Answer:
To convert grams of CO2 to moles, we need to divide the given mass by the molar mass of CO2.
The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for carbon + 2(16.00 g/mol) for oxygen).
Dividing 12.3 g by 44.01 g/mol gives:
12.3 g / 44.01 g/mol = 0.279 moles
Therefore, 12.3 grams of CO2 is equivalent to 0.279 moles.
2.6. A mortar mixture of portland cement, sand, and water, but no hydrated lime, would probably produce a mortar with A. greater strength and workability.
B. insufficient bonding strength. C. little resistance to moisture penetration.
D. insufficient water retention.
B. insufficient bonding strength.
Hydrated lime is often added to mortar mixes to improve bonding strength between the bricks or stones being used. Without hydrated lime, the mortar may not bond well to the building materials, resulting in a weaker overall structure. While the absence of hydrated lime may slightly increase the strength and workability of the mortar, it is not worth sacrificing bonding strength.
The mortar may also have little resistance to moisture penetration without the addition of hydrated lime. Insufficient water retention may also be a possibility, but it is not as significant a concern as inadequate bonding strength.
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How many g of Al(NO3)3 would be in
0.089 L of a 0.63 M solution of
AL(NO3)3?
There are 12.00 grams of Al(NO₃)₃ in 0.089 L of a 0.63 M solution of Al(NO₃)₃.
What do you understand by the number of moles?The number of moles is a unit used to measure the amount of a substance, defined as the amount of a substance that contains as many elementary entities (such as atoms, molecules, or ions) as there are atoms in 12 grams of carbon-12. One mole of a substance contains Avogadro's number of entities, which is approximately 6.022 × 10^23 particles.
The number of moles can be calculated by dividing the mass of a substance by its molar mass or by dividing the amount of substance (in units of molecules, atoms or ions) by Avogadro's number.
To calculate the amount of Al(NO₃)₃ in grams present in 0.089 L of a 0.63 M solution of Al(NO₃)₃, we can use the formula:
mass = molarity × volume × molar mass
where:
molarity is the concentration of the solution in moles per liter (M)
volume is the volume of the solution in liters (L)
molar mass is the mass of one mole of the compound in grams per mole (g/mol)
First, let's calculate the number of moles of Al(NO₃)₃ present in 0.089 L of the solution:
moles = molarity × volume = 0.63 M × 0.089 L = 0.05607 mol
The molar mass of Al(NO₃)₃ is:
Al(NO₃)₃ = Al + 3(NO₃) = 1(26.98 g/mol) + 3(63.01 g/mol) = 213.97 g/mol
Now we can use the formula to calculate the mass of Al(NO₃)₃:
mass = moles × molar mass = 0.05607 mol × 213.97 g/mol = 12.00 g
Therefore, there are 12.00 grams of Al(NO₃)₃ in 0.089 L of a 0.63 M solution of Al(NO₃)₃.
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A mixture of air and gas is considered hazardous when the mixture exceeds what percentage of the lower explosive limit (LEL)?
a.) 0%
b.) 3%
c.) 7%
d.) 10%
A mixture of air and gas is considered hazardous when the mixture exceeds 10% of the lower explosive limit (LEL).
In gas-detection systems, the amount of gas present is specified as a percentage (%) of LEL. Zero percent Lower Explosive Limit (0% LEL) denotes a combustible gas-free atmosphere. One hundred percent lower explosive limit (100% LEL) denotes an atmosphere in which gas is at its lower flammable limit. The relationship between percent LEL and percent by volume differs from gas to gas. The Lower Explosive Limit (LEL) is the lowest concentration of a gas or vapour that will burn in air. The Lower Explosive Limit (LEL) varies from gas to gas, but for most flammable gases it is less than 5% by volume. Atmospheres with a concentration of flammable vapors at or above 10 percent of the lower explosive limit (LEL) are considered hazardous when located in confined spaces. However, atmospheres with flammable vapors below 10 percent of the LEL are not necessarily safe. Such atmospheres are too lean to burn.
