 2 (2L, d, 2V)

The amount of current flowing through a device affects how quickly electrons drift, while the cross-sectional area of a rod has an adverse effect. Because of its smaller diameter and consequently smaller cross-sectional area, which makes up for its longer length, Rod 3 has the highest electron drift speed of all the rods.

Due to its smaller diameter than Rod 2 and longer length, Rod 1 has the next-highest electron drift speed, and Rod 2 has the lowest electron drift speed.

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Complete Question:

In the following questions, you will be asked to rank these rods. If multiple rods rank equally, use the same rank for each, then exclude the intermediate ranking (i.e. if objects A, B, and C must be ranked, and A and B must both be ranked first, the ranking would be A:1, B:1, C:3). If all rods rank equally, rank each as '1'.

A 11 N force moves an object 9 m. What is the work?

Answers

Answer :

99 Joules

Step-by-step explanation :

Given:

Force = 11 N Displacement = 9 m

Work done = Force × Displacement

On substituting the values, we get :

Work done = 11 × 9

Work done = 99 joules

which of the following structures is/are necessary to initiate the muscle action potential? select all that apply. view available hint(s)for part c which of the following structures is/are necessary to initiate the muscle action potential?select all that apply. tropomyosin troponin motor neuron myosin acetylcholine muscle fiber actin t-tubule ryanodine receptor calcium motor end plate ach receptor-channels ca2 -atpase submit

Answers

Answer:

muscle fiber, acetylcholine, ACh receptor-channels, motor neuron, motor end plate

Explanation:

Those are the ones that are necessary to initiate the muscle action.

An object is dropped from a height of 23 m. At what height will its kinetic energy and its potential energy be equal?

Answers

Answer:

Explanation:

We can use the conservation of energy to determine at what height the kinetic energy (KE) and potential energy (PE) of the object are equal. At any given point during the fall, the total mechanical energy of the object is equal to the sum of its kinetic energy and potential energy, and it remains constant throughout the fall.

Initially, when the object is dropped from a height of 23 m, it only has potential energy. At this point, the potential energy of the object is given by:

PE = mgh

where m is the mass of the object, g is the acceleration due to gravity (9.81 m/s^2), and h is the height of the object above some reference point. Plugging in the given values, we get:

PE = mgh = m × 9.81 m/s^2 × 23 m

Next, we need to determine the kinetic energy of the object when its potential energy is equal to the potential energy at some height h. At this point, the object has fallen a distance of (23 - h) meters, and its potential energy has been converted into kinetic energy. Therefore, we can write:

KE = 1/2 mv^2 = PE = mgh

where v is the velocity of the object at height h. Solving for v, we get:

v = sqrt(2gh)

Now we can calculate the kinetic energy of the object at height h:

KE = 1/2 mv^2 = 1/2 m (sqrt(2gh))^2 = mgh

We can see that the kinetic energy is equal to the potential energy at height h. So we can set the two equations for PE and KE equal to each other and solve for h:

mgh = 1/2 m (sqrt(2gh))^2

Simplifying this equation, we get:

h = 1/2 (sqrt(2gh))^2 / g

h = 1/2 (2gh) / g

h = h

Therefore, the height at which the kinetic energy and potential energy of the object are equal is h = 23 / 2 = 11.5 meters.

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