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Question 65
The highest home radon concentration levels are most likely to be found in:
a. Upstairs halls
b. Dining areas
c. Basements
d. Near windows
The highest home radon concentration levels are most likely to be found in: c. Basements
Radon is a radioactive gas that comes from the natural decay of uranium in soil, rock, and water. It typically moves up through the ground and into homes through cracks and other holes in the foundation. Basements are closest to the ground and have more direct contact with the soil, which leads to higher radon concentration levels compared to other areas of the home.Radon gas enters homes through the foundation and accumulates in damp, low-lying areas such as basements, crawl spaces, and other areas with poor ventilation. Upstairs halls, dining areas, and near windows are not typically areas where radon gas concentrations are high.
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in the following reaction, how many molecules of bh3 are required to react with 6 molecules of 2-methyl-2-butene? ch9 d2 q5.pdf
The number of molecules of BH₃ is 2 to react with 6 molecules of 2-methyl-2-butene.
The smallest recognisable unit into which a pure material may be split while retaining its composition and chemical characteristics is a molecule, which is a collection of two or more atoms.
Until portions consisting of single molecules are reached, the division of a sample of a substance into progressively smaller parts does not result in a change in either its composition or its chemical characteristics. Still smaller parts of the substance are produced by further subdivision, and these parts are always different chemically and typically have different compositions from the original substance. The chemical links that hold the atoms in the molecule together are severed at this final step of fragmentation.
Atoms are made up of a single positively charged nucleus that is surrounded by a cloud of negatively charged electrons. Atoms interact with one another and with their nuclei when they are near to one another. The atoms join together to form molecules if this contact lowers the system's overall energy level.
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mr. turner would like to fill his alprazolam 1mg with a sig of 1 q8h, what is wrong with this prescription?
The prescription for Mr. Turner's alprazolam 1mg with a sig of 1 q8h is missing important information such as the duration of the treatment and the total number of pills to be dispensed.
Without this information, the patient may not know how long to take the medication and may run out before the treatment is complete. Additionally, the frequency of 1 q8h (once every 8 hours) may be too frequent for alprazolam and could result in an overdose or other adverse effects. It is important for the prescriber to provide clear and accurate instructions to ensure safe and effective use of the medication.
Mr. Turner's prescription for alprazolam 1mg has a sig of 1 q8h, which means he should take 1 tablet every 8 hours. There is nothing inherently wrong with this prescription, as long as it has been prescribed by a healthcare professional and is appropriate for Mr. Turner's medical condition.
Alprazolam is typically used to treat anxiety and panic disorders, and the dosage depends on the patient's individual needs and response to the medication.
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Mr. Turner's prescription for alprazolam 1mg with a sig of 1 q8h has the following issue:
The term "sig" refers to the directions for use, which in this case is "1 q8h." This means Mr. Turner should take 1 tablet every 8 hours. However, alprazolam is a benzodiazepine used to treat anxiety and panic disorders, and its dosing frequency is typically not as high as every 8 hours. The standard dosing frequency for alprazolam is usually 2-3 times a day.
The wrong aspect of this prescription is the dosing frequency (1 q8h) which may lead to potential overuse or increased side effects. It is essential to consult with a healthcare professional to determine the appropriate dosing and frequency for Mr. Turner's needs.
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If I have an unknown quantity of gas at a pressure of 2.2 atm, a volume of 31 liters, and a temperature of 67
∘
C, how many moles of gas do I have?
The moles of gas do that he has is 0.024 moles.
The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g
Given,
Pressure = 2.2 atm
Volume = 31 L
Temperature = 67C
PV = nRT
2.2 × 31 = n × 8.314 × 341
n = 0.024 moles
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there are some data that suggest that zinc lozenges can significantly shorten the duration of a cold. if the solubility of zinc acetate, zn(ch3coo)2 , is 43.0 g/l , what is the solubility product ksp of this compound? express your answer numerically.
The solubility product, ksp = 2.58 x 10^-2 mol^3/L^3.
What do you understand by solubility product?Solubility product refers to the equilibrium constant for the dissolution of a sparingly soluble compound in water. In other words, it is a measure of the extent to which a solid compound will dissolve in water.
The solubility product constant (Ksp) for zinc acetate, Zn(CH₃COO)₂, is given by the following equation:
Zn(CH₃COO)₂ ⇌ Zn²⁺ + 2CH₃COO⁻
The Ksp expression for this reaction is:
Ksp = [ Zn²⁺][CH₃COO⁻]^2
To determine the Ksp of zinc acetate, we need to know the concentration of Zn²⁺and CH₃COO⁻ ions in a saturated solution. Since the solubility of zinc acetate is 43.0 g/L, we can assume that a saturated solution contains 43.0 g of zinc acetate per liter of water.
The molar mass of zinc acetate is:
MZn(CH₃COO)₂ = (1 x 65.38 g/mol Zn) + (2 x 12.01 g/mol C) + (6 x 1.01 g/mol H) + (4 x 16.00 g/mol O)
= 183.48 g/mol
The number of moles of zinc acetate in a liter of saturated solution is:
moles(Zn(CH₃COO)₂) = 43.0 g / 183.48 g/mol = 0.2344 mol/L
Since zinc acetate dissociates into one Zn²⁺ ion and two CH₃COO⁻ ions, the concentration of Zn²⁺ ions in the saturated solution is:
[ Zn²⁺] = 0.2344 mol/L
The concentration of CH₃COO⁻ ions is twice the concentration of Zn²⁺ ions:
[CH3COO-] = 2 x [ Zn²⁺] = 2 x 0.2344 mol/L = 0.4688 mol/L
Therefore, the Ksp of zinc acetate is:
Ksp = [ Zn²⁺][CH₃COO⁻]^2
= (0.2344 mol/L)(0.4688 mol/L)^2
= 0.0258 mol^3/L^3
Expressing this answer in scientific notation, we get:
Ksp = 2.58 x 10^-2 mol^3/L^3
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List two ways that carbon is found in its pure form:
Carbon is found in its pure form in two ways:
1) Graphite: Graphite is a form of pure carbon that is found naturally in crystalline form. It is a soft, black substance that is commonly used in pencils, lubricants, and batteries.
2) Diamond: Diamond is another form of pure carbon that is found naturally in the Earth's crust. It is the hardest known substance and is prized for its beauty and durability in jewelry and industrial uses.
Both graphite and diamond are pure forms of carbon, but they have different physical properties due to their different molecular structures. Graphite consists of sheets of carbon atoms arranged in a hexagonal lattice, while diamond consists of a three-dimensional network of carbon atoms arranged in a tetrahedral structure.
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The molecular formula of aspirin is C9H8O4. How many aspirin molecules are present inone 500-milligram tablet?A) 2.77 molecules D) 1.67 × 1021 moleculesB) 2.77 × 10-3 molecules E) None of these is correct.C) 1.67 × 1024 molecules
B) 2.77 × 10-3 molecules. To calculate the number of aspirin molecules in a 500-milligram tablet, we need to convert the mass to moles using the molar mass of aspirin.
The molar mass of aspirin (C9H8O4) is: 9 x 12.01 g/mol (for carbon) + 8 x 1.01 g/mol (for hydrogen) + 4 x 16.00 g/mol (for oxygen) = 180.16 g/mol So, the number of moles of aspirin in a 500-milligram tablet is: 500 mg ÷ 1000 mg/g ÷ 180.16 g/mol = 2.77 x 10^-3 moles Finally, we can convert moles to molecules by multiplying by Avogadro's number (6.02 x 10^23 molecules/mol): 2.77 x 10^-3 moles x 6.02 x 10^23 molecules/mol = 1.67 x 10^21 molecules Therefore, there are approximately 1.67 x 10^21 aspirin molecules in one 500-milligram tablet.
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a 25.00-ml sample of 0.175 m hcl is being titrated with 0.250 m naoh. what is the ph after 19.00 ml of naoh has been added?
The concentration of hydrogen ions in the solution rises as a result.
Calculation
To calculate the pH of the solution after the addition of the NaOH solution, we need to use the stoichiometry of the reaction between HCl and NaOH. The reaction's balanced equation is:
HCl + NaOH → NaCl + H2O
According to the equation, one mole of HCl interacts with one mole of NaOH to generate one mole of water and one mole of NaCl. Therefore, we can use the following equation to calculate the concentration of HCl remaining after the addition of the NaOH solution:
moles of HCl = initial moles of HCl - moles of NaOH added
The initial moles of HCl in the 25.00 mL of 0.175 M solution are:
moles of HCl = 0.175 mol/L x 0.02500 L = 0.004375 mol
The moles of NaOH added to the solution are:
moles of NaOH = 0.250 mol/L x 0.01900 L = 0.00475 mol
Therefore, the moles of HCl remaining after the addition of the NaOH solution are:
moles of HCl = 0.004375 mol - 0.00475 mol = -0.000375 mol
This negative value indicates that all of the HCl has been neutralized by the NaOH solution. The excess NaOH will contribute to the final pH of the solution.
To calculate the concentration of NaOH remaining in the solution, we can use the following equation:
moles of NaOH = initial moles of NaOH - moles of HCl added
The initial moles of NaOH in the 19.00 mL of 0.250 M solution are:
moles of NaOH = 0.250 mol/L x 0.01900 L = 0.00475 mol
The moles of HCl added to the solution are as follows:
moles of HCl added = 0.00475 mol
Therefore, the moles of NaOH remaining in the solution are:
moles of NaOH = 0.00475 mol - 0.00475 mol = 0 mol
The total volume of the solution after the addition of the NaOH solution is:
total volume = 25.00 mL + 19.00 mL = 44.00 mL = 0.04400 L
The concentration of the resulting solution is:
concentration = moles of NaCl / total volume
Since the moles of NaCl formed by the reaction are equal to the moles of HCl initially present, we can use the initial moles of HCl to calculate the concentration of the resulting solution:
concentration = 0.004375 mol / 0.04400 L = 0.0994 M
To calculate the pH of the resulting solution, we can use the formula:
pH = -log[H+]
where [H+] denotes the concentration of hydrogen ions in the solution. In this case, the hydrogen ions are formed by the dissociation of water:
H2O → H+ + OH-
The concentration of hydrogen ions in the solution is equal to the concentration of hydroxide ions since the solution is neutral:
[H+] = [OH-] = 1.0 x 10^-14 / [OH-]
Substituting the value of [OH-] from the equation for the dissociation of NaOH in water:
NaOH → Na+ + OH-
[OH-] = moles of NaOH remaining / total volume
[OH-] = 0 mol / 0.04400 L = 0 M
The concentration of hydrogen ions in the solution rises as a result.
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In an insulated cup of negligible heat capacity, 50 g of water at 40 C mixed with 30 g of water at 20 C. The final temperature of the mixture is closest toA. 22 CB. 27 CC. 30 CD. 33 CE. 38 C
The final temperature of the mixture is closest to C. 30 C
The temperature of the mixture will depend on the amount of heat transferred between the two bodies of water. We can use the formula Q = mcΔT, where Q is the heat transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
First, we need to find the initial heat content of the 40°C water and the 20°C water. For the 40°C water, we have:
Q1 = (50 g) (4.18 J/g°C) (40°C) = 8,360 J
For the 20°C water, we have:
Q2 = (30 g) (4.18 J/g°C) (20°C) = 2,514 J
When we mix the two waters together, they will eventually reach a final temperature that is somewhere in between 40°C and 20°C. Let's call this final temperature T. The total heat content of the mixture is then:
Qtotal = (50 g + 30 g) (4.18 J/g°C) (T - 20°C)
Since the insulated cup has negligible heat capacity, we can assume that no heat is lost to the surroundings. Therefore, the total heat content of the mixture is equal to the initial heat content of the 40°C water plus the initial heat content of the 20°C water:
Qtotal = Q1 + Q2
Substituting the values we calculated earlier and solving for T, we get:
(50 g + 30 g) (4.18 J/g°C) (T - 20°C) = 8,360 J + 2,514 J
T - 20°C = (10,874 J) / [(50 g + 30 g) (4.18 J/g°C)]
T - 20°C = 9.95°C
T = 29.95°C
The final temperature of the mixture is closest to 30°C. and therefore Option C is correct.
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The choices all have the same 4 sentences.
1.8. The steel in reinforced concrete A. furnishes rigidity. B. provides tensile strength. C. increases bond strength. D. adds ductility and durability.
In reinforced concrete, the steel (B) provides tensile strength, while the concrete itself offers compressive strength. The combination of these materials results in a more durable and rigid structure, with increased ductility and durability.
The steel reinforcement in reinforced concrete is added to provide tensile strength to the concrete. This is because concrete is strong in compression but weak in tension. The steel helps to distribute the tensile forces and increase the overall strength and durability of the concrete.At the atomic level, when atoms or molecules are pulled apart from each other and gain potential energy with a restoring force still existing, the restoring force might create what is also called tension. Each end of a string or rod under such tension could pull on the object it is attached to, in order to restore the string/rod to its relaxed length.
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2.8. A masonry course in which the long dimension of the exposed ends is placed vertically is called a A. header.
C. stretcher.
B. soldier.
D. rowlock.
A masonry course in which the long dimension of the exposed ends is placed vertically is called a
B. soldier.
Masons build structures with brick, block, and stone, some of the most common and durable materials used in construction. They also use concrete—a mixture of cement, sand, gravel, and water—as the foundation for everything from patios and floors to dams and roads. A course is a layer of the same unit running horizontally in a wall. It can also be defined as a continuous row of any masonry unit such as bricks, concrete masonry units (CMU), stone, shingles, tiles, etc
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A chemical system that resists changes in pH and prevents large swings in the pH is called __________.
A chemical system that resists changes in pH and prevents large swings in the pH is called a buffer system.
A buffer system is a mixture of a weak acid and its conjugate base, or a weak base and its conjugate acid. When a small amount of acid or base is added to a buffer solution, the buffer system reacts to neutralize the added acid or base, minimizing the change in pH. This is because the weak acid or base in the buffer solution can release or accept H+ ions to maintain the equilibrium of the system.
Buffer systems are important in many biological and chemical processes where pH control is crucial. In the human body, for example, the blood contains buffer systems that help to maintain the pH within a narrow range of 7.35-7.45, which is essential for proper physiological function.
In laboratory settings, buffer solutions are used to maintain a constant pH for experiments involving enzymes, DNA, and other biological molecules. Overall, buffer systems play an important role in maintaining the stability of chemical and biological systems.
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Part A Fluoroacetate functions as a poison by what mechanism? - The compound binds very tightly to but does not form a covalent complex with aconitase. - The compound forms a covalent complex with the aconitase. - This compound is first converted to 2-fluorocitrate, which subsequently inhibits aconitase. - Aconitase converts this compound to a reactive species that covalently modifies the next enzyme in the citric acid cycle
The mechanism by which Fluoroacetate functions as a poison involves the compound being first converted to 2-fluorocitrate, which subsequently inhibits aconitase.
This inhibition disrupts the citric acid cycle, which is necessary for cellular respiration and energy production. Fluoroacetate does not form a covalent complex with aconitase, but rather binds tightly to it. This binding ultimately leads to the inhibition of aconitase and disruption of the citric acid cycle, making it a potent and deadly poison. Fluoroacetate binds very tightly to but does not form a covalent complex with aconitase, preventing it from functioning. This process leads to the accumulation of citrate, which is then converted to 2-fluorocitrate by hydrolysis. 2-fluorocitrate then inhibits aconitase, leading to a decrease in the amount of ATP production. Ultimately, this leads to cellular death due to a decrease in ATP production.
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What happens if you block calcium influx into the axon terminal?
Blocking calcium influx into the axon terminal can have several effects on neuronal communication and neurotransmitter release.
Calcium influx into the axon terminal is a key step in the process of neurotransmitter release. When an action potential reaches the axon terminal, it triggers the opening of voltage-gated calcium channels, allowing calcium ions to flow into the terminal. The increase in intracellular calcium concentration triggers the fusion of synaptic vesicles containing neurotransmitters with the presynaptic membrane, and the subsequent release of the neurotransmitters into the synaptic cleft.
If calcium influx into the axon terminal is blocked, neurotransmitter release is inhibited or reduced. This can lead to a variety of effects, depending on the specific neurotransmitter and the location of the synapse. For example:
- Inhibition of excitatory neurotransmitter release could reduce synaptic transmission and decrease neuronal activity.
- Inhibition of inhibitory neurotransmitter release could increase synaptic transmission and increase neuronal activity.
- Inhibition of neurotransmitter release at neuromuscular junctions could lead to muscle weakness or paralysis.
Calcium channel blockers are a class of drugs that can be used to block calcium influx into axon terminals and reduce neurotransmitter release. These drugs are used to treat a variety of conditions, including high blood pressure, angina, and arrhythmias.
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#26. The pH of a 1L phosphate buffer solution was measured as 7.6, but the experimental procedure calls for a pH 7.2 buffer. Which method will adjust the solution to the proper pH? (Note: pKa values for phosphoric acid are 2.2, 7.2, and 12.3.)
The method that will adjust the solution to the proper pH is C. Alter the ratio of monosodium/disodium phosphate added to favor the monosodium species.
Phosphate buffer solutions consist of a mixture of monosodium phosphate ([tex]NaH_{2} PO_{4}[/tex]) and disodium phosphate ([tex]Na_{2} HPO_{4}[/tex]). These compounds are conjugate acid-base pairs, and their ratio determines the pH of the buffer solution. The pKa value of 7.2 corresponds to the second ionization constant of phosphoric acid ([tex]H_{3} PO_{4}H[/tex]), which is the most relevant in this case.
Since the current pH of 7.6 is higher than the desired pH of 7.2, you need to increase the concentration of the acidic species (monosodium phosphate) relative to the basic species (disodium phosphate). This will shift the equilibrium of the buffer solution towards a lower pH. Simply adding more [tex]Na_{2} HPO_{3}[/tex], NaOH, or distilled water, as suggested in options A, B, and D, would not effectively adjust the pH to the desired level.
By carefully adjusting the monosodium phosphate to disodium phosphate ratio, you can achieve the desired pH of 7.2 for your phosphate buffer solution. Therefore, option C is correct
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In the reduction reaction, the hot water and the 95% ethanol act as a solvent pair for the benzil. Which is the better solvent and which is the poorer one?
In the reduction reaction involving benzil, hot water and 95% ethanol act as a solvent pair. Among the two, ethanol is the better solvent as it can dissolve benzil more efficiently, while hot water serves as the poorer solvent due to its lower solubility for benzil.
In the reduction reaction, the 95% ethanol is the better solvent for benzil as it is able to dissolve more of the compound due to its polar nature. Hot water, on the other hand, is a poorer solvent for benzil as it is less polar and less able to dissolve the compound. However, both solvents are necessary for the reduction reaction as they help to create the necessary conditions for the reduction of benzil to take place.
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Emergency oxygen supplies aboard aircraft often are generated by the decomposition of sodium chlorate (NaClO3). NaClO3(s) + NaCl(s) + O2(g) Determine the percent yield if the decomposition of 75.0 g sodium chlorate generates 29.45 g of oxygen. (Hint: Check if the chemical reaction is balanced)
The chemical reaction is not balanced and must be balanced before the percent yield can be calculated. The balanced equation is: 25.2%
What is chemical reaction?A chemical reaction is a process in which substances interact with each other to form new substances with different properties. During a chemical reaction, atoms break apart from their original molecules and form new molecules by forming new bonds with other atoms. These new molecules have different properties from the original molecules, and the process of forming them is known as a chemical reaction.
2 NaClO₃(s) → 2 NaCl(s) + 3 O₂(g)
Theoretical yield of oxygen = 75.0 g NaClO₃ x (3 moles O₂/2 moles NaClO₃) x (32 g O₂/1 mole O₂) = 117.0 g O₂
Actual yield of oxygen = 29.45 g O₂
Therefore, percent yield = (Actual yield/Theoretical yield) x 100 = 25.2%
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A balloon filled with 1.92 g of He has a volume of 13.2 L. What is the balloon's volume after 0.850 g of He has leaked out through a small hole (assume ideal gas conditions)? Round your answer to 2 decimal places (mass of He = 4.003 g/mol)
2.05L is the balloon's volume after 0.850 g of He has leaked out through a small hole
What does the ideal gas law mean?
The rule that states that the sum of a gram's worth of an ideal gas's pressure, volume, and universal gas constant is equal to the sum of the gas's absolute temperature and universal gas constant.
There are four guiding presumptions for a gas to be "ideal": The gas particles' volume is minuscule. There are no intermolecular forces (attraction or repulsion) between the equal-sized gas particles and other gas particles. According to Newton's Laws of Motion, the gas particles travel at random.
V∝n
V₁/n₁m= V₂/n₂
V1 = 13.2L
V2 = ?
n1 = 4/1.92 = 2.08moles
n2 = 4/12.35 = 0.323
V2 = V1n2/n1
= 13.2*0.323/2.08
= 2.05L
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You label cells with a radioactive isotope of sulfur (35S). The only molecules that would be radioactively labeled in these cells are:
The only molecules that would be radioactively labeled in these cells are: Protein molecules.
Large biomolecules and macromolecules known as proteins are made up of one or more extended chains of amino acid residues. Among the many tasks that proteins carry out in living things include catalysing metabolic processes, replicating DNA, reacting to stimuli, giving cells and organisms shape, and moving chemicals from one place to another. The primary way that proteins differ from one another is in the order of their amino acids, which is determined by the nucleotide sequence of their genes and often causes a protein to fold into a certain 3D shape that controls its function.
A polypeptide is an ordered sequence of amino acid residues. At least one lengthy polypeptide is present in every protein. Less than 20–30 residue polypeptides are frequently referred to as peptides and are seldom thought of as proteins. Peptide bonds and nearby amino acid residues hold the individual amino acid residues together. The sequence of a gene, which is encoded in the genetic code, determines the arrangement of amino acid residues in a protein. The genetic code typically only defines the 20 conventional amino acids, but in certain species it may also include selenocysteine and—in some archaea—pyrrolysine.
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How did Dalton explain the formation of compounds?
A) Atoms divide into smaller parts.
B) Atoms chemically combine.
C) Mixtures of atoms are formed.
D) Copies of atoms are made
Dalton explained the formation of compounds by Atoms chemically combine. Option B is correct.
According to the Dalton's atomic theory, atoms are indivisible and they will combine in fixed ratios to form a compounds. He proposed that elements will consist of tiny, indivisible particles termed as atoms that will combine in simple, whole-number ratios to form a compounds.
He believed that atoms of different elements combine in the fixed ratios to form compounds, and that the ratio of their masses determines the ratio of their combining atoms.
Thus, Dalton explained that the formation of the compounds can occurs through a chemical combination of atoms, rather than through the division or copying of atoms.
Hence, B. is the correct option.
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Why would a chiral starting material yield a 50:50 mixture of enantiomers when it undergoes Sn1?
When a chiral starting material undergoes an Sn1 reaction, it yields a 50:50 mixture of enantiomers because of the formation of a planar carbocation intermediate.
1. The chiral starting material undergoes ionization, forming a planar carbocation intermediate. The chirality is lost during this process, as the intermediate is achiral.
2. Nucleophilic attack can occur from either face of the planar carbocation intermediate, leading to the formation of two enantiomers.
3. Since both faces of the carbocation intermediate are equally accessible to the nucleophile, the probability of attack from each side is the same. This results in a 50:50 mixture of enantiomers.
In summary, a chiral starting material yields a 50:50 mixture of enantiomers when it undergoes an Sn1 reaction due to the formation of a planar carbocation intermediate, which allows for nucleophilic attack from either face, ultimately leading to the equal probability of forming both enantiomers.
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calculate the final partial pressures of the gaseous components when you place 0.5 atm of carbon dioxide in a flask at 1000k
To calculate the final partial pressures of the gaseous components when 0.5 atm of carbon dioxide is placed in a flask at 1000K, we need to know the composition of the gas mixture.
We can use the ideal gas law and the mole fraction of each component to calculate the partial pressure of each component.
To calculate the final partial pressures of the gaseous components when 0.5 atm of carbon dioxide is placed in a flask at 1000K, we need to know the composition of the gas mixture.
Assuming we have a mixture of carbon dioxide and other gases, we can use the ideal gas law to determine the partial pressures of each component. The ideal gas law is expressed as PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
We can rearrange this equation to solve for the partial pressure of each component:
P = nRT/V
Assuming the volume of the flask is constant, we can simplify this equation to:
P = (n/V)RT
The number of moles of each component can be calculated using the mole fraction: n_i = x_i * n_total where n_i is the number of moles of component i, x_i is the mole fraction of component i, and n_total is the total number of moles in the mixture.
Assuming that carbon dioxide is the only component in the mixture, the partial pressure of carbon dioxide would be 0.5 atm. However, if there are other gases present in the mixture, we would need to know their mole fractions in order to calculate their partial pressures.
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Indicate the element that has been oxidized and the one that has been reduced.2Na + FeCl2 --> 2NaCl + Fe
In this reaction, the element that has been oxidized is Fe (iron) because it has lost electrons to form Fe²⁺ ions. The element that has been reduced is Na (sodium) because it has gained electrons to form Na+ ions.
Oxidation is the process of losing electrons, while reduction is the process of gaining electrons. In this case, sodium (Na) is oxidized because it loses electrons, going from its elemental state (Na) to forming Na+ ions (NaCl). Sodium loses one electron to become a Na+ ion. On the other hand, iron (Fe) is reduced because it gains electrons, going from a compound FeCl₂ (where iron is in the +2 oxidation state) to its elemental state (Fe). Iron gains two electrons to become neutral iron atoms.
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Write out the mechanism for the reaction of t-pentyl alcohol with concentrated hydrochloric acid including all proper electron pushing arrows.
The final product of the reaction is t-pentyl chloride.
The reaction of t-pentyl alcohol with concentrated hydrochloric acid proceeds via an S<sub>N</sub>1 mechanism, which can be described as follows:
Step 1: Protonation of the alcohol
The concentrated hydrochloric acid protonates the hydroxyl group of t-pentyl alcohol to form a oxonium ion intermediate, which is a better leaving group than the hydroxyl group.
t-pentyl alcohol + HCl → t-pentyl oxonium ion + Cl<sup>-</sup>
Step 2: Formation of the carbocation
The oxonium ion intermediate loses a water molecule to form a t-pentyl carbocation intermediate, which is stabilized by the electron-donating effect of the three methyl groups.
t-pentyl oxonium ion → t-pentyl carbocation + H<sub>2</sub>O
Step 3: Deprotonation of the chloride ion
A chloride ion acts as a nucleophile and attacks the carbocation, forming a new bond and releasing H<sup>+<sup> ion.
t-pentyl carbocation + Cl<sup>-</sup> → t-pentyl chloride + HCl
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How many grams of ethanol (C2H60) are required to produce 1,000
kJ during boiling? The heat of vaporization of ethanol is 38.6 kJ /
mole. Round to a whole number
16.95g is the mass of ethanol (C2H60) that are required to produce 1,000 kJ during boiling? The heat of vaporization of ethanol is 38.6 kJ / mole.
The most fundamental characteristic of matter is mass, which is one of the basic quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the international standard of mass. A nuclear reaction, for instance, results in the total weight of the substance being reduced as a tiny quantity of matter is transformed into a very large amount of energy.
moles of ethanol = 38.6/ 1,000=0.368moles
molecular weight of ethanol =46.07g/mol
mass = 0.368×46.07
= 16.95g
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Select all the options that correctly describe the electron configuration 1s^2 2s^2 2p^4
Option(A) and option(B) are the options that are correctly describe the electronic configuration 1s²2s²2p⁴, that is oxygen and N⁻ atoms.
In a modern periodic table which is organized by increasing atomic number. The atomic number is refer as the number of electrons present in the ground state of atom. Thus, the electronic configuration can be used to identify the atoms or ions. The electronic configuration is used to describe the distribution of electrons in different energy level around the nucleus. We have an electronic configuration is written as 1s²2s²2p⁴.
The atomic number of oxygen(O) atom is 8, and contains 8 electrons. So, electron configuration of oxygen atom is 1s²2s²2p⁴. The atomic number of Nitrogen(N) is 7, and contains 7 electrons. So, electron configuration of Nitrogen atom is 1s²2s²2p³. But for N⁻ the electronic configuration is addition of one electron in electronic configuration of N. That is 1s²2s²2p⁴. The electronic configuration of O²⁻ is written by 1s²2s²2p⁶.Hence, required answer are option(A) and (B).
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Complete question:
Select all the options that correctly describe the electron configuration 1s^2 2s^2 2p^4
A) Oxygen
B) [tex]N^{ -}[/tex]
C) [tex]O^{2 -}[/tex